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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 705 questions

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121 Medium
121 of 705
Remembering +4 | -1
Among HClO2,\mathrm{HClO}_2, HClO3,\mathrm{HClO}_3, HClO\mathrm{HClO} and HClO4\mathrm{HClO}_4 which is most acidic in nature:
View answer and explanation
Correct option: D
HClO4\mathrm{HClO}_4
Option D (HClO4\mathrm{HClO}_4) is correct because the acidity of oxyacids increases with the number of oxygen atoms.
122 Easy
122 of 705
Understanding +4 | -1
The product formed when Cl2C{l_2} reacts with hot con. NaOHNaOH
View answer and explanation
Correct option: B
NaClO3NaCl{O_3}
Option B (NaClO3NaCl{O_3}) is correct because chlorine reacts with hot concentrated NaOH to form sodium chlorate (NaClO3NaCl{O_3}) along with sodium chloride and water.
123 Medium
123 of 705
Understanding +4 | -1
Which of the following is more acidic in nature?
View answer and explanation
Correct option: D
HCIO4HCI{O_4}
Option D (HCIO4HCI{O_4}) is correct because the acidity of oxyacids increases with the oxidation state of the central atom. Higher oxidation state means more polar O-H bond and easier release of H+.
124 Hard
124 of 705
Analyzing +4 | -1
Consider the following statements
(a) In acidic medium nitrous acid disproportionate to nitric acid and nitrogen gas
(b) Ammonium nitrate on heating gives nitrous oxide
(c) N – N bond is present both in N2O3andN2O4{N_2}{O_3}\mathrm{ }and\mathrm{ }{N_2}{O_4} gases
The correct statements are
View answer and explanation
Correct option: B
(b) and (c) only
Option B ((b) and (c) only) is correct because ammonium nitrate on heating gives nitrous oxide, and N-N bonds are present in both N₂O₃ and N₂O₄.
125 Easy
125 of 705
Remembering +4 | -1
Ozone is manufactured by carrying silent electric discharge using:
View answer and explanation
Correct option: C
Siemens and Halske’s ozonizer
Option C (Siemens and Halske’s ozonizer) is correct because ozone is manufactured using Siemens and Halske's ozonizer by carrying out a silent electric discharge.
126 Medium
126 of 705
Analyzing +4 | -1
Assertion: Group 15 elements are less reactive than Group 16 elements.
Reason: Group 15 elements have a higher ionization energy and a lower electronegativity than Group 16 elements.
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
Option B (Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion) is correct because while both statements are true, the reason doesn't fully explain the assertion.
127 Easy
127 of 705
Analyzing +4 | -1
When NF3\mathrm{NF}_3 undergoes hydrolysis at room temperature, then the product will be:
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because NF3NF_3 does not undergo hydrolysis at room temperature due to the absence of vacant d-orbitals on nitrogen and the high electronegativity of fluorine.
128 Medium
128 of 705
Understanding +4 | -1
Which of the following(s) when heated give nitrogen gas?
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Correct option: D
Both 1 and 2
Option D (Both 1 and 2) is correct because both ammonium dichromate and barium azide decompose upon heating to produce nitrogen gas.
129 Medium
129 of 705
Analyzing +4 | -1
Which of the following statements is wrong?
View answer and explanation
Correct option: A
Single N – N bond is stronger than the single P – P bond
Option C (CH3OCH2CH2CH3& CH3OCH(CH3)2\mathrm{CH}_3 \mathrm{OCH}_2 \mathrm{CH}_2 \mathrm{CH}_3 \&\, \mathrm{CH}_3 \mathrm{OCH}(\mathrm{CH}_3)_2) is correct because these two compounds are chain isomers, not metamers, as they differ in the carbon chain branching.
130 Easy
130 of 705
Understanding +4 | -1
Nitric acid whether diluted or concentrated:
