Back to CO-ORDINATION COMPOUNDS
Your Progress
0 / 326 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS
Co-ordination compounds practice · Mixed difficulty
Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.
Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
Take a chapter quiz →
Showing 181-210 of 326 questions
Preparing practice and saved progress…
181
Medium
181 of 326
Understanding
+4 | -1
The crystal field splitting energy for ion in an octahedral field increases for the ligands , and the order is such that
View answer and explanation
Correct option: A
Option A () is correct because it represents the correct order of ligands in the spectrochemical series, which determines the crystal field splitting energy.
182
Medium
182 of 326
Analyzing
+4 | -1
A s- block element (M) reacts with oxygen to form an oxide of the formula The oxide is pale yellow in colour and paramagnetic. The element(M) is
View answer and explanation
Correct option: D
K
Option D (K) is correct because potassium reacts with oxygen to form potassium superoxide (), which is paramagnetic due to the presence of an unpaired electron.
183
Medium
183 of 326
Analyzing
+4 | -1
Of the following complex ions, which is diamagnetic in nature?
View answer and explanation
Correct option: C
Option C () is correct because it has a d8 configuration with strong field ligands causing pairing of electrons, resulting in a diamagnetic complex.
184
Medium
184 of 326
Analyzing
+4 | -1
Among the complex ions given below which is/are outer - orbital's complex
I)
II)
III)
IV)
I)
II)
III)
IV)
View answer and explanation
Correct option: A
II, III, IV
Option C (If A is correct but R is incorrect) is correct because at very high pressures, the compressibility factor is greater than 1, but the reason provided about neglecting 'b' is incorrect.
185
Medium
185 of 326
Analyzing
+4 | -1
Select the correct statement set?
A) Bis-(glycinato) Zinc (II) is optically active
B) and differ in shapes
C) and have same magnetic moment
D) cis- cannot show optical activity
A) Bis-(glycinato) Zinc (II) is optically active
B) and differ in shapes
C) and have same magnetic moment
D) cis- cannot show optical activity
View answer and explanation
Correct option: C
A, B, C
The correct answer is B (Due to formation of CH₃COOH which acts as a weak acid) because the hydrolysis of methyl acetate produces acetic acid, which neutralizes the NaOH, causing the phenolphthalein to become colorless.
186
Easy
186 of 326
Understanding
+4 | -1
The complexes and
are examples for which type of isomerism
are examples for which type of isomerism
View answer and explanation
Correct option: C
Ionization
Option C is correct because ionization isomerism involves the exchange of ligands between the coordination sphere and the ionization sphere.
187
Easy
187 of 326
Application
+4 | -1
In the valency and coordination number of will be respectively
View answer and explanation
Correct option: D
2 and 4
Option D (2 and 4) is correct because the oxidation state of Ni is +2 and the coordination number is 4.
188
Easy
188 of 326
Remembering
+4 | -1
Out of the following the metal which forms polynuclear carbonyl is:
View answer and explanation
Correct option: C
Option C () is correct because manganese forms polynuclear carbonyls such as .
189
Hard
189 of 326
Analyzing
+4 | -1
Which of the following ions can exhibit optical isomerism-
View answer and explanation
Correct option: C
Option C (Cis- [Co(en)2Cl2]+) is correct because the cis isomer of [M(aa)2b2] complexes can exhibit optical isomerism, while the trans isomer cannot.
190
Easy
190 of 326
Analyzing
+4 | -1
The possible number of isomers for the complex is:
View answer and explanation
Correct option: D
5
The correct answer is D (5) because the complex [MCl2Br2]SO4 can have five isomers: three geometrical isomers (cis, trans, and another trans) and two ionization isomers.
191
Medium
191 of 326
Analyzing
+4 | -1
Comment on the magnetic behavior of and .
View answer and explanation
Correct option: B
Diamagnetic and paramagnetic
Option B is correct because K₂[NiF₆] is diamagnetic due to strong field caused by high charge on Ni, while K₄[NiF₆] is paramagnetic due to weak field ligand F⁻.
192
Medium
192 of 326
Application
+4 | -1
Specify the coordination number of the metal in
View answer and explanation
Correct option: D
6
Option D (6) is correct because the coordination number is the number of ligands directly attached to the central metal ion, which is 6 in this case.
193
Medium
193 of 326
Analyzing
+4 | -1
Maximum bond length present in:
View answer and explanation
Correct option: B
Option B () is correct because the negative charge on the metal increases back-bonding, which weakens the C-O bond and thus increases the C-O bond length.
194
Medium
194 of 326
Analyzing
+4 | -1
S-I: is a low spin complex.
S-II: ion in this complex undergoes hybridization.
S-II: ion in this complex undergoes hybridization.
View answer and explanation
Correct option: B
Statement-I is true, Statement-II is false
Option B (Statement-I is true, Statement-II is false) is correct because is indeed a low spin complex, but the hybridization of is .
195
Easy
195 of 326
Understanding
+4 | -1
Each metal possesses:
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because metals in coordination complexes possess primary valencies satisfied by anions, secondary valencies satisfied by donor molecules, and a coordination number.
