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NEET • CHEMISTRY • SOLUTIONS

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Showing 91-120 of 226 questions

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91 Easy
91 of 226
Understanding +4 | -1
For negative deviation from Raoult’s law, which of the following is an incorrect relation?
View answer and explanation
Correct option: C
ΔSmix<0\Delta {S_{mix}} < 0
Option C (ΔSmix<0\Delta {S_{mix}} < 0) is correct because for negative deviation, the entropy of mixing should be positive, not negative.
92 Hard
92 of 226
Remembering +4 | -1
Scuba divers may experience a condition called To avoids this, the tanks used by scuba divers are filled with air diluted with
View answer and explanation
Correct option: D
Bends, Helium
Option D (Bends, Helium) is correct because scuba divers can experience 'the bends' and helium is used to dilute the air to prevent this.
93 Medium
93 of 226
Remembering +4 | -1
A solution that obeys Raoult’s law is called
View answer and explanation
Correct option: C
Ideal solution
Option C (Ideal solution) is correct because it is defined as a solution that obeys Raoult's law.
94 Medium
94 of 226
Application +4 | -1
If vapour pressure of two liquids A and B in pure state are 400 and 500 mm of Hg respectively then mole fraction of A in vapour phase of solution obtained by mixing equal moles of A and B is
View answer and explanation
Correct option: C
49\frac{4}{9}
Option C (49\frac{4}{9}) is correct because it is calculated using Raoult's law and Dalton's law of partial pressures.
95 Medium
95 of 226
Analyzing +4 | -1
Consider the following statements about osmotic pressure method of molar mass determination.

I. Molarity of the solution is used instead of molality.

II. Magnitude of osmotic pressure is very large even for dilute solutions.

III. Molar mass of biomolecules can be determined as they are not stable at higher temperatures.

IV. Determine the molar mass of polymer as they have poor solubility.

Which of the above statements are responsible for advantage of osmotic pressure for determination of molar mass over the other colligative properties?
View answer and explanation
Correct option: C
I, II, III and IV
Option C is correct because all the statements (I, II, III, and IV) highlight the advantages of using osmotic pressure for molar mass determination, especially for biomolecules and polymers.
96 Medium
96 of 226
Application +4 | -1
The vapour density of undecomposed N2O4{\mathrm{N}_2}{\mathrm{O}_4} is 46. When heated, vapour density decreases to 24.5 due to its dissociation to NO2.\mathrm{N}{\mathrm{O}_2}. The per cent dissociation of N2O4{\mathrm{N}_2}{\mathrm{O}_4} at the final temperature is :
View answer and explanation
Correct option: A
87
Option A (87) is correct because the percent dissociation is calculated using the change in vapor density and the stoichiometry of the reaction.
97 Easy
97 of 226
Analyzing +4 | -1
Which has the highest freezing point at one atmosphere?
View answer and explanation
Correct option: B
0.1  M0.1\;M sugar solution
Option B (0.1  M0.1\;M sugar solution) is correct because sugar is a non-electrolyte, resulting in the smallest freezing point depression compared to the electrolyte solutions.
98 Hard
98 of 226
Analyzing +4 | -1
ΔTf/Kf\Delta T_f / K_f has the same value of 1 mol kg−11 \mathrm{~mol} \mathrm{~kg}^{-1} for 8%8 \% AB2A B_2 and 10%A2B10 \% A_2 B by mass of solvent, both AB2A B_2 and A2BA_2 B being non- electrolytes. Atomic masses of AA and BB will be respectively
View answer and explanation
Correct option: C
40,20
Option C is correct. By setting up equations based on the given information about ΔTf/Kf\Delta T_f / K_f and solving for the atomic masses of A and B, we find that A = 40 and B = 20.
99 Easy
99 of 226
Remembering +4 | -1
The vapour pressure of a liquid in a closed container depends upon
View answer and explanation
Correct option: C
Temperature
The correct answer is C (Temperature) because the vapor pressure of a liquid is directly related to its temperature.
100 Hard
100 of 226
Application +4 | -1
At temperature 327∘C327^\circ C and concentration C osmotic pressure of a solution is p, the same solutions at concentration C/2 and a temperature 427∘C427^\circ C shows osmotic pressure 2 atm, value of p will be
View answer and explanation
Correct option: B
247\frac{{24}}{7}
Option B (247\frac{{24}}{7}) is correct because it is calculated using the osmotic pressure formula and the given conditions.
101 Medium
101 of 226
Analyzing +4 | -1
When a substance is distributed between two immiscible solvents and remains in the same state in the solvent I, while, dissociates in the solvent II. If the concentration of solute are cI  and  cII{c_\mathrm{I}}\;\mathrm{and}\;{c_{\mathrm{II}}} in phase I and II respectively then :
View answer and explanation
Correct option: A
cIcII(1−α)=K\frac{{{c_\mathrm{I}}}}{{{c_{\mathrm{II}}}\left( {1 - \mathrm{\alpha }} \right)}} = K
Option A is correct because it represents the distribution law when the solute dissociates in one of the solvents, considering the degree of dissociation.
102 Easy
102 of 226
Application +4 | -1
Lowering in vapour pressure is the highest for:
View answer and explanation
Correct option: D
0.1  m  BaCl20.1\;m\;\mathrm{BaC}{\mathrm{l}_2}
Option D (0.1  m  BaCl20.1\;m\;\mathrm{BaC}{\mathrm{l}_2}) is correct because it has the highest van't Hoff factor, leading to the greatest lowering in vapor pressure.
103 Hard
103 of 226
Analyzing +4 | -1
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): At 10∘C,10^\circ C, the density of a 5 M solution of KClKCl [atomic masses of K  &  ClK\,\,\& \,\,Cl are 39 & 35.5 g  mol−1g\,\,mo{l^{ - 1}} respectively] is ′x′  g  ml−1.'x'\,\,g\,\,m{l^{ - 1}}. The solution is cooled to −21∘C.- 21^\circ C. The molality of the solution will remain unchanged.
Reason (R) : The molality of a solution does not change with temperature as mass remains unaffected with temperature.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A).
Option A is correct. Molality is defined as moles of solute per kilogram of solvent, which is independent of temperature because mass does not change with temperature. Therefore, both the assertion and reason are true, and the reason correctly explains the assertion.
104 Hard
104 of 226
Application +4 | -1
In which ratio of volume 0.4  M  HCl  and  0.9  M  HCl0.4\mathrm{ }\;M\;\mathrm{ }HCl\;\mathrm{ }and\;\mathrm{ }0.9\;\mathrm{ }M\;\mathrm{ }HCl are to be mixed such that the concentration of the resultant solution becomes 0.7 M ?
View answer and explanation
Correct option: B
2:32\mathrm{ }:\mathrm{ }3
Option B (2:32\mathrm{ }:\mathrm{ }3) is correct because it is the ratio of volumes calculated using the alligation method or a weighted average approach.
105 Medium
105 of 226
Understanding +4 | -1
Assertion (A): Sum of mole fraction of all components in a mixture is 1.

