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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Showing 211-240 of 705 questions

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211 Easy
211 of 705
Remembering +4 | -1
Mixture used in Holme’s signals is
View answer and explanation
Correct option: C
CaC2+Ca3P2Ca{C_2} + C{a_3}{P_2}
Option C (CaC2+Ca3P2Ca{C_2} + C{a_3}{P_2}) is correct because the mixture of calcium carbide and calcium phosphide produces acetylene and phosphine, which ignite spontaneously and produce a visible flame.
212 Medium
212 of 705
Analyzing +4 | -1
Which reaction is not valid?
View answer and explanation
Correct option: B
HF+Cl2→F2+HClHF\mathrm{ } + \mathrm{ }C{l_2} \to {F_2} + \mathrm{ }HCl
Option B (HF+Cl2→F2+HClHF\mathrm{ } + \mathrm{ }C{l_2} \to {F_2} + \mathrm{ }HCl) is not valid because fluorine is more electronegative than chlorine and can displace it, but chlorine cannot displace fluorine.
213 Medium
213 of 705
Analyzing +4 | -1
Which species has the largest dipole moment?
View answer and explanation
Correct option: A
NH3\mathrm{N}{\mathrm{H}_3}
Option A is correct. NH₃ has the largest dipole moment because nitrogen is more electronegative than phosphorus, arsenic, and antimony, leading to a greater difference in electronegativity between N and H.
214 Medium
214 of 705
Analyzing +4 | -1
Statement I: Single N−N\mathrm{N}-\mathrm{N} bond is weaker than the single P−P\mathrm{P}-\mathrm{P} bond due to high interelectronic repulsion of the non-bonding electrons, owing to the small bond length.

Statement II: The catenation tendency is stronger in nitrogen as compared to phosphorus.
View answer and explanation
Correct option: B
Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I.
Option B (Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I) is correct because both statements are true, but the catenation tendency of nitrogen is weaker, not stronger, than that of phosphorus.
215 Medium
215 of 705
Analyzing +4 | -1
Which of the following is the correct code for statements below?

(i) Due to small size oxygen has less negative electron gain enthalpy than sulphur.

(ii) Oxygen shows only -2 oxidation state whereas S{S}, Se{Se} and Te shows +4 O.S in their compounds with oxygen and +6 with fluorine.

(iii) All hydrides of oxygen family possess reducing property which increases from H2 S{H}_2 {~S} to H2{H}_2 TeTe.

(iv) Among hexahalides of group 16 hexafluorides are the onlys table halides.

(v) Dimeric monohalides of group 16 undergo disproportionation.
View answer and explanation
Correct option: A
TFFTT
Option A (TFFTT) is correct because statements (i), (iv), and (v) are true, while statements (ii) and (iii) are false.
216 Easy
216 of 705
Remembering +4 | -1
The noble gas used in atomic reactor ,is
View answer and explanation
Correct option: D
Helium
Option D (Helium) is correct because helium is a noble gas often used in atomic reactors due to its inertness, high thermal conductivity, and low neutron absorption cross-section.
217 Easy
217 of 705
Remembering +4 | -1
Which of the following is pseudohalogen?
View answer and explanation
Correct option: B
(CN)2{\left( {CN} \right)_2}
Option B ((CN)2{\left( {CN} \right)_2}) is correct because dicyanogen ((CN)2{\left( {CN} \right)_2}) exhibits properties similar to halogens and is thus classified as a pseudohalogen.
218 Easy
218 of 705
Remembering +4 | -1
The poisson’s ratio for inert gases is:
View answer and explanation
Correct option: B
1.66
Option B (1.66) is correct because inert gases are monatomic, and for monatomic gases, the ratio of specific heats (γ = Cp/Cv) is approximately 1.66.
219 Easy
219 of 705
Remembering +4 | -1
Which of the following elements is good conductor of electricity?
View answer and explanation
Correct option: C
Bi
Option C (Bi) is correct because Bismuth is a metal and metals are generally good conductors of electricity.
220 Medium
220 of 705
Remembering +4 | -1
Which of the following is strongest oxyacid of chlorine?
View answer and explanation
Correct option: C
Perchloric acid
Option C (Perchloric acid) is correct because Perchloric acid has the highest oxidation state of chlorine, making it the strongest oxyacid.
221 Easy
221 of 705
Understanding +4 | -1
Which of the following inert gas liquefies easily?
View answer and explanation
Correct option: B
Kr\mathrm{Kr}
Option B (Kr\mathrm{Kr}) is correct because Krypton has the highest boiling point among the given noble gases, indicating stronger intermolecular forces and easier liquefaction.
222 Easy
222 of 705
Remembering +4 | -1
Which of the following halogens is solid at room temperature?
View answer and explanation
Correct option: A
Iodine
Option A (Iodine) is correct because iodine is a solid at room temperature, while fluorine and chlorine are gases, and bromine is a liquid.
223 Medium
223 of 705
Understanding +4 | -1
Assertion: Fluorine forms only one oxo acid HOFHOF.

