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NEET • CHEMISTRY • SOLUTIONS

Solutions practice · Mixed difficulty

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Showing 151-180 of 226 questions

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151 Easy
151 of 226
Understanding +4 | -1
Solvent is the component of a solution
View answer and explanation
Correct option: D
Both (1) and (3 )
Option D (Both (1) and (3 )) is correct because the solvent is present in large excess and determines the physical state of the solution.
152 Medium
152 of 226
Remembering +4 | -1
The exact mathematical expression of Raoult's law is (n=n= moles of non-volatile solute, N=N= moles of solvent, P=P= V.P. of solution & P0=P^{0}= V.P. of pure solvent)
View answer and explanation
Correct option: A
P0−PP0=nN\frac{{P}^0-{P}}{P^0}=\frac{{n}}{{N}}
Option A (P0−PP0=nN\frac{{P}^0-{P}}{P^0}=\frac{{n}}{{N}}) is correct because it represents the correct mathematical expression of Raoult's law for non-volatile solutes.
153 Medium
153 of 226
Understanding +4 | -1
The degree of dissociation (α)(\alpha ) of a weak electrolyte , AxBy{A_x}{B_y} is related to van’t Hoff factor (i) by the expression
View answer and explanation
Correct option: A
α=i−1(x+y−1)\alpha = \frac{{i - 1}}{{\left( {x + y - 1} \right)}}
Option A is correct because it correctly relates the degree of dissociation to the van't Hoff factor for a weak electrolyte.
154 Medium
154 of 226
Analyzing +4 | -1
Assertion (A): Azeotropic mixtures are formed only by non-ideal solutions.

Reason (R): The composition of the vapour phase is same as that of the liquid phase of an azeotropic mixture.
View answer and explanation
Correct option: B
Both A & R are true, R is not correct explanation of A
Option B (Both A & R are true, R is not correct explanation of A) is correct because azeotropic mixtures are indeed formed by non-ideal solutions, and the vapor phase composition is the same as the liquid phase, but the latter doesn't explain the former.
155 Medium
155 of 226
Analyzing +4 | -1
Statement I: Molarity of a solution is always greater than that of molality.

Statement II: Ratio of molarity and molality depends on density of solvent.
View answer and explanation
Correct option: D
If Statement I is false but Statement II is correct
Option D is correct because Statement I is false (molarity is not always greater than molality) and Statement II is correct (the ratio of molarity and molality depends on the density of the solvent).
156 Easy
156 of 226
Analyzing +4 | -1
Assertion (A) Osmotic pressure of 0.1  N0.1\, {~N} urea solution is less than that of 0.1 M NaCl0.1 \,{M}\,{NaCl} solution.