View answer and explanation
Correct option: D
Hardly affects Al\mathrm{Al}
Option D (Hardly affects Al\mathrm{Al}) is correct because aluminum forms a passive layer of aluminum oxide (Al2O3\mathrm{A}{\mathrm{l}_2}{\mathrm{O}_3}) on its surface when exposed to nitric acid, preventing further reaction.
131 Easy
131 of 705
Remembering +4 | -1
Xenon directly combines with:
View answer and explanation
Correct option: C
Fluorine
Option C (Fluorine) is correct because Xenon directly combines with Fluorine to form fluorides.
132 Medium
132 of 705
Understanding +4 | -1
The substance which does not liberate oxygen on treatment with ozone is
View answer and explanation
Correct option: C
SO2S{O_2}
Option C (SO2S{O_2}) is correct because SO2S{O_2} reacts with ozone to form SO3S{O_3} without liberating oxygen.
133 Medium
133 of 705
Analyzing +4 | -1
Assertion (A): Noble gases have very high boiling point.
Reason (R): Noble gases have strong dispersion forces hence they liquify at low temperature, hence they have high boiling point.
View answer and explanation
Correct option: C
Assertion and Reason are false
Option C (Assertion and Reason are false) is correct because noble gases have very low boiling points due to weak dispersion forces, and the reason provided is also incorrect.
134 Easy
134 of 705
Understanding +4 | -1
When a brown compound of Mn(A)\mathrm{Mn}(\mathrm{A}) is treated with HCl\mathrm{HC}{l}, it gives a gas (B). The gas (B)(\mathrm{B}) taken in excess reacts with NH3\mathrm{NH}_3 to give an explosive compound (C)(\mathrm{C}). The compound A,B\mathrm{A}, \mathrm{B} and C\mathrm{C} are
View answer and explanation
Correct option: A
A=MnO2, B=Cl2,C=NCl3\mathrm{A}=\mathrm{MnO}_2, \mathrm{~B}=\mathrm{C}{l}_2, \mathrm{C}=\mathrm{NC}{l}_3
Option D (All of these) is correct because all the given expressions are valid representations of Kf, the cryoscopic constant.
135 Easy
135 of 705
Remembering +4 | -1
Which of the elements listed below shows allotropic forms?
View answer and explanation
Correct option: C
Sulphur
Option C (Sulphur) is correct because sulphur exhibits allotropy, existing in different forms such as rhombic, monoclinic, and plastic sulphur.
136 Easy
136 of 705
Understanding +4 | -1
NaOH can absorb :
View answer and explanation
Correct option: A
N2O5{N_2}{O_5}
Option A is correct because NaOH is a base and can absorb acidic oxides like N2O5, forming a salt and water.
137 Easy
137 of 705
Remembering +4 | -1
]The idea which prompted Bartlett to prepare first ever compound of noble gas was:
View answer and explanation
Correct option: C
Ionization energies of O2{O_2} and xenon were almost similar
Option C (Ionization energies of O2{O_2} and xenon were almost similar) is correct because Bartlett's initial discovery was based on the similar ionization energies of oxygen and xenon.
138 Medium
138 of 705
Analyzing +4 | -1
Consider NH3,  PH3,  AsH3  &  SbH3N{H_3},\,\,P{H_3},\,\,As{H_3}\,\,\& \,\,Sb{H_3} find which statements are correct for NH3N{H_3}
A) Most basic
B) Highest bond angle
C) Strongest Reducing agent
D) Highest B.P.
E) Most −ve ΔHf0- ve\,\Delta H_f^0
View answer and explanation
Correct option: D
A, B, E
Option D (A, B, E) is correct because NH3 is the most basic, has the highest bond angle, and the most negative enthalpy of formation among the given hydrides.
139 Easy
139 of 705
Understanding +4 | -1
I2{I_2} dissolves in KI solution due to the formation of
View answer and explanation
Correct option: C
I3−I_3^ -
Option C is correct because iodine dissolves in KI solution due to the formation of the triiodide ion (I3−I_3^ -).
140 Medium
140 of 705
Analyzing +4 | -1
Assertion (A): (NH4)2Cr2O7,\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7, on heating doesn't form any residue.

