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NEET • CHEMISTRY • SOLUTIONS

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121 Easy
121 of 226
Remembering +4 | -1
The distribution law was given by :
View answer and explanation
Correct option: B
Nernst
Option B (Nernst) is correct because Walther Nernst formulated the distribution law.
122 Easy
122 of 226
Understanding +4 | -1
Two solutions of KNO3\mathrm{KN}{\mathrm{O}_3} and CH3COOH\mathrm{C}{\mathrm{H}_3}\mathrm{COOH} are prepared separately. Molarity of both is 0.1  M0.1\;M and osmatic pressures are p1  and  p2{p_1}\;and\;{p_2} respectively. The correct relationship between the osmatic pressures is
View answer and explanation
Correct option: B
p1>p2{p_1} > {p_2}
Potassium nitrate (KNO3) is a strong electrolyte and dissociates completely, while acetic acid (CH3COOH) is a weak electrolyte and only partially dissociates. Therefore, the osmotic pressure of KNO3 will be greater than that of CH3COOH, making option B the correct answer.
123 Easy
123 of 226
Application +4 | -1
PA{P_A} and PB{P_B} are the vapour pressures of pure liquid components AA and BB respectively of an ideal binary solution. If XA{X_A} represents the mole fraction of component AA , the total pressure of the solution will be
View answer and explanation
Correct option: D
PB+XA(PA−PB){P_B} + {X_A}\left( {{P_A} - {P_B}} \right)
Option D (PB+XA(PA−PB){P_B} + {X_A}\left( {{P_A} - {P_B}} \right)) is correct because it correctly represents the total pressure of an ideal binary solution based on Raoult's law.
124 Medium
124 of 226
Analyzing +4 | -1
Which pair will not be isotonic
View answer and explanation
Correct option: D
2.5 M−KCl  2.5\,M - KCl\,\, and 1M−K3[Fe(CN)6]1M - {K_3}\left[ {Fe{{\left( {CN} \right)}_6}} \right]
Option D is correct because isotonic solutions have the same osmotic pressure, which depends on the van't Hoff factor (i) and molar concentration (C). For option D, the product iC is not equal for both solutions.
125 Medium
125 of 226
Understanding +4 | -1
Which of the following acid has the same molecular weight and equivalent weight.
View answer and explanation
Correct option: A
H3PO2{H_3}P{O_2}
Option A (H3PO2{H_3}P{O_2}) is correct because it is a monoprotic acid, meaning it has only one replaceable hydrogen atom.
126 Medium
126 of 226
Application +4 | -1
Which of the following solution highest boiling point?
View answer and explanation
Correct option: B
0.1    M  Al(NO3)30.1\;\;M\;Al{(N{O_3})_3}
Option B is correct because Al(NO3)3Al(NO_3)_3 dissociates into the highest number of ions (4), leading to the greatest boiling point elevation.
127 Hard
127 of 226
Analyzing +4 | -1
You are given 100 mL of CCl4\mathrm{CC}{\mathrm{l}_4} to extract iodine from 200 mL of its aqueous solution. For extracting maximum amount of iodine, which one of the following processes would you use?
View answer and explanation
Correct option: C
Use 10 mL of CCl4\mathrm{CC}{\mathrm{l}_4} 10 times
Option C is correct because using smaller volumes of CCl4 multiple times is more efficient for extraction than using a larger volume at once, leading to a higher overall extraction of iodine.
128 Easy
128 of 226
Application +4 | -1
Which solution will have least vapour pressure?
View answer and explanation
Correct option: D
0.1  M  Na3PO40.1\;M\;\mathrm{N}{\mathrm{a}_3}\mathrm{P}{\mathrm{O}_4}
Option D is correct because Na3PO4Na_3PO_4 dissociates into the highest number of ions (4), leading to the greatest lowering of vapor pressure.
129 Hard
129 of 226
Application +4 | -1
On shaking 10 mL of 0.1 molar solution of an organic compound in water with 10 mL of CCl4\mathrm{CC}{\mathrm{l}_4} til equilibrium is attained, concentration of the organic compound in water would be (K=9)(K = 9) in molar units :
View answer and explanation
Correct option: A
0.010.01
Option A (0.01) is correct because it is the concentration of the organic compound in water after equilibrium, calculated using the partition coefficient.
