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NEET • CHEMISTRY • SOLUTIONS

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Showing 181-210 of 226 questions

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181 Hard
181 of 226
Application +4 | -1
The K for I2{\mathrm{I}_2} between CS2\mathrm{C}{\mathrm{S}_2} and H2O{\mathrm{H}_2}\mathrm{O} is 588 in favour of CS2\mathrm{C}{\mathrm{S}_2}. One litre of aqueous solution containing 1 g of I2{\mathrm{I}_2} is shaken with 50 mL of CS2\mathrm{C}{\mathrm{S}_2}. What will be the amount of I2{\mathrm{I}_2} in aqueous layer?
View answer and explanation
Correct option: A
0.035  g0.035\;\mathrm{ }g
Option A (0.035  g0.035\;\mathrm{ }g) is correct because it is calculated by using the partition coefficient to determine the amount of iodine remaining in the aqueous layer after extraction.
182 Medium
182 of 226
Understanding +4 | -1
On mixing 10 mL10\,mL of carbon tetrachloride with 10 mL10\,mL of benzene the total volume of the solution is:
View answer and explanation
Correct option: C
= 20 mL
Option C (= 20 mL) is correct because when mixing carbon tetrachloride and benzene, which are non-polar liquids, the solution formed is nearly ideal, resulting in no significant volume change.
183 Easy
183 of 226
Application +4 | -1
What is the molality of ethyl alcohol (mol. wt. = 416) in aqueous solution which freezes at −10∘C?.  (Kf  for  water=1.86  K  molality−1)- 10^\circ \mathrm{C}?.\;\left( {{K_f}\;\mathrm{for}\;\mathrm{ water} = 1.86\;\mathrm{K}\;\mathrm{ molalit}{\mathrm{y}^{ - 1}}} \right)
View answer and explanation
Correct option: C
5.3765.376
Option C is correct because the molality is calculated using the formula ΔTf=Kf×m\Delta T_f = K_f \times m, where ΔTf\Delta T_f is the freezing point depression, KfK_f is the cryoscopic constant, and m is the molality.
184 Hard
184 of 226
Application +4 | -1
Kf{{K_f}} for water is 1.86  K  kg  mol−1{1.86\;K\;kg\;\mathrm{mo}{\mathrm{l}^{ - 1}}}. If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C2H6O2)\left( {{\mathrm{C}_2}{\mathrm{H}_6}{\mathrm{O}_2}} \right) must you add to get the freezing point of the solution lowered to −2.8∘C\mathrm{ - 2}\mathrm{.8}^\circ \mathrm{C}?
View answer and explanation
Correct option: A
93 g
Option A (93 g) is correct because it is the calculated mass of ethylene glycol needed to lower the freezing point to -2.8°C, considering the Kf value and the mass of water.
185 Easy
185 of 226
Analyzing +4 | -1
Which of the following statements is false?
View answer and explanation
Correct option: A
Two sucrose solution of same molality prepared in different solvent will have the same freezing point depression
Option A is false because freezing point depression depends on the solvent's cryoscopic constant (KfK_f), which varies with the solvent.
186 Medium
186 of 226
Remembering +4 | -1
Two solutions of different osmotic pressure. The solution of lower osmotic pressure is called
View answer and explanation
Correct option: C
Hypotonic
Option C (Hypotonic) is correct because a hypotonic solution has a lower osmotic pressure compared to another solution.
187 Hard
187 of 226
Understanding +4 | -1
Which of the following statements is true about bends?
View answer and explanation
Correct option: D
Both (1) and (2) are true
Option D (Both (1) and (2) are true) is correct because bends, or decompression sickness, involve the formation of gas bubbles in the bloodstream, which can block capillaries and cause pain and be life-threatening.
188 Medium
188 of 226
Analyzing +4 | -1
Assertion (A): Van't Hoff factor for benzoic acid in aqueous medium is 2 assuming complete ionisation.

