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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 705 questions
1 Easy
1 of 705
Remembering +4 | -1
The gas used for inflating the tyres of aeroplanes is:
View answer and explanation
Correct option: B
He\mathrm{He}
Option B (He) is correct because Helium is the lightest non-inflammable gas after Hydrogen, making it suitable for inflating aircraft tires.
2 Medium
2 of 705
Remembering +4 | -1
Which of the following is correct stability order of oxides of 17th 17^{\text {th }} group elements is:
View answer and explanation
Correct option: C
I2>Cl2>Br2\mathrm{I}_2>\mathrm{Cl}_2>\mathrm{Br}_2
Option D (Cl2>I2>Br2\mathrm{Cl}_2>\mathrm{I}_2>\mathrm{Br}_2) is incorrect, the correct order is Cl2O>Br2O>I2O\mathrm{Cl}_2O > \mathrm{Br}_2O > \mathrm{I}_2O.
3 Medium
3 of 705
Analyzing +4 | -1
Assertion: Ozone is a powerful oxidising agent in comparison to O2{O}_2.

Reason: Ozone is diamagnetic but O2{O}_2 is paramagnetic.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
Option B (If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion) is correct because ozone is a stronger oxidizing agent than oxygen, and ozone is diamagnetic while oxygen is paramagnetic, but the paramagnetism of oxygen is not the reason for ozone's stronger oxidizing power.
4 Easy
4 of 705
Remembering +4 | -1
Which of the following is kept in water?
View answer and explanation
Correct option: A
White phosphorus
Option A (White phosphorus) is correct because white phosphorus is highly reactive and spontaneously ignites in air, so it's stored under water.
5 Easy
5 of 705
Understanding +4 | -1
CN−\mathrm{C}{\mathrm{N}^ - } ion and N2{\mathrm{N}_2} are isoelectronic but in contrast to CN−,  N2\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2} is chemically inert because of:
View answer and explanation
Correct option: B
Absence of bond polarity
Option B (Absence of bond polarity) is correct because N2 is chemically inert due to its non-polar nature and high bond energy, unlike the polar CN- ion.
6 Medium
6 of 705
Understanding +4 | -1
Consider the following statements

(i) Reaction 2Fe3++SO2+2H2O→2Fe2++SO42−+4H+2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+} shows reducing character of sulphur dioxide

(ii) H2 S2O8{H}_2 {~S}_2 {O}_8 contains four S=O{S}={O}, two S−OH{S}-{OH} and one O−{O}- O{O} bond

(iii) NH3{NH}_3 gas can be dried effectively by using conc. H2SO4{H}_2 {SO}_4.

(iv) One of the major use of H2SO4{H}_2 {SO}_4 is in the manufacture of fertilizers.

Which of the following is the correct code for the statements above?
View answer and explanation
Correct option: B
TTFT
Option B (TTFT) is correct because statements (i), (ii), and (iv) are true, while statement (iii) is false due to the reaction between ammonia and sulfuric acid.
7 Easy
7 of 705
Remembering +4 | -1
Superphosphate of lime is used in:
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Correct option: C
Agriculture
Option C (Agriculture) is correct because superphosphate of lime is a fertilizer used to provide phosphorus to plants.
8 Easy
8 of 705
Analyzing +4 | -1
Statement I: The bond angle in NH3\mathrm{NH}_3 is more than that of PH3\mathrm{PH}_3

Statement II: Increasing size and decreasing electronegativity of central atom permit the bonding electrons to be drawn out further, lowering the repulsion between the bonding pairs
View answer and explanation
Correct option: A
Statement I and statement II are correct and statement II is the correct explanation of statement I
Option A (Statement I and statement II are correct and statement II is the correct explanation of statement I) is correct because the bond angle in NH3 is greater than PH3 due to the smaller size and higher electronegativity of Nitrogen.
9 Hard
9 of 705
Understanding +4 | -1
Assertion (A): SO2{SO}_2 converts ferric ions to ferrous ions.

Reason (R): SO2{SO}_2 act as reducing agent.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
The correct answer is A (Both (A) and (R) are true and (R) is the correct explanation of (A)) because sulfur dioxide reduces ferric ions to ferrous ions by acting as a reducing agent.
10 Medium
10 of 705
Analyzing +4 | -1
Assertion (A) : Each N\mathrm{N}-atom is sp3s p^3-hybridised in N2H4\mathrm{N}_2 \mathrm{H}_4.

