Ionization of ${\rm{K}}\left[ {{\rm{Ag}}{{\left( {{\rm{CN}}} \right)}_2}} \right]$ will give:

${{\rm{K}}^ + }$ and ${\left[ {{\rm{Ag}}{{\left( {{\rm{CN}}} \right)}_2}} \right]^ - }$ ion

${{\rm{K}}^ + },{\rm{\;A}}{{\rm{g}}^ + },{\rm{\;C}}{{\rm{N}}^ - }$

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JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS

Co-ordination compounds practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Easy

1 of 89

Understanding +4 | -1

Ionization of

\mathrm{K}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right]

will give:

View answer and explanation

Correct option: A

{\mathrm{K}^ + }

and

{\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right]^ - }

ion

Option A (

{\mathrm{K}^ + }

and

{\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right]^ - }

ion) is correct because the complex salt dissociates into its constituent ions in solution.

2 Easy

2 of 89

Understanding +4 | -1

The cation that does not form an ammine complex with excess of ammonia is:

View answer and explanation

Correct option: A

\mathrm{A}{\mathrm{l}^{3 + }}

Option A (

\mathrm{A}{\mathrm{l}^{3 + }}

) is correct because

Al^{3+}

does not form stable ammine complexes in aqueous solution due to its high charge density and strong polarizing power, which favors hydrolysis over ammine complex formation.

3 Easy

3 of 89

Application +4 | -1

EAN of Fe in

{\left[ {Fe{{\left( {{C_2}{O_4}} \right)}_3}} \right]^{3 - }}

View answer and explanation

Correct option: C

Option C (35) is correct because the Effective Atomic Number (EAN) is calculated using the atomic number, oxidation number, and coordination number of the metal.

4 Easy

4 of 89

Application +4 | -1

A complex of platinum, ammonia and chlorine produces four ions per molecule in the solution. The structure consistent with the observation is:

View answer and explanation

Correct option: C

\left[ {\mathrm{Pt}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{Cl}} \right]\mathrm{C}{\mathrm{l}_3}

Option C (

\left[ {\mathrm{Pt}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{Cl}} \right]\mathrm{C}{\mathrm{l}_3}

) is correct because it produces four ions upon ionization, with three chloride ions outside the coordination sphere.

5 Easy

5 of 89

Understanding +4 | -1

Which is not a

\pi -

bonded complex?

View answer and explanation

Correct option: D

Tetraethyl lead

Option D (Tetraethyl lead) is correct because it is an organometallic compound that does not involve

\pi

-bonding.

6 Easy

6 of 89

Understanding +4 | -1

\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{Br}} \right]\mathrm{S}{\mathrm{O}_4}\mathrm{\;}

and

\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{S}{\mathrm{O}_4}} \right]

\mathrm{Br}

are examples of which type of isomerism?

View answer and explanation

Correct option: D

Ionisation

Option D (Ionisation) is correct because the isomers differ in the counter-ion that is directly bonded to the metal center.

7 Easy

7 of 89

Understanding +4 | -1

Change in composition of coordination sphere yields which type of isomer?

View answer and explanation

Correct option: B

Ionization

Option B is correct because ionization isomers arise when the composition of the coordination sphere changes, resulting in different ions being present in the solution.

8 Easy

8 of 89

Remembering +4 | -1

The coordination number of a metal in coordination compound is

View answer and explanation

Correct option: C

Same as secondary valency

Option C (Same as secondary valency) is correct because the coordination number is defined as the number of ligands directly attached to the central metal ion, which corresponds to the secondary valency.

9 Easy

9 of 89

Remembering +4 | -1

Which is the strongest field ligand?

View answer and explanation

Correct option: A

\mathrm{C}{\mathrm{N}^ - }

Option A (

\mathrm{C}{\mathrm{N}^ - }

) is correct because cyanide (

CN^−

) is a strong field ligand, causing a large splitting of d-orbitals.

10 Easy

10 of 89

Analyzing +4 | -1

Assertion : On cooling a freezing mixture, colour of the mixture turns to pink from deep blue for a reaction.

