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JEE CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Understanding +4 | -1
Assertion : Isomorphous substances form crystals of same shape and can grow in saturated solution of each other.

Reason : They have similar constitution and chemical formulae.
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Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because isomorphous substances have similar constitution and chemical formulae, leading to similar crystal shapes and the ability to grow in each other's saturated solutions.

More Questions from CO-ORDINATION COMPOUNDS

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Which has maximum paramagnetic character? Ionization of K[Ag(CN)2]\mathrm{K}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right] will give: The cation that does not form an ammine complex with excess of ammonia is: The complexes [PtCl2(NH3)4]Br2β€…β€Šandβ€…β€Š[PtBr2(NH3)4]Cl2β€…β€Š\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;} are example for isomerism The correct name of [Pt(NH3)4Cl2][PtCl4]\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\left[\mathrm{PtCl}_4\right] is: Which of the following pairs of isomers and types of isomerism are correctly matched?

(I) [Co(NH3)5(NO2)]Cl2\left[{Co}\left({NH}_3\right)_5\left({NO}_2\right)\right] {Cl}_2 and [Co(NH3)5(ONO)]Cl2………\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots Linkage

(II) [Cu(NH3)4][PtCl4]  &  [Pt(NH3)4][CuCl4]………\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots Coordinations

(III) [Pt(NH3)4Cl2]Br2  &  [Pt(NH3)4Br2]Cl2………\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots Ionization

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