Skip to main content
Back to THERMODYNAMICS

Your Progress

0 / 363 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 301-330 of 363 questions

Preparing practice and saved progress…

301 Medium
301 of 363
Understanding +4 | -1
In adiabatic process, the work done by system is 50 J50 \mathrm{~J}, then
View answer and explanation
Correct option: D
the internal energy of the system will decrease by 50 J50 \mathrm{~J}
Option D (the internal energy of the system will decrease by 50 J50 \mathrm{~J}) is correct because in an adiabatic process, work done by the system results in a decrease in internal energy.
302 Medium
302 of 363
Application +4 | -1
A refrigerator consumes an average 35 W power to operate between temperature 10∘C10^\circ C to 25∘C25^\circ C. If there is no loss of energy, then how much average heat per second does it transfer?
View answer and explanation
Correct option: A
263 J/s
Option A (263 J/s) is correct because it is the heat transferred calculated using the coefficient of performance of a refrigerator.
303 Medium
303 of 363
Application +4 | -1
A bullet of mass 5 g,5\,g, travelling with a speed of 210  m/s, 210\,\,m/s,\, strikes a fixed wooden target. One-half of its kinetic
energy is converted into heat in the bullet while the other half is converted into heat in the wood. The rise of
temperature of the bullet, if the specific heat of its material is 0.030   calg−1  ∘C−10.030\,\,\,\mathrm{cal }{g^{ - 1}}\,\,^\circ {C^{ - 1}} is close to
View answer and explanation
Correct option: A
87.5o C{87.5^\mathrm{o}}\,C
Option A (87.5o C{87.5^\mathrm{o}}\,C) is correct because it is the temperature rise calculated from the heat generated in the bullet, which is half of the kinetic energy converted.
304 Medium
304 of 363
Understanding +4 | -1
Assertion: Coefficient of performance in refrigerator may be greater than one.
Reason: Heat extracted from lower temperature reservoir.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B is correct because both the assertion and the reason are true, but the reason does not explain why the coefficient of performance can be greater than one.
305 Medium
305 of 363
Application +4 | -1
A gaseous mixture enclosed in a vessel consists of 3 g3 \mathrm{~g} mole of a gas XX with γ=(5/3)\gamma=(5 / 3) and some amount of gas YY with γ=(7/5)\gamma=(7 / 5) at a temperature TT. The gases XX and YY do not react with each other and are assumed to be ideal. If γ\gamma for the gaseous mixture is (2923)\left(\frac{29}{23}\right), then the number of gram moles of the gas YY is
View answer and explanation
Correct option: A
0.50.5
Option A (0.5) is correct because the number of gram moles of gas Y is calculated using the mixture rule for specific heats.
306 Medium
306 of 363
Remembering +4 | -1
Universal gas constant is
View answer and explanation
Correct option: B
Cp−CV{C_p} - {C_V}
Option B (Cp−CV{C_p} - {C_V}) is correct because the universal gas constant (R) is equal to the difference between the molar specific heat at constant pressure (CpC_p) and the molar specific heat at constant volume (CVC_V).
307 Medium
307 of 363
Application +4 | -1
At 500 K500 \mathrm{~K} for an isobaric process.

ΔSsystem =−10kJmolK and ΔSsurr =12kJmolK\Delta \mathrm{S}_{\text {system }}=-10 \frac{\mathrm{kJ}}{\mathrm{mol} \mathrm{K}} \text { and } \Delta \mathrm{S}_{\text {surr }}=12 \frac{\mathrm{kJ}}{\mathrm{molK}}

