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JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS

Co-ordination compounds practice · Medium

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61 Medium
61 of 200
Understanding +4 | -1
The number of water molecule(s) directly bonded to the metal centre in CuSO4  .5H2O  \mathrm{CuS}{\mathrm{O}_4}\mathrm{\;}.5{\mathrm{H}_2}\mathrm{O\;} is
View answer and explanation
Correct option: D
4
Option D (4) is correct because in CuSO4.5H2OCuSO_4.5H_2O, four water molecules are directly coordinated to the copper ion, forming the complex [Cu(H2O)4]2+[Cu(H_2O)_4]^{2+}.
62 Medium
62 of 200
Analyzing +4 | -1
A cobaltamine has the formula Co(NH3)6Cl3{Co}\left({NH}_3\right)_6 {Cl}_3, with AgNO3{AgNO}_3 solution, one third of the chloride is precipitated. The complex shows cis-trans isomerism. It can have the structure-
View answer and explanation
Correct option: C
[Co(NH3)4Cl2]Cl\left[{Co}\left({NH}_3\right)_4 {Cl}_2\right] {Cl}
Option C ([Co(NH3)4Cl2]Cl\left[{Co}({NH}_3)_4 {Cl}_2\right] {Cl}) is correct because it has one ionizable chloride ion, which precipitates with silver nitrate, and it exhibits cis-trans isomerism.
63 Medium
63 of 200
Understanding +4 | -1
The correct IUPAC name for [Cr(en)2F2]Cl\left[ {Cr{{\left( {en} \right)}_2}{F_2}} \right]Cl is
View answer and explanation
Correct option: B
Difluorido bis-(ethylene diamine) chromium (III) chloride
The correct answer is B (Difluorido bis-(ethylene diamine) chromium (III) chloride) because it follows the IUPAC naming conventions for coordination compounds.
64 Medium
64 of 200
Understanding +4 | -1
The solution of the complex [Cu(NH3)4]SO4\left[{Cu}\left({NH}_3\right)_4\right] {SO}_4 in water will
View answer and explanation
Correct option: C
Give the test for SO42−{SO}_4^{2-} ion
Option C (Give the test for SO42−{SO}_4^{2-} ion) is correct because the sulfate ion is a simple ion outside the coordination complex and will give its characteristic test.
65 Medium
65 of 200
Analyzing +4 | -1
Which of the following complex species is not expected to exhibit optical isomerism
View answer and explanation
Correct option: A
[CO(NH3)3Cl3]\left[ {CO{{(N{H_3})}_3}C{l_3}} \right]
Option A, [CO(NH3)3Cl3]\left[ {CO{{(N{H_3})}_3}C{l_3}} \right], is the correct answer because Ma3b3M{a_3}{b_3} complexes in octahedral geometry can exist as fac- and mer- isomers, but neither is chiral and thus does not exhibit optical isomerism.
66 Medium
66 of 200
Remembering +4 | -1
Coordination number (CN)(\mathrm{CN}) of a metal ion in a complex can be defined as
View answer and explanation
Correct option: C
number of ligand donor atoms to which the metal is directly bonded
Option C (number of ligand donor atoms to which the metal is directly bonded) is correct because the coordination number is defined as the number of ligands directly attached to the central metal ion through coordinate bonds.
67 Medium
67 of 200
Analyzing +4 | -1
Assertion (A) Complexes of MX6\mathrm{MX}_6 and MX3L\mathrm{MX}_3 \mathrm{L} type (X and L\mathrm{L} are unidentate) do not show geometrical isomerism.

