Addition of ${H_2}S{O_4}$ to $Ba{O_2}$ produces

$BaO,S{O_2}\,\,\,{\text{and}}\,\,\,\,{H_2}O$

$BaHS{O_4}\,\,{\text{and}}\,\,\,{O_2}$

$BaS{O_4},\,\,{H_2}\,\,{\text{and}}\,\,\,{O_2}$

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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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151 Medium

151 of 705

Understanding +4 | -1

Which one of the following correctly represents the order of stability of oxides,

{X_2}O

(X = halogen)?

View answer and explanation

Correct option: D

I > Cl > Br

Option D (

I > Cl > Br

) is correct because iodine forms more stable oxides due to greater polarity, and chlorine can form multiple bonds with oxygen.

152 Medium

152 of 705

Remembering +4 | -1

Which of the following is a double base propellant?

View answer and explanation

Correct option: B

Nitroglycerine and nitrocellulose

The correct answer is B (Nitroglycerine and nitrocellulose) because double-base propellants contain both the fuel and oxidizer in the same molecule, and this combination is a common example.

153 Medium

153 of 705

Understanding +4 | -1

Which statement is not correct?

View answer and explanation

Correct option: A

White and red phosphorus react with chlorine at room temperature

Option A (White and red phosphorus react with chlorine at room temperature) is not correct because red phosphorus is less reactive and does not react with chlorine at room temperature.

154 Easy

154 of 705

Understanding +4 | -1

With excess of chlorine, ammonia forms:

View answer and explanation

Correct option: A

NC{l_3}

Option A (

NC{l_3}

) is correct because with excess chlorine, ammonia reacts to form nitrogen trichloride (

NC{l_3}

155 Hard

155 of 705

Understanding +4 | -1

Iodine may be liberated from sodium iodate by:

View answer and explanation

Correct option: B

NaHS{O_3}

Option B (

NaHS{O_3}

) is correct because

NaHS{O_3}

reduces iodate ions to iodine.

156 Medium

156 of 705

Analyzing +4 | -1

The spectrum of helium is similar to:

View answer and explanation

Correct option: B

Option C is correct because Li+ and He have the same number of electrons and similar electronic structure, resulting in similar spectra.

157 Medium

157 of 705

Analyzing +4 | -1

Statement I:

\mathrm{PF}_5

and IF have similar shapes

Statement II:

\mathrm{PF}_5

has to two types of

\mathrm{P}-\mathrm{F}

bond lengths

View answer and explanation

Correct option: D

Statement I if false but statement II is correct

Option D is correct because PF₅ has trigonal bipyramidal shape, IF is unknown, and PF₅ has two different P-F bond lengths (axial and equatorial).

158 Hard

158 of 705

Remembering +4 | -1

Yellow ammonium sulphide is:

View answer and explanation

Correct option: B

{\left( {\mathrm{N}{\mathrm{H}_4}} \right)_2}{\mathrm{S}_\mathrm{x}}

Option B (

( {\mathrm{N}{\mathrm{H}_4}} )_2{\mathrm{S}_\mathrm{x}}

) is correct because yellow ammonium sulfide contains polysulfide ions (

S_x^{2-}

), giving it a yellow color.

159 Easy

159 of 705

Understanding +4 | -1

Which one of the following represents noble gas configuration?

View answer and explanation

Correct option: C

1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^{10}},4{s^2}4{p^6}4{d^{10}},5{s^2}5{p^6}

Option B, C, and E are correct statements, while A and D are incorrect.

160 Easy

160 of 705

Analyzing +4 | -1

Which one of the following statements is not true?

View answer and explanation

Correct option: D

HF is a stronger acid than HCl

Option D (HF is a stronger acid than HCl) is not true because HF is a weaker acid than HCl due to strong hydrogen bonding in HF which stabilizes it and makes it less likely to donate a proton.

161 Medium

161 of 705

Remembering +4 | -1

Weldon mud is:

View answer and explanation

Correct option: C

2CaO.Mn{O_2}

Option C (

2CaO.Mn{O_2}

) is the correct answer because

2CaO.Mn{O_2}

is the chemical formula for Weldon mud.

162 Hard

162 of 705

Analyzing +4 | -1

A sodium salt when react with dil.

\mathrm{H}_2 \mathrm{SO}_4

produce acidic gas which have reducing property but not have oxidising property. Sodium salt is

View answer and explanation

Correct option: D

\mathrm{Na}_2 \mathrm{S}

Option D (

\mathrm{Na}_2 \mathrm{S}

) is correct because sulfide ions (

\mathrm{S}^{2-}

) are already in their minimum oxidation state, exhibiting reducing properties without oxidizing capabilities.

163 Easy

163 of 705

Remembering +4 | -1

The element which is the most abundant in the earth crust is

View answer and explanation

Correct option: A

{O}

Option A (

{O}

) is correct because oxygen is the most abundant element in the Earth's crust.

164 Easy

164 of 705

Understanding +4 | -1

Which of the following gives

\;{M^{3 + }}

ion most readily?

View answer and explanation

Correct option: D

Option D (Bi) is correct because Bismuth (Bi) readily forms a +3 ion due to the inert pair effect, where the 6s² electrons are reluctant to participate in bonding.

165 Easy

165 of 705

Understanding +4 | -1

When chlorine reacts with dil. NaOH under cold conditions, the oxidation state of chlorine changes from zero to

View answer and explanation

Correct option: D

- 1\,\,\,\mathrm{and} + 1

Option D (-1 and +1) is correct because when chlorine reacts with cold dilute NaOH, it forms NaCl (oxidation state -1) and NaClO (oxidation state +1).