Reason (R) Osmotic pressure is not a colligative property.
View answer and explanation
Correct option: C
If Assertion is true but Reason is false.
Option C (Assertion is true but Reason is false) is correct because osmotic pressure is a colligative property, and the osmotic pressure of 0.1 N urea is less than that of 0.1 M NaCl.
157 Medium
157 of 226
Remembering +4 | -1
Relation between partial pressure and mole fraction is stated by
View answer and explanation
Correct option: B
Raoult's law
Option B (Raoult's law) is correct because it relates partial pressure and mole fraction in ideal solutions.
158 Medium
158 of 226
Remembering +4 | -1
A solution which boils at constant temperature is called:
View answer and explanation
Correct option: A
Azeotrope
A solution that boils at a constant temperature is called an azeotrope, making option A the correct answer. Azeotropes are mixtures with a fixed boiling point.
159 Easy
159 of 226
Remembering +4 | -1
The elevation in boiling point for one molal solution of a solute in a solvent is called :
View answer and explanation
Correct option: C
Molal ebullioscopic constant
Option C (Molal ebullioscopic constant) is correct because it is the elevation in boiling point for a one molal solution.
160 Easy
160 of 226
Understanding +4 | -1
Which statement is wrong for distribution law?
View answer and explanation
Correct option: D
The concentration of the solute in both the solvents must be kept high
Option D (The concentration of the solute in both the solvents must be kept high) is wrong because the distribution law is most accurate at low solute concentrations.
161 Medium
161 of 226
Understanding +4 | -1
One component of a solution follows Raoult’s law over the entire range 0≤x1≤10 \le {x_1} \le 1 . The second component must follow Raoult’s law in the range when x2{x_2} is
View answer and explanation
Correct option: D
0≤x2≤10 \le {x_2} \le 1
Option D (0≤x2≤10 \le {x_2} \le 1) is correct because if one component follows Raoult's law over the entire range, the other component must also follow Raoult's law over the entire range for the solution to be ideal.
162 Easy
162 of 226
Remembering +4 | -1
According to the classification based on the physical states of dispersed phase and dispersion medium. There are how many types of colloidal sols possible?
View answer and explanation
Correct option: A
8
Option A (8) is correct because there are 8 possible combinations of dispersed phase (solid, liquid, gas) and dispersion medium (solid, liquid, gas), excluding gas in gas.
163 Hard
163 of 226
Remembering +4 | -1
Solution of azeotropic nitric acid mixture contain
View answer and explanation
Correct option: B
68% HNO3,32% H2O68 \% \mathrm{~HNO}_3, 32 \% \mathrm{~H}_2 \mathrm{O} by mass
Option B (68% HNO3,32% H2O68 \% \mathrm{~HNO}_3, 32 \% \mathrm{~H}_2 \mathrm{O} by mass) is correct because the azeotropic mixture of nitric acid and water contains approximately 68% nitric acid by mass.
164 Medium
164 of 226
Analyzing +4 | -1
Total vapour pressure of mixture of 1 mol of volatile
Component A (PAo=100  mm Hg)\left( {P_A^\mathrm{o} = 100\,\,mm\,Hg} \right) and 3 mol of volatile
Component B (PBo=80  mm Hg)\left( {P_B^\mathrm{o} = 80\,\,mm\,Hg} \right) is 90 mm Hg, for such case:
View answer and explanation
Correct option: D
All the above statements are correct
Option D (All the above statements are correct) is correct because the total vapor pressure is less than expected from Raoult's law, indicating negative deviation, which lowers the boiling point and implies weaker A-B interactions.
165 Easy
165 of 226
Understanding +4 | -1
A solution containing components AA and BB follows Raoult’s law
View answer and explanation
Correct option: C
A−BA - B attraction force remains same as A−AA - A and B−BB - B
Option C (A−BA - B attraction force remains same as A−AA - A and B−BB - B) is correct because this is the condition for a solution to follow Raoult's law.
166 Hard
166 of 226
Analyzing +4 | -1
Statement I: When urea is added to water, boiling point of water increases.

Statement II: When a volatile solute is added to a volatile solvent, elevation in boiling point is observed.
View answer and explanation
Correct option: C
Statement I is correct but Statement II is incorrect.
Statement I is correct, and Statement II is incorrect, making option C the correct answer. Urea is a non-volatile solute, and volatile solutes lower the boiling point.
167 Easy
167 of 226
Understanding +4 | -1
An example of a solution having liquid in gas is:
View answer and explanation
Correct option: A
Moist air
Option A (Moist air) is correct because it contains water (liquid) dispersed in air (gas).
168 Medium
168 of 226
Analyzing +4 | -1
Assertion: The molarity of a solution depends on the temperature of the solvent.