Reason (R) Geometrical isomerism is not shown by complexes of coordinate number -6 .
View answer and explanation
Correct option: C
Assertion is true but Reason is false.
Option C is correct because complexes of MX6\mathrm{MX}_6 and MX3L\mathrm{MX}_3 \mathrm{L} type do not show geometrical isomerism, but the reason that geometrical isomerism is not shown by complexes of coordinate number -6 is false, as some complexes with coordination number 6 do exhibit geometrical isomerism.
68 Medium
68 of 200
Understanding +4 | -1
Which of the following is bidentate ligand?
View answer and explanation
Correct option: D
All
Option D (All) is correct because Diphos, Tetrameen, and tn are all bidentate ligands, meaning they can coordinate to a metal ion through two donor atoms.
69 Medium
69 of 200
Analyzing +4 | -1
Complex compound [Co(SCN)2(NH3)4]Cl\left[\mathrm{Co}(\mathrm{SCN})_2\left(\mathrm{NH}_3\right)_4\right] \mathrm{Cl} does not exhibit:
View answer and explanation
Correct option: D
Optical isomerism
Option D is correct because the complex [Co(SCN)2(NH3)4]Cl\left[\mathrm{Co}(\mathrm{SCN})_2\left(\mathrm{NH}_3\right)_4\right] \mathrm{Cl} does not exhibit optical isomerism due to the presence of a plane of symmetry.
70 Medium
70 of 200
Understanding +4 | -1
Assertion: The ligands nitro and nitrito are called ambidentate ligands.

Reason: These ligands give linkage isomers.
View answer and explanation
Correct option: A
Assertion is true, Reason is true and Reason is correct explanation for Assertion
The correct answer is A (Assertion is true, Reason is true and Reason is correct explanation for Assertion) because ambidentate ligands can bind through different atoms, leading to linkage isomers.
71 Medium
71 of 200
Analyzing +4 | -1
Among the following metal carbonyls, C−O\mathrm{C} - \mathrm{O} bond order is lowest in
View answer and explanation
Correct option: B
[Fe(CO)5]\left[ {\mathrm{Fe}{{\left( {\mathrm{CO}} \right)}_5}} \right]
Option B ([Fe(CO)5]) is correct because it has the highest number of electrons available for back-bonding, leading to the lowest C-O bond order.
72 Medium
72 of 200
Analyzing +4 | -1
Which of the following statements is not correct?
View answer and explanation
Correct option: D
The complexes [NiCl4]2−  and   [Ni(CN)4]2−{\left[ {\mathrm{NiC}{\mathrm{l}_4}} \right]^{2 - }}\mathrm{\;and}\,\mathrm{\;}{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^{2 - }} differ in primary valencies of nickel.
Option C (Both statements are correct) is incorrect. Both statements are incorrect because the heat of neutralization of HF(aq) with NaOH(aq) is *more* than 13.7 kcal due to the high hydration energy of F-, and some heat is *released* during the hydration of F-.
73 Medium
73 of 200
Understanding +4 | -1
The IUPAC name of K3[Ir⁡(C2O4)3]\mathrm{K}_3\left[\operatorname{Ir}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right] is
View answer and explanation
Correct option: B
potassium trioxalatoiridate (III)
Option D (potassium tris (oxalato) iridate (III)) is correct because it follows IUPAC nomenclature rules for coordination compounds, naming the cation first, then the ligand alphabetically with appropriate prefixes, and ending with the metal name with its oxidation state in Roman numerals and \"-ate\" suffix because the complex is an anion.
74 Medium
74 of 200
Understanding +4 | -1
Assertion: (Ph3P)3RhCl\left({Ph}_3 P\right)_3 {RhCl} is Wilkinson's catalyst.
Reason: (Ph3P)3RhCl\left({Ph}_3 {P}\right)_3 {RhCl} can show optical isomerism but does not show geometrical isomerism.
View answer and explanation
Correct option: C
Assertion is true, Reason is false
Option C (Assertion is true, Reason is false) is correct because Wilkinson's catalyst is indeed (Ph3P)3RhCl(Ph_3P)_3RhCl, but it does not show optical isomerism or geometrical isomerism.
75 Medium
75 of 200
Application +4 | -1
Spin only magnetic moment of which complex is highest?
View answer and explanation
Correct option: C
[FeF6]3−\left[\mathrm{FeF}_{{6}}\right]^{3-}
The correct answer is C ([FeF_{{6}}]3-) because it has the highest number of unpaired electrons, resulting in the highest spin-only magnetic moment.
76 Medium
76 of 200
Analyzing +4 | -1
Which of the following complex has highest C−O\mathrm{C}-\mathrm{O} bond energy?
View answer and explanation
Correct option: B
[Co(CO)6]3+\left[\mathrm{Co}(\mathrm{CO})_6\right]^{3+}
Option B is correct because a higher positive charge on the metal center reduces back-bonding, leading to a stronger C-O bond.
77 Medium
77 of 200
Understanding +4 | -1
Which of the following ligand is tridentate type?
View answer and explanation
Correct option: C
Diethylamine (dien)
Option C (Diethylamine (dien)) is correct because diethylamine (dien) acts as a tridentate ligand, coordinating through three nitrogen atoms.
78 Medium
78 of 200
Analyzing +4 | -1
Consider the following statements
I. Chain and position isomerism are not possible together between two isomers
II. Tautomerism is a chemical phenomenon which is catalysed by acid as well as base
III. Tautomers are always metamers
IV. Tautomers are always functional isomers
Select the correct answer by using the codes given below
View answer and explanation
Correct option: D
I, II and IV are correct
The correct answer is D (I, II and IV are correct) because chain and position isomerism cannot occur together, tautomerism is acid/base catalyzed, and tautomers are functional isomers.
79 Medium
79 of 200
Understanding +4 | -1
Coordination number of Co\mathrm{Co} in the complex [Co(en)3]3∗\left[\mathrm{Co}(\mathrm{en})_3\right]^{3 *} is
View answer and explanation
Correct option: C
66
Option C (6) is correct because ethylenediamine (en) is a bidentate ligand, and three en ligands coordinate to the cobalt ion, resulting in a coordination number of 6.
80 Medium
80 of 200
Analyzing +4 | -1
Which of the following complexes will have four different isomers?
View answer and explanation
Correct option: B
[Co(en)(NH3)2Cl2]Cl\left[ {Co(en){{(N{H_3})}_2}C{l_2}} \right]Cl
Option B ([Co(en)(NH3)2Cl2]Cl) is correct because this complex can exhibit both geometrical (cis/trans) and optical isomerism, resulting in a total of four isomers.
81 Medium
81 of 200
Understanding +4 | -1
Which of the following is not correctly matched?