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166 Easy

166 of 705

Understanding +4 | -1

The species that does not contain peroxide ion is

View answer and explanation

Correct option: A

Pb{O_2}

Option A (

Pb{O_2}

) is correct because lead dioxide does not contain the peroxide ion (O2^2-).

167 Easy

167 of 705

Remembering +4 | -1

Calcium phosphide is:

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{a}_3}{\mathrm{P}_2}

Option B (

\mathrm{C}{\mathrm{a}_3}{\mathrm{P}_2}

) is correct because the chemical formula for calcium phosphide is Ca3P2, representing the correct ratio of calcium and phosphorus atoms.

168 Medium

168 of 705

Application +4 | -1

Oxidation states of

{P}

{H}_4 {P}_2 {O}_5, {H}_4 {P}_2 {O}_6, {H}_4 {P}_2 {O}_7

are respectively

View answer and explanation

Correct option: A

+3,+4,+5

Option D (17.325 mm Hg) is correct because it is calculated using Raoult's law for vapor pressure lowering.

169 Easy

169 of 705

Understanding +4 | -1

Number of hydroxyl groups present in pyrosulphuric acid is:

View answer and explanation

Correct option: C

Option B (5) is correct because one molecule of the compound dissociates into 5 ions: Fe2+, 2 SO42-, and 2 NH4+.

170 Easy

170 of 705

Remembering +4 | -1

Which of the following is formed by xenon?

View answer and explanation

Correct option: B

Xe{F_4}

The correct answer is B (

Xe{F_4}

) because Xenon tetrafluoride (

XeF_4

) is a known and well-characterized compound of xenon, while the others are not typically formed.

171 Easy

171 of 705

Understanding +4 | -1

S-I: Hybridisation of

{Xe}

{XeF}_2

{sp}^3 {d}

.

S-II: Shape of

{XeF}_2

is angular.

View answer and explanation

Correct option: C

S-I is true, S-II is false

Option C (S-I is true, S-II is false) is correct because the hybridization of Xe in XeF2 is sp3d, but the shape is linear, not angular.

172 Easy

172 of 705

Analyzing +4 | -1

Assertion:

{Fe}^{3+}

does not give brown ring test.

Reason: Because

{NO}_3^{-}

is first converted into

{NO}_2^{-}

View answer and explanation

Correct option: C

If Assertion is correct but Reason is incorrect.

Option C is correct because in the brown ring test, Fe2+ oxidizes to Fe3+, and NO3- reduces to NO, not NO2- as stated in the reason, and Fe3+ does not give the brown ring test.

173 Easy

173 of 705

Analyzing +4 | -1

Which of the following statements are correct?

(I)

{HF}

is a stronger acid than

{HCl}

(II) Among halide ions, iodide is the most powerful reducing agent.

(III) Fluorine is the only halogen that does not show a variable oxidation state.

(IV)

{HOCl}

is a stronger acid than

{HOBr}

View answer and explanation

Correct option: D

II, III and IV

The correct answer is D (II, III and IV) because iodide is the strongest reducing agent, fluorine has a fixed oxidation state, and HOCl is a stronger acid than HOBr.

174 Hard

174 of 705

Understanding +4 | -1

Addition of

{H_2}S{O_4}

Ba{O_2}

produces

View answer and explanation

Correct option: D

BaS{O_4}\,{\text{and}}\,\,{H_2}{O_2}

Option D (

BaS{O_4}\,{\text{and}}\,{H_2}{O_2}

) is correct because the reaction of barium peroxide with sulfuric acid produces barium sulfate and hydrogen peroxide.

175 Easy

175 of 705

Remembering +4 | -1

Which of the following is not an interhalogen compound?

View answer and explanation

Correct option: C

\mathrm{HF}

Option C (

\mathrm{HF}

) is correct because

\mathrm{HF}

is a hydrogen halide, not an interhalogen compound.

176 Easy

176 of 705

Remembering +4 | -1

Which of the element of nitrogen family produce maximum number of oxy-acids?

View answer and explanation

Correct option: B

Option B (P) is correct because phosphorus forms a greater variety of oxyacids compared to other elements in the nitrogen family.

177 Easy

177 of 705

Remembering +4 | -1

Which one among the following non-metals is liquid at

{25^ \circ }C

View answer and explanation

Correct option: A

Bromine

Option A (Bromine) is correct because bromine is the only non-metal that exists as a liquid at room temperature (25°C).

178 Easy

178 of 705

Remembering +4 | -1

The strongest oxidising agent is :

View answer and explanation

Correct option: A

{F}_2

Option A (

\mathrm{F_2}

) is correct because fluorine is the strongest oxidizing agent among the halogens due to its high electronegativity and small size.

179 Easy

179 of 705

Remembering +4 | -1

Which of the following attacks glass:

View answer and explanation

Correct option: B

Option B (HF) is correct because hydrofluoric acid (HF) is known to react with silica (

SiO_2

), the main component of glass.

180 Easy

180 of 705

Remembering +4 | -1

Fluorine is usually obtained from:

View answer and explanation

Correct option: A

Fluorspar

The correct answer is A (Fluorspar) because fluorine is commercially obtained from fluorspar, which is calcium fluoride (CaF2).

Revision notes and key takeaways

Review P-BLOCK ELEMENTS in your textbook or class notes, then use this set to check your understanding.

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