Explore Other Chapters in CHEMISTRY
View All →
196
Medium
196 of 326
Understanding
+4 | -1
For the square planar complex (where , central metal and and are monodentate ligands), the number of possible geometrical isomers are
View answer and explanation
Correct option: C
3
Option C (3) is correct because for a square planar complex with four different monodentate ligands, there are 3 possible geometrical isomers.
197
Easy
197 of 326
Remembering
+4 | -1
In the ligands are:
View answer and explanation
Correct option: C
Both
Option C (Both ) is correct because both ammonia and chloride ions are directly bonded to the central metal ion.
198
Medium
198 of 326
Application
+4 | -1
A spin only magnetic moment of will be shown by which one among the following:
View answer and explanation
Correct option: B
Option B ([{Cu}({NH}_3)_4]2+) is correct because Cu2+ has a 3d9 configuration, resulting in 1 unpaired electron and a magnetic moment of approximately 1.73 BM.
199
Medium
199 of 326
Analyzing
+4 | -1
Assertion : Coordination number of Pt in Zeise's salt is 5.
Reason : act as bidentate ligand
Reason : act as bidentate ligand
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because Zeise's salt has Pt with a coordination number of 3, and ethylene acts as a monodentate ligand.
200
Easy
200 of 326
Application
+4 | -1
Which one is an outer orbital complex?
View answer and explanation
Correct option: A
The correct answer is because Ni in this complex has hybridization, which is an outer orbital complex.
201
Medium
201 of 326
Application
+4 | -1
An octahedral complex with the formula upon reaction with excess of solution given 2 moles of . Consider the oxidation state of Co in the complex is ' '. The value of " " is ______.
View answer and explanation
Correct option: C
8
Option C (8) is correct because the complex gives 2 moles of AgCl, indicating two chloride ions outside the coordination sphere, leading to the formula [Co(NH3)5Cl]Cl2. Therefore, x=3 and n=5, so x+n=8.
202
Easy
202 of 326
Analyzing
+4 | -1
Which of the following statements is true for the complexes: (I) and (II) ?
View answer and explanation
Correct option: A
Both (I) and (II) are paramagnetic.
Option A (Both (I) and (II) are paramagnetic) is correct because both complexes have unpaired electrons due to F- being a weak field ligand, resulting in high-spin configurations.
203
Easy
203 of 326
Understanding
+4 | -1
is used to detect the presence of:
View answer and explanation
Correct option: C
Ferric ion
Option C (Ferric ion) is correct because reacts with ferric ions () to form Prussian blue, a characteristic colored precipitate.
204
Medium
204 of 326
Analyzing
+4 | -1
Statement I: is more acidic compared to
Statement II: Both are inner orbital complexes
Statement II: Both are inner orbital complexes
View answer and explanation
Correct option: D
Statement I if false but statement II is correct
Statement I is false and Statement II is correct because [Cr(H2O)6]+3 is less acidic than [Fe(H2O)6]+3 due to the higher charge density of Fe3+, and both are indeed inner orbital complexes.
205
Easy
205 of 326
Application
+4 | -1
IUPAC name of is
View answer and explanation
Correct option: B
Sodium hexanitro cobaltate (III)
Option C (Sodium hexanitrito cobaltate (III)) is correct because it follows the IUPAC naming conventions for coordination compounds, indicating the ligands and oxidation state of the central metal atom.
206
Medium
206 of 326
Remembering
+4 | -1
In which year, IUPAC draft recommends that anionic ligands will end with-ido so that chloro would become chlorido?
View answer and explanation
Correct option: D
2004
Option D (2004) is correct because IUPAC recommended the change in 2004.
207
Easy
207 of 326
Analyzing
+4 | -1
Which possesses tetrahedral shape (hybridization of central atom)?
View answer and explanation
Correct option: D
All are correct
Option D is correct because all the given complexes, , , and , have tetrahedral shape with hybridization.
208
Medium
208 of 326
Analyzing
+4 | -1
Which of the following has maximum number of geometrical isomers?
View answer and explanation
Correct option: C
Option C (Ma2b2C2) is correct because it has the highest number of possible geometrical isomers (5) compared to the other options.
209
Medium
209 of 326
Remembering
+4 | -1
To inhibit the growth of tumours, identify the compounds used from the following :
(A) EDTA
(B) Coordination Compounds of Pt
(C) D - Penicillamine
(D) Cis - Platin
Choose the correct answer from the option given below :
(A) EDTA
(B) Coordination Compounds of Pt
(C) D - Penicillamine
(D) Cis - Platin
Choose the correct answer from the option given below :
View answer and explanation
Correct option: B
B and D only
Option B (B and D only) is correct because coordination compounds of platinum and Cis-platin are used to inhibit tumor growth.
210
Medium
210 of 326
Analyzing
+4 | -1
Select correct match :
View answer and explanation
Correct option: D
Co-or dination isomerism
Option D ([{CoBrCl}({H}_2 {O})_4][{Ag}({CN})_2]) is the correct match because it exhibits coordination isomerism, where ligands are exchanged between the complex ions.
Revision notes and key takeaways
Review CO-ORDINATION COMPOUNDS in your textbook or class notes, then use this set to check your understanding.
Showing 181-210 of 326 questions
