In the complexes ${\left[ {{\rm{Fe}}{{\left( {{{\rm{H}}_2}{\rm{O}}} \right)}_6}} \right]^{3 + }},{\rm{\;}}{\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_6}} \right]^{3 - }},{\rm{\;}}{\left[ {{\rm{Fe}}{{\left( {{{\rm{C}}_2}{{\rm{O}}_4}} \right)}_3}} \right]^{3 - }}{\rm{\;and}}\,{\rm{\;}}{\left[ {{\rm{FeC}}{{\rm{l}}_6}} \right]^{3 - }},$ more stability is shown by:

${\left[ {{\rm{Fe}}{{\left( {{{\rm{C}}_2}{{\rm{O}}_4}} \right)}_3}} \right]^{3 - }}$

${\left[ {{\rm{Fe}}{{\left( {{{\rm{H}}_2}{\rm{O}}} \right)}_6}} \right]^{3 + }}$

${\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_6}} \right]^{3 - }}$

${\left[ {{\rm{FeC}}{{\rm{l}}_6}} \right]^{3 - }}$

$\left[\mathrm{MnCl}_6\right]^{3-}$ - Paramagnetic

$\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ - Diamagnetic

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JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS

Co-ordination compounds practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 200 questions

1 Medium

1 of 200

Analyzing +4 | -1

Which has maximum paramagnetic character?

View answer and explanation

Correct option: D

{\left[ {\mathrm{Mn}{{\left( {{\mathrm{H}_2}\mathrm{O}} \right)}_6}} \right]^{2 + }}

Option D (

{\left[ {\mathrm{Mn}{{\left( {{\mathrm{H}_2}\mathrm{O}} \right)}_6}} \right]^{2 + }}

) is correct because it has the maximum number of unpaired electrons (5).

2 Medium

2 of 200

Understanding +4 | -1

The complexes

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

are example for isomerism

View answer and explanation

Correct option: C

Ionization

Option C (Ionization) is correct because the complexes differ in the counter ions (Br⁻ and Cl⁻) that can exchange with ligands inside the coordination sphere.

3 Medium

3 of 200

Understanding +4 | -1

The correct name of

\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\left[\mathrm{PtCl}_4\right]

is:

View answer and explanation

Correct option: A

Tetraammine dichloro platinum (IV) tetrachloro platinate (II)

Option A (Tetraammine dichloro platinum (IV) tetrachloro platinate (II)) is correct because it follows the IUPAC naming conventions for coordination compounds, where the cation is named before the anion, ligands are named alphabetically, and oxidation states are indicated in Roman numerals.

4 Medium

4 of 200

Understanding +4 | -1

Which of the following pairs of isomers and types of isomerism are correctly matched?

(I)

\left[{Co}\left({NH}_3\right)_5\left({NO}_2\right)\right] {Cl}_2

and

\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots

Linkage

(II)

\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots

Coordinations

(III)

\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots

Ionization

Select the correct answer using the codes given below:

View answer and explanation

Correct option: D

I, II, III

Option D (I, II, III) is correct because all three pairs correctly identify the type of isomerism present: linkage, coordination, and ionization, respectively.

5 Medium

5 of 200

Application +4 | -1

Which of the following is a pair of diamagnetic complex?

View answer and explanation

Correct option: A

\left[{Co}({ox})_3\right]^{3-},\left[{Fe}({CN})_6\right]^{3-}

Option A (

\left[{Co}({ox})_3\right]^{3-},\left[{Fe}({CN})_6\right]^{3-}

) is correct because both complexes are diamagnetic, meaning they have no unpaired electrons.

6 Medium

6 of 200

Application +4 | -1

The IUPAC name of the complex

[Ag{({H_2}O)_2}][Ag{(CN)_2}]

View answer and explanation

Correct option: A

diaquasilver(I) dicyanidoargentate(I)

The correct answer is A (diaquasilver(I) dicyanidoargentate(I)) because it correctly names the complex with the correct oxidation state and ligands.