Coordination polyhedronShape(A)[Co(NH3)6]3 + Octahedral(B)[Ni(CO)4]Square planar(C)[PtCl4]2 - Tetrahedral\begin{array}{cccccccccccccccccccc} {}&{{\text{Coordination}}\,{\text{polyhedron}}}&{{\text{Shape}}} \\ {{\text{(A)}}}&{{{{\text{[Co(N}}{{\text{H}}_{\text{3}}}{{\text{)}}_{\text{6}}}{\text{]}}}^{{\text{3 + }}}}}&{{\text{Octahedral}}} \\ {{\text{(B)}}}&{{\text{[Ni(CO}}{{\text{)}}_{\text{4}}}{\text{]}}}&{{\text{Square}}\,{\text{planar}}} \\ {{\text{(C)}}}&{{{{\text{[PtC}}{{\text{l}}_{\text{4}}}{\text{]}}}^{{\text{2 - }}}}}&{{\text{Tetrahedral}}} \end{array}
View answer and explanation
Correct option: B
B and C
Option B (B and C) is correct because [Ni(CO)4] is tetrahedral and [PtCl4]2- is square planar, so the shapes listed are incorrect.
82 Medium
82 of 200
Analyzing +4 | -1
Amongst the following statements.

I: The structure of [BrF4]+\left[\mathrm{BrF}_4\right]^{+} is regular tetrahedral

II: Bond order of O2\mathrm{O}_2 decreases by the removal of an electron

III: Br3−\mathrm{Br}_3^{-} and Br3+\mathrm{Br}_3^{+} are having same shape and same structure

IV Hybrid orbital of P in PCl5\mathrm{PCl}_5 is sp3dxy\mathrm{sp}^3 \mathrm{d}_{\mathrm{xy}}.

