Iodine was added to a system of water and ${\rm{C}}{{\rm{S}}_2}$. The concentrations of iodine in water and ${\rm{C}}{{\rm{S}}_2}$ were found to be ${c_1}\;and\;{c_2}$ respectively. The ratio ${c_1}/{c_2}$ will not change only if :

More ${\rm{C}}{{\rm{S}}_2}$ is added

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Showing 1-30 of 53 questions

1 Hard

1 of 53

Understanding +4 | -1

Assertion: Isotonic solutions don't show net phenomenon of osmosis.

Reason: Isotonic solutions have equal osmotic pressure at constant temperature.

View answer and explanation

Correct option: A

If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion

Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because isotonic solutions have the same osmotic pressure, which is why there is no net osmosis.

2 Hard

2 of 53

Application +4 | -1

The vapour pressures of pure liquids

A

and

B

are 400 and 600 mmHg, respectively at 298 K. On mixing the two liquids, the sum of their initial volumes is equal to the volume of the final mixture. The mole fraction of liquid

B

is 0.5 in the mixture. The vapour pressure of the final solution, the mole fractions of components

A

and

B

in vapour phase, respectively are

View answer and explanation

Correct option: D

500 mmHg, 0.4, 0.6

Option D (500 mmHg, 0.4, 0.6) is correct because it follows Raoult's law for ideal solutions, and the vapor phase mole fractions are calculated using partial pressures.

3 Hard

3 of 53

Analyzing +4 | -1

A solute when distributed between two immiscible phases remains associated in phase II and dissociated in phase I. If αis the degree of dissociation and n is the number of molecules associated then :

View answer and explanation

Correct option: D

K = \frac{{{c_\mathrm{I}}\left( {1 - \mathrm{\alpha }} \right)}}{{\sqrt[n]{{{c_{\mathrm{II}}}}}}}

Option D is correct because it represents the distribution law when the solute associates in phase II and dissociates in phase I, considering the degree of dissociation and association number.

4 Hard

4 of 53

Application +4 | -1

The osmotic pressure

(At\;27^\circ C)

of an aqueous solution (200 mL) containing 6 g of a protein is

2 \times {10^{ - 3}}\;\mathrm{atm}.

R = 0.080\mathrm{ }L - atm\mathrm{ }\;mo{l^{ - 1}}{K^{ - 1}},

the molecular weight of protein is

View answer and explanation

Correct option: B

3.6 \times {10^5}

Option B (

3.6 \times {10^5}

) is correct because it is the calculated molecular weight of the protein using the osmotic pressure formula.

5 Hard

5 of 53

Understanding +4 | -1

{K}_{{H}}

value for some gases at the same temperature '

{T}

' are given:

\begin{array}{cccccccccccccccccccc} {{\text{Gas}}}&{{K_H}/k\,\,{\text{bar}}} \\ {Ar}&{40.3} \\ {C{O_2}}&{1.67} \\ {HCHO}&{1.83 \times {{10}^{ - 5}}} \\ {C{H_4}}&{0.413} \end{array}

where

{K}_{{H}}

is Henry's Law constant in water. The order of their solubility in water is:

View answer and explanation

Correct option: B

{Ar} < {CO}_2 < {CH}_4 < {HCHO}

Option B (

{Ar} < {CO}_2 < {CH}_4 < {HCHO}

) is correct because the solubility of a gas is inversely proportional to its Henry's Law constant (

K_H

6 Hard

6 of 53

Understanding +4 | -1

Assertion: In positive deviation of non-idea If solution attraction between solute solvent is less than the attraction between solute-solute and solvent-solvent.

Reason: In negative deviation of non-ideal solution attraction between solute-solvent is more than the attraction between solute-solute and solvent-solvent.

View answer and explanation

Correct option: B

If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion

Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because both statements about positive and negative deviations are true, but the reason doesn't directly explain the assertion.

7 Hard

7 of 53

Analyzing +4 | -1

Two components A and B form an ideal solution. The mole fractions of

A

and

B

in ideal solution are

X_A

and

X_B

, while that of in vapour phase, these components have their mole fractions as

\mathrm{Y}_{\mathrm{A}}

and

\mathrm{Y}_{\mathrm{B}}

. Then, the slope and intercept of plot of

\frac{1}{\mathrm{Y}_{\mathrm{A}}}

vs.

