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JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS
Co-ordination compounds practice · Medium
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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 31-60 of 200 questions
31
Medium
31 of 200
Application
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In all the following complexes, the coordination number of iron is six. In which of them is the oxidation state of iron the lowest?
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Correct option: B
Option B () is correct because the oxidation state of iron in this complex is 0, which is the lowest among the given options.
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Analyzing
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Which of the following complex is optically inactive?
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Correct option: A
Option A is correct because is optically inactive due to the presence of a plane of symmetry.
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Remembering
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The donar sites of are:
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Correct option: C
Two atoms and four atoms
Option C (Two N atoms and four O atoms) is correct because EDTA has two nitrogen and four oxygen atoms that can donate electron pairs to form coordinate bonds.
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Understanding
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Which of the following complex is expected to be the most stable?
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Correct option: A
Option A () is the correct answer due to the chelation effect, which enhances the stability of the complex.
35
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Remembering
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The shape of Wilkinson’s catalyst is
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Correct option: B
Square planar
Option B (Square planar) is correct because Wilkinson's catalyst, , has a square planar geometry.
36
Medium
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Understanding
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In , the isomerism shown is:
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Correct option: B
Optical
Option B is correct because the complex is a tris-chelate complex of the type which exhibits optical isomerism.
37
Medium
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Analyzing
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Given below are two statements:
Statement I: is square planar and diamagnetic complex, with hybridization for but is tetrahedral, paramagnetic and with -hybridization for .
Statement II: and both have same -electron configuration, have same geometry and are paramagnetic.
In light of the above statements, choose the correct answer from the options given below:
Statement I: is square planar and diamagnetic complex, with hybridization for but is tetrahedral, paramagnetic and with -hybridization for .
Statement II: and both have same -electron configuration, have same geometry and are paramagnetic.
In light of the above statements, choose the correct answer from the options given below:
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Correct option: B
Both Statement I and Statement II are false
Option B is correct. Statement I is false because Ni(CO)4 is diamagnetic, and Statement II is false because [NiCl4]2- is tetrahedral and paramagnetic, while Ni(CO)4 is tetrahedral and diamagnetic.
38
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Assertion: is high spin complex.
Reason: is strong field ligand.
Reason: is strong field ligand.
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Correct option: B
Assertion is true but Reason is false
Option B (Assertion is true but Reason is false) is correct because [CoF6]3- is indeed a high spin complex, but F- is a weak field ligand, not a strong field ligand.
39
Medium
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Analyzing
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Given below are two statements.
Statement-I: In , bonds are present.
Statement-II: In , ligands coordinating with ion are -and -based ligands.
In the light of the above statements, choose the correct answer from the options given below:
Statement-I: In , bonds are present.
Statement-II: In , ligands coordinating with ion are -and -based ligands.
In the light of the above statements, choose the correct answer from the options given below:
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Correct option: C
Statement-I is correct but Statement-II is incorrect
Option C is correct because in , only oxygen atoms of water molecules coordinate with ion, not sulfur.
40
Medium
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Remembering
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cation gives a Prussian blue precipitate on addition of potassium ferrocyanide solution due to the formation of:
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Correct option: D
Option D () is correct because it represents the formula of Prussian blue, the precipitate formed when reacts with potassium ferrocyanide.
41
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Understanding
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In the complex
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Correct option: B
Both atoms are in the same oxidation state
Option B (Both atoms are in the same oxidation state) is correct because the complex should be and Fe is in +2 oxidation state.
42
Medium
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Remembering
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Dimethyl glyoxime forms a coloured complex with
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Correct option: B
Option B () is correct because dimethyl glyoxime (DMG) forms a characteristic red precipitate complex with nickel(II) ions.
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Understanding
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The complex cation which has two isomers is:
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Correct option: C
Option C () is correct because it can exhibit linkage isomerism due to the ambidentate ligand , which can coordinate through either the nitrogen or the oxygen atom.
44
Medium
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Analyzing
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Which complex compound is most stable?
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Correct option: A
Option A ([CoCl2(en)2]NO3) is correct because chelating ligands like ethylenediamine (en) form more stable complexes than monodentate ligands due to the chelate effect.