The incorrect statements is/ are
View answer and explanation
Correct option: D
I, II, III, IV
Option B (I, III, IV only) is correct because statements I, III, and IV are all incorrect regarding the structure and properties of the given chemical species.
83 Medium
83 of 200
Analyzing +4 | -1
Which of the following is false?
View answer and explanation
Correct option: B
[FeF6]3−{\left[ {Fe{F_6}} \right]^{3 - }} is an inner orbital complex
The correct answer is B ([FeF6]3−{\left[ {Fe{F_6}} \right]^{3 - }} is an inner orbital complex) because fluoride is a weak field ligand, and therefore [FeF6]3−{\left[ {Fe{F_6}} \right]^{3 - }} is an outer orbital complex, not an inner orbital complex.
84 Medium
84 of 200
Understanding +4 | -1
Assertion :- Organic compounds which do not contain chiral carbon atoms can be optically
active.

Reason :-Presence of chiral carbon is an essential condition for optical activity.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because optical activity can occur without chiral carbon atoms, and the presence of a chiral carbon is not an essential condition.
85 Medium
85 of 200
Analyzing +4 | -1
The [Fe(CN)6]3−\left[{Fe}({CN})_6\right]^{3-} complex ion
View answer and explanation
Correct option: C
Should be very stable
Option C (Should be very stable) is correct because the high charge density of Fe3+Fe^{3+} and the strong basic character of CN−CN^- contribute to the stability of the complex.
86 Medium
86 of 200
Analyzing +4 | -1
Wrong match is
View answer and explanation
Correct option: D
NH4ClN{H_4}Cl - Both cationic and anionic hydrolysis
Option D (NH4ClN{H_4}Cl - Both cationic and anionic hydrolysis) is the wrong match because NH4ClNH_4Cl only undergoes cationic hydrolysis.
87 Medium
87 of 200
Analyzing +4 | -1
The crystal field stabilization energy (CFSE) is highest for
View answer and explanation
Correct option: C
[Co(NH3)6]3+\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}
Option C ([Co(NH3)6]3+[Co(NH_3)_6]^{3+}) is correct because NH3NH_3 is a strong field ligand, leading to a higher crystal field stabilization energy (CFSE).
88 Medium
88 of 200
Analyzing +4 | -1
Statement I: Under the influence of a strong field ligand, d7d^7-system will have only one unpaired electron either in coordination number six or four

Statement II: t2 g6eg1\mathrm{t}_{2 \mathrm{~g}}{ }^6 \mathrm{e}_{\mathrm{g}}{ }^1 is the electronic configuration for both cases
View answer and explanation
Correct option: C
Statement I is correct but statement II is false
Statement I is correct, but Statement II is false because the electronic configuration for a strong field d7d^7 system is t2g6eg1t_{2g}^6e_g^1 in an octahedral field and e4t23e^4t_2^3 in a tetrahedral field.
89 Medium
89 of 200
Analyzing +4 | -1
The most stable ion is
View answer and explanation
Correct option: C
[Fe(CN)6]3−{\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right]^{3 - }}
Option C is correct because CN⁻ is a strong field ligand and forms a stable complex with Fe³⁺.
90 Medium
90 of 200
Analyzing +4 | -1
According to valence bond theory which of the following statement is correct about the complexes Ni(CO)4{Ni}({CO})_4 and [Ni(CN)4]2−\left[{Ni}({CN})_4\right]^{2-} if both are diamagnetic in nature
View answer and explanation
Correct option: D
One is tetrahedral and other is square planar
The correct answer is D because Ni(CO)4{Ni}({CO})_4 is tetrahedral due to sp3sp^3 hybridization, while [Ni(CN)4]2−\left[{Ni}({CN})_4\right]^{2-} is square planar due to dsp2dsp^2 hybridization.
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