{Co}\left({H}_2 {O}\right)_6^{2+}{ }_{(a q)}+4 {Cl}_{(a q)}^{-} \rightleftharpoons

{CoCl}_4^{2-}(a q)+6 {H}_2 {O}_{(l)}

.

Reason : Reaction is endothermic so on cooling, the reaction moves to backward direction.

View answer and explanation

Correct option: A

If both assertion and reason are true and the reason is the correct explanation of the assertion.

Option A is correct because both the assertion and reason are true, and the reason correctly explains why cooling shifts the equilibrium towards the pink complex due to Le Chatelier's principle.

11 Easy

11 of 89

Remembering +4 | -1

Which of the following represents a chelating ligand?

View answer and explanation

Correct option: D

DMG

Option D (DMG) is correct because DMG (dimethylglyoxime) is a bidentate ligand that can form a chelate complex.

12 Easy

12 of 89

Understanding +4 | -1

The number of isomeric forms in which

{\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}\mathrm{C}{\mathrm{l}_2}} \right]^ + }

ion can occur is:

View answer and explanation

Correct option: A

Option A (2) is correct because the complex can exhibit geometrical isomerism (cis-trans) and ionization isomerism.

13 Easy

13 of 89

Remembering +4 | -1

The number of unidentate ligands in the complex ion is called

View answer and explanation

Correct option: C

Coordination number

Option C (Coordination number) is correct because the coordination number of a complex ion is the number of ligands directly bonded to the central metal ion.

14 Easy

14 of 89

Understanding +4 | -1

Which of the following complex will show largest splitting of d-orbitals?

View answer and explanation

Correct option: C

\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}

Option C (

[Fe(CN)_6]^{3-}

) is correct because cyanide (CN-) is a strong field ligand, leading to a larger splitting of d-orbitals compared to the other ligands.

15 Easy

15 of 89

Remembering +4 | -1

All ligands are:

View answer and explanation

Correct option: B

Lewis base

Option B (Lewis base) is correct because ligands donate electron pairs to the central metal atom/ion, which is the definition of a Lewis base.

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16 Easy

16 of 89

Application +4 | -1

Which of the following has least oxidation state of

\mathrm{Fe}

View answer and explanation

Correct option: C

\mathrm{FeS}{\mathrm{O}_4}{\left( {\mathrm{N}{\mathrm{H}_4}} \right)_2}\mathrm{S}{\mathrm{O}_4}\mathrm{\;}.6{\mathrm{H}_2}\mathrm{O}

Option C (

\mathrm{FeS}{\mathrm{O}_4}{\left( {\mathrm{N}{\mathrm{H}_4}} \right)_2}\mathrm{S}{\mathrm{O}_4}\mathrm{\;}.6{\mathrm{H}_2}\mathrm{O}

) is correct because the oxidation state of Fe in this compound is +2, which is the lowest among the given options.

17 Easy

17 of 89

Remembering +4 | -1

Carnallite in solution in water shows the properties of

View answer and explanation

Correct option: A

{\mathrm{K}^ + },\mathrm{M}{\mathrm{g}^{2 + }},\mathrm{C}{\mathrm{l}^ - }

Option A (

{\mathrm{K}^ + },\mathrm{M}{\mathrm{g}^{2 + }},\mathrm{C}{\mathrm{l}^ - }

) is correct because carnallite (KCl.MgCl2.6H2O) dissociates into these ions in water.

18 Easy

18 of 89

Analyzing +4 | -1

The possible number of isomers for the complex

\left[ {\mathrm{MC}{\mathrm{l}_2}\mathrm{B}{\mathrm{r}_2}} \right]\mathrm{S}{\mathrm{O}_4}

is:

View answer and explanation

Correct option: D

The correct answer is D (5) because the complex [MCl2Br2]SO4 can have five isomers: three geometrical isomers (cis, trans, and another trans) and two ionization isomers.

19 Easy

19 of 89

Remembering +4 | -1

\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]\mathrm{C}{\mathrm{l}_3}

is called:

View answer and explanation

Correct option: A

Hexaammine cobalt (III) chloride

Option A (Hexaammine cobalt (III) chloride) is correct because it follows the IUPAC nomenclature rules for coordination complexes.

