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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 41 questions
1 Hard
1 of 41
Understanding +4 | -1
Assertion (A): SO2{SO}_2 converts ferric ions to ferrous ions.

Reason (R): SO2{SO}_2 act as reducing agent.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
The correct answer is A (Both (A) and (R) are true and (R) is the correct explanation of (A)) because sulfur dioxide reduces ferric ions to ferrous ions by acting as a reducing agent.
2 Hard
2 of 41
Analyzing +4 | -1
Assertion: Salts of H3PO3\mathrm{H}_3 \mathrm{PO}_3 and H3PO4\mathrm{H}_3 \mathrm{PO}_4 used as a fertilizers.

Reason: Formed H3PO3\mathrm{H}_3 \mathrm{PO}_3 increases solubility of water in soil on addition of phosphate fertilizers.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is correct explanation of the Assertion
Option A is correct. Salts of both H3PO3H_3PO_3 and H3PO4H_3PO_4 are used as fertilizers, and H3PO3H_3PO_3 increases water solubility in soil when phosphate fertilizers are added.
3 Hard
3 of 41
Understanding +4 | -1
Assertion (A): Cr,Al,Fe{Cr},{Al}, {Fe} and Ni{Ni} are passive with concentrated Nitric acid.

Reason (R): Thin film of oxide layer is formed which prevents further action of concentrated Nitric acid on metal.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
The correct answer is A (Both (A) and (R) are true and (R) is the correct explanation of (A)) because Cr, Al, Fe, and Ni become passive due to the formation of a protective oxide layer.
4 Hard
4 of 41
Analyzing +4 | -1
Assertion (A): ClFC l F is more reactive than F2F_2.

Reason (R): The F−FF-F bond is weaker than ClFClF bond.
View answer and explanation
Correct option: D
(A) is false and (R) is true
Option D is correct because the F-F bond is indeed weaker than the Cl-F bond, but this makes ClF more reactive, not less. Therefore, the assertion is false, and the reason is true.
5 Hard
5 of 41
Remembering +4 | -1
A cold, green flame can be made by passing CO2C{O_2} over warm:
View answer and explanation
Correct option: B
White P
The correct answer is B (White P) because white phosphorus reacts with carbon dioxide to produce a cold, green flame.
6 Hard
6 of 41
Understanding +4 | -1
The oxide insoluble in water is:
View answer and explanation
Correct option: C
PoO2\mathrm{Po}{\mathrm{O}_2}
Option C (PoO2\mathrm{Po}{\mathrm{O}_2}) is correct because Polonium dioxide is known to be insoluble in water, unlike the other oxides listed.
7 Hard
7 of 41
Remembering +4 | -1
A gas ' XX ' is added to Nessler's reagent then brown precipitate is formed, gas XX is
View answer and explanation
Correct option: A
NH3\mathrm{NH}_3
Option A (NH3\mathrm{NH}_3) is correct because ammonia gas reacts with Nessler's reagent to form a brown precipitate.
8 Hard
8 of 41
Understanding +4 | -1
When excess of KI is added to copper sulphate solution:
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because when excess KI is added to copper sulphate solution, cuprous iodide is formed, and iodine is liberated, indicating that potassium iodide is oxidized.
9 Hard
9 of 41
Analyzing +4 | -1
Assertion: SO2\mathrm{SO}_2 mixed with H2SO4\mathrm{H}_2 \mathrm{SO}_4 to make oleum.

Reason: SO2\mathrm{SO}_2 in presence of water forms H2SO4\mathrm{H}_2 \mathrm{SO}_4 in air.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because SO2 is used to make oleum by reacting with H2SO4, and SO2 does not form H2SO4 in air in the way described.
10 Hard
10 of 41
Analyzing +4 | -1
Assertion: SiCl4\mathrm{SiCl}_4 is more hydrolysed then SiF4\mathrm{SiF}_4.

