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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 320 questions
1 Medium
1 of 320
Remembering +4 | -1
Which of the following is correct stability order of oxides of 17th 17^{\text {th }} group elements is:
View answer and explanation
Correct option: C
I2>Cl2>Br2\mathrm{I}_2>\mathrm{Cl}_2>\mathrm{Br}_2
Option D (Cl2>I2>Br2\mathrm{Cl}_2>\mathrm{I}_2>\mathrm{Br}_2) is incorrect, the correct order is Cl2O>Br2O>I2O\mathrm{Cl}_2O > \mathrm{Br}_2O > \mathrm{I}_2O.
2 Medium
2 of 320
Analyzing +4 | -1
Assertion: Ozone is a powerful oxidising agent in comparison to O2{O}_2.

Reason: Ozone is diamagnetic but O2{O}_2 is paramagnetic.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
Option B (If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion) is correct because ozone is a stronger oxidizing agent than oxygen, and ozone is diamagnetic while oxygen is paramagnetic, but the paramagnetism of oxygen is not the reason for ozone's stronger oxidizing power.
3 Medium
3 of 320
Understanding +4 | -1
Consider the following statements

(i) Reaction 2Fe3++SO2+2H2O→2Fe2++SO42−+4H+2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+} shows reducing character of sulphur dioxide

(ii) H2 S2O8{H}_2 {~S}_2 {O}_8 contains four S=O{S}={O}, two S−OH{S}-{OH} and one O−{O}- O{O} bond

(iii) NH3{NH}_3 gas can be dried effectively by using conc. H2SO4{H}_2 {SO}_4.

(iv) One of the major use of H2SO4{H}_2 {SO}_4 is in the manufacture of fertilizers.

Which of the following is the correct code for the statements above?
View answer and explanation
Correct option: B
TTFT
Option B (TTFT) is correct because statements (i), (ii), and (iv) are true, while statement (iii) is false due to the reaction between ammonia and sulfuric acid.
4 Medium
4 of 320
Analyzing +4 | -1
Assertion (A) : Each N\mathrm{N}-atom is sp3s p^3-hybridised in N2H4\mathrm{N}_2 \mathrm{H}_4.

Reason (R) : It has gauche conformation.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Both A and R are true but R is not the correct explanation of A because while N_2H_4 does have sp3 hybridized N atoms and a gauche conformation, the conformation doesn't explain the hybridization.
5 Medium
5 of 320
Understanding +4 | -1
Which is correct statement?
View answer and explanation
Correct option: C
Nitric oxide is an endothermic compound
Option C is correct. Nitric oxide (NO) is an endothermic compound, meaning its formation requires energy input (positive enthalpy change).
6 Medium
6 of 320
Analyzing +4 | -1
Which of the following will not form disproportionated product?
View answer and explanation
Correct option: D
XeF2+H2O⟶{XeF}_2+{H}_2 {O} \longrightarrow
Option D is correct because XeF2 reacts with water to form Xe, HF, and O2, without disproportionation.
7 Medium
7 of 320
Application +4 | -1
Iodine reacts with concentrated HNO3HN{O_3} to yield Y along with other products. The oxidation state of iodine in Y,Y, is
View answer and explanation
Correct option: D
5
Option D (5) is correct because iodine reacts with concentrated HNO₃ to form iodic acid (HIO₃), where the oxidation state of iodine is +5.
8 Medium
8 of 320
Understanding +4 | -1
Which would quickly absorb oxygen?
View answer and explanation
Correct option: A
Alkaline solution of pyrogallic acid
Option A (Alkaline solution of pyrogallic acid) is correct because alkaline pyrogallol readily absorbs oxygen, making it suitable for removing oxygen from gas mixtures.
9 Medium
9 of 320
Analyzing +4 | -1
The true statement for the acids of phosphorus, H3PO2,H3PO3\mathrm{H}_3 \mathrm{PO}_2, \mathrm{H}_3 \mathrm{PO}_3 and H3PO4\mathrm{H}_3 \mathrm{PO}_4 is
View answer and explanation
Correct option: D
The geometry of phosphorus is tetrahedral in all the three
Option D is correct because H3PO2,H3PO3\mathrm{H}_3 \mathrm{PO}_2, \mathrm{H}_3 \mathrm{PO}_3 and H3PO4\mathrm{H}_3 \mathrm{PO}_4 all have phosphorus with sp3sp^3 hybridization, resulting in a tetrahedral geometry.
10 Medium
10 of 320
Understanding +4 | -1
Assertion (A): N2O5\mathrm{N}_2 \mathrm{O}_5 is not possible due to