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Medium
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Application
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The magnetic moment of an octahedral (II) complex is 4.0 B.M (nearly) The electronic configuration of the complex is
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Correct option: A
Option A () is correct because the ratio of diffusion rates is inversely proportional to the square root of the ratio of their molar masses.
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46
Medium
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Understanding
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Type of isomerism which exists between and is :
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Correct option: A
Linkage isomerism
The correct answer is A (Linkage isomerism) because the SCN ligand can coordinate through either the sulfur or the nitrogen atom.
47
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Analyzing
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Which among the following is incorrect regarding colour in coordination compounds?
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Correct option: D
Gradual addition of ethylene diamine to does not affect its colour observed
Option D is correct because the gradual addition of ethylenediamine to *does* affect the observed color due to ligand exchange.
48
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Understanding
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The IUPAC name of is :
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Correct option: C
Tetracarbonylnickel(0)
Option C (Tetracarbonylnickel(0)) is correct because the carbonyl ligand is neutral, so the oxidation state of nickel is 0.
49
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Remembering
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The correct sequence of ligands in the order of decreasing field strength is:
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Correct option: A
Option A () is correct because it represents the correct decreasing order of ligand field strength according to the spectrochemical series.
50
Medium
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Application
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One mode of a complex compound gives three moles of ions on dissolution in water. One of the same complex reacts with two moles of solution to yield two moles of . The structure of the complex is
View answer and explanation
Correct option: D
Option D ([Co(NH3)5Cl]Cl2) is correct because it gives three ions in solution and two moles of AgCl precipitate with two moles of AgNO3, indicating two ionizable chloride ions.
51
Medium
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Application
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Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour?
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Correct option: C
Option C () is correct because it forms an outer orbital complex with unpaired electrons, exhibiting paramagnetic behavior.
52
Medium
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Application
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Atomic numbers of are respectively 24 and 26. Which of the following is paramagnetic with the spin of the electron?
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Correct option: D
The correct answer is D () because Cr³⁺ has a 3d³ configuration with 3 unpaired electrons, making it paramagnetic.
53
Medium
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Analyzing
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Which of the following does not have optical isomer?
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Correct option: C
The correct answer is C ([Co(NH3)3Cl3]) because complexes of the type MA3B3 do not exhibit optical isomerism.
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Understanding
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is detected by ring test. Ring formed has formula
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Correct option: C
Option C is correct because the brown ring formed in the nitrate test is due to the formation of the complex ion $.
55
Medium
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Application
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What is the magnetic moment of ?
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Correct option: A
5.92
Option A (5.92) is correct because the magnetic moment is calculated using the number of unpaired electrons in the complex ion, which is 5 for [FeF6]3-.
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In which of the following octahedral complexes of (at. No. 27), will be magnitude of be the highest?
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Correct option: A
Option A () is correct because cyanide (CN) is a strong field ligand, resulting in a larger crystal field splitting energy ().
57
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Application
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The hybridization involved in complex is: (Atomic number of )
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Correct option: C
Option C () is correct because the complex is square planar, requiring dsp² hybridization due to the strong field ligand.
58
Medium
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Application
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Which one of the following complexes is diamagnetic?
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Correct option: B
Option B () is correct because it is a square planar complex with strong field ligands, resulting in pairing of electrons and thus diamagnetism.
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Understanding
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Yellow compound of lead chromate gets dissolved on treatment with hot solution. The product of lead formed is a :
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Correct option: D
Dianionic complex with coordination number four
Option D (Dianionic complex with coordination number four) is correct because lead chromate () reacts with hot NaOH to form the tetrahydroxoplumbate(II) ion, which is a dianionic complex, , with a coordination number of four.
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The magnetic behavior of and , respectively, are
View answer and explanation
Correct option: B
Diamagnetic, diamagnetic and paramagnetic
The correct answer is B (Diamagnetic, diamagnetic and paramagnetic) because Li2O and Na2O2 are diamagnetic while KO2 is paramagnetic due to the presence of unpaired electrons in O2-.
Revision notes and key takeaways
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