\frac{1}{\mathrm{X}_{\mathrm{A}}}

will be:

View answer and explanation

Correct option: B

\frac{\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}, \frac{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}-\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}

Option B (

\frac{\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}, \frac{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}-\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}

) is correct because it is derived from Raoult's law and the definition of mole fractions in the vapor phase.

8 Hard

8 of 53

Application +4 | -1

What is molarity of

{{K^ + }}

in aqueous solution that contains 17.4 ppm of

{K_2}S{O_4}(174\;g\;mo{l^{ - 1}})

View answer and explanation

Correct option: D

2 \times {10^{ - 4}}\;M

Option D (

2 \times {10^{ - 4}}\;M

) is correct because it is the molarity of

{{K^+}}

calculated from the given ppm of

{K_2}S{O_4}

9 Hard

9 of 53

Understanding +4 | -1

Which will form maximum boiling point azeotrope

View answer and explanation

Correct option: A

{HNO}_3+{H}_2 {O}

solution

Option A (

{HNO}_3+{H}_2 {O}

solution) is correct because it forms a maximum boiling azeotrope due to strong negative deviations from Raoult's law.

10 Hard

10 of 53

Understanding +4 | -1

Assertion: When Benzoic acid is dissolved in benzene its Van't Hoff factor is less than one.

Reason: in benzene, benzoic acid has tendency to form dimer.

View answer and explanation

Correct option: A

If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion

Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because benzoic acid dimerizes in benzene, reducing the number of solute particles and thus the van't Hoff factor.

11 Hard

11 of 53

Analyzing +4 | -1

Statement I: Acetic acid has a molecular weight of

120 \mathrm{~g} \mathrm{~mol}^{-1}

in benzene.

Statement II: van't Hoff factor for acetic acid in benzene is 0.5 when

100 \%

dimer is formed.

View answer and explanation

Correct option: A

Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.

Both statements are correct, and Statement II correctly explains Statement I, making option A the correct answer. Acetic acid dimerizes in benzene, effectively doubling its molecular weight.

12 Hard

12 of 53

Application +4 | -1

A mixture of ethane and ethene occupies 41 L at 1 atm and

500\;K

. the mixture reacts completely with

\;\frac{{10}}{3}

mole of

{O_2}

to produce

C{O_2}\,and\;{H_2}\mathrm{O}

. The mole fraction of ethane and ethene in the mixture are

\left( {R = 0.082\;L\;\mathrm{atm}\;{\mathrm{K}^{ - 1}}\;\mathrm{mo}{\mathrm{l}^{ - 1}}} \right)

respectively

View answer and explanation

Correct option: C

0.67,\mathrm{ }0.33

Option C (

0.67,\mathrm{ }0.33

) is correct because it represents the mole fractions of ethane and ethene calculated from the given reaction and conditions using the ideal gas law.

13 Hard

13 of 53

Analyzing +4 | -1

When a solute is added in two immiscible solvents, it distributes itself between two liquids so that its concentration in first liquid is

{c_1}

and that in the second liquid is

{c_2}

. If the solute forms a stable trimer in the first liquid, the distribution law suggests that :

View answer and explanation

Correct option: D

{c_2}/\sqrt[3]{{{c_1}}} = \mathrm{ }constant

Option D is correct because, according to the distribution law, if the solute forms a trimer in the first liquid, the ratio of the concentration in the second liquid to the cube root of the concentration in the first liquid is constant:

{c_2}/\sqrt[3]{{{c_1}}} = constant

14 Hard

14 of 53

Understanding +4 | -1

We have three aqueous solutions of

\mathrm{NaCl}

labelled as (A), (B) and (C) with concentration of

0.1 \mathrm{~M}, 0.01 \mathrm{~M}

and

0.001 \mathrm{~M}

, respectively. The value of van't Hoff factor (i) of these solutions will be in order

View answer and explanation

Correct option: B

i_{\mathrm{A}} < i_{\mathrm{B}} < i_{\mathrm{C}}

Option B (

i_{\mathrm{A}} < i_{\mathrm{B}} < i_{\mathrm{C}}

) is correct. At higher concentrations, the interionic attractions are greater, leading to a lower degree of dissociation and a lower van't Hoff factor.