Reason (R) : It has gauche conformation.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Both A and R are true but R is not the correct explanation of A because while N_2H_4 does have sp3 hybridized N atoms and a gauche conformation, the conformation doesn't explain the hybridization.
11 Hard
11 of 705
Analyzing +4 | -1
Assertion: Salts of H3PO3\mathrm{H}_3 \mathrm{PO}_3 and H3PO4\mathrm{H}_3 \mathrm{PO}_4 used as a fertilizers.

Reason: Formed H3PO3\mathrm{H}_3 \mathrm{PO}_3 increases solubility of water in soil on addition of phosphate fertilizers.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is correct explanation of the Assertion
Option A is correct. Salts of both H3PO3H_3PO_3 and H3PO4H_3PO_4 are used as fertilizers, and H3PO3H_3PO_3 increases water solubility in soil when phosphate fertilizers are added.
12 Medium
12 of 705
Understanding +4 | -1
Which is correct statement?
View answer and explanation
Correct option: C
Nitric oxide is an endothermic compound
Option C is correct. Nitric oxide (NO) is an endothermic compound, meaning its formation requires energy input (positive enthalpy change).
13 Easy
13 of 705
Remembering +4 | -1
Freons are used as:
View answer and explanation
Correct option: A
Refrigerant
Option A (Refrigerant) is correct because freons are commonly used as refrigerants due to their properties.
14 Medium
14 of 705
Analyzing +4 | -1
Which of the following will not form disproportionated product?
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Correct option: D
XeF2+H2O⟶{XeF}_2+{H}_2 {O} \longrightarrow
Option D is correct because XeF2 reacts with water to form Xe, HF, and O2, without disproportionation.
15 Easy
15 of 705
Analyzing +4 | -1
Which of the following pair have same hybridisation for central atom?
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Correct option: D
XeF2\mathrm{XeF}_2 and I3−\mathrm{I}_3^{-}
Option D (XeF2\mathrm{XeF}_2 and I3−\mathrm{I}_3^{-}) is correct because both have sp3dsp^3d hybridization for the central atom.
16 Medium
16 of 705
Application +4 | -1
Iodine reacts with concentrated HNO3HN{O_3} to yield Y along with other products. The oxidation state of iodine in Y,Y, is
View answer and explanation
Correct option: D
5
Option D (5) is correct because iodine reacts with concentrated HNO₃ to form iodic acid (HIO₃), where the oxidation state of iodine is +5.
17 Easy
17 of 705
Understanding +4 | -1
Xenon best reacts with:
View answer and explanation
Correct option: B
The most electronegative element
Option B (The most electronegative element) is correct because xenon, being a noble gas, reacts best with highly electronegative elements like fluorine and oxygen.
18 Medium
18 of 705
Understanding +4 | -1
Which would quickly absorb oxygen?
View answer and explanation
Correct option: A
Alkaline solution of pyrogallic acid
Option A (Alkaline solution of pyrogallic acid) is correct because alkaline pyrogallol readily absorbs oxygen, making it suitable for removing oxygen from gas mixtures.
19 Medium
19 of 705
Analyzing +4 | -1
The true statement for the acids of phosphorus, H3PO2,H3PO3\mathrm{H}_3 \mathrm{PO}_2, \mathrm{H}_3 \mathrm{PO}_3 and H3PO4\mathrm{H}_3 \mathrm{PO}_4 is
View answer and explanation
Correct option: D
The geometry of phosphorus is tetrahedral in all the three
Option D is correct because H3PO2,H3PO3\mathrm{H}_3 \mathrm{PO}_2, \mathrm{H}_3 \mathrm{PO}_3 and H3PO4\mathrm{H}_3 \mathrm{PO}_4 all have phosphorus with sp3sp^3 hybridization, resulting in a tetrahedral geometry.
20 Medium
20 of 705
Understanding +4 | -1
Assertion (A): N2O5\mathrm{N}_2 \mathrm{O}_5 is not possible due to

