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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 705 questions

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181 Easy
181 of 705
Remembering +4 | -1
Swimming pools are disinfected by bubbling through water with a controlled quantity of:
View answer and explanation
Correct option: A
Br2\mathrm{B}{\mathrm{r}_2}
Option B (Cl2\mathrm{C}{\mathrm{l}_2}) is correct because chlorine is commonly used to disinfect swimming pools due to its antibacterial properties.
182 Medium
182 of 705
Analyzing +4 | -1
[Fe(H2O)5NO]2+\left[{Fe}\left({H}_2 {O}\right)_5 {NO}\right]^{2+} is a complex formed during the brown ring test for NO3−{NO}_3^{-}ion. In this complex.
View answer and explanation
Correct option: D
All of the above statements are correct
Option D (All of the above statements are correct) is correct because the complex has three unpaired electrons, the color is due to charge transfer, and the electronic configuration of Fe and NO are as described.
183 Easy
183 of 705
Understanding +4 | -1
Assertion (A): Sulphur shows paramagnetism.

Reason (R): In vapour state sulphur partly exists as S2\mathrm{S}_2 molecule which has two unpaired electrons in the antibonding π^\hat{\pi}-orbitals.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct; R\mathrm{R} is the correct explanation of AA.
Option A is correct because both the assertion and the reason are true, and the reason correctly explains why sulfur exhibits paramagnetism in the vapor state.
184 Easy
184 of 705
Understanding +4 | -1
Statement-I: Red phosphorus glows in dark and is frequently used in glow signs.

Statement-II: White phosphorus is an allotropic form of red phosphorus.
View answer and explanation
Correct option: D
Statement I is wrong but Statement II is correct
Option D (Statement I is wrong but Statement II is correct) is correct because red phosphorus does not glow in the dark, while white phosphorus is an allotrope of red phosphorus.
185 Medium
185 of 705
Understanding +4 | -1
Assertion (A) Elementary phosphorus exists in three principal allotropic forms, i.e. white (or yellow), red (or violet) and black.

Reason (R) Of the three forms, white phosphorus is the most important and most reactive.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is correct explanation of Assertion.
Option A (If both Assertion and Reason are true and Reason is correct explanation of Assertion) is correct because white phosphorus is indeed the most reactive allotrope due to its unstable tetrahedral structure.
186 Easy
186 of 705
Remembering +4 | -1
The last member of inert gas family is:
View answer and explanation
Correct option: B
Radon
Option B (Radon) is correct because Radon (Rn) is the last element in Group 18, the noble gases.
187 Easy
187 of 705
Understanding +4 | -1
Assertion (A): Most of the reactions of fluorine are exothermic.

Reason (R): Fluorine forms small and strong bond with it and other elements.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct; R\mathrm{R} is the correct explanation of AA.
The correct answer is A (Both A and R are correct; R is the correct explanation of A) because fluorine's reactions are exothermic due to its small size and strong bond formation.
188 Easy
188 of 705
Remembering +4 | -1
Ammonia is dried over
View answer and explanation
Correct option: D
Quick lime
Option D (Quick lime) is correct because quick lime (CaO) is used to dry ammonia as ammonia reacts with other given dehydrating agents.
189 Easy
189 of 705
Remembering +4 | -1
Which of the following is called Berthelot’s salt?
View answer and explanation
Correct option: C
KClO3KCl{O_3}
Option C (KClO3KCl{O_3}) is correct because potassium chlorate (KClO3KCl{O_3}) is commonly known as Berthelot's salt.
190 Medium
190 of 705
Analyzing +4 | -1
Statement I: The dipole moment of NF3\mathrm{NF}_3 is less than NH3\mathrm{NH}_3