Reason (R): In Cr2O72−\mathrm{Cr}_2 \mathrm{O}_7^{2-} there are six equivalent Cr−O\mathrm{Cr}-\mathrm{O} bonds.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D is correct because both the assertion and the reason are false. Ammonium dichromate on heating leaves a residue of Cr2O3, and the Cr-O bonds in dichromate are not all equivalent.
141 Medium
141 of 705
Understanding +4 | -1
KF{KF} combines with HF{HF} to form KHF2{KHF}_2. The compound contains the species:
View answer and explanation
Correct option: C
K+{K}^{+}and [HF2]−\left[{HF}_2\right]^{-}
Option C (K+{K}^{+}and [HF2]−\left[{HF}_2\right]^{-}) is correct because KHF2{KHF}_2 dissociates into K+{K}^{+} and [HF2]−\left[{HF}_2\right]^{-} ions in solution.
142 Hard
142 of 705
Understanding +4 | -1
Ammonia on reaction with hypochlorite anion, can form
View answer and explanation
Correct option: B
N2H4{N_2}{H_4}
Option B (N2H4N_2H_4) is correct because ammonia reacts with hypochlorite ion to form hydrazine (N2H4N_2H_4).
143 Medium
143 of 705
Understanding +4 | -1
The hydrides of the first elements in groups 15-17 namely NH3,H2O\mathrm{NH}_3, \mathrm{H}_2 \mathrm{O} and HF\mathrm{HF} respectively shows abnormally high values for melting and boiling points. This is due to
View answer and explanation
Correct option: B
the ability to form extensive intermolecular H\mathrm{H}-bonding
Option B (the ability to form extensive intermolecular H\mathrm{H}-bonding) is correct because the high melting and boiling points are due to the strong intermolecular hydrogen bonds in NH3,H2O\mathrm{NH}_3, \mathrm{H}_2 \mathrm{O} and HF\mathrm{HF}.
144 Medium
144 of 705
Understanding +4 | -1
Which of the following acid posses oxidising, reducing and complex forming properties?
View answer and explanation
Correct option: C
HNO2HN{O_2}
Option C (HNO2HN{O_2}) is correct because nitrous acid can act as both an oxidizing and reducing agent, and it can also form complexes.
145 Medium
145 of 705
Understanding +4 | -1
The products obtained when I2\mathrm{I}_2 reacts with hot and concentrated aqueous NaOH\mathrm{NaOH} are
View answer and explanation
Correct option: D
I−\mathrm{I}^{-} and IO3−\mathrm{IO}_3^{-}
Option D is correct because the reaction of iodine with hot and concentrated sodium hydroxide produces iodide (I−I^−) and iodate (IO3−IO_3^−) ions.
146 Medium
146 of 705
Understanding +4 | -1
Hydrolysis of ‘XX’ is an example of disproportionation. XX is
View answer and explanation
Correct option: C
XeF4Xe{F_4}
Option C (XeF4XeF_4) is correct because its hydrolysis results in disproportionation, where Xenon is both oxidized and reduced.
147 Easy
147 of 705
Understanding +4 | -1
Consider the following compounds

Sulphur dioxide

Hydrogen peroxide

Ozone

Among these compounds identify those that can act as bleaching agent.
View answer and explanation
Correct option: D
1,2 and 3
Option D (1,2 and 3) is correct because Sulphur dioxide, Hydrogen peroxide and Ozone can act as bleaching agents.
148 Easy
148 of 705
Remembering +4 | -1
Bond angle in O3{O_3} molecule is:
View answer and explanation
Correct option: C
116∘90′{116^ \circ }90'
Option C (116∘90′{116^ \circ }90') is correct because the bond angle in O3{O_3} molecule is 116∘90′{116^ \circ }90'.
149 Hard
149 of 705
Analyzing +4 | -1
Assertion: Peroxy disulphuric acid & oleum have same oxidation state

Reason: In oleum oxygen bridges two sulphur atoms.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct because both the assertion and the reason are true, but the reason does not explain the assertion.
150 Easy
150 of 705
Remembering +4 | -1
Good conductor of electricity is:
View answer and explanation
Correct option: D
Black P
Option D (Black P) is correct because Black Phosphorus is the most thermodynamically stable allotrope and exhibits metallic properties, making it a good conductor of electricity.
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