7 Medium

7 of 200

Analyzing +4 | -1

Assertion (A) :

{CoCl}_3 \cdot 4{NH}_3

gives two ions when ionised.

Reason (R) : Complex is

\left[{Co}\left({NH}_3\right)_4\right] {Cl}_3

View answer and explanation

Correct option: C

\mathbf{A}

is true but

\mathbf{R}

is false.

Option C (

\mathbf{A}

is true but

\mathbf{R}

is false.) is correct because the complex gives three ions, not two, and the formula is incorrect.

8 Medium

8 of 200

Analyzing +4 | -1

S-I:

\left[{Ni}({CN})_4\right]^{2-}

is a diamagnetic complex.

S-II: Compound is low spin complex.

View answer and explanation

Correct option: A

Statement-I and Statement-II are true

Option A (Statement-I and Statement-II are true) is correct because

\left[{Ni}({CN})_4\right]^{2-}

is indeed a diamagnetic complex due to the strong field ligand

CN^-

, which causes pairing of electrons, making it a low spin complex.

9 Medium

9 of 200

Analyzing +4 | -1

Which of the following complexes will show geometrical as well as optical isomerism? (en

=

ethylene diamine)

View answer and explanation

Correct option: D

\left[ {\mathrm{Pt}{{\left( {\mathrm{en}} \right)}_2}\mathrm{C}{\mathrm{l}_2}} \right]

Option D (

\left[ {\mathrm{Pt}{{\left( {\mathrm{en}} \right)}_2}\mathrm{C}{\mathrm{l}_2}} \right]

) is correct because it can exhibit both geometrical (cis/trans) and optical isomerism (for the cis isomer).

10 Medium

10 of 200

Remembering +4 | -1

{K}_3\left[{Al}\left({C}_2 {O}_4\right)_3\right]

is called

View answer and explanation

Correct option: B

Potassium trioxalatoaluminate(III)

Option B (Potassium trioxalatoaluminate(III)) is correct because it follows the IUPAC naming conventions for coordination compounds.

11 Medium

11 of 200

Understanding +4 | -1

The number of ions formed when a molecule of

{\mathrm{K}_4}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}

dissociates is:

View answer and explanation

Correct option: B

Option B (5) is correct because the complex dissociates into 4 potassium ions and one complex ion, resulting in a total of 5 ions.

12 Medium

12 of 200

Understanding +4 | -1

Ammonia forms the complex ion

{\left[ {\mathrm{Cu}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]^{2 + }}

with copper ions in alkaline solution but not in acidic solution. What is the reason for it?

View answer and explanation

Correct option: D

In acidic solutions, protons coordinate with ammonia molecules forming

\mathrm{NH}_4^ +

ions and

\mathrm{N}{\mathrm{H}_3}

molecules are not available

Option D is correct. In acidic solutions, ammonia molecules are protonated to form ammonium ions (

\mathrm{NH}_4^ +

), which cannot act as ligands.

13 Medium

13 of 200

Analyzing +4 | -1

Statement I: Cadmium sulphide is yellow coloured

Statement II: The d-d transition does not take place in this compound

View answer and explanation

Correct option: B

Statement I and statement II are correct but statement II is not the correct explanation of statement I

Option B is correct because both statements are correct, but the absence of d-d transition is not the reason for the yellow color of cadmium sulfide.

14 Medium

14 of 200

Understanding +4 | -1

Which of the following compounds does not dissolve in conc.

{\mathrm{H}_\mathrm{2}}\mathrm{S}{\mathrm{O}_\mathrm{4}}

even on warning?

View answer and explanation

Correct option: C

Hexane

Option C (Hexane) is correct because alkanes like hexane are generally unreactive and do not dissolve in concentrated sulfuric acid, even upon warming.