130 Hard
130 of 226
Understanding +4 | -1
Iodine was added to a system of water and CS2\mathrm{C}{\mathrm{S}_2}. The concentrations of iodine in water and CS2\mathrm{C}{\mathrm{S}_2} were found to be c1  and  c2{c_1}\;and\;{c_2} respectively. The ratio c1/c2{c_1}/{c_2} will not change only if :
View answer and explanation
Correct option: A
More iodine is added
Option A (More iodine is added) is correct because the distribution coefficient (c1/c2) is constant at a given temperature and is independent of the amount of solute added.
131 Medium
131 of 226
Application +4 | -1
Vapour pressure of pure A = 100 torr, moles = 2; vapour pressure of pure B=80 torr, moles = 3. Total vapour pressure of the mixture is
View answer and explanation
Correct option: D
88 torr
Option D (88 torr) is correct because it is calculated using Raoult's Law to find the total vapor pressure of the mixture.
132 Medium
132 of 226
Analyzing +4 | -1
20 mL20 \,\mathrm{mL} of calcium hydroxide was consumed when it was reacted with 10 mL10 \,\mathrm{mL} of unknown solution of H2SO4\mathrm{H}_{2} \mathrm{SO}_{4}. Also 20 mL20 \,\mathrm{mL} standard solution of 0.5 M HCl0.5 \,\mathrm{M} \,\mathrm{HCl} containing 2 drops of phenolphthalein was titrated with calcium hydroxide, the mixture showed pink colour when burette displayed the value of 35.5 mL35.5 \,\mathrm{mL} whereas the burette showed 25.5 mL25.5 \,\mathrm{mL} initially. The concentration of H2SO4\mathrm{H}_{2} \mathrm{SO}_{4} is _____ M. (Nearest integer)
View answer and explanation
Correct option: A
1
The concentration of H2SO4 is 1 M. This is determined by first calculating the moles of Ca(OH)2 used to neutralize HCl, then subtracting that from the total moles of Ca(OH)2 used to neutralize both HCl and H2SO4, and finally calculating the concentration of H2SO4.
133 Easy
133 of 226
Understanding +4 | -1
At 25∘C25^\circ C , the highest osmotic pressure is exhibited by 0.1  M0.1\;M solution of
View answer and explanation
Correct option: A
CaCl2CaC{l_2}
Option A (CaCl2CaC{l_2}) is correct because it dissociates into three ions (Ca2+Ca^{2+} and 2Cl−2Cl^−), resulting in the highest van't Hoff factor and thus the highest osmotic pressure.
134 Medium
134 of 226
Understanding +4 | -1
When an ideal binary solution is in equilibrium with its vapour, molar ratio of the two components in the solution and in the vapour phase is :
View answer and explanation
Correct option: C
May or may not be same depending upon volatile nature of the two components
Option C is correct because the molar ratio depends on the vapor pressures of the components, which are related to their volatility.
135 Hard
135 of 226
Analyzing +4 | -1
At 35∘C35^\circ \mathrm{C}, the vapour pressure of CS2C{S_2} is 512 mm Hg and that of acetone is 344 mm Hg. A solution of CS2C{S_2} in acetone has a total vapour pressure of 600 mm Hg. The false statement amongst the following is
View answer and explanation
Correct option: C
a mixture of 100 mL CS2C{S_2} and 100 mL acetone has a volume < 200 mL
Option C (a mixture of 100 mL CS2C{S_2} and 100 mL acetone has a volume < 200 mL) is correct because the total vapor pressure is higher than predicted by Raoult's law, indicating positive deviation, which means the volume of mixing is greater than the sum of individual volumes.
136 Medium
136 of 226
Application +4 | -1
When 36 grams of solute having the empirical formula CH2OC{H_2}O is dissolved in 1.2 kg of water, the solution freezes at −0.930C- {0.93^0}C what is the molecular formula of solute? (Kf=1.860C.kg.mol−1)\left( {{K_f} = {{1.86}^0}C.kg.mo{l^{ - 1}}} \right)
View answer and explanation
Correct option: D
C2H4O2{C_2}{H_4}{O_2}
Option D (C2H4O2{C_2}{H_4}{O_2}) is correct because the calculated molar mass matches the empirical formula multiplied by 2.
137 Medium
137 of 226
Understanding +4 | -1
Consider the following statements.

