A mixture of ethane and ethene occupies 41 L at 1 atm and $500\;K$. the mixture reacts completely with $\;\frac{{10}}{3}$ mole of ${O_2}$ to produce $C{O_2}\,and\;{H_2}{\rm{O}}$. The mole fraction of ethane and ethene in the mixture are $\left( {R = 0.082\;L\;{\rm{atm}}\;{{\rm{K}}^{ - 1}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}} \right)$ respectively

NEET UG CHEMISTRY MCQ: SOLUTIONS

1 Hard

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Application +4 | -1

A mixture of ethane and ethene occupies 41 L at 1 atm and

500\;K

. the mixture reacts completely with

\;\frac{{10}}{3}

mole of

{O_2}

to produce

C{O_2}\,and\;{H_2}\mathrm{O}

. The mole fraction of ethane and ethene in the mixture are

\left( {R = 0.082\;L\;\mathrm{atm}\;{\mathrm{K}^{ - 1}}\;\mathrm{mo}{\mathrm{l}^{ - 1}}} \right)

respectively

View answer and explanation

Correct option: C

0.67,\mathrm{ }0.33

Option C (

0.67,\mathrm{ }0.33

) is correct because it represents the mole fractions of ethane and ethene calculated from the given reaction and conditions using the ideal gas law.

Practice All Chapter MCQs →

0.52\,K\,kg\,mo{l^{ - 1}}

A

B

B

A

B

--{0.93^0}C

{K_f}

1.86\mathrm{ }K\mathrm{ }kg\mathrm{ }mo{l^{ - 1}}