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NEET • CHEMISTRY • SOLUTIONS

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61 Medium
61 of 226
Analyzing +4 | -1
Assertion: The molarity and normality of a solution of sodium carbonate are same.
Reason: Molarity is the product of normality & valency factor.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false. The molarity and normality of sodium carbonate are not the same, and molarity is not the product of normality and valency factor; rather, normality is the product of molarity and valency factor.
62 Easy
62 of 226
Understanding +4 | -1
Boiling point of water is defined as the temperature at which :
View answer and explanation
Correct option: A
Vapour pressure of water is equal to one atmospheric pressure
The boiling point of water is defined as the temperature at which its vapor pressure equals the surrounding atmospheric pressure, making option A the correct answer.
63 Hard
63 of 226
Analyzing +4 | -1
Statement I: Acetic acid has a molecular weight of 120 g mol−1120 \mathrm{~g} \mathrm{~mol}^{-1} in benzene.

Statement II: van't Hoff factor for acetic acid in benzene is 0.5 when 100%100 \% dimer is formed.
View answer and explanation
Correct option: A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.
Both statements are correct, and Statement II correctly explains Statement I, making option A the correct answer. Acetic acid dimerizes in benzene, effectively doubling its molecular weight.
64 Hard
64 of 226
Application +4 | -1
A mixture of ethane and ethene occupies 41 L at 1 atm and 500  K500\;K. the mixture reacts completely with   103\;\frac{{10}}{3} mole of O2{O_2} to produce CO2 and  H2OC{O_2}\,and\;{H_2}\mathrm{O}. The mole fraction of ethane and ethene in the mixture are (R=0.082  L  atm  K−1  mol−1)\left( {R = 0.082\;L\;\mathrm{atm}\;{\mathrm{K}^{ - 1}}\;\mathrm{mo}{\mathrm{l}^{ - 1}}} \right) respectively
View answer and explanation
Correct option: C
0.67,0.330.67,\mathrm{ }0.33
Option C (0.67,0.330.67,\mathrm{ }0.33) is correct because it represents the mole fractions of ethane and ethene calculated from the given reaction and conditions using the ideal gas law.
65 Hard
65 of 226
Analyzing +4 | -1
When a solute is added in two immiscible solvents, it distributes itself between two liquids so that its concentration in first liquid is c1{c_1} and that in the second liquid is c2{c_2}. If the solute forms a stable trimer in the first liquid, the distribution law suggests that :
View answer and explanation
Correct option: D
c2/c13=constant{c_2}/\sqrt[3]{{{c_1}}} = \mathrm{ }constant
Option D is correct because, according to the distribution law, if the solute forms a trimer in the first liquid, the ratio of the concentration in the second liquid to the cube root of the concentration in the first liquid is constant: c2/c13=constant{c_2}/\sqrt[3]{{{c_1}}} = constant.
66 Hard
66 of 226
Understanding +4 | -1
We have three aqueous solutions of NaCl\mathrm{NaCl} labelled as (A), (B) and (C) with concentration of 0.1 M,0.01 M0.1 \mathrm{~M}, 0.01 \mathrm{~M} and 0.001 M0.001 \mathrm{~M}, respectively. The value of van't Hoff factor (i) of these solutions will be in order
View answer and explanation
Correct option: B
iA<iB<iCi_{\mathrm{A}} < i_{\mathrm{B}} < i_{\mathrm{C}}
Option B (iA<iB<iCi_{\mathrm{A}} < i_{\mathrm{B}} < i_{\mathrm{C}}) is correct. At higher concentrations, the interionic attractions are greater, leading to a lower degree of dissociation and a lower van't Hoff factor.
67 Easy
67 of 226
Understanding +4 | -1
Which of the following concentration term is/are independent of temperature?
View answer and explanation
Correct option: C
Mole fraction and molality
Mole fraction and molality are independent of temperature because they are defined in terms of moles and mass, which do not change with temperature, making option C the correct answer. Molarity and normality involve volume, which is temperature-dependent.
68 Hard
68 of 226
Analyzing +4 | -1
The ratio of concentration of NH3{NH}_3 in H2O{H}_2 {O} to the concentration of NH3{NH}_3 in CHCl3{CHCl}_3 at 290 K290 \mathrm{~K} is 24 at any pressure. Through one litre of pure water ammonia gas was passed, the concentration of NH3{NH}_3 was measured to be 0.38(M)0.38 ({M}). To this solution 0.025 moles of CuSO4{CuSO}_4 was added. In NH3{NH}_3 solution all Cu2+{Cu}^{2+} ions form the complex Cu(NH3)x2+{Cu}\left({NH}_3\right)_x^{2+}. Now over this solution one litre of CHCl3{CHCl}_3 was added, thoroughly shaken and equilibrated. In CHCl3{CHCl}_3 layer, Cu(NH3)x2+{Cu}\left({NH}_3\right)_x^{2+} was absent but in CHCl3{CHCl}_3 the concentration of NH3{NH}_3 was reduced to 0.0112(M)0.0112({M}) at 290 K290 \mathrm{~K}. Determine the value of x{x} in nearest possible integers.