Reason (R): incapability of 'N' to show pentavalency Max. covalency of 'N' can be 4.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D is correct because N2O5 is a known compound, and nitrogen can exhibit a covalency of more than 4 using d-orbitals, though it is less common.
11 Medium
11 of 320
Analyzing +4 | -1
When Cl2\mathrm{C}{\mathrm{l}_2} water is added to an aqueous solution of potassium halide in presence of chloroform a violet colour is obtained. On adding more of Cl2\mathrm{C}{\mathrm{l}_2} water, the violet colour disappears and a colourless solution is obtained. This test confirms the presence of the following in aqueous solution:
View answer and explanation
Correct option: A
Iodide
Option A (Iodide) is correct because the violet color in chloroform indicates the presence of iodine, which is formed by the reaction of iodide with chlorine water. The disappearance of the color with excess chlorine water indicates further oxidation of iodine.
12 Medium
12 of 320
Analyzing +4 | -1
Given below are two statements:
Statement I: Noble gases have very high boiling
points
Statement II: Noble gases are monoatomic gases.
They are held together by strong dispersion forces.
Because of this they are liquefied at very low
temperature. Hence, they have very high boiling
points.
In the light of the above statements, choose the
correct answer from the options given below.
View answer and explanation
Correct option: B
Both statement I and statement II are false
The correct answer is B (Both statement I and statement II are false) because noble gases have very *low* boiling points due to *weak* dispersion forces.
13 Medium
13 of 320
Analyzing +4 | -1
Which statement is incorrect.
View answer and explanation
Correct option: C
BrBr can be prepared from carnalite
The correct answer is D (Br can be prepared from carnalite) because bromine is not directly prepared from carnallite.
14 Medium
14 of 320
Understanding +4 | -1
Among the halogens, the one which is oxidised by nitric acid is
View answer and explanation
Correct option: B
Iodine
Option B (Iodine) is correct because nitric acid oxidizes iodine to iodic acid.
15 Medium
15 of 320
Analyzing +4 | -1
The electronic configurations of four elements are given below. Which element does not belong to the same family as others?
View answer and explanation
Correct option: C
[Ne]3s2,  3p5\left[ {\mathrm{Ne}} \right]3{s^2},\mathrm{\;}3{p^5}
Option C is correct because the element with electronic configuration [Ne]3s2,  3p5\left[ {\mathrm{Ne}} \right]3{s^2},\mathrm{\;}3{p^5} is Chlorine, which is a halogen and belongs to a different family than the others, which are transition metals.

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16 Medium
16 of 320
Understanding +4 | -1
The least stable anion of oxo-acids of chlorine is
View answer and explanation
Correct option: A
ClO−Cl{O^ - }
Option A (ClO−Cl{O^-}) is correct because the stability of oxoanions of chlorine increases with increasing oxidation number of chlorine, making ClO−ClO^- the least stable.
17 Medium
17 of 320
Analyzing +4 | -1
Which of the following is wrong statement?
View answer and explanation
Correct option: D
The inter halogen compound XX1X X^1 hydrolysis as follows.
XX1+H2O→HX+HOX1\mathrm{XX}^1+\mathrm{H}_2 \mathrm{O} \rightarrow H X+\mathrm{HOX}^1 [when X=\mathrm{X}= larger halogen]
Option D is the wrong statement because in the hydrolysis of interhalogen compounds, the larger halogen forms the oxyacid, while the smaller halogen forms the hydrohalic acid.
18 Medium
18 of 320
Analyzing +4 | -1
Select incorrect statement(s) from following and choose the correct option.

(I) In PF5\mathrm{PF}_5 expanded octet is observed.

(II) Central atom in O3\mathrm{O}_3 molecule has zero formal charge.

(III) NO2\mathrm{NO}_2 is an odd electron molecule.
View answer and explanation
Correct option: B
(II) only
Option B is correct because the central atom in the ozone molecule (O3) has a formal charge of +1, not zero. The other statements are correct: PF5 exhibits an expanded octet, and NO2 is an odd electron molecule.
19 Medium
19 of 320
Remembering +4 | -1
The reaction of P4{P_4} with aqueous NaOH gives
View answer and explanation
Correct option: D
PH3P{H_3}
Option D (PH3P{H_3}) is correct because the reaction of white phosphorus (P4P_4) with aqueous NaOH produces phosphine (PH3PH_3) and sodium hypophosphite (NaH2PO2NaH_2PO_2).
20 Medium
20 of 320
Understanding +4 | -1
Assertion : White phosphorus is more reactive than red phosphorus.