Therefore, ΔG\Delta \mathrm{G} for the entire process is-
View answer and explanation
Correct option: B
−1000 kJ/mol-1000 \mathrm{~kJ} / \mathrm{mol}
Option B (-1000 kJ/mol) is correct because it is calculated using the relationship between ΔStotal\Delta S_{\text {total}} and ΔG\Delta G for an isobaric process.
308 Medium
308 of 363
Application +4 | -1
In an isobaric process, the absolute temperature is doubled. The mean free path (λ)\left( \lambda \right) and the relaxation time (τ)\left( \tau \right) will become respectively
View answer and explanation
Correct option: B
times and 2\sqrt 2 times
Option B (2 times and 2\sqrt{2} times) is correct because at isobaric process, mean free path is directly proportional to temperature and relaxation time is directly proportional to square root of temperature.
309 Medium
309 of 363
Understanding +4 | -1
A balloon filled with helium (32∘C32^\circ C and 1.7 atm) bursts. Immediately afterwards; the expansion of helium can be considered as
View answer and explanation
Correct option: B
irreversible adiabatic
Option A (its magnitude changes but the direction remains same) is correct because the angular momentum increases as the cylinder rolls down, but the direction stays constant.
310 Medium
310 of 363
Application +4 | -1
The temperature of 5 moles of a gas at constant volume is changed from 100∘C^ \circ C to 120∘C^ \circ C. The change in internal energy is 80 J. the total heat capacity of the gas at constant volume will be in JK−1\mathrm{J}{\mathrm{K}^{ - 1}} is
View answer and explanation
Correct option: C
0.8
Option B (4) is correct because the total heat capacity at constant volume is calculated using the change in internal energy and the temperature difference.
311 Medium
311 of 363
Understanding +4 | -1
Statement-1: The quantity of heat in a solid body determines its temperature.
Statement-2: Whenever heat is supplied to a solid body which is not undergoing phase change the temperature of the solid body increases.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D (Statement-1 is false, Statement-2 is true) is correct because the quantity of heat in a solid body does not directly determine its temperature, but adding heat to a solid (without phase change) will increase its temperature.
312 Medium
312 of 363
Application +4 | -1
A bullet of mass 10×10−3 kg10 \times 10^{-3} \mathrm{~kg} moving with a speed of 20 ms−120 \mathrm{~ms}^{-1} hits an ice block (0∘C)\left(0^{\circ} \mathrm{C}\right) of 990 g990 \mathrm{~g} kept at rest on a frictionless floor and gets embedded in it. If ice takes 50%50 \% of KE lost by the system, the amount of ice melted (in grams) approximately is: (J=4.2 J/cal(J=4.2 \mathrm{~J} / \mathrm{cal}; latent heat of ice =80 cal/g=80 \mathrm{~cal} / \mathrm{g})
View answer and explanation
Correct option: D
3×10−33 \times 10^{-3}
Option D (3×10−33 \times 10^{-3}) is correct because it is the calculated amount of ice melted based on the kinetic energy lost by the bullet and the latent heat of fusion.
313 Medium
313 of 363
Application +4 | -1
A sample of ideal gas (γ=1.4)(\gamma=1.4) is heated at constant pressure. If an amount 140 J140 \mathrm{~J} of heat is supplied to the gas, find (a) the change in internal energy of the gas, (b) the work done by the gas.
View answer and explanation
Correct option: C
100 J; 40 J
Option C (100 J; 40 J) is correct because when heat is supplied at constant pressure, part of it increases internal energy and the rest does work, with Δ U = 100 J and Δ W = 40 J.
314 Medium
314 of 363
Remembering +4 | -1
The first operation involved in a carnot cycle is
View answer and explanation
Correct option: A
Isothermal Expansion
Option A (Isothermal Expansion) is correct because the Carnot cycle starts with isothermal expansion.
315 Medium
315 of 363
Understanding +4 | -1
If CpC_p and CvC_v are the specific heats for a gas at constant pressure and at constant volume respectively, then the relation Cp−Cv=RC_p-C_v=R is exact for
View answer and explanation
Correct option: C
Ideal gas and nearly true for real gases at moderate pressure
Option D (Ideal gas at all pressure and real gas at moderate pressure) is correct because the relation Cp−