Statement II: The presence of lone pair of electrons on nitrogen atom shows an additive contribution in dipole moment of NH3\mathrm{NH}_3 whereas it shows negative contribution towards dipole moment of NF3\mathrm{NF}_3
View answer and explanation
Correct option: A
Statement I and statement II are correct and statement II is the correct explanation of statement I
Option A (Statement I and statement II are correct and statement II is the correct explanation of statement I) is correct because the dipole moment of NF3 is less than NH3 due to the opposing directions of bond dipoles and lone pair dipole.
191 Easy
191 of 705
Understanding +4 | -1
Phosphorus pentoxide cannot be used to dry:
View answer and explanation
Correct option: B
Ammonia
Option B (Ammonia) is correct because phosphorus pentoxide reacts with ammonia.
192 Easy
192 of 705
Analyzing +4 | -1
Assertion (A): N2\mathrm{N}_2 is more stable than N2+\mathrm{N}_2^{+}.
Reason (R): Bond order of N2\mathrm{N}_2 is 2.5 while N2+\mathrm{N}_2^+ is 3.
View answer and explanation
Correct option: C
Assertion (A) is true, but Reason (R) is false
Option C (Assertion (A) is true, but Reason (R) is false) is correct because N2 is indeed more stable than N2+, but the bond order values provided in the reason are incorrect.
193 Easy
193 of 705
Understanding +4 | -1
Which substance chars when warmed with conc. H2SO4{H_2}S{O_4} ?
View answer and explanation
Correct option: D
Carbohydrate
Option D (Carbohydrate) is correct because concentrated H2SO4{H_2}S{O_4} is a strong dehydrating agent and removes water from carbohydrates, leaving behind carbon.
194 Easy
194 of 705
Remembering +4 | -1
Collectively the elements of group 15 are called -
View answer and explanation
Correct option: A
Pnicogens
Option A (Pnicogens) is correct because group 15 elements are collectively known as pnicogens.
195 Medium
195 of 705
Understanding +4 | -1
What is the oxidising agent chlorine water?
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Correct option: C
HOCI
Option C (HOCI) is correct because hypochlorous acid (HOCl) decomposes to release nascent oxygen, which acts as the oxidizing agent.
196 Hard
196 of 705
Understanding +4 | -1
Presence of sulphide ion cannot be confirmed by:
View answer and explanation
Correct option: A
BaCl2\mathrm{BaC}{\mathrm{l}_2}
Option A (BaCl2\mathrm{BaC}{\mathrm{l}_2}) is correct because BaCl2BaCl_2 does not produce a characteristic reaction that confirms the presence of sulphide ions (S2−S^{2-}).
197 Easy
197 of 705
Remembering +4 | -1
Noble gases are group of elements which exhibit very
View answer and explanation
Correct option: D
Low chemical activity
Option D (Low chemical activity) is correct because noble gases have a full valence shell, making them very stable and unreactive.
198 Medium
198 of 705
Remembering +4 | -1
Iodine exists in which form in iodised salt
View answer and explanation
Correct option: B
NaIO3{NaIO}_3
Option B (NaIO3{NaIO}_3) is correct because iodized salt typically contains sodium iodate (NaIO3{NaIO}_3) to provide iodine.
199 Medium
199 of 705
Understanding +4 | -1
Hydrolysis of PCl5{PCl}_5 gives:
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Correct option: C
H3PO4{H}_3 {PO}_4
Option C (H3PO4{H}_3 {PO}_4) is correct because the complete hydrolysis of PCl5{PCl}_5 results in the formation of orthophosphoric acid (H3PO4{H}_3 {PO}_4) and hydrochloric acid.
200 Medium
200 of 705
Analyzing +4 | -1
In a reaction, 4 mole of electrons are transferred to 1 mole of HNO3{HNO}_3, the possible product obtained due to reduction is :-
View answer and explanation
Correct option: B
0.5 mole of N2O{N}_2 {O}
The correct answer is B (0.5 mole of N2O{N}_2 {O}) because the reduction of HNO3{HNO}_3 by 4 moles of electrons results in nitrogen having a +1 oxidation state, corresponding to N2O{N}_2 {O}.
201 Medium
201 of 705
Understanding +4 | -1
The stability of +2 oxidation state among Si, Ge, Sn and Pb increase in the sequence
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Correct option: D
Si < Ge < Sn < Pb
Option D (Si < Ge < Sn < Pb) is correct because the stability of the +2 oxidation state increases down the group due to the inert pair effect.
202 Medium
202 of 705
Analyzing +4 | -1
Which is bad conductor of electricity?
View answer and explanation
Correct option: A
H2F2{H_2}{F_2}
Option A (C22−C_2^{2 - } is expected to be diamagnetic) is correct because C22−C_2^{2-} has 14 electrons, resulting in a completely filled molecular orbital diagram and thus diamagnetism.
203 Easy
203 of 705
Remembering +4 | -1
In Kipp’s apparatus, H2S{\mathrm{H}_2}\mathrm{S} is prepared:
View answer and explanation
Correct option: C
By  FeS+dil.  H2SO4\mathrm{By\;FeS} + \mathrm{dil}.\mathrm{\;}{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}
Option C (By  FeS+dil.  H2SO4\mathrm{By\;FeS} + \mathrm{dil}.\mathrm{\;}{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}) is correct because Kipp's apparatus uses the reaction between ferrous sulfide (FeS) and dilute sulfuric acid to produce H2S gas.
204 Easy
204 of 705
Remembering +4 | -1
Noble gases are used in discharge tubes to gives different colours. Reddish orange glow is due to
View answer and explanation
Correct option: B
Ne{Ne}
Option B (Ne{Ne}) is correct because Neon gas is used in discharge tubes to produce a reddish-orange glow.
205 Easy
205 of 705
Remembering +4 | -1
The noble gas used in the preparation of first noble gas compound was:
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Correct option: A
Xe
Option A (Xe) is correct because xenon was the first noble gas used to prepare a stable noble gas compound, specifically XePtF6XePtF_6.
206 Easy
206 of 705
Remembering +4 | -1
Poison for platinum, a catalyst in contact process of H2SO4{H_2}S{O_4} is:
View answer and explanation
Correct option: C
As
Option C (As) is correct because arsenic (As) is a known poison for platinum catalysts used in the contact process for sulfuric acid production.
207 Easy
207 of 705
Remembering +4 | -1
Compound of Sulphur used in electrical transformer is:
View answer and explanation
Correct option: D
SF6S{F_6}
Option D (SF6S{F_6}) is correct because sulfur hexafluoride is chemically inert and used as an insulator in electrical transformers.
208 Easy
208 of 705
Understanding +4 | -1
Polyanion formation is maximum in
View answer and explanation
Correct option: B
Sulphur
The correct answer is Sulphur because sulphur exhibits catenation to a greater extent than other elements in the given options, leading to maximum polyanion formation.
209 Medium
209 of 705
Analyzing +4 | -1
Statement I: All the halogens exhibit -1 oxidation state.

Statement II: The oxidation states of +4 and +6 occur in the oxides and oxoacids of chlorine and bromine.
View answer and explanation
Correct option: A
Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.
Option D (Statement II is correct but Statement I is incorrect) is correct because not all halogens exhibit only -1 oxidation state, and the oxides and oxoacids of chlorine and bromine can have +4 and +6 oxidation states.
210 Medium
210 of 705
Application +4 | -1
Hot conc. H2SO4{H_2}S{O_4} act as moderately strong oxidizing agent. It oxidises both metals and non-metals. Which of the following element is oxidized by conc. H2SO4{H_2}S{O_4} into two gaseous products.
View answer and explanation
Correct option: C
C
Option C is correct because carbon is oxidized by concentrated H2SO4 into two gaseous products: CO2 and SO2.
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