15 Hard

15 of 53

Analyzing +4 | -1

The ratio of concentration of

{NH}_3

{H}_2 {O}

to the concentration of

{NH}_3

{CHCl}_3

290 \mathrm{~K}

is 24 at any pressure. Through one litre of pure water ammonia gas was passed, the concentration of

{NH}_3

was measured to be

0.38 ({M})

. To this solution 0.025 moles of

{CuSO}_4

was added. In

{NH}_3

solution all

{Cu}^{2+}

ions form the complex

{Cu}\left({NH}_3\right)_x^{2+}

. Now over this solution one litre of

{CHCl}_3

was added, thoroughly shaken and equilibrated. In

{CHCl}_3

layer,

{Cu}\left({NH}_3\right)_x^{2+}

was absent but in

{CHCl}_3

the concentration of

{NH}_3

was reduced to

0.0112({M})

290 \mathrm{~K}

. Determine the value of

{x}

in nearest possible integers.

View answer and explanation

Correct option: A

Option A (4) is correct because the concentration of ammonia in water decreases after adding copper sulfate due to the formation of the complex, allowing us to calculate the number of ammonia molecules coordinated to copper.

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16 Hard

16 of 53

Understanding +4 | -1

Statement I: People living at high altitudes have symptoms of a condition known as anoxia.

Statement II: At high altitudes, the partial pressure of oxygen is less than that at the ground level.

View answer and explanation

Correct option: B

Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I.

Option B (Both statements are correct, but Statement II is not the correct explanation of Statement I) is correct. Anoxia is caused by a lack of oxygen, and the partial pressure of oxygen is indeed lower at high altitudes, but anoxia is a broader condition than just altitude sickness.

17 Hard

17 of 53

Application +4 | -1

Two liquids X and Y form an ideal solution. The mixture has a vapour pressure of 400 mm at 300 K when mixed in the molar ratio of 1:1 and a vapour pressure of 350 mm when mixed in the molar ratio of 1:2 at the same temperature. The vapour pressures of the two pure liquids X and Y respectively are

View answer and explanation

Correct option: D

550 mm, 250 mm

Option D (550 mm, 250 mm) is correct because it satisfies Raoult's law for ideal solutions with the given vapor pressures and molar ratios.

18 Hard

18 of 53

Analyzing +4 | -1

Assertion: There will not be any change in concentration of an ethanol and water mixture containing

85 \%

ethanol by volume on boiling.

Reason: It is because azeotropes boil out in constant composition.

View answer and explanation

Correct option: D

Assertion is wrong, but reason is correct statement.

The assertion is incorrect, but the reason is correct, making option D the correct answer. Azeotropes do boil at a constant composition, but an 85% ethanol mixture is not necessarily an azeotrope.

19 Hard

19 of 53

Application +4 | -1

The Henry’s law constant for the solubility of

{{N_2}}

gas in water at

298\;K

1.0 \times 105\;atm

. The mole fraction of

{{N_2}}

In air is 0.8 The number of moles of

{{N_2}}

from air dissolved in 10 moles of water of

298\;K

and 5 atm pressure is

View answer and explanation

Correct option: A

4 \times {10^{ - 4}}

Option A (

4 \times {10^{ - 4}}

) is correct because it is calculated using Henry's Law to find the mole fraction of N2 in water, and then using that to find the number of moles of N2.

20 Hard

20 of 53

Application +4 | -1

How many grams of dibasic acid

{\mathrm{mole}\mathrm{.wt}\mathrm{.200}}

should be present in

100\;mL

of the aqueous solution to give

{0.1\;N}

View answer and explanation

Correct option: D

1 g

Option D (1 g) is correct because it is the mass of the dibasic acid required to prepare the given solution, calculated using the normality formula.

21 Hard

21 of 53

Remembering +4 | -1

Scuba divers may experience a condition called To avoids this, the tanks used by scuba divers are filled with air diluted with

View answer and explanation

Correct option: D

Bends, Helium

Option D (Bends, Helium) is correct because scuba divers can experience 'the bends' and helium is used to dilute the air to prevent this.

22 Hard

22 of 53

Analyzing +4 | -1

\Delta T_f / K_f

has the same value of

1 \mathrm{~mol} \mathrm{~kg}^{-1}

for

8 \%

A B_2

and

10 \% A_2 B

by mass of solvent, both

A B_2

and

A_2 B

being non- electrolytes. Atomic masses of

A

and

B

will be respectively

View answer and explanation

Correct option: C

40,20

Option C is correct. By setting up equations based on the given information about

\Delta T_f / K_f

and solving for the atomic masses of A and B, we find that A = 40 and B = 20.