15 Medium

15 of 200

Analyzing +4 | -1

In the complexes

{\left[ {\mathrm{Fe}{{\left( {{\mathrm{H}_2}\mathrm{O}} \right)}_6}} \right]^{3 + }},\mathrm{\;}{\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right]^{3 - }},\mathrm{\;}{\left[ {\mathrm{Fe}{{\left( {{\mathrm{C}_2}{\mathrm{O}_4}} \right)}_3}} \right]^{3 - }}\mathrm{\;and}\,\mathrm{\;}{\left[ {\mathrm{FeC}{\mathrm{l}_6}} \right]^{3 - }},

more stability is shown by:

View answer and explanation

Correct option: C

{\left[ {\mathrm{Fe}{{\left( {{\mathrm{C}_2}{\mathrm{O}_4}} \right)}_3}} \right]^{3 - }}

Option C (

{\left[ {\mathrm{Fe}{{\left( {{\mathrm{C}_2}{\mathrm{O}_4}} \right)}_3}} \right]^{3 - }}

) is correct because

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

is a bidentate ligand, leading to a more stable complex due to chelation.

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16 Medium

16 of 200

Understanding +4 | -1

Assertion: Carbon monoxide is a deadly poison.

Reason:

CO

can form strong complexes with haemoglobin.

View answer and explanation

Correct option: A

Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.

Option A (Both assertion and reason are correct statements, and reason is the correct explanation of the assertion) is correct because carbon monoxide is a deadly poison because it binds strongly to hemoglobin, preventing oxygen transport.

17 Medium

17 of 200

Understanding +4 | -1

Which one of the following will not show geometrical isomerism?

View answer and explanation

Correct option: C

\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{N}{\mathrm{O}_2}} \right]\mathrm{C}{\mathrm{l}_2}

Option C (

\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}\mathrm{N}{\mathrm{O}_2}} \right]\mathrm{C}{\mathrm{l}_2}

) is correct because complexes of the type

MA_5B

(where all ligands except one are the same) do not exhibit geometrical isomerism.

18 Medium

18 of 200

Analyzing +4 | -1

Wrong match is

View answer and explanation

Correct option: A

\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}

- Diamagnetic

Option A (8) is correct because there are 4 geometrical isomers for the first complex and 4 stereoisomers for the second complex, summing to 8.

19 Medium

19 of 200

Analyzing +4 | -1

Which of the following complex species is not expected to exhibit optical isomerism?

View answer and explanation

Correct option: C

[Co{(NH)_3}C{l_3}]

The correct answer is C (

[Co{(NH)_3}C{l_3}]

) because it exhibits facial and meridional isomerism, both of which contain a plane of symmetry, thus preventing optical isomerism.

20 Medium

20 of 200

Application +4 | -1

Total number of electron count in

{Ni}({CO})_4

and

{Fe}({CO})_5

respectively are.

View answer and explanation

Correct option: A

36,36

Option A (36,36) is correct because both

{Ni}({CO})_4

and

{Fe}({CO})_5

have a total electron count of 36 based on the 18-electron rule.

21 Medium

21 of 200

Application +4 | -1

Consider the following complexes:
(I)

{K}_2 {PtCl}_6

(II)

{PtCl}_4 .2 {NH}_3

(III)

{PtCl}_4 .3 {NH}_3

(IV)

{PtCl}_4 .5 {NH}_3

Their electrical conductances in aq. solutions are-

View answer and explanation

Correct option: A

256,0,97,404

Option A (

256,0,97,404

) is correct because the electrical conductance is directly proportional to the number of ions produced in the solution.

22 Medium

22 of 200

Application +4 | -1

The coordination number, oxidation state and the number of

d

electrons of the metal in the complex

\left[{Co}\left({NH}_3\right)_5\left({CO}_3\right)\right] {Cl}

are respectively

View answer and explanation

Correct option: A

6,3,6

Option A (6, 3, 6) is correct because the coordination number is 6, the oxidation state of Co is +3, and the number of d electrons in

Co^{3+}

is 6.

23 Medium

23 of 200

Analyzing +4 | -1

The complex ion which has the highest magnetic moment among the following is

View answer and explanation

Correct option: A

{\left[ {\mathrm{Co}{\mathrm{F}_6}} \right]^{3 - }}

Option A (

{\left[ {\mathrm{Co}{\mathrm{F}_6}} \right]^{3 - }}

) is correct because it has the highest number of unpaired electrons (4) among the given complexes, leading to the highest magnetic moment.

