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JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS

Co-ordination compounds practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 326 questions

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211 Medium
211 of 326
Understanding +4 | -1
Assertion: AgCl{AgCl} dissolves in NH4OH{NH}_4 {OH} solution.

Reason: Due toformation of a complex.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
Option A (If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion) is correct because AgCl dissolves in NH4OH due to the formation of a complex ion, [Ag(NH3)2]+.
212 Easy
212 of 326
Understanding +4 | -1
[Sc(H2O)6]3+\left[{Sc}\left({H}_2 {O}\right)_6\right]^{3+} ion is :
View answer and explanation
Correct option: A
Colourless and diamagnetic
Option A (Colourless and diamagnetic) is correct because Sc3+ has a d0 electronic configuration, meaning it has no unpaired electrons and therefore does not absorb visible light and is diamagnetic.
213 Easy
213 of 326
Application +4 | -1
The complex that violates the EAN:
View answer and explanation
Correct option: B
Potassium ferricyanide
Option B (Potassium ferricyanide) is correct because the EAN of Fe in K3[Fe(CN)6] is 35, which does not satisfy the EAN rule (next inert gas configuration).
214 Easy
214 of 326
Understanding +4 | -1
The element which does not form mononuclear carbonyl is:
View answer and explanation
Correct option: B
Mn\mathrm{Mn}
Option D (W\mathrm{W}) is correct because manganese typically forms polynuclear carbonyls, not mononuclear carbonyls.
215 Easy
215 of 326
Understanding +4 | -1
Which of the following give good synergic bond with metal?
View answer and explanation
Correct option: A
CO{CO}
Option A (CO{CO}) is correct because CO{CO} can accept d-electrons from the metal in its antibonding orbitals, leading to synergic bonding.
216 Medium
216 of 326
Analyzing +4 | -1
Assertion: Cis - [Fe(en)2Cl2]+\left[{Fe}({en})_2{Cl}_2\right]^{+} can form recemic mixture.

Reason: Cis - [Fe(en)2Cl2]+\left[{Fe}({en})_2 {Cl}_2\right]^{+} is optically active square planar complex.
View answer and explanation
Correct option: C
Assertion is true, Reason is false
Option C (Assertion is true, Reason is false) is correct because the assertion about the racemic mixture is true, but the reason stating it's an optically active square planar complex is false.
217 Easy
217 of 326
Understanding +4 | -1
Some salts although containing two different metallic elements give test for only one of them in solution. Such salts are:
View answer and explanation
Correct option: A
Complex salts
Option A (Complex salts) is correct because complex salts contain complex ions that do not dissociate completely in solution, thus giving tests for only one of the metallic elements.
218 Medium
218 of 326
Analyzing +4 | -1
Correct for Ni(CO)4{Ni}({CO})_4 and [Ni(CN)4]2−\left[{Ni}({CN})_4\right]^{2-} respectively
View answer and explanation
Correct option: C
Both are diamagnetic
Option C (Both are diamagnetic) is correct because both Ni(CO)4 and [Ni(CN)4]2- have strong field ligands that cause pairing of electrons, resulting in no unpaired electrons and thus diamagnetism.
219 Hard
219 of 326
Understanding +4 | -1
[Fe(CN)6]4−\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} and [Fe(H2O)6]2+\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} are of different colours in dilute solutions. This is because of
View answer and explanation
Correct option: A
difference in the nature of ligands
Option A (difference in the nature of ligands) is correct because different ligands cause different crystal field splitting, leading to different absorption of light and thus different colors.
220 Medium
220 of 326
Analyzing +4 | -1
Statement I: PF3\mathrm{PF}_3 is weakest donor as well as weakest acceptor compared to PMe3\mathrm{PMe}_3 in synergic bonding
Statement II: Me group is having +l+ l effect while FF atom is having −I-I effect
View answer and explanation
Correct option: D
Statement I if false but statement II is correct
Option D (Statement I if false but statement II is correct) is correct because PF{_3} is a stronger π-acceptor and weaker σ-donor than PMe{_3}, and the inductive effects of Me and F are correctly stated.
221 Hard
221 of 326
Analyzing +4 | -1
Amongst the following, the most stable complex is
View answer and explanation
Correct option: D
[FeCl6]3−\left[\mathrm{FeCl}_6\right]^{3-}
Option C is correct because [Fe(C2O4)3]3−\left[\mathrm{Fe}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-} forms a chelate due to the bidentate nature of oxalate ions, making it the most stable complex.
222 Easy
222 of 326
Application +4 | -1
The coordination number and oxidation number of XX in the following compound [X(SO4)(NH3)5]Cl  \left[ {X\left( {\mathrm{S}{\mathrm{O}_4}} \right){{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}} \right]\mathrm{Cl\;} will be
View answer and explanation
Correct option: C
6 and 3
Option C (6 and 3) is correct because the coordination number is the number of ligands attached to the metal, and the oxidation number is calculated based on the charges of the ligands and counter-ion.
223 Medium
223 of 326
Understanding +4 | -1
The complex that doesn’t give a precipitate with AgNO3\mathrm{AgN}{\mathrm{O}_3} solution
View answer and explanation
Correct option: A
[Co(NH3)33Cl3]\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_3}3\mathrm{C}{\mathrm{l}_3}} \right]
Option A is correct because the complex [Co(NH3)33Cl3]\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_3}3\mathrm{C}{\mathrm{l}_3}} \right] does not have any ionizable chloride ions outside the coordination sphere to react with AgN03.
224 Hard
224 of 326
Understanding +4 | -1
Assertion : Square planar complex Ma2b2{\text{M}}{{\text{a}}_{\text{2}}}{{\text{b}}_{\text{2}}} has two optical isomers.