Reason: Fluorine does not have dd- orbitals in its valence shell.
View answer and explanation
Correct option: A
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
Option A (Both assertion and reason are correct statements, and reason is the correct explanation of the assertion) is correct because fluorine's inability to expand its octet due to the absence of d-orbitals limits it to forming only one oxoacid.
224 Easy
224 of 705
Understanding +4 | -1
How many lone pair of electrons are present on XeXe in XeOF4XeO{F_4} ?
View answer and explanation
Correct option: A
1
Option B (2) is correct because a 3p orbital has one angular node (l=1) and one radial node (n-l-1 = 3-1-1 = 1).
225 Medium
225 of 705
Understanding +4 | -1
White phosphorus reacts with thionyl chloride to give
View answer and explanation
Correct option: B
PCl3,SO2\mathrm{PCl}_3, \mathrm{SO}_2 and S2Cl2\mathrm{S}_2 \mathrm{Cl}_2
Option B (PCl3,SO2\mathrm{PCl}_3, \mathrm{SO}_2 and S2Cl2\mathrm{S}_2 \mathrm{Cl}_2) is correct because white phosphorus reacts with thionyl chloride to produce phosphorus trichloride, sulfur dioxide, and disulfur dichloride.

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226 Medium
226 of 705
Analyzing +4 | -1
Which of the following combination does not liberate NH3{NH}_3 gas?
View answer and explanation
Correct option: A
Heating of NH4ClO4{NH}_4 {ClO}_4
Option A (Heating of NH4ClO4{NH}_4 {ClO}_4) is correct because it decomposes into nitrogen, chlorine, oxygen, and water, not ammonia.
227 Easy
227 of 705
Analyzing +4 | -1
Assertion (A): The fluorine has lower reactivity.

Reason (R): F−F{F}-F bond in F2{F}_2 molecule is weak.
View answer and explanation
Correct option: D
(A) is false and (R) is true
Option D ((A) is false and (R) is true) is correct because fluorine is highly reactive, and the F-F bond is weak due to the small size and high interelectronic repulsion.
228 Easy
228 of 705
Analyzing +4 | -1
A gas reacts with CaO\mathrm{CaO}, but not with NaHCO3\mathrm{NaHC}{\mathrm{O}_3}. The gas is:
View answer and explanation
Correct option: B
Cl2\mathrm{C}{\mathrm{l}_2}
Option B is correct because Cl2 reacts with CaO to form calcium chloride and calcium hypochlorite, but does not react with NaHCO3.
229 Medium
229 of 705
Remembering +4 | -1
Nitrogen gas is obtained by thermal decomposition of
View answer and explanation
Correct option: B
Ba(N3)2Ba{\left( {{N_3}} \right)_2}
Option B (Ba(N3)2Ba{\left( {{N_3}} \right)_2}) is correct because barium azide decomposes upon heating to produce barium metal and nitrogen gas.
230 Easy
230 of 705
Remembering +4 | -1
Clathrates are
View answer and explanation
Correct option: A
Non-stoichiometric compounds
Option A (Non-stoichiometric compounds) is correct because clathrates are non-stoichiometric compounds where the ratio of guest and host molecules does not correspond to an ideal chemical formula.
231 Medium
231 of 705
Understanding +4 | -1
Xenon hexafluoride reacts with silica to form a xenon compound X. The oxidation state of xenon in X is
View answer and explanation
Correct option: C
6
Option C is correct because in the reaction of XeF6XeF_6 with silica, XeOF4XeO{F_4} is formed, where the oxidation state of Xe is +6.
232 Easy
232 of 705
Understanding +4 | -1
Assertion (A) : O2\mathrm{O}_2 gas is effected in magnetic field.

