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JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS

Co-ordination compounds practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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151 Easy
151 of 326
Understanding +4 | -1
The coordination number of cobalt in [Co(en)2Br2]Cl2\left[ {\mathrm{Co}{{\left( {\mathrm{en}} \right)}_2}\mathrm{B}{\mathrm{r}_2}} \right]\mathrm{C}{\mathrm{l}_2} is:
View answer and explanation
Correct option: C
6
Option C (6) is correct because the coordination number is the number of ligands directly attached to the central metal atom, and in this case, there are two ethylenediamine (en) ligands (each donating 2) and two bromide ions (each donating 1).
152 Medium
152 of 326
Analyzing +4 | -1
Which of the following are false about [Cu(NH3)4]SO4\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right] \mathrm{SO}_4 ?

I. It is paramagnetic with one unpaired electron in the dd-subshell.

II. Its aqueous solution cannot conduct electricity.

III. It gives white BaCl2\mathrm{BaCl}_2 solution.

IV. It is a square planar complex.

Choose the correct option.
View answer and explanation
Correct option: A
I and II
Option A (I and II) is correct because [Cu(NH3)4]SO4 is paramagnetic and its aqueous solution conducts electricity.
153 Medium
153 of 326
Application +4 | -1
Which of the following do not Obeys Sidwick's rule of EAN
View answer and explanation
Correct option: A
[V(CO)6]\left[{V}({CO})_6\right]
Option A ([V(CO)6]) is correct because it does not obey Sidgwick's EAN rule, as its EAN is 35, not the expected 36 for Krypton.
154 Hard
154 of 326
Analyzing +4 | -1
Assertion : AgI\mathrm{AgI} is coloured while AgF\mathrm{AgF} is colourless.