View answer and explanation
Correct option: A
4
Option A (4) is correct because the concentration of ammonia in water decreases after adding copper sulfate due to the formation of the complex, allowing us to calculate the number of ammonia molecules coordinated to copper.
69 Hard
69 of 226
Understanding +4 | -1
Statement I: People living at high altitudes have symptoms of a condition known as anoxia.

Statement II: At high altitudes, the partial pressure of oxygen is less than that at the ground level.
View answer and explanation
Correct option: B
Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I.
Option B (Both statements are correct, but Statement II is not the correct explanation of Statement I) is correct. Anoxia is caused by a lack of oxygen, and the partial pressure of oxygen is indeed lower at high altitudes, but anoxia is a broader condition than just altitude sickness.
70 Easy
70 of 226
Remembering +4 | -1
Most of the processes in our body occur in
View answer and explanation
Correct option: B
liquid solution
Option B (liquid solution) is correct because the biological fluids in our body, such as blood and lymph, are primarily liquid solutions.
71 Medium
71 of 226
Remembering +4 | -1
Isotonic solutions are solutions having the same
View answer and explanation
Correct option: C
Osmotic pressure
Option C (Osmotic pressure) is correct because isotonic solutions, by definition, have the same osmotic pressure.
72 Easy
72 of 226
Analyzing +4 | -1
An aqueous solution is 1.0 molal in KI. Which change will cause the vapour pressure of solution to increase :
View answer and explanation
Correct option: D
Addition of water
Option D (Addition of water) is correct because adding water dilutes the solution, decreasing the concentration of KI and increasing the vapor pressure.
73 Medium
73 of 226
Application +4 | -1
The relative lowering of vapour pressure produced by dissolving 71.5 g of a substance in 1000 g of water is 0.00713. The molecular weight of the substance will be :
View answer and explanation
Correct option: A
180
Option A (180) is correct because it is calculated using the relative lowering of vapor pressure formula.
74 Medium
74 of 226
Understanding +4 | -1
On mixing 10 ml10\,ml of acetone with 40 ml40\,ml of chloroform, the total volume of the solution is
View answer and explanation
Correct option: B
> 50 ml> \,50\,ml
Option B (>50ml> 50 ml) is correct because mixing acetone and chloroform results in positive deviations from Raoult's law, leading to an increase in volume.
75 Medium
75 of 226
Remembering +4 | -1
The distribution law holds good for :
View answer and explanation
Correct option: A
Heterogeneous systems
Option A (Heterogeneous systems) is correct because the distribution law applies to the distribution of a solute between two immiscible (heterogeneous) solvents.
76 Easy
76 of 226
Application +4 | -1
The exact volumes of 1M NaOH1M\,NaOH solution required to neutralise 50 mL of 1M H3PO31M\,{H_3}P{O_3} solution and 100 ml of 2M H3PO22M\,{H_3}P{O_2} solution, respectively, are
View answer and explanation
Correct option: C
100 mL and 200 mL
Option C (100 mL and 200 mL) is correct because it correctly calculates the volumes of 1M NaOH required to neutralize the given amounts of H3PO3 and H3PO2 solutions, considering their respective basicities.
77 Easy
77 of 226
Remembering +4 | -1
The statement “the relative lowering of the vapour pressure is equal to th ratio ot moles of the solute to the total number of the moles in the solution” refers to
View answer and explanation
Correct option: C
Raoult’s law
Option C (Raoult’s law) is correct because Raoult's law states that the relative lowering of vapor pressure is equal to the mole fraction of the solute.
78 Hard
78 of 226
Application +4 | -1
Two liquids X and Y form an ideal solution. The mixture has a vapour pressure of 400 mm at 300 K when mixed in the molar ratio of 1:1 and a vapour pressure of 350 mm when mixed in the molar ratio of 1:2 at the same temperature. The vapour pressures of the two pure liquids X and Y respectively are
View answer and explanation
Correct option: D
550 mm, 250 mm
Option D (550 mm, 250 mm) is correct because it satisfies Raoult's law for ideal solutions with the given vapor pressures and molar ratios.
79 Medium
79 of 226
Understanding +4 | -1
Which of the following associated with isotonic solutions is not correct?
View answer and explanation
Correct option: C
They have same weight concentrations
Option C (They have same weight concentrations) is not correct because isotonic solutions have the same osmotic pressure, not necessarily the same weight concentrations.