Reason : Mirror image of Ma2b2{\text{M}}{{\text{a}}_{\text{2}}}{{\text{b}}_{\text{2}}} is non-super imposable.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because square planar complexes of the type Ma2b2 do not exhibit optical isomerism, and their mirror images are superimposable.
225 Easy
225 of 326
Understanding +4 | -1
Which of the following organometallic compound is σ  and  π\sigma \,\,\mathrm{and}\,\,\pi bonded?
View answer and explanation
Correct option: C
[Fe(η5−C5H5)2]\left[ {\mathrm{Fe}{{\left( {{\mathrm{\eta }^5} - {\mathrm{C}_5}{\mathrm{H}_5}} \right)}_2}} \right]
Option C, \left[ {\mathrm{Fe}{{\left( {{{\mathrm{\eta }^5} - {\mathrm{C}_5}{\mathrm{H}_5}} \right)}_2}} \right]\left[ {\mathrm{Fe}{{\left( {{{\mathrm{\eta }^5} - {\mathrm{C}_5}{\mathrm{H}_5}} \right)}_2}} \right], is correct because ferrocene exhibits both sigma and pi bonding between the iron center and the cyclopentadienyl rings.
226 Medium
226 of 326
Application +4 | -1
The value of CFSE for complex ion [CoCl6]4−\left[\mathrm{CoCl}_6\right]^{4-} is 18000 cm−118000 \mathrm{~cm}^{-1}. The CFSE for [CoCl4]2−\left[\mathrm{CoCl}_4\right]^{2-} complex ion will be
View answer and explanation
Correct option: C
8000 cm−18000 \mathrm{~cm}^{-1}
Option C (8000 cm−18000 \mathrm{~cm}^{-1}) is correct because the crystal field splitting energy (CFSE) for a tetrahedral complex is approximately 4/9 of that for an octahedral complex with the same ligands and metal ion.
227 Medium
227 of 326
Analyzing +4 | -1
Among the following compounds, the most stable compound is
View answer and explanation
Correct option: A
[Co(EDTA)]−1[\mathrm{Co}(\mathrm{EDTA})]^{-1}
Option A ([Co(EDTA)]⁻¹) is correct because EDTA is a strong chelating ligand, forming a highly stable complex with cobalt due to the chelate effect.
228 Easy
228 of 326
Understanding +4 | -1
The shape of the complex [Ag(NH3)2]+{\left[ {\mathrm{Ag}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_2}} \right]^ + } is:
View answer and explanation
Correct option: D
Linear
Option D (Linear) is correct because the complex ion [Ag(NH3)2]+{\left[ {\mathrm{Ag}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_2}} \right]^ + } has a coordination number of 2, resulting in a linear geometry.
229 Hard
229 of 326
Application +4 | -1
The conductivity measurement of a coordination compound of Cobalt (III) shows that it dissociates into 3 ions in solution. The compound is
View answer and explanation
Correct option: D
Pentaamminechloridocobalt(III) chloride
Option D (Pentaamminechloridocobalt(III) chloride) is correct because it dissociates into three ions in solution: [Co(NH₃)₅Cl]²⁺ and 2Cl⁻.
230 Medium
230 of 326
Application +4 | -1
The calculated spin-only magnetic moments of K3[Fe(OH)6]\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{OH})_6\right] and K4[Fe(OH)6]\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{OH})_6\right] respectively are:
View answer and explanation
Correct option: B
5.92 and 4.90 B.M.
Option B (5.92 and 4.90 B.M.) is correct because the spin-only magnetic moments are calculated based on the number of unpaired electrons in the high-spin complexes.
231 Easy
231 of 326
Understanding +4 | -1
The coordination number of a central metal atom in a complex is determined by
View answer and explanation
Correct option: D
The number of ligands around a metal ion bonded by sigma bonds
Option D (The number of ligands around a metal ion bonded by sigma bonds) is correct because the coordination number is determined by the number of sigma bonds formed between the ligands and the central metal atom.
232 Hard
232 of 326
Application +4 | -1
Which of the following compound is not colored?
View answer and explanation
Correct option: B
Na2Cd⋅Cl4{Na}_2 {Cd} \cdot {Cl}_4
Option B (Na2[CdCl4]) is correct because cadmium has a d10 configuration, meaning no d-d transitions are possible, hence it's colorless.
233 Easy
233 of 326
Understanding +4 | -1
The example of coordination isomerism is
View answer and explanation
Correct option: A
[Co  (NH3)6]  [Cr(CN)6]\left[ {\mathrm{Co\;}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}\left] \mathrm{\;} \right[\mathrm{Cr}{{\left( {\mathrm{CN}} \right)}_6}} \right] and \left[ {\mathrm{Cr}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}\left] \mathrm{\;} \right[\mathrm{Co}{{\left( {{\mathrm{CN}\left[ {\mathrm{Cr}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}\left] \mathrm{\;} \right[\mathrm{Co}{{\left( {{\mathrm{CN}
Option A is the correct example of coordination isomerism because it involves the exchange of ligands between the cationic and anionic coordination complexes.
234 Medium
234 of 326
Application +4 | -1
A) [Co(CN)6]−3\text{A) }\left[\mathrm{Co}(\mathrm{CN})_6\right]^{-3}

