JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Analyzing +4 | -1

The correct order of acidic nature is:

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Correct option: A

\mathrm{C}{\mathrm{l}_2}{\mathrm{O}_7} > \mathrm{S}{\mathrm{O}_2} > {\mathrm{P}_4}{\mathrm{O}_{10}}

Option A is correct because acidic character of oxides increases across a period, and Cl2O7 is the most acidic among the given options.

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4