Reason (R): Mole fraction is temperature dependent mode of concentration.
View answer and explanation
Correct option: C
A is true, R is false
Option C (A is true, R is false) is correct because the sum of mole fractions in a mixture is always 1, but mole fraction is independent of temperature.
106 Easy
106 of 226
Application +4 | -1
The values of observed and calculated molecular weights of silver nitrate are 92.64 and 170 respectively. The degree of dissociation of silver nitrate is :
View answer and explanation
Correct option: B
83.5%83.5\%
Option B (83.5%) is correct because the degree of dissociation is calculated using the observed and calculated molecular weights and the van't Hoff factor.
107 Medium
107 of 226
Understanding +4 | -1
Which of the following statements is not correct about homogeneous mixtures?
View answer and explanation
Correct option: D
These always contain a solute and a solvent
Option D (These always contain a solute and a solvent) is correct because homogeneous mixtures do not *always* contain both a solute and a solvent; they simply have uniform composition and properties.
108 Easy
108 of 226
Remembering +4 | -1
In two solutions having different osmotic pressure, the solution of higher osmotic pressure is called :
View answer and explanation
Correct option: B
Hypertonic solution
Option B (Hypertonic solution) is correct because a hypertonic solution has a higher osmotic pressure compared to another solution.
109 Medium
109 of 226
Application +4 | -1
Which one of the following aqueous solutions will exhibit highest boiling point?
View answer and explanation
Correct option: A
0.01  M  Na2SO40.01\;\mathrm{M }\;\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_4}
Option A is correct because Na2SO4Na_2SO_4 dissociates into the largest number of ions (3), resulting in the highest boiling point elevation.
110 Easy
110 of 226
Application +4 | -1
A and B ideal gases. The molecular weights of A and B are in the ratio of 1:4. The pressure of a gas mixture containing equal weight of A and B is p atm. What is the partial pressure (in atm) of B in the mixture?
View answer and explanation
Correct option: A
P5\frac{P}{5}
Option A (P5\frac{P}{5}) is correct because the partial pressure of B is calculated based on its mole fraction in the mixture, considering the ratio of molecular weights.
111 Easy
111 of 226
Remembering +4 | -1
The temperature at which vapour pressure of a solvent in its liquid and solid phase becomes same is called :
View answer and explanation
Correct option: B
f. p.
Option B is correct because the freezing point is the temperature at which the vapor pressure of the liquid and solid phases are equal.
112 Medium
112 of 226
Analyzing +4 | -1
The vapour pressure of the solution of two liquids A(P∘=80mm)A\left(P^{\circ}=80 \mathrm{mm}\right), and B(P∘=120mm)B\left(P^{\circ}=120 \mathrm{mm}\right) is found to be 100mm100 \mathrm{mm} when XA=0.4X_{A}=0.4. The result shows that
View answer and explanation
Correct option: C
Solution shows negative deviations
Option C (Solution shows negative deviations) is correct because the observed vapor pressure is lower than that predicted by Raoult's law, indicating stronger intermolecular forces between A and B.
113 Medium
113 of 226
Understanding +4 | -1
If the various terms in the below given expressions have usual meanings, the van’t Hoff factor (i) cannot be calculated by which one of the expressions?
View answer and explanation
Correct option: A
πV=inRT\pi V = \sqrt {inRT}
Option A (πV=inRT\pi V = \sqrt {inRT}) is correct because the correct formula for osmotic pressure is πV=inRT\pi V = inRT, not πV=inRT\pi V = \sqrt {inRT}.
114 Easy
114 of 226
Application +4 | -1
The molal elevation constant for water is 0.52  K  molality−1\mathrm{0}\mathrm{.52}\;\mathrm{K}\;\mathrm{molalit}{\mathrm{y}^{ - 1}}. The elevation caused in the boiling point of water by dissolving 0.25 mole of a non-volatile solute in 250 g of water will be :
View answer and explanation
Correct option: C
0.52∘C0.52^\circ \mathrm{C}
Option C is correct because the elevation in boiling point is calculated using the formula ΔTb=Kb×m\Delta T_b = K_b \times m, where m is the molality of the solution.
115 Easy
115 of 226
Remembering +4 | -1
The solubility of a gas in water depends on :
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because the solubility of a gas in water depends on the nature of the gas, the temperature, and the pressure of the gas.
116 Hard
116 of 226
Understanding +4 | -1
On mixing 10 mL10 \mathrm{~mL} of acetone with 40 mL40 \mathrm{~mL} of chloroform, the total volume of the solution is :
View answer and explanation
Correct option: A
<50 mL< 50 \mathrm{~mL}
Option A (< 50 mL) is correct because when acetone and chloroform are mixed, there's a decrease in volume due to intermolecular interactions.
117 Hard
117 of 226
Application +4 | -1
A solution of protein (extracted from crabs) was prepared by dissolving 0.75 g in 125  cm3125\;\mathrm{c}{\mathrm{m}^3} of an aqueous solution. At 4∘C4^\circ C an osmotic pressure rise of 2.6 mm of the solution was observed. Then molecular weight of protein is : (Assume density of solution is 1.00  g/cm31.00\;g/\mathrm{c}{\mathrm{m}^3})
View answer and explanation
Correct option: B
5.4×1055.4 \times {10^5}
Option B (5.4×1055.4 \times {10^5}) is correct because the molecular weight of the protein is calculated using the osmotic pressure formula.
118 Medium
118 of 226
Analyzing +4 | -1
Molarity and molality of a solution of NaOH{NaOH} is calculated. If now temperature of the solution is increased then which of the following statement(s) is/are correct ?