20 Easy

20 of 89

Understanding +4 | -1

Geometrical isomerism is found in coordination compounds having coordination number:

View answer and explanation

Correct option: D

Option D (6) is correct because geometrical isomerism is commonly found in coordination compounds with coordination number 4 (square planar) and 6 (octahedral).

21 Easy

21 of 89

Understanding +4 | -1

The number of geometrical isomers of

\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_3}{{\left( {\mathrm{N}{\mathrm{O}_2}} \right)}_3}} \right]

are:

View answer and explanation

Correct option: B

Option B (2) is correct because the complex can exist as cis and trans isomers.

22 Easy

22 of 89

Application +4 | -1

The oxidation number of platinum in

\left[ {\mathrm{Pt}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{Cl}} \right]\mathrm{C}{\mathrm{l}_3}

View answer and explanation

Correct option: C

Option C (4) is correct because the oxidation number of Pt is calculated by considering the charges of the ligands and the overall charge of the complex.

23 Easy

23 of 89

Remembering +4 | -1

Lithium tetrahydridoaluminate is correctly represented as:

View answer and explanation

Correct option: C

\mathrm{Li}\left[ {\mathrm{Al}{\mathrm{H}_4}} \right]

Option C is correct because Lithium tetrahydridoaluminate, commonly known as Lithium aluminum hydride, is correctly represented as Li[AlH₄].

24 Easy

24 of 89

Remembering +4 | -1

In haemoglobin the iron shows oxidation state:

View answer and explanation

Correct option: A

Option A (2) is correct because the iron in hemoglobin is in the +2 oxidation state, allowing it to bind reversibly with oxygen.

25 Easy

25 of 89

Understanding +4 | -1

The ligand

{N}\left({CH}_2 {CH}_2 {NH}_2\right)_3

View answer and explanation

Correct option: C

Tetradentate

Option C (Tetradentate) is correct because the ligand has one nitrogen atom and three amine groups, each capable of donating a lone pair, resulting in four donor atoms.

26 Easy

26 of 89

Remembering +4 | -1

cis

-\left[\mathrm{PtC}{l}_2\left(\mathrm{NH}_3\right)_2\right]

is used

View answer and explanation

Correct option: C

As anticancer agent

Option C (As anticancer agent) is correct because cis-[PtCl2(NH3)2] (Cisplatin) is a well-known anticancer drug.

27 Easy

27 of 89

Understanding +4 | -1

The set which does not have ambidentate ligand(s) is

View answer and explanation

Correct option: A

\mathrm{C}_2 \mathrm{O}_4^{2-}

, ethylene diammine,

\mathrm{H}_2 \mathrm{O}

Option A is correct because none of the ligands in the set (

\mathrm{C}_2 \mathrm{O}_4^{2-}

, ethylene diammine,

\mathrm{H}_2 \mathrm{O}

) are ambidentate ligands.

28 Easy

28 of 89

Application +4 | -1

The EAN of

\mathrm{Fe}

{\mathrm{K}_3}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right]

is:

View answer and explanation

Correct option: D

The correct answer is 35 because the Effective Atomic Number (EAN) is calculated by subtracting the oxidation state of the central metal atom from its atomic number and adding twice the number of ligands.

29 Easy

29 of 89

Application +4 | -1

Iron has lowest oxidation state in:

View answer and explanation

Correct option: A

\mathrm{Fe}{\left( {\mathrm{CO}} \right)_5}

Option A (Fe(CO)5) is correct because the oxidation state of Fe in this compound is 0, which is the lowest among the given options.

30 Easy

30 of 89

Understanding +4 | -1

Assertion : Isomorphous substances form crystals of same shape and can grow in saturated solution of each other.

Reason : They have similar constitution and chemical formulae.

View answer and explanation

Correct option: A

If both assertion and reason are true and the reason is the correct explanation of the assertion.

Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because isomorphous substances have similar constitution and chemical formulae, leading to similar crystal shapes and the ability to grow in each other's saturated solutions.

Revision notes and key takeaways

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Key Takeaways

✓ This set contains 89 single-correct-answer MCQs on CO-ORDINATION COMPOUNDS.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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