Reason: -1 effect of F>Cl\mathrm{F} > \mathrm{Cl}.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because SiCl4 is more easily hydrolyzed than SiF4 due to the availability of d-orbitals for accepting electrons from water, and the lower bond enthalpy of Si-Cl compared to Si-F. The -I effect is true, but not the primary reason.
11 Hard
11 of 41
Analyzing +4 | -1
Consider the following statements
(a) In acidic medium nitrous acid disproportionate to nitric acid and nitrogen gas
(b) Ammonium nitrate on heating gives nitrous oxide
(c) N – N bond is present both in N2O3andN2O4{N_2}{O_3}\mathrm{ }and\mathrm{ }{N_2}{O_4} gases
The correct statements are
View answer and explanation
Correct option: B
(b) and (c) only
Option B ((b) and (c) only) is correct because ammonium nitrate on heating gives nitrous oxide, and N-N bonds are present in both N₂O₃ and N₂O₄.
12 Hard
12 of 41
Understanding +4 | -1
Ammonia on reaction with hypochlorite anion, can form
View answer and explanation
Correct option: B
N2H4{N_2}{H_4}
Option B (N2H4N_2H_4) is correct because ammonia reacts with hypochlorite ion to form hydrazine (N2H4N_2H_4).
13 Hard
13 of 41
Analyzing +4 | -1
Assertion: Peroxy disulphuric acid & oleum have same oxidation state

Reason: In oleum oxygen bridges two sulphur atoms.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct because both the assertion and the reason are true, but the reason does not explain the assertion.
14 Hard
14 of 41
Understanding +4 | -1
Iodine may be liberated from sodium iodate by:
View answer and explanation
Correct option: B
NaHSO3NaHS{O_3}
Option B (NaHSO3NaHS{O_3}) is correct because NaHSO3NaHS{O_3} reduces iodate ions to iodine.
15 Hard
15 of 41
Remembering +4 | -1
Yellow ammonium sulphide is:
View answer and explanation
Correct option: B
(NH4)2Sx{\left( {\mathrm{N}{\mathrm{H}_4}} \right)_2}{\mathrm{S}_\mathrm{x}}
Option B ((NH4)2Sx( {\mathrm{N}{\mathrm{H}_4}} )_2{\mathrm{S}_\mathrm{x}}) is correct because yellow ammonium sulfide contains polysulfide ions (Sx2−S_x^{2-}), giving it a yellow color.

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16 Hard
16 of 41
Analyzing +4 | -1
A sodium salt when react with dil. H2SO4\mathrm{H}_2 \mathrm{SO}_4 produce acidic gas which have reducing property but not have oxidising property. Sodium salt is
View answer and explanation
Correct option: D
Na2S\mathrm{Na}_2 \mathrm{S}
Option D (Na2S\mathrm{Na}_2 \mathrm{S}) is correct because sulfide ions (S2−\mathrm{S}^{2-}) are already in their minimum oxidation state, exhibiting reducing properties without oxidizing capabilities.
17 Hard
17 of 41
Understanding +4 | -1
Addition of H2SO4{H_2}S{O_4} to BaO2Ba{O_2} produces
View answer and explanation
Correct option: D
BaSO4 and  H2O2BaS{O_4}\,{\text{and}}\,\,{H_2}{O_2}
Option D (BaSO4 and H2O2BaS{O_4}\,{\text{and}}\,{H_2}{O_2}) is correct because the reaction of barium peroxide with sulfuric acid produces barium sulfate and hydrogen peroxide.
18 Hard
18 of 41
Understanding +4 | -1
Presence of sulphide ion cannot be confirmed by:
View answer and explanation
Correct option: A
BaCl2\mathrm{BaC}{\mathrm{l}_2}
Option A (BaCl2\mathrm{BaC}{\mathrm{l}_2}) is correct because BaCl2BaCl_2 does not produce a characteristic reaction that confirms the presence of sulphide ions (S2−S^{2-}).
19 Hard
19 of 41
Remembering +4 | -1
The propellant in the proposed PSLV rocket of the Indian space programme shall consist of:
View answer and explanation
Correct option: C
Both (1) and (2) in different stages of rocket propulsion
Option C (Both (1) and (2) in different stages of rocket propulsion) is correct because PSLV rockets use a combination of solid and liquid propellants in different stages to achieve the required thrust and efficiency.
20 Hard
20 of 41
Analyzing +4 | -1
Assertion: SO2\mathrm{SO}_2 (at. room temp.) and SeO2\mathrm{SeO}_2 (at higher temperature vapour condition) have same shape.