Reason : Unpaired e−{{\text{e}}^ - } is present in AgI\mathrm{AgI}
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because while AgI is colored and AgF is colorless, the reason is due to charge transfer spectra, not unpaired electrons.
155 Medium
155 of 326
Analyzing +4 | -1
Assertion: In zieses salt coordination no. of PtPt is five.
Reason: Ethene is monodentate ligand.
View answer and explanation
Correct option: D
Assertion is false, Reason is true
Option D (Assertion is false, Reason is true) is correct because in Zeise's salt, the coordination number of Pt is 4, and ethene is indeed a monodentate ligand.
156 Medium
156 of 326
Analyzing +4 | -1
Which of the following will not show geometrical isomerism?
View answer and explanation
Correct option: A
[Co(ox)3]3−\left[\mathrm{Co}(o x)_3\right]^{3-}
Option A ([Co(ox)3]3−\left[\mathrm{Co}(o x)_3\right]^{3-}) is correct because M(aa)3M(a a)_3 type complexes do not exhibit geometrical isomerism.
157 Medium
157 of 326
Analyzing +4 | -1
The d−d -electron configurations of Cr2+,  Mn2+,  Fe2+\mathrm{C}{\mathrm{r}^{2 + }},\mathrm{\;M}{\mathrm{n}^{2 + }},\mathrm{\;F}{\mathrm{e}^{2 + }} and Co2+\mathrm{C}{\mathrm{o}^{2 + }} are d4,d5,d6  and  d7{d^4},{d^5},{d^6}\;and\;{d^7} respectively. Which one of the following will exhibit minimum paramagnetic behaviour?
(At. Nos.Cr=24,  Mn=25,  Fe=26,  Co=27\mathrm{Cr} = 24,\mathrm{\;Mn} = 25,\mathrm{\;Fe} = 26,\mathrm{\;Co} = 27)
View answer and explanation
Correct option: D
[Co(H2O)6]2+{\left[ {\mathrm{Co}{{\left( {{\mathrm{H}_2}\mathrm{O}} \right)}_6}} \right]^{2 + }}
The correct answer is D ([Co(H2O)6]2+) because H2O is a weak field ligand, resulting in only 3 unpaired electrons for Co2+, leading to minimum paramagnetic behavior.
158 Easy
158 of 326
Application +4 | -1
Which complex compound obeys 18-electron rule?
View answer and explanation
Correct option: B
[Fe(NH3)6]2+{\left[ {\mathrm{Fe}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]^{2 + }}
Option B ([Fe(NH3)6]2+{\left[ {\mathrm{Fe}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]^{2 + }}) is correct because it obeys the 18-electron rule, having 18 valence electrons.
159 Easy
159 of 326
Understanding +4 | -1
The number of ions given by K[Pt(NH3)5Cl5]\mathrm{K}\left[ {\mathrm{Pt}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{C}{\mathrm{l}_5}} \right] in aqueous solution is:
View answer and explanation
Correct option: A
2
Option A (2) is correct because the complex dissociates into two ions: K+ and [Pt(NH3)5Cl5]-.
160 Easy
160 of 326
Analyzing +4 | -1
Which of the following ions forms most stable complex compound?
View answer and explanation
Correct option: B
Mn2+\mathrm{M}{\mathrm{n}^{2 + }}
Option D (Cu2+{\mathrm{C}{\mathrm{u}^{2 + }}}) is correct because Cu2+{\mathrm{C}{\mathrm{u}^{2 + }}} exhibits Jahn-Teller distortion, which enhances the stability of its complexes.
161 Medium
161 of 326
Application +4 | -1
The coordination number and oxidation state of central atom for [TiF9]6−\left[{TiF}_9\right]^{6-} are respectively
View answer and explanation
Correct option: B
9,+39,+3
The correct answer is B (9, +3) because the coordination number is 9 (number of ligands) and the oxidation state of Ti is +3.
162 Medium
162 of 326
Analyzing +4 | -1
Which of the following complex does not show geometrical isomerism?
View answer and explanation
Correct option: C
[Cr(en)3]3+\left[\mathrm{Cr}(\mathrm{en})_3\right]^{3+}
The correct answer is C ([Cr(en)_3]3+) because this complex does not exhibit geometrical isomerism due to its symmetrical structure.
163 Medium
163 of 326
Understanding +4 | -1
Mercuric chloride is soluble in KI{KI} solution due to:
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Correct option: A
The formation of complex ion
Option A is correct because mercuric chloride (HgCl2{HgCl}_2) dissolves in KI solution due to the formation of a complex ion, HgI42−{HgI}_4^{2-}.
164 Medium
164 of 326
Analyzing +4 | -1
Which of the following does not show optical isomerism?
View answer and explanation
Correct option: C
[Co(NH3)3Cl3]0{\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_3}\mathrm{C}{\mathrm{l}_3}} \right]^0}
Option C ([Co(NH3)3Cl3]0{\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_3}\mathrm{C}{\mathrm{l}_3}} \right]^0}) does not show optical isomerism because it does not contain any chiral center and exists as geometrical isomers (fac and mer).
165 Easy
165 of 326
Remembering +4 | -1
The tetrahedral complexes have coordination number
View answer and explanation
Correct option: C
4
Option C (4) is correct because tetrahedral complexes have a coordination number of 4, meaning the central metal atom is directly bonded to four ligands.
166 Hard
166 of 326
Analyzing +4 | -1
Which of the following coordination entities should be expected to absorb light of lowest frequency?
View answer and explanation
Correct option: B
[CrCl6]3−\left[\mathrm{CrCl}_6\right]^{3-}
Option B is correct because [CrCl6]3- has the weakest field ligand (Cl-), leading to the smallest crystal field splitting and absorption of light at the lowest frequency.
167 Easy
167 of 326
Analyzing +4 | -1
Which complex is likely to show optical activity?
View answer and explanation
Correct option: C
Cis−[Co(NH3)2(en)2]3+Cis - {\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_2}{{\left( {\mathrm{en}} \right)}_2}} \right]^{3 + }}
Option C (Cis−Co(NH3)2(en)23+Cis - { {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_2}{{\left( {\mathrm{en}} \right)}_2}} }^{3 + }) is correct because only cis-octahedral complexes can exhibit optical activity due to their non-superimposable mirror images.
168 Medium
168 of 326
Understanding +4 | -1
Which of the following is a square planar complex?
View answer and explanation
Correct option: B
[Cu(NH3)4]2+\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+}
Option B ([Cu(NH3)4]2+\left[\mathrm{Cu}(\mathrm{NH}_3)_4\right]^{2+}) is correct because [Cu(NH3)4]2+\left[\mathrm{Cu}(\mathrm{NH}_3)_4\right]^{2+} has a d8d^8 configuration and strong field ligands, leading to a square planar geometry.
169 Easy
169 of 326
Remembering +4 | -1
The tetrahedral complexes have coordination number
View answer and explanation
Correct option: C
4
Option C (4) is correct because tetrahedral complexes have a coordination number of 4.
170 Medium
170 of 326
Understanding +4 | -1
When an aqueous solution of copper (II) sulphate is saturated with ammonia, the blue compound crystallises on evaporation. The formula of this blue compound is:
View answer and explanation
Correct option: A
[Cu(NH3)4]SO4⋅H2O\left[{Cu}\left({NH}_3\right)_4\right] {SO}_4 \cdot {H}_2 {O} (square planar)
Option A ([Cu(NH3)4]SO4⋅H2O\left[{Cu}\left({NH}_3\right)_4\right] {SO}_4 \cdot {H}_2 {O} (square planar)) is correct because copper(II) ions react with ammonia to form a tetraamminecopper(II) complex, which is square planar and includes a water molecule in the crystal structure.
171 Medium
171 of 326
Application +4 | -1
The CFSE for octahedral [CoCl6]4+{\left[ {CoC{l_6}} \right]^{4 + }} is 18,000 cm−1c{m^{ - 1}}. The CFSE for tetrahedral [COCl4]2−{\left[ {COC{l_4}} \right]^{2 - }} will be
View answer and explanation
Correct option: C
8,000  cm−18,000\,\,c{m^{ - 1}}
Option C (8,000  cm−18,000\,\,c{m^{ - 1}}) is correct because the CFSE for tetrahedral complexes is approximately 4/9 of the octahedral CFSE.
172 Easy
172 of 326
Understanding +4 | -1
[Co(NH3)5SO4]Br    and  [Co(NH3)5  Br]SO4\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{S}{\mathrm{O}_4}} \right]\mathrm{Br\;}\,\,\mathrm{and}\,\,\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{\;Br}} \right]\mathrm{S}{\mathrm{O}_4} are a pair of ….. Isomers.
View answer and explanation
Correct option: A
Ionisation
Option A (Ionisation) is correct because the isomers differ in the counter ion that is coordinated to the metal center, leading to different ions in solution.
173 Medium
173 of 326
Understanding +4 | -1
Consider the following statements: According to the Werner's theory.
(1) Ligands are connected to the central metal ions by ionic bonds.
(2) Secondary valencies have directional properties
(3) Secondary valencies are non-ionisable
The correct statements are:
View answer and explanation
Correct option: B
2 and 3 are correct
Option B is correct because, according to Werner's theory, ligands are connected to the central metal ions by coordinate bonds, not ionic bonds, and secondary valencies (coordination number) are non-ionizable and have directional properties.
174 Medium
174 of 326
Analyzing +4 | -1
Assertion :- Ethanol cannot show position isomerism.