Reason : Red phosphorus consists of P4{P}_4 tetrahedral units linked to one another to form linear chains.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the polymeric structure of red phosphorus is not the reason why white phosphorus is more reactive.
21 Medium
21 of 320
Analyzing +4 | -1
Assertion: Sulphuric acid can be used to prepare hydrochloric acid from chloride salts.

Reason: Sulphuric acid is less volatile than hydrochloric acid.
View answer and explanation
Correct option: C
Assertion is correct, but reason is wrong statement.
Option C (Assertion is correct, but reason is wrong statement) is correct because sulfuric acid is actually *more* volatile than hydrochloric acid.
22 Medium
22 of 320
Remembering +4 | -1
Iron present in brown ring complex in the form of
View answer and explanation
Correct option: C
[Fe(H2O)5NO]2+\left[{Fe}\left({H}_2 {O}\right)_5 {NO}\right]^{2+}
Option C ([Fe(H2O)5NO]2+\left[{Fe}\left({H}_2 {O}\right)_5 {NO}\right]^{2+}) is correct because the brown ring complex formed in the nitrate test has the formula [Fe(H2O)5NO]2+\left[{Fe}\left({H}_2 {O}\right)_5 {NO}\right]^{2+}.
23 Medium
23 of 320
Remembering +4 | -1
The uses of ammonia are

I. to produce various nitrogenous fertilisers

II. in the manufacture of nitric acid.

III. as a refrigerant

The correct option is
View answer and explanation
Correct option: D
I, II and III
Option D (I, II and III) is correct because ammonia is used in the production of nitrogenous fertilizers, nitric acid, and as a refrigerant.
24 Medium
24 of 320
Analyzing +4 | -1
Which one has the highest percentage of nitrogen?
View answer and explanation
Correct option: C
Urea
Option C (Urea) is correct because urea (NH2CONH2) has the highest nitrogen content (46.66%) compared to the other options.
25 Medium
25 of 320
Understanding +4 | -1
The correct group of halide ions which can be oxidised by oxygen in acidic medium is
View answer and explanation
Correct option: C
I−\text{I}^- only
Option C (I−\text{I}^- only) is correct because iodide ions can be oxidized by oxygen in acidic medium, while chloride and bromide ions typically do not undergo this reaction under normal conditions.
26 Medium
26 of 320
Analyzing +4 | -1
Assertion (A): F2{F}_2 is stronger oxidant than chlorine.

Reason (R): Fluorine has low bond dissociation energy and more hydration energy.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because fluorine is a stronger oxidizing agent than chlorine due to its low bond dissociation energy and high hydration energy.
27 Medium
27 of 320
Analyzing +4 | -1
Which of the following statements is not valid for oxoacids of phosphorous
View answer and explanation
Correct option: B
Hypophosphorous acid is a diprotic acid
Option B (Hypophosphorous acid is a diprotic acid) is not valid because hypophosphorous acid (H3PO2{H_3}{PO_2}) is a monoprotic acid, not a diprotic acid.
28 Medium
28 of 320
Analyzing +4 | -1
Chemical nature of the nitrogen oxide compound obtained from a reaction of concentrated nitric acid and P4O10{\mathrm{P}_4}{\mathrm{O}_{10}} (in 4: 1 ratio) is
View answer and explanation
Correct option: A
acidic
The correct answer is acidic because the reaction between concentrated nitric acid and P4O10 produces nitrogen pentaoxide (N2O5), which is an acidic oxide.
29 Medium
29 of 320
Understanding +4 | -1
Assertion (A): H2O\mathrm{H}_2 \mathrm{O} is the hydride of chalcogen family which is liquid.

Reason (R): Acidic nature of hydrides of chalcogen family increases down the group.
View answer and explanation
Correct option: B
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
Option B (Both (A) & (R) are true but the (R) is not the correct explanation of the (A)) is correct because while both the assertion and reason are true statements, the reason does not explain why water is a liquid.
30 Medium
30 of 320
Remembering +4 | -1
Nitric oxide is prepared by the action of cold dil. HNO3HN{O_3} on :
View answer and explanation
Correct option: B
Cu
Option B (Cu) is correct because copper reacts with cold dilute nitric acid to produce nitric oxide.
Revision notes and key takeaways

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Key Takeaways

  • ✓ This set contains 320 single-correct-answer MCQs on P-BLOCK ELEMENTS.
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