(i) On adding methyl alcohol to water, boiling point of water increases

(ii) When NaCl{NaCl} is added to water, depression in freezing point is observed

(iii) Diffusion of solution occurs from a region of its high concentration to a region of its low concentration

Choose the correct options
View answer and explanation
Correct option: C
(ii) and (iii)
Option C ((ii) and (iii)) is correct because adding NaCl to water lowers the freezing point, and diffusion occurs from high to low concentration.
138 Easy
138 of 226
Application +4 | -1
How many grams of concentrated HNO3HN{O_3} solution should be used to prepare 250ml  of  2.0M  HNO3250ml\,\,of\,\,2.0M\,\,HN{O_3}. The concentrated acid is 70%HNO370\% HN{O_3}
View answer and explanation
Correct option: C
45.0 g conc.HNO345.0\,g\,conc.HN{O_3}
Option C (45.0 g conc. HNO3) is correct because it is calculated by determining the mass of HNO3 needed and then accounting for the concentration of the stock solution.
139 Easy
139 of 226
Remembering +4 | -1
When the solute is present in trace quantities, the following expression is used:
View answer and explanation
Correct option: D
Parts per million
Parts per million (ppm) is the appropriate unit for expressing concentrations of solutes present in trace amounts, making option D the correct answer.
140 Easy
140 of 226
Analyzing +4 | -1
Equimolal solutions of A and B show depression in freezing point in the ratio 2:1.2 : 1. A remains in its normal state in solution. BB will be ……. in solution:
View answer and explanation
Correct option: C
Associated
Option C (Associated) is correct because the depression in freezing point is half of what is expected, indicating that two molecules of B are associating into one particle.
141 Hard
141 of 226
Understanding +4 | -1
Which of the aqueous equimolal solution will have its vapour pressure near to solvent?
View answer and explanation
Correct option: A
Urea
Option A (Urea) is correct because it is a non-electrolyte and does not dissociate in water, resulting in the smallest change in vapor pressure compared to the solvent.
142 Hard
142 of 226
Understanding +4 | -1
The size of a raw mango shrinks to a much smaller size when kept in a concentrated salt solution. Which one of the following processes can explain this?
View answer and explanation
Correct option: A
Osmosis
Option A (Osmosis) is correct because osmosis explains the movement of water from the mango into the concentrated salt solution, causing it to shrink.
143 Medium
143 of 226
Application +4 | -1
The vapour pressure of benzene at 90∘C90^\circ C is 1020 torr. A solution of 5 g of a solute in 58.5 g benzene has vapour pressure 990 torr. The molecular weight of the solute is :
View answer and explanation
Correct option: D
220220
Option D (220) is correct because it is calculated using the relative lowering of vapor pressure formula.
144 Medium
144 of 226
Analyzing +4 | -1
The plots of 1XA  vs.  1YA\frac{1}{{{X_A}}}\;vs.\;\frac{1}{{{Y_A}}} (where XA  and  YA{X_A}\;\mathrm{and}\;{Y_A} are the mole fraction of liquid A in liquid and vapour phase respectively) is linear with slope and intercepts respectively:
View answer and explanation
Correct option: B
PA∘/PB∘  and  (PB∘−PA∘)PB∘P_A^ \circ /P_B^ \circ \;and\;\frac{{(P_B^ \circ - P_A^ \circ )}}{{P_B^ \circ }}
Option D (PB∘/PA∘  and  (PB∘−PA∘)PB∘P_B^ \circ /P_A^ \circ \;and\;\frac{{(P_B^ \circ - P_A^ \circ )}}{{P_B^ \circ }}) is correct because it represents the slope and intercept of the linear plot of 1/XA vs 1/YA derived from Raoult's Law.
145 Hard
145 of 226
Understanding +4 | -1
The solution that forms maximum boiling azeotrope is