Reason (R): Van't Hoff factor for 100%100 \% ionised solute equal to the number of ions produced.
View answer and explanation
Correct option: A
Both A & R are true, R is the correct explanation of A
Option D is correct because the assertion is false as benzoic acid associates in aqueous medium, not ionizes, and the reason is true.
189 Medium
189 of 226
Application +4 | -1
18g glucose (C6H22O6)\left( {{C_6}{H_{22}}{O_6}} \right) is added to 178.2 g water. The vapor pressure of water (in torr) for this aqueous solution is.
View answer and explanation
Correct option: B
752.4752.4
Option B (752.4) is correct because it is calculated using Raoult's Law, which relates vapor pressure lowering to the mole fraction of the solute.
190 Medium
190 of 226
Understanding +4 | -1
Which one of the following electrolyte has the same value of the vant Hoff factor (i) as that of A2(SO4)3{A_2}{\left( {S{O_4}} \right)_3} (if all are 100% ionised)
View answer and explanation
Correct option: D
K4[Fe(CN)6]{K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]
Option D is correct because both A2(SO4)3{A_2}{\left( {S{O_4}} \right)_3} and K4[Fe(CN)6]{K_4}{\left[ {Fe{{\left( {CN} \right)}_6}} \right]} dissociate into 5 ions.
191 Medium
191 of 226
Remembering +4 | -1
Which is correct representation of phase rule?
View answer and explanation
Correct option: B
F+P=C+2F + P = C + 2
Option B (F+P=C+2F + P = C + 2) is correct because it represents the Gibbs phase rule, where F is the degrees of freedom, P is the number of phases, and C is the number of components.
192 Hard
192 of 226
Analyzing +4 | -1
Assume a living cell with 0.9%(ω/ω)0.9 \%(\omega / \omega) of glucose solution (aqueous). This cell is immersed in another solution having equal mole fraction of glucose and water.

(Consider the data upto first decimal place only)

The cell will:
View answer and explanation
Correct option: D
show no change in volume since solution is 0.9%(ω/ω)0.9 \%(\omega / \omega)
Option D is correct because if the cell is immersed in a solution with an equal mole fraction of glucose and water that results in a 0.9% (w/w) glucose solution, there will be no net movement of water, and the cell volume will remain unchanged.
193 Easy
193 of 226
Application +4 | -1
One mole of non-volatile solute is dissolved in two mole of water. The vapour pressure of the solution relative to that of water is :
View answer and explanation
Correct option: A
2/32/3
Option A (2/32/3) is correct because the relative vapor pressure is calculated using Raoult's Law, considering the mole fractions of the solute and solvent.
194 Easy
194 of 226
Understanding +4 | -1
Vapour pressure of a solvent containing non-volatile solute is :
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Correct option: B
Less than the vapour pressure of solvent
The vapor pressure of a solvent is lowered when a non-volatile solute is added, making option B the correct answer. This is due to fewer solvent molecules being able to escape into the vapor phase.
195 Easy
195 of 226
Understanding +4 | -1
If the temperature increase from 0∘C  to  50∘C  0^\circ C\;to\;50^\circ C\; at atmospheric pressure, which of the following processes is expected to take place more in case of liquids?
View answer and explanation
Correct option: B
Vaporization
Option B (Vaporization) is correct because increasing the temperature favors the phase transition from liquid to gas, which is vaporization.
196 Easy
196 of 226
Remembering +4 | -1
The natural semipermeable membrane is :
View answer and explanation
Correct option: C
Plant cell
Plant cells act as natural semipermeable membranes, allowing water and small molecules to pass through while restricting larger molecules, making option C the correct answer.
197 Medium
197 of 226
Analyzing +4 | -1
Which of the given solutions has highest osmotic pressure?
View answer and explanation
Correct option: A
1  N  NaNO31\;N\;\mathrm{NaN}{\mathrm{O}_3}
Option A (1  N  NaNO31\;N\;\mathrm{NaN}{\mathrm{O}_3}) is correct because, at the same normality, it has the lowest van't Hoff factor compared to the other options, which have higher numbers of ions upon dissociation.
198 Easy
198 of 226
Application +4 | -1
A solution containing 10 g per dm3{\mathrm{d}{\mathrm{m}^3}} of urea (mol. mass = 60) is isotonic with a 5% (wt.by vol.) solution of a non-volatile solute. The molecular mass (in g  mol−1\mathrm{g}\;\mathrm{mo}{\mathrm{l}^{ - 1}}) of non-volatile solute is :
View answer and explanation
Correct option: D
300
Option D (300) is correct because it is calculated by equating the osmotic pressures of the urea solution and the non-volatile solute solution.
199 Easy
199 of 226
Remembering +4 | -1
Colligative properties are used for the determination of
View answer and explanation
Correct option: A
Molar mass
Option A (Molar mass) is correct because colligative properties directly relate to the number of solute particles, which is used to determine molar mass.
200 Hard
200 of 226
Remembering +4 | -1
The relationship which describes the variation of vapour pressure of a liquid with temperature is called :
View answer and explanation
Correct option: B
Clausius Clapeyron equation
Option B (Clausius Clapeyron equation) is correct because the Clausius-Clapeyron equation describes the relationship between vapor pressure and temperature.
201 Medium
201 of 226
Understanding +4 | -1
What happen at increasing pressure at constant temperature
View answer and explanation
Correct option: B
Solubility of gas increase in liquid
Option B (Solubility of gas increase in liquid) is correct because, according to Henry's Law, the solubility of a gas in a liquid increases with increasing pressure at constant temperature.
202 Hard
202 of 226
Understanding +4 | -1
Assertion (A): Experimentally determined molar mass is always lower than the true value.