(i) Molarity of solution decreases

(ii) Molality of the solution increases
View answer and explanation
Correct option: B
Statement (i) is correct only
Option B (Statement (i) is correct only) is correct because molarity is temperature-dependent due to volume changes, while molality is not.
119 Easy
119 of 226
Analyzing +4 | -1
Consider the following aqueous solutions and assume 100% ionisation in electrolytes

I. 0.1 m urea

II. 0.04 m Al2(SO4)3\mathrm{A}{\mathrm{l}_2}{\left( {\mathrm{S}{\mathrm{O}_4}} \right)_3}

III. 0.05 m CaCl2\mathrm{CaC}{\mathrm{l}_2}

IV. 0.005 m NaCl

The correct statement regarding the above solution is
View answer and explanation
Correct option: B
Freezing point will be highest for solution IV
Option B (Freezing point will be highest for solution IV) is correct because the solution with the lowest total molality of ions will have the highest freezing point.
120 Easy
120 of 226
Application +4 | -1
Which of the following solutions has the highest normality?
View answer and explanation
Correct option: A
6  g  of    NaOH/1006\mathrm{ }\;g\;\mathrm{ }of\;\;\mathrm{NaOH}/100 mL\mathrm{mL}
Option A (6  g  of    NaOH/1006\mathrm{ }\;g\;\mathrm{ }of\;\;\mathrm{NaOH}/100 mL\mathrm{mL}) is correct because it has the highest number of gram equivalents per liter of solution.
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