80 Medium
80 of 226
Analyzing +4 | -1
For an ideal binary liquid solution with PA∘>PB∘P_A^ \circ > P_B^ \circ which relation between XA{X_A} (mole fraction of A in liquid phase) and YA{Y_A} (mole fraction of A in vapour phase) is correct, XB{X_B} and YB{Y_B} are mole fraction of B in liquid and vapour phase respectively :
View answer and explanation
Correct option: C
XAXB<YAYB\frac{{{X_A}}}{{{X_B}}} < \frac{{{Y_A}}}{{{Y_B}}}
Option C is correct because the vapor phase is richer in the more volatile component (A), leading to a higher ratio of mole fractions in the vapor phase compared to the liquid phase.
81 Medium
81 of 226
Remembering +4 | -1
Which of the following compounds can be used as antifreeze in automobile radiators?
View answer and explanation
Correct option: B
Glycol
Option B (Glycol) is correct because glycol (ethylene glycol) is commonly used as an antifreeze due to its ability to lower the freezing point of water.
82 Easy
82 of 226
Remembering +4 | -1
Aqueous solutions of two acids having same concentrations of common ion [H+]\left[ {{\mathrm{H}^ + }} \right] are called:
View answer and explanation
Correct option: A
Isohydric solutions
The correct answer is A (Isohydric solutions) because isohydric solutions are defined as solutions having the same hydrogen ion concentration.
83 Hard
83 of 226
Analyzing +4 | -1
Assertion: There will not be any change in concentration of an ethanol and water mixture containing 85%85 \% ethanol by volume on boiling.

Reason: It is because azeotropes boil out in constant composition.
View answer and explanation
Correct option: D
Assertion is wrong, but reason is correct statement.
The assertion is incorrect, but the reason is correct, making option D the correct answer. Azeotropes do boil at a constant composition, but an 85% ethanol mixture is not necessarily an azeotrope.
84 Easy
84 of 226
Understanding +4 | -1
Which of the following compounds correspond to maximum van’thoff factor for dilute solution?
View answer and explanation
Correct option: D
K4Fe(CN)6{\mathrm{K}_4}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}
Potassium ferrocyanide, K4[Fe(CN)6], dissociates into the highest number of ions (5) in solution compared to the other options, resulting in the maximum van't Hoff factor, making option D the correct answer.
85 Hard
85 of 226
Application +4 | -1
The Henry’s law constant for the solubility of N2{{N_2}} gas in water at 298  K298\;K is 1.0×105  atm1.0 \times 105\;atm . The mole fraction of N2{{N_2}} In air is 0.8 The number of moles of N2{{N_2}} from air dissolved in 10 moles of water of 298  K298\;K and 5 atm pressure is
View answer and explanation
Correct option: A
4×10−44 \times {10^{ - 4}}
Option A (4×10−44 \times {10^{ - 4}}) is correct because it is calculated using Henry's Law to find the mole fraction of N2 in water, and then using that to find the number of moles of N2.
86 Easy
86 of 226
Application +4 | -1
A solution is prepared by dissolving 24.5 g of sodium hydroxide in distilled water to give 1L solution. The molarity of NaOHNaOH in the solution is
(Given, that molar mass of NaOH=40.0  g  mol−1NaOH = 40.0\;g\;mo{l^{ - 1}})
View answer and explanation
Correct option: C
1 L of solution
Option C (1 L of solution) is correct because molarity is defined as moles of solute per liter of solution.
87 Hard
87 of 226
Application +4 | -1
How many grams of dibasic acid mole.wt.200{\mathrm{mole}\mathrm{.wt}\mathrm{.200}} should be present in 100  mL100\;mL of the aqueous solution to give 0.1  N{0.1\;N}?
View answer and explanation
Correct option: D
1 g
Option D (1 g) is correct because it is the mass of the dibasic acid required to prepare the given solution, calculated using the normality formula.
88 Medium
88 of 226
Remembering +4 | -1
The osmotic pressure of a solution can be accurately measured in the shortest possible time by :
View answer and explanation
Correct option: A
Berkeley and Hartley method
Option A (Berkeley and Hartley method) is correct because it is a dynamic method that directly measures osmotic pressure, allowing for faster measurements.
89 Easy
89 of 226
Understanding +4 | -1
When a solute distributes itself between two immiscible liquids in contact with each other, a mathematical constant ratio exists between :
View answer and explanation
Correct option: B
The concentration of solute in the two liquids
Option B (The concentration of solute in the two liquids) is correct because the distribution law states that the ratio of solute concentrations in two immiscible liquids is constant.
90 Medium
90 of 226
Application +4 | -1
The solubility of iodine in water is 0.8  g/L{0.8\;g/L}. If the partition coefficient of iodine between CCl4{\mathrm{CC}{\mathrm{l}_4}} and water (in favour of CCl4{\mathrm{CC}{\mathrm{l}_4}}) is 82, the solubility of iodine in CCl4{\mathrm{CC}{\mathrm{l}_4}} is :
View answer and explanation
Correct option: B
65.6  g/L65.6\mathrm{ }\;g/L
Option B (65.6  g/L65.6\mathrm{ }\;g/L) is correct because the solubility in CCl4 is calculated by multiplying the solubility in water by the partition coefficient.
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