Reason: Molarity is defined as the number of moles of solute per litre of solution, and the volume of the solvent changes with temperature.
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
Option B is correct because both the assertion and reason are true, but the reason explains the effect of temperature on volume, not the fundamental definition of molarity.
169 Hard
169 of 226
Analyzing +4 | -1
A current of dry air was passed through a series of bulbs containing 1.25 g1.25 \mathrm{~g} of a solute A2B\mathrm{A}_2 \mathrm{B} (molar mass =90 g/mol=90 \mathrm{~g} / \mathrm{mol}) in 49 g49 \mathrm{~g} of water and then through pure water. The loss in weight of the former series of bulbs was 0.98 g0.98 \mathrm{~g} and in the later series 0.01 g.0.01 \mathrm{~g}. The percentage dissociation of solute is
View answer and explanation
Correct option: A
50%50 \%
Option A (50 %) is correct because the percentage dissociation is calculated by comparing the observed and theoretical colligative properties.
170 Hard
170 of 226
Application +4 | -1
The freezing point (in  ∘C)(in\;^\circ C) of a solution containing 0.1  g  of  K3[Fe(CN)6]0.1\;g\;of\;{\mathrm{K}_3}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right] (mol.wt.329) in 100 g of water is : (Kf=1.86  K  kg  mol−1)({K_f} = 1.86\;K\;\mathrm{kg}\;\mathrm{mo}{\mathrm{l}^{ - 1}})
View answer and explanation
Correct option: A
−2.3×10−2- 2.3 \times {10^{ - 2}}
Option A (−2.3×10−2- 2.3 \times {10^{ - 2}}) is correct because it is the calculated freezing point depression using the colligative properties formula, van't Hoff factor, and given constants.
171 Medium
171 of 226
Understanding +4 | -1
The van’t Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is
View answer and explanation
Correct option: A
3
Option A is correct because barium hydroxide, being a strong electrolyte, dissociates into three ions in solution.
172 Hard
172 of 226
Application +4 | -1
A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and C. The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of A = 100 g  mol−1;g\,\,mo{l^{ - 1}}; B=200  g mol−1 ;  C=10,000  g  mol−1]B = 200\,\,g\,mo{l^{ - 1}}\,;\,\,C = 10,000\,\,g\,\,mo{l^{ - 1}}]
View answer and explanation
Correct option: C
A>B>CA > B > C
Option C (A>B>CA > B > C) is correct because the relative lowering of vapor pressure is a colligative property that depends on the number of moles of solute, and A has the most moles for the same mass.
173 Hard
173 of 226
Application +4 | -1
K2HgI4{K_2}Hg{I_4} is 40% ionized in aqueous solution. The value of its van’t Hoff factor (i)(i) is
View answer and explanation
Correct option: B
1.8
Option B (1.8) is correct because the van't Hoff factor is calculated based on the ionization of K2HgI4 into ions.
174 Medium
174 of 226
Analyzing +4 | -1
Henry’s constant (in kbar) for four gases α\alpha, β\beta, γ\gamma and δ\delta in water at 298 K is given below:
αβγδKH5022×10−50.5\begin{array}{cccccccccccccccccccc} {}&\alpha &\beta &\gamma &\delta \\ {{K_H}}&{50}&2&{2 \times {{10}^{ - 5}}}&{0.5} \end{array}
(density of water =103 kg m−3= {10^3}\,kg\,{m^{ - 3}} at 298 K)
This implies that
View answer and explanation
Correct option: D
The pressure of a 55.5 molal solution of δ\delta is 250 bar
Option D is correct because according to Henry's law, the partial pressure of a gas is proportional to its mole fraction in the solution. Using the given Henry's constant for δ and the molality, we can calculate the pressure, which is approximately 250 kbar.
175 Easy
175 of 226
Understanding +4 | -1
Camphor is used as solvent to determine mol. wt. of non-volatile solute by Rast method because for camphor :
View answer and explanation
Correct option: C
Molal depression constant is high
Camphor has a high molal depression constant, which leads to a significant depression in freezing point even for small amounts of solute, making option C the correct answer. This makes it suitable for determining the molecular weight of non-volatile solutes using the Rast method.
176 Medium
176 of 226
Understanding +4 | -1
The degree of dissociation '∝\propto' of a weak electrolyte is
View answer and explanation
Correct option: A
i−1n−1\frac{{i - 1}}{{n - 1}}
Option A is correct because the degree of dissociation is related to the van't Hoff factor and the number of ions produced.
177 Medium
177 of 226
Remembering +4 | -1
Molal depression constant is given by the expression:
View answer and explanation
Correct option: D
ΔTfm\frac{{\Delta {T_f}}}{m}
Option D is correct because the molal depression constant (KfK_f) is calculated by dividing the freezing point depression (ΔTf\Delta T_f) by the molality (m).
178 Easy
178 of 226
Application +4 | -1
XX is dissolved in water. Maximum boiling point is observed when XX is ….(0.1  M0.1\;M each)
View answer and explanation
Correct option: B
BaCl2BaC{l_2}
Option B (BaCl2BaC{l_2}) is correct because it dissociates into 3 ions, resulting in the highest van't Hoff factor and thus the maximum boiling point elevation.
179 Medium
179 of 226
Understanding +4 | -1
The condition for the validity of Henry’s law are :
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because all the listed conditions are necessary for Henry's law to be valid.
180 Medium
180 of 226
Application +4 | -1
Vapour pressure of dilute aqueous solution of glucose is 750  mm750\;mm of mercury at 373  K373\;K. The mole fraction of solute is
View answer and explanation
Correct option: A
176\frac{1}{{76}}
Option A (176\frac{1}{{76}}) is correct because it is calculated using Raoult's Law and the definition of mole fraction.
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