Reason (R) : It has north and south pole.
View answer and explanation
Correct option: C
A\mathbf{A} is true but R\mathbf{R} is false.
Option C (A\mathbf{A} is true but R\mathbf{R} is false) is correct because oxygen gas is paramagnetic and is attracted to magnetic fields due to the presence of unpaired electrons, but it does not have fixed north and south poles.
233 Easy
233 of 705
Remembering +4 | -1
The gas used in gas thermometer is:
View answer and explanation
Correct option: A
HeHe
Option A (HeHe) is correct because helium is an inert gas with a low boiling point, making it suitable for use in gas thermometers over a wide temperature range.
234 Hard
234 of 705
Remembering +4 | -1
The propellant in the proposed PSLV rocket of the Indian space programme shall consist of:
View answer and explanation
Correct option: C
Both (1) and (2) in different stages of rocket propulsion
Option C (Both (1) and (2) in different stages of rocket propulsion) is correct because PSLV rockets use a combination of solid and liquid propellants in different stages to achieve the required thrust and efficiency.
235 Easy
235 of 705
Remembering +4 | -1
The fertilizer named ‘Nitrolim’ is prepared by the use of :
View answer and explanation
Correct option: D
CaC2+N2Ca{C_2} + {N_2}
Option D (CaC2+N2Ca{C_2} + {N_2}) is correct because Nitrolim (CaCN2CaCN_2) is produced by reacting calcium carbide (CaC2CaC_2) with nitrogen gas (N2N_2).
236 Medium
236 of 705
Analyzing +4 | -1
Which of the following orders are correct as per the properties mentioned against each.
View answer and explanation
Correct option: A
AS2O3<SiO2<P2O3<SO2A{S_2}{O_3} < Si{O_2} < {P_2}{O_3} < S{O_2} : Acid strength
Option A is correct because the acid strength order ASH3<SiO2<P2O3<SO2AS{H_3} < Si{O_2} < {P_2}{O_3} < S{O_2} is correct.
237 Easy
237 of 705
Remembering +4 | -1
Nitrogen forms …. Oxides.
View answer and explanation
Correct option: C
5
Option C (5) is correct because nitrogen forms five stable oxides: N₂O, NO, N₂O₃, N₂O₄, and N₂O₅.
238 Medium
238 of 705
Analyzing +4 | -1
The largest bond angle exists in:
View answer and explanation
Correct option: B
NH3N{H_3}
Option B (NH3NH_3) is correct because it has one lone pair, while the others have two, leading to a larger bond angle due to less lone pair repulsion.
239 Medium
239 of 705
Understanding +4 | -1
Nitrogen forms N2,{N_2}, but phosphorous does not form P2,{P_2}, however it converts P4,{P_4}, reason is
View answer and explanation
Correct option: B
Pπ−PπP\pi \mathrm{ - }P\pi Bonding is weak.
Option B is correct. Phosphorus does not form P2 because Pπ-Pπ bonding is weak due to its larger size and lower electronegativity compared to nitrogen.
240 Easy
240 of 705
Remembering +4 | -1
The increasing order of reactivity of halogens is:
View answer and explanation
Correct option: A
I2<Br2<Cl2<F2{I_2} < B{r_2} < C{l_2} < {F_2}
Option A (I2<Br2<Cl2<F2{I_2} < B{r_2} < C{l_2} < {F_2}) is correct because the reactivity of halogens decreases down the group, with fluorine being the most reactive and iodine being the least reactive.
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