24 Medium

24 of 200

Analyzing +4 | -1

Assertion : Penta ammiliethiocyanato-N-chromium(III) tetrachloridozincate(II) is a coloured compound and is an example of ionization isomerism.

Reason : The compound is paramagnetic and therefore, d-d transition is possible

View answer and explanation

Correct option: D

If both Assertion & Reason are false

Option D is correct because both the assertion and the reason are false. The given complex is not an example of ionization isomerism and may or may not be colored depending on the specific ligands and metal ion, and the reason is not necessarily true as the compound's color depends on d-d transitions.

25 Medium

25 of 200

Analyzing +4 | -1

Both geometrical and optical isomerisms are shown by

View answer and explanation

Correct option: A

{\left[ {CO{{\left( {en} \right)}_2}C{l_2}} \right]^ + }

Option A (

{\left[ {CO{{\left( {en} \right)}_2}C{l_2}} \right]^ + }

) is correct because this complex can exhibit both geometrical (cis-trans) and optical isomerism due to the arrangement of ligands around the central metal ion.

26 Medium

26 of 200

Analyzing +4 | -1

Which one of the following has highest number of isomers?

View answer and explanation

Correct option: B

{\left[ {\mathrm{Co}{{\left( {\mathrm{en}} \right)}_2}\mathrm{C}{\mathrm{l}_2}} \right]^ + }

The correct answer is B (

{\left[ {\mathrm{Co}{{\left( {\mathrm{en}} \right)}_2}\mathrm{C}{\mathrm{l}_2}} \right]^ + }

) because it exhibits both geometrical and optical isomerism, leading to a higher number of isomers.

27 Medium

27 of 200

Analyzing +4 | -1

Which of the following is correct?

View answer and explanation

Correct option: B

\left[\mathrm{Ni}(\mathrm{CO})_4\right]

- diamagnetic,

\left[\mathrm{NiCl}_4\right]^{2-}

- paramagnetic

Option D (Both (A) and (R) are false) is correct because NaBH4 cannot reduce esters, and ethyl acetoacetate would not form butane-1,4-diol with NaBH4.

28 Medium

28 of 200

Application +4 | -1

Atomic number of

{Cr}

and

{Fe}

are respectively 25 and 26, which of the following is paramagnetic?

View answer and explanation

Correct option: D

\left[{Cr}\left({NH}_3\right)_6\right]^{+3}

Option D (

{Cr}\left({NH}_3\right)_6^{+3}

) is correct because the

Cr^{3+}

ion has unpaired electrons, making the complex paramagnetic.

29 Medium

29 of 200

Analyzing +4 | -1

Assertion : The 'spin only' magnetic moment of a green complex, potassium amminetetracyani donitrosonium chromate(I) is 1.73 BM.

Reason : To have two d-orbitals empty for

{{\text{d}}^{\text{2}}}{\text{s}}{{\text{p}}^{\text{3}}}

hybridisation, the pairing of electrons take place leaving behind one unpaired electron as

{\text{C}}{{\text{N}}^ - }

is a stronger ligand.

View answer and explanation

Correct option: A

If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.

Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the complex has one unpaired electron, resulting in a magnetic moment of 1.73 BM, and the pairing of electrons occurs due to the strong field ligand.

30 Medium

30 of 200

Analyzing +4 | -1

Of the following complexes, the one with the largest value of the crystal field splitting is:

View answer and explanation

Correct option: B

{\left[ {\mathrm{Ru}{{\left( {\mathrm{CN}} \right)}_6}} \right]^{3 - }}

The correct answer is B (

{\left[ {\mathrm{Ru}{{\left( {\mathrm{CN}} \right)}_6}} \right]^{3 - }}

) because

\mathrm{C}{\mathrm{N}^ - }

is a strong field ligand, leading to a larger crystal field splitting.

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