Reason: Covalent radius of Se\mathrm{Se} is some what oxidising agent. larger than sulphur.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because both the shape similarity and the larger covalent radius of Se are true, but the radius isn't the direct cause of the shape.
21 Hard
21 of 41
Analyzing +4 | -1
Assertion (A): The geometry of XeO3F2{XeO}_3 {F}_2 is trigonal bipyramidal.
Reason (R): XeXe shows sp3dsp^3d hybridisation with three oxygen atoms at equatorial position and two FF atoms at axial positions.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
The correct answer is A (Both (A) and (R) are true and (R) is the correct explanation of (A)) because XeO3F2{XeO}_3 {F}_2 indeed has a trigonal bipyramidal geometry due to sp3dsp^3d hybridization with the described arrangement.
22 Hard
22 of 41
Analyzing +4 | -1
Which reaction represents the oxidizing behaviour of H2SO4{H_2}S{O_4} ?
View answer and explanation
Correct option: D
2HI+H2SO4→I2+SO2+2H2O2HI + {H_2}S{O_4} \to {I_2} + S{O_2} + 2{H_2}O
Option D (2HI+H2SO4→I2+SO2+2H2O2HI + {H_2}S{O_4} \to {I_2} + S{O_2} + 2{H_2}O) represents the oxidizing behavior of H2SO4{H_2}S{O_4} because sulfur is reduced from +6 to +4, while iodide is oxidized to iodine.
23 Hard
23 of 41
Remembering +4 | -1
The word neon signifies:
View answer and explanation
Correct option: A
New
Option A (New) is correct because the word neon is derived from the Greek word 'neos', which means 'new'.
24 Hard
24 of 41
Understanding +4 | -1
Assertion: Conc. H2SO4\mathrm{H}_2 \mathrm{SO}_4 on addition to HCOOH\mathrm{HCOOH} liberates CO\mathrm{CO}.

Reason: Hot conc. H2SO4\mathrm{H}_2 \mathrm{SO}_4 is a moderate oxidising agent.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because concentrated H2SO4 dehydrates formic acid to produce CO, and while H2SO4 can act as an oxidizing agent, the reaction proceeds via dehydration.
25 Hard
25 of 41
Analyzing +4 | -1
Assertion: As temperature increases intensity of brown colour of NO2\mathrm{NO}_2 decreases.

Reason: Formation of NO2\mathrm{NO}_2 is an endothermic process.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
The correct answer is D (If both Assertion & Reason are false) because as temperature increases, the equilibrium shifts towards the formation of NO2, increasing the intensity of the brown color, and the formation of NO2 is endothermic.
26 Hard
26 of 41
Analyzing +4 | -1
Which of the following dissolves in water but does not give any oxyacid solution?
View answer and explanation
Correct option: B
OF2O{F_2}
Option B (OF2O{F_2}) is correct because OF2O{F_2} reacts with water to form HFHF and O2O_2, not an oxyacid.
27 Hard
27 of 41
Understanding +4 | -1
Assertion: Ba(N3)2\mathrm{Ba}\left(\mathrm{N}_3\right)_2 give highly pure N2\mathrm{N}_2

Reason: Atomic weight of Ba\mathrm{Ba} is very high
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct because both the assertion and the reason are true, but the reason doesn't explain why barium azide gives pure nitrogen.
28 Hard
28 of 41
Understanding +4 | -1
When concentrated H2SO4{H_2}S{O_4} is added to dry KNO3KN{O_3}, brown fumes evolve.These fumes are of:
View answer and explanation
Correct option: C
NO2N{O_2}
Option C (NO2N{O_2}) is correct because the reaction of concentrated sulfuric acid with potassium nitrate produces nitrogen dioxide (NO2N{O_2}) gas, which is brown in color.
29 Hard
29 of 41
Understanding +4 | -1
The ionic character of the metal halides, MClM \mathrm{Cl}, MI,MBr,M FM \mathrm{I}, M \mathrm{Br}, M \mathrm{~F} decreases in the order:
View answer and explanation
Correct option: C
M F>MCl>MBr>MIM \mathrm{~F}>M \mathrm{Cl}>M \mathrm{Br}>M \mathrm{I}
Option C (M F>MCl>MBr>MIM \mathrm{~F}>M \mathrm{Cl}>M \mathrm{Br}>M \mathrm{I}) is correct because ionic character decreases with increasing size of the halide ion due to increased polarizability.
30 Hard
30 of 41
Understanding +4 | -1
Which of the following compounds gives chlorine dioxide when it reacts with SO2S{O_2} in the presence of acid?
View answer and explanation
Correct option: B
Sodium chlorate
Option B is correct because sodium chlorate reacts with SO2 in the presence of acid to produce chlorine dioxide.
Revision notes and key takeaways

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Key Takeaways

  • ✓ This set contains 41 single-correct-answer MCQs on P-BLOCK ELEMENTS.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
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