B) [Co(H2O)6]+3\text{B) }\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{+3}

Correct combination about the hybridization of central metal in these complexes is
View answer and explanation
Correct option: B
d2sp3,d2sp3d^2 s p^3, d^2 s p^3
Option D (d2sp3,d2sp3d^2 s p^3, d^2 s p^3) is correct because both complexes are inner orbital complexes with d2sp3d^2sp^3 hybridization due to strong field ligands or high oxidation state.
235 Hard
235 of 326
Analyzing +4 | -1
Assertion : Triethylenediamine is a bidentate mono anion.

Reason : Complex containing propylenediamine ligand shows ligand isomerism.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because triethylenediamine is a neutral bidentate ligand, and complexes with propylenediamine do not show ligand isomerism.
236 Medium
236 of 326
Analyzing +4 | -1
The order of energy absorbed which is responsible for the color of complexes.
A) [Ni(H2O)2(en)2]2+{\left[ {Ni{{({H_2}O)}_2}{{(en)}_2}} \right]^{2 + }}
B) [Ni(H2O)4(en)]2+{\left[ {Ni{{({H_2}O)}_4}(en)} \right]^{2 + }} and
C) [Ni(en)3]2+{\left[ {Ni{{(en)}_3}} \right]^{2 + }}
View answer and explanation
Correct option: D
(C) > (A) > (B)
Option D is correct because the spectrochemical series dictates that en (ethylenediamine) is a stronger field ligand than water, leading to greater splitting and thus higher energy absorption.
237 Medium
237 of 326
Understanding +4 | -1
Read the following statements

(i) Macromolecules cannot behave as a ligand.

(ii) [EDTA]4−[{EDTA}]^{4-} can bind through two oxygen and four nitrogen atom.

(iii) Chelate complexes are more stable than similar complexes containing unidentate ligands.

(iv) Coordination number of the central atom/ion is determined only by the number of sigma bonds formed by the ligand with central atom/ion

Which of the following is the correct code for statements above?
View answer and explanation
Correct option: A
FFTT
Option A (FFTT) is correct because statements (i) and (ii) are false, while statements (iii) and (iv) are true.
238 Easy
238 of 326
Understanding +4 | -1
[Pt((NH3)4]Cl2[\mathrm{Pt}\left( {{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2} is
View answer and explanation
Correct option: D
Square planar
Option D is correct because the complex has a coordination number of 4 and no lone pairs on the central metal atom, indicating a square planar geometry.
239 Medium
239 of 326
Analyzing +4 | -1
Assertion: The spin only magnetic moment of [MnBr4]2−\left[{MnBr}_4\right]^{2-} is 5.9 BM.5.9 \, \mathrm{BM}.

Reason: [MnBr4]2−\left[{MnBr}_4\right]^{2-} is tetrahedral with sp3s p^3 hybridisation of Mn2+{Mn}^{2+} having 3d53 d^5 configuration.
View answer and explanation
Correct option: A
Assertion is true, Reason is true and Reason is correct explanation for Assertion
Option A is correct because the assertion about the spin-only magnetic moment is true, the reason about the tetrahedral structure and hybridization is true, and the reason correctly explains the assertion.
240 Medium
240 of 326
Understanding +4 | -1
S-I:- The complex
[Cr(SCN)(NH3)5]Cl2\left[{Cr}({SCN})\left({NH}_3\right)_5\right] {Cl}_2 is linkage isomer of [Cr(NCS)(NH3)5]Cl2\left[{Cr}({NCS})\left({NH}_3\right)_5\right] {Cl}_2.

S-II:- SCN−S C N^{-}is an ambident ligand.
View answer and explanation
Correct option: A
Statement-I and Statement-II are true
Option A (Statement-I and Statement-II are true) is correct because SCN- is an ambident ligand and can coordinate through either S or N, leading to linkage isomerism.
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