View answer and explanation
Correct option: A
acetone - chloroform
Option A (acetone - chloroform) is correct because it forms a maximum boiling azeotrope due to hydrogen bonding between acetone and chloroform, leading to negative deviations from Raoult's law.
146 Hard
146 of 226
Analyzing +4 | -1
Evaluate the following statements for their correctness.
A. The elevation in boiling point temperature of water will be same for 0.1 M NaCl0.1 \,\mathrm{M}\, \mathrm{NaCl} and 0.1 M0.1 \,\mathrm{M} urea
B. Azeotropic mixture boil without change in their composition.
C. Osmosis always takes place from hypertonic to hypotonic solution.
D. The density of 32%32\% H2SO4H_2S{O_4} solution having molarity 4.09 M is approximately 1.26 g mL–1.1.26 \,g \,mL^{–1}.
E. A negatively charged sol is obtained when KI\mathrm{KI} solution is added to silver nitrate solution.
Choose the correct answer from the options given below.
View answer and explanation
Correct option: D
B and D only
Options B and D are correct. Azeotropic mixtures do boil without changing composition, and the density of the H2SO4 solution is approximately 1.26 g/mL. The other statements are incorrect.
147 Hard
147 of 226
Application +4 | -1
20  g20\;g of binary electrolyte (mol. wt. =100) are dissolved in 500  g500\;g of water. The depression in freezing point of the solution is 0.74∘C  (kf=1.86  Km−1)0.74^\circ C\;({k_f} = 1.86\;K{m^{ - 1}}) the degree of ionisation of the electrolyte is
View answer and explanation
Correct option: A
0%0\%
Option D is incorrect. The correct answer is 75%. The degree of ionization is calculated using the van't Hoff factor and the freezing point depression.
148 Hard
148 of 226
Analyzing +4 | -1
Liquid MM and liquid NN form an ideal solution. The vapour pressures of pure liquids MM and NN are 450 and 700 mmHg, respectively, at the same temperature. Then correct statement is
xM={x_M} = mole fraction of MM in solution;            xN=\,\,\,\,\,\,\,\,\,\,\,{x_N} = mole fraction of NN in solution;
yM={y_M} = mole fraction of MM in vapour phase;               yN=\,\,\,\,\,\,\,\,\,\,\,\,\,\,{y_N} = mole fraction of NN in vapour phase;
View answer and explanation
Correct option: A
xMxN>yMyN\frac{{{x_M}}}{{{x_N}}} > \frac{{{y_M}}}{{{y_N}}}
Option A (xMxN>yMyN\frac{{{x_M}}}{{{x_N}}} > \frac{{{y_M}}}{{{y_N}}}) is correct because liquid N has a higher vapor pressure than liquid M, so it will have a higher mole fraction in the vapor phase relative to the liquid phase.
149 Easy
149 of 226
Application +4 | -1
Among the following mixtures, dipole-dipole as the major interaction is present in :
View answer and explanation
Correct option: C
Acetonitrile and acetone
Option C (Acetonitrile and acetone) is correct because both acetonitrile and acetone are polar molecules and exhibit dipole-dipole interactions as the major intermolecular force.
150 Medium
150 of 226
Understanding +4 | -1
Formation of a solution from two components can be considered as

(1) pure solvent →\to separated solvent moleculesΔH1\Delta {H_1}

(2) pure solute→\to separated solvent molecules,ΔH2\Delta {H_2}

(3) separated solvent and solute molecules →\to solution,ΔH3\Delta {H_3}

Solution so formed will be ideal if

View answer and explanation
Correct option: C
ΔHsoln=ΔH1+ΔH2+ΔH3\Delta {H_{soln}} = \Delta {H_1} + \Delta {H_2} + \Delta {H_3}
Option C (ΔHsoln=ΔH1+ΔH2+ΔH3\Delta {H_{soln}} = \Delta {H_1} + \Delta {H_2} + \Delta {H_3}) is correct because the enthalpy of solution is the sum of the enthalpy changes of each step in the solution formation process.
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