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NEET • CHEMISTRY • SOLUTIONS

Solutions practice · Hard

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Showing 31-53 of 53 questions
31 Hard
31 of 53
Analyzing +4 | -1
At 35∘C35^\circ \mathrm{C}, the vapour pressure of CS2C{S_2} is 512 mm Hg and that of acetone is 344 mm Hg. A solution of CS2C{S_2} in acetone has a total vapour pressure of 600 mm Hg. The false statement amongst the following is
View answer and explanation
Correct option: C
a mixture of 100 mL CS2C{S_2} and 100 mL acetone has a volume < 200 mL
Option C (a mixture of 100 mL CS2C{S_2} and 100 mL acetone has a volume < 200 mL) is correct because the total vapor pressure is higher than predicted by Raoult's law, indicating positive deviation, which means the volume of mixing is greater than the sum of individual volumes.
32 Hard
32 of 53
Understanding +4 | -1
Which of the aqueous equimolal solution will have its vapour pressure near to solvent?
View answer and explanation
Correct option: A
Urea
Option A (Urea) is correct because it is a non-electrolyte and does not dissociate in water, resulting in the smallest change in vapor pressure compared to the solvent.
33 Hard
33 of 53
Understanding +4 | -1
The size of a raw mango shrinks to a much smaller size when kept in a concentrated salt solution. Which one of the following processes can explain this?
View answer and explanation
Correct option: A
Osmosis
Option A (Osmosis) is correct because osmosis explains the movement of water from the mango into the concentrated salt solution, causing it to shrink.
34 Hard
34 of 53
Understanding +4 | -1
The solution that forms maximum boiling azeotrope is
View answer and explanation
Correct option: A
acetone - chloroform
Option A (acetone - chloroform) is correct because it forms a maximum boiling azeotrope due to hydrogen bonding between acetone and chloroform, leading to negative deviations from Raoult's law.
35 Hard
35 of 53
Analyzing +4 | -1
Evaluate the following statements for their correctness.
A. The elevation in boiling point temperature of water will be same for 0.1 M NaCl0.1 \,\mathrm{M}\, \mathrm{NaCl} and 0.1 M0.1 \,\mathrm{M} urea
B. Azeotropic mixture boil without change in their composition.
C. Osmosis always takes place from hypertonic to hypotonic solution.
D. The density of 32%32\% H2SO4H_2S{O_4} solution having molarity 4.09 M is approximately 1.26 g mL–1.1.26 \,g \,mL^{–1}.
E. A negatively charged sol is obtained when KI\mathrm{KI} solution is added to silver nitrate solution.
Choose the correct answer from the options given below.
View answer and explanation
Correct option: D
B and D only
Options B and D are correct. Azeotropic mixtures do boil without changing composition, and the density of the H2SO4 solution is approximately 1.26 g/mL. The other statements are incorrect.
36 Hard
36 of 53
Application +4 | -1
20  g20\;g of binary electrolyte (mol. wt. =100) are dissolved in 500  g500\;g of water. The depression in freezing point of the solution is 0.74∘C  (kf=1.86  Km−1)0.74^\circ C\;({k_f} = 1.86\;K{m^{ - 1}}) the degree of ionisation of the electrolyte is
View answer and explanation
Correct option: A
0%0\%
Option D is incorrect. The correct answer is 75%. The degree of ionization is calculated using the van't Hoff factor and the freezing point depression.
37 Hard
37 of 53
Analyzing +4 | -1
Liquid MM and liquid NN form an ideal solution. The vapour pressures of pure liquids MM and NN are 450 and 700 mmHg, respectively, at the same temperature. Then correct statement is
xM={x_M} = mole fraction of MM in solution;            xN=\,\,\,\,\,\,\,\,\,\,\,{x_N} = mole fraction of NN in solution;
yM={y_M} = mole fraction of MM in vapour phase;               yN=\,\,\,\,\,\,\,\,\,\,\,\,\,\,{y_N} = mole fraction of NN in vapour phase;
View answer and explanation
Correct option: A
xMxN>yMyN\frac{{{x_M}}}{{{x_N}}} > \frac{{{y_M}}}{{{y_N}}}
Option A (xMxN>yMyN\frac{{{x_M}}}{{{x_N}}} > \frac{{{y_M}}}{{{y_N}}}) is correct because liquid N has a higher vapor pressure than liquid M, so it will have a higher mole fraction in the vapor phase relative to the liquid phase.
38 Hard
38 of 53
Remembering +4 | -1
Solution of azeotropic nitric acid mixture contain
View answer and explanation
Correct option: B
68% HNO3,32% H2O68 \% \mathrm{~HNO}_3, 32 \% \mathrm{~H}_2 \mathrm{O} by mass
Option B (68% HNO3,32% H2O68 \% \mathrm{~HNO}_3, 32 \% \mathrm{~H}_2 \mathrm{O} by mass) is correct because the azeotropic mixture of nitric acid and water contains approximately 68% nitric acid by mass.
39 Hard
39 of 53
Analyzing +4 | -1
Statement I: When urea is added to water, boiling point of water increases.