Reason (R): Lower molar mass is due to dissociation of solute into ions.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct, R\mathrm{R} is the correct explanation of A\mathrm{A}.
Option A (Both A and R are correct, and R is the correct explanation of A) is correct. Dissociation increases the number of particles in solution, leading to a lower observed molar mass.
203 Easy
203 of 226
Remembering +4 | -1
The energy that opposes the dissolution of a solute in a solvent is called :
View answer and explanation
Correct option: C
Lattice energy
Option C (Lattice energy) is correct because lattice energy is the energy that opposes the dissolution of a solute in a solvent, especially for ionic compounds.
204 Medium
204 of 226
Application +4 | -1
If 0.2 m aqueous solution of K4[Fe(CN)6]{K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right] is 100% ionized then the freezing point of the solution will be (Kf=1.86 K kg mol−1)\left( {{K_f} = 1.86\,K\,kg\,mo{l^{ - 1}}} \right)
View answer and explanation
Correct option: B
−1.860C- {1.86^0}C
Option A is incorrect. The correct answer is -1.86, which is not listed. The freezing point depression is calculated using the van't Hoff factor and the molality.
205 Hard
205 of 226
Analyzing +4 | -1
The freezing point of an aqueous solution of KCN{KCN} containing 0.2 mole/kg water was −0.8∘C-0.8^{\circ} \mathrm{C}. On addition of 0.1 mole of Hg(CN)2{Hg}({CN})_2 in the solution containing 1 kg of water, the freezing point of the solution was −0.6∘C-0.6^{\circ} \mathrm{C}. Assuming that the complex is formed according to the following equation:
Hg(CN)2+mCN−⟶Hg(CN)m+2−m{Hg}({CN})_2+{mCN}^{-} \longrightarrow {Hg}({CN})_{{m}+2}^{-{m}} and Hg(CN)2{Hg}({CN})_2 is the limiting reagent, the value of 4 m4 \mathrm{~m} is:
View answer and explanation
Correct option: A
8
Option A (8) is correct because the freezing point depression indicates the formation of a complex ion with 2 additional cyanide ions, thus m=2 and 4m=8.
206 Medium
206 of 226
Understanding +4 | -1
The melting point of most of the solid substances increase with an increase of pressure acting on them. However, ice melts at a temperature lower than its usual melting point, when the pressure increase. This is because :
View answer and explanation
Correct option: A
Ice is less denser than water
Option A (Ice is less denser than water) is correct because the increased pressure favors the liquid phase (water) which is denser, causing ice to melt at a lower temperature.
207 Easy
207 of 226
Application +4 | -1
Molarity of a given orthophosphoric acid solution is 3 M. It’s normality is
View answer and explanation
Correct option: A
9N
Option A (9N) is correct because the normality of an acid is its molarity multiplied by its basicity (number of replaceable H⁺ ions), and orthophosphoric acid (H₃PO₄) has a basicity of 3.
208 Medium
208 of 226
Remembering +4 | -1
The van't Hoff factor (i) for a dilute aqueous solution of glucose is:
View answer and explanation
Correct option: B
1
Glucose is a non-electrolyte and does not dissociate in solution; therefore, its van't Hoff factor is 1, making option B the correct answer.
209 Easy
209 of 226
Application +4 | -1
Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is
View answer and explanation
Correct option: A
23.077%23.077\%
Option C (2.3077%) is incorrect. Option A (2.3077) is correct because molality is calculated by finding the mass of the solvent and then dividing the moles of solute by the mass of the solvent in kg.
210 Medium
210 of 226
Understanding +4 | -1
Assertion (A): Molality is independent of temperature.

Reason (R): There is no volume factor in the expression of molality.
View answer and explanation
Correct option: A
Both A & R are true, R is the correct explanation of A
Option A (Both A & R are true, R is the correct explanation of A) is correct because molality is defined as moles of solute per kilogram of solvent, which is mass-based and therefore independent of temperature.
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