23 Hard

23 of 53

Application +4 | -1

At temperature

327^\circ C

and concentration C osmotic pressure of a solution is p, the same solutions at concentration C/2 and a temperature

427^\circ C

shows osmotic pressure 2 atm, value of p will be

View answer and explanation

Correct option: B

\frac{{24}}{7}

Option B (

\frac{{24}}{7}

) is correct because it is calculated using the osmotic pressure formula and the given conditions.

24 Hard

24 of 53

Analyzing +4 | -1

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): At

10^\circ C,

the density of a 5 M solution of

KCl

[atomic masses of

K\,\,\& \,\,Cl

are 39 & 35.5

g\,\,mo{l^{ - 1}}

respectively] is

'x'\,\,g\,\,m{l^{ - 1}}.

The solution is cooled to

- 21^\circ C.

The molality of the solution will remain unchanged.
Reason (R) : The molality of a solution does not change with temperature as mass remains unaffected with temperature.
In the light of the above statements, choose the correct answer from the options given below.

View answer and explanation

Correct option: A

Both (A) and (R) are true and (R) is the correct explanation of (A).

Option A is correct. Molality is defined as moles of solute per kilogram of solvent, which is independent of temperature because mass does not change with temperature. Therefore, both the assertion and reason are true, and the reason correctly explains the assertion.

25 Hard

25 of 53

Application +4 | -1

In which ratio of volume

0.4\mathrm{ }\;M\;\mathrm{ }HCl\;\mathrm{ }and\;\mathrm{ }0.9\;\mathrm{ }M\;\mathrm{ }HCl

are to be mixed such that the concentration of the resultant solution becomes 0.7 M ?

View answer and explanation

Correct option: B

2\mathrm{ }:\mathrm{ }3

Option B (

2\mathrm{ }:\mathrm{ }3

) is correct because it is the ratio of volumes calculated using the alligation method or a weighted average approach.

26 Hard

26 of 53

Understanding +4 | -1

On mixing

10 \mathrm{~mL}

of acetone with

40 \mathrm{~mL}

of chloroform, the total volume of the solution is :

View answer and explanation

Correct option: A

< 50 \mathrm{~mL}

Option A (< 50 mL) is correct because when acetone and chloroform are mixed, there's a decrease in volume due to intermolecular interactions.

27 Hard

27 of 53

Application +4 | -1

A solution of protein (extracted from crabs) was prepared by dissolving 0.75 g in

125\;\mathrm{c}{\mathrm{m}^3}

of an aqueous solution. At

4^\circ C

an osmotic pressure rise of 2.6 mm of the solution was observed. Then molecular weight of protein is : (Assume density of solution is

1.00\;g/\mathrm{c}{\mathrm{m}^3}

)

View answer and explanation

Correct option: B

5.4 \times {10^5}

Option B (

5.4 \times {10^5}

) is correct because the molecular weight of the protein is calculated using the osmotic pressure formula.

28 Hard

28 of 53

Analyzing +4 | -1

You are given 100 mL of

\mathrm{CC}{\mathrm{l}_4}

to extract iodine from 200 mL of its aqueous solution. For extracting maximum amount of iodine, which one of the following processes would you use?

View answer and explanation

Correct option: C

Use 10 mL of

\mathrm{CC}{\mathrm{l}_4}

10 times

Option C is correct because using smaller volumes of CCl4 multiple times is more efficient for extraction than using a larger volume at once, leading to a higher overall extraction of iodine.

29 Hard

29 of 53

Application +4 | -1

On shaking 10 mL of 0.1 molar solution of an organic compound in water with 10 mL of

\mathrm{CC}{\mathrm{l}_4}

til equilibrium is attained, concentration of the organic compound in water would be

(K = 9)

in molar units :

View answer and explanation

Correct option: A

0.01

Option A (0.01) is correct because it is the concentration of the organic compound in water after equilibrium, calculated using the partition coefficient.

30 Hard

30 of 53

Understanding +4 | -1

Iodine was added to a system of water and

\mathrm{C}{\mathrm{S}_2}

. The concentrations of iodine in water and

\mathrm{C}{\mathrm{S}_2}

were found to be

{c_1}\;and\;{c_2}

respectively. The ratio

{c_1}/{c_2}

will not change only if :

View answer and explanation

Correct option: A

More iodine is added

Option A (More iodine is added) is correct because the distribution coefficient (c1/c2) is constant at a given temperature and is independent of the amount of solute added.

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