Reason :- Ethanol cannot show isomerism.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because while ethanol cannot show position isomerism, it *can* show isomerism (constitutional isomerism with ethers).
175 Medium
175 of 326
Analyzing +4 | -1
Which of the following 0.1 M complex compound solutions will have the minimum electrical conductivity?
View answer and explanation
Correct option: D
Trichloro triammine platinum (IV) chloride
Option D (Trichloro triammine platinum (IV) chloride) is correct because it produces the fewest number of ions in solution, resulting in the lowest electrical conductivity.
176 Medium
176 of 326
Understanding +4 | -1
Given below are two statements:

Statement (I): A solution of [Ni(H2O)6]2+\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} is green in colour.

Statement (II): A solution of [Ni(CN)4]2−\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-} is colourless.

In the light of the above statements, choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: B
Both Statement I and Statement II are correct
Option B (Both Statement I and Statement II are correct) is correct because [Ni(H2O)6]2+\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} is green due to d-d transitions, and [Ni(CN)4]2−\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-} is colorless due to being diamagnetic.
177 Easy
177 of 326
Remembering +4 | -1
[EDTA]4− is  a{\left[ {\mathrm{EDTA}} \right]^{4 - }}{\mkern 1mu} \mathrm{is}{\mkern 1mu} {\mkern 1mu} \mathrm{a}
View answer and explanation
Correct option: D
Hexadentate ligand
Option D (Hexadentate ligand) is correct because [EDTA]4−{\left[ {\mathrm{EDTA}} \right]^{4 - }} can donate six pairs of electrons to the central metal atom, making it a hexadentate ligand.
178 Medium
178 of 326
Understanding +4 | -1
Which of the following has the highest molar conductivity in solution?
View answer and explanation
Correct option: A
[Pt(NH3)6]Cl4\left[ {\mathrm{Pt}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]\mathrm{C}{\mathrm{l}_4}
Option A ([Pt(NH3)6]Cl4\left[ {\mathrm{Pt}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]\mathrm{C}{\mathrm{l}_4}) is correct because it dissociates into the largest number of ions in solution, leading to the highest molar conductivity.
179 Medium
179 of 326
Analyzing +4 | -1
Assertion: [Fe(CN)6]3−\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-} is more paramagnetic than [FeF6]3−\left[\mathrm{FeF}_6\right]^{3-}.

Reason: [FeF6]3−[\mathrm{FeF} 6]^{3-} has more number of unpaired electrons.
View answer and explanation
Correct option: D
Assertion is wrong, but reason is correct statement.
Option D is correct because the assertion is wrong, and the reason is correct. [FeF6]3- has more unpaired electrons than [Fe(CN)6]3-.
180 Medium
180 of 326
Analyzing +4 | -1
Which is high spin complex?
View answer and explanation
Correct option: D
All are correct
The correct answer is D (All are correct) because all the given complexes have weak field ligands, resulting in high spin complexes.
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