Reason (R): incapability of 'N' to show pentavalency Max. covalency of 'N' can be 4.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D is correct because N2O5 is a known compound, and nitrogen can exhibit a covalency of more than 4 using d-orbitals, though it is less common.
21 Medium
21 of 705
Analyzing +4 | -1
When Cl2\mathrm{C}{\mathrm{l}_2} water is added to an aqueous solution of potassium halide in presence of chloroform a violet colour is obtained. On adding more of Cl2\mathrm{C}{\mathrm{l}_2} water, the violet colour disappears and a colourless solution is obtained. This test confirms the presence of the following in aqueous solution:
View answer and explanation
Correct option: A
Iodide
Option A (Iodide) is correct because the violet color in chloroform indicates the presence of iodine, which is formed by the reaction of iodide with chlorine water. The disappearance of the color with excess chlorine water indicates further oxidation of iodine.
22 Easy
22 of 705
Remembering +4 | -1
Ammonia is:
View answer and explanation
Correct option: A
Polar solvent
Option A (Polar solvent) is correct because ammonia (NH3N{H_3}) is a polar molecule and acts as a polar solvent.
23 Hard
23 of 705
Understanding +4 | -1
Assertion (A): Cr,Al,Fe{Cr},{Al}, {Fe} and Ni{Ni} are passive with concentrated Nitric acid.

Reason (R): Thin film of oxide layer is formed which prevents further action of concentrated Nitric acid on metal.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
The correct answer is A (Both (A) and (R) are true and (R) is the correct explanation of (A)) because Cr, Al, Fe, and Ni become passive due to the formation of a protective oxide layer.
24 Easy
24 of 705
Application +4 | -1
In which of the following compound central atom has +4+4 oxidation state?
View answer and explanation
Correct option: B
H2SO3\mathrm{H}_2 \mathrm{SO}_3
The correct answer is B (H2SO3\mathrm{H}_2 \mathrm{SO}_3) because the oxidation state of sulfur in this compound is +4.
25 Medium
25 of 705
Analyzing +4 | -1
Given below are two statements:
Statement I: Noble gases have very high boiling
points
Statement II: Noble gases are monoatomic gases.
They are held together by strong dispersion forces.
Because of this they are liquefied at very low
temperature. Hence, they have very high boiling
points.
In the light of the above statements, choose the
correct answer from the options given below.
View answer and explanation
Correct option: B
Both statement I and statement II are false
The correct answer is B (Both statement I and statement II are false) because noble gases have very *low* boiling points due to *weak* dispersion forces.
26 Easy
26 of 705
Understanding +4 | -1
The correct order of reducing abilities of hydrides of V group elements is
View answer and explanation
Correct option: A
NH3<PH3<AsH3<SbH3<BiH3N{H_3} < P{H_3} < As{H_3} < Sb{H_3} < Bi{H_3}
Option A (NH3<PH3<AsH3<SbH3<BiH3N{H_3} < P{H_3} < As{H_3} < Sb{H_3} < Bi{H_3}) is correct because the reducing ability of hydrides increases down the group due to decreasing bond strength and stability.
27 Hard
27 of 705
Analyzing +4 | -1
Assertion (A): ClFC l F is more reactive than F2F_2.

Reason (R): The F−FF-F bond is weaker than ClFClF bond.
View answer and explanation
Correct option: D
(A) is false and (R) is true
Option D is correct because the F-F bond is indeed weaker than the Cl-F bond, but this makes ClF more reactive, not less. Therefore, the assertion is false, and the reason is true.
28 Easy
28 of 705
Remembering +4 | -1
The only element in VIA group or group 16 elements, which is definitely a metal, is:
View answer and explanation
Correct option: D
Polonium
Option D (Polonium) is correct because metallic character increases down the group, and Polonium is the last element in Group 16 that exhibits metallic properties.
29 Medium
29 of 705
Analyzing +4 | -1
Which statement is incorrect.
View answer and explanation
Correct option: C
BrBr can be prepared from carnalite
The correct answer is D (Br can be prepared from carnalite) because bromine is not directly prepared from carnallite.
30 Medium
30 of 705
Understanding +4 | -1
Among the halogens, the one which is oxidised by nitric acid is
View answer and explanation
Correct option: B
Iodine
Option B (Iodine) is correct because nitric acid oxidizes iodine to iodic acid.
Revision notes and key takeaways

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Key Takeaways

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