Statement II: When a volatile solute is added to a volatile solvent, elevation in boiling point is observed.
View answer and explanation
Correct option: C
Statement I is correct but Statement II is incorrect.
Statement I is correct, and Statement II is incorrect, making option C the correct answer. Urea is a non-volatile solute, and volatile solutes lower the boiling point.
40 Hard
40 of 53
Analyzing +4 | -1
A current of dry air was passed through a series of bulbs containing 1.25 g1.25 \mathrm{~g} of a solute A2B\mathrm{A}_2 \mathrm{B} (molar mass =90 g/mol=90 \mathrm{~g} / \mathrm{mol}) in 49 g49 \mathrm{~g} of water and then through pure water. The loss in weight of the former series of bulbs was 0.98 g0.98 \mathrm{~g} and in the later series 0.01 g.0.01 \mathrm{~g}. The percentage dissociation of solute is
View answer and explanation
Correct option: A
50%50 \%
Option A (50 %) is correct because the percentage dissociation is calculated by comparing the observed and theoretical colligative properties.
41 Hard
41 of 53
Application +4 | -1
The freezing point (in  ∘C)(in\;^\circ C) of a solution containing 0.1  g  of  K3[Fe(CN)6]0.1\;g\;of\;{\mathrm{K}_3}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right] (mol.wt.329) in 100 g of water is : (Kf=1.86  K  kg  mol−1)({K_f} = 1.86\;K\;\mathrm{kg}\;\mathrm{mo}{\mathrm{l}^{ - 1}})
View answer and explanation
Correct option: A
−2.3×10−2- 2.3 \times {10^{ - 2}}
Option A (−2.3×10−2- 2.3 \times {10^{ - 2}}) is correct because it is the calculated freezing point depression using the colligative properties formula, van't Hoff factor, and given constants.
42 Hard
42 of 53
Application +4 | -1
A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and C. The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of A = 100 g  mol−1;g\,\,mo{l^{ - 1}}; B=200  g mol−1 ;  C=10,000  g  mol−1]B = 200\,\,g\,mo{l^{ - 1}}\,;\,\,C = 10,000\,\,g\,\,mo{l^{ - 1}}]
View answer and explanation
Correct option: C
A>B>CA > B > C
Option C (A>B>CA > B > C) is correct because the relative lowering of vapor pressure is a colligative property that depends on the number of moles of solute, and A has the most moles for the same mass.
43 Hard
43 of 53
Application +4 | -1
K2HgI4{K_2}Hg{I_4} is 40% ionized in aqueous solution. The value of its van’t Hoff factor (i)(i) is
View answer and explanation
Correct option: B
1.8
Option B (1.8) is correct because the van't Hoff factor is calculated based on the ionization of K2HgI4 into ions.
44 Hard
44 of 53
Application +4 | -1
The K for I2{\mathrm{I}_2} between CS2\mathrm{C}{\mathrm{S}_2} and H2O{\mathrm{H}_2}\mathrm{O} is 588 in favour of CS2\mathrm{C}{\mathrm{S}_2}. One litre of aqueous solution containing 1 g of I2{\mathrm{I}_2} is shaken with 50 mL of CS2\mathrm{C}{\mathrm{S}_2}. What will be the amount of I2{\mathrm{I}_2} in aqueous layer?
View answer and explanation
Correct option: A
0.035  g0.035\;\mathrm{ }g
Option A (0.035  g0.035\;\mathrm{ }g) is correct because it is calculated by using the partition coefficient to determine the amount of iodine remaining in the aqueous layer after extraction.
45 Hard
45 of 53
Application +4 | -1
Kf{{K_f}} for water is 1.86  K  kg  mol−1{1.86\;K\;kg\;\mathrm{mo}{\mathrm{l}^{ - 1}}}. If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C2H6O2)\left( {{\mathrm{C}_2}{\mathrm{H}_6}{\mathrm{O}_2}} \right) must you add to get the freezing point of the solution lowered to −2.8∘C\mathrm{ - 2}\mathrm{.8}^\circ \mathrm{C}?
View answer and explanation
Correct option: A
93 g
Option A (93 g) is correct because it is the calculated mass of ethylene glycol needed to lower the freezing point to -2.8°C, considering the Kf value and the mass of water.
46 Hard
46 of 53
Understanding +4 | -1
Which of the following statements is true about bends?
View answer and explanation
Correct option: D
Both (1) and (2) are true
Option D (Both (1) and (2) are true) is correct because bends, or decompression sickness, involve the formation of gas bubbles in the bloodstream, which can block capillaries and cause pain and be life-threatening.
47 Hard
47 of 53
Analyzing +4 | -1
Assume a living cell with 0.9%(ω/ω)0.9 \%(\omega / \omega) of glucose solution (aqueous). This cell is immersed in another solution having equal mole fraction of glucose and water.

(Consider the data upto first decimal place only)

The cell will:
View answer and explanation
Correct option: D
show no change in volume since solution is 0.9%(ω/ω)0.9 \%(\omega / \omega)
Option D is correct because if the cell is immersed in a solution with an equal mole fraction of glucose and water that results in a 0.9% (w/w) glucose solution, there will be no net movement of water, and the cell volume will remain unchanged.
48 Hard
48 of 53
Remembering +4 | -1
The relationship which describes the variation of vapour pressure of a liquid with temperature is called :
View answer and explanation
Correct option: B
Clausius Clapeyron equation
Option B (Clausius Clapeyron equation) is correct because the Clausius-Clapeyron equation describes the relationship between vapor pressure and temperature.
49 Hard
49 of 53
Understanding +4 | -1
Assertion (A): Experimentally determined molar mass is always lower than the true value.

Reason (R): Lower molar mass is due to dissociation of solute into ions.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct, R\mathrm{R} is the correct explanation of A\mathrm{A}.
Option A (Both A and R are correct, and R is the correct explanation of A) is correct. Dissociation increases the number of particles in solution, leading to a lower observed molar mass.
50 Hard
50 of 53
Analyzing +4 | -1
The freezing point of an aqueous solution of KCN{KCN} containing 0.2 mole/kg water was −0.8∘C-0.8^{\circ} \mathrm{C}. On addition of 0.1 mole of Hg(CN)2{Hg}({CN})_2 in the solution containing 1 kg of water, the freezing point of the solution was −0.6∘C-0.6^{\circ} \mathrm{C}. Assuming that the complex is formed according to the following equation:
Hg(CN)2+mCN−⟶Hg(CN)m+2−m{Hg}({CN})_2+{mCN}^{-} \longrightarrow {Hg}({CN})_{{m}+2}^{-{m}} and Hg(CN)2{Hg}({CN})_2 is the limiting reagent, the value of 4 m4 \mathrm{~m} is:
View answer and explanation
Correct option: A
8
Option A (8) is correct because the freezing point depression indicates the formation of a complex ion with 2 additional cyanide ions, thus m=2 and 4m=8.
51 Hard
51 of 53
Application +4 | -1
At certain temperature a 5.12% solution of cane sugar is isotonic with a 0.9% solution of an unknown solute. The molar mass of solute is
View answer and explanation
Correct option: A
60
Option A (60) is correct because it is the calculated molar mass of the unknown solute using the isotonic condition.
52 Hard
52 of 53
Application +4 | -1
1 mole of heptane (V.P = 92 mm of Hg) was mixed with 4 moles of octane (V.P = 31 mm of Hg). The V.P of resulting ideal solution is
View answer and explanation
Correct option: C
43.2 mm of Hg
Option C (43.2 mm of Hg) is correct because it is calculated using Raoult's law for ideal solutions, considering the mole fractions and vapor pressures of each component.
53 Hard
53 of 53
Understanding +4 | -1
The degree of dissociation (α)(\alpha) of a week electrolyte, A2SO4\mathrm{A}_2 \mathrm{SO}_4 is related to Vant Hoff factor (i) by the expression
View answer and explanation
Correct option: A
i=1+2α\mathrm{i}=1+2 \alpha
Option A (i = 1 + 2α) is correct because A₂SO₄ dissociates into 3 ions (2A⁺ and SO₄²⁻), so i = 1 + (n-1)α = 1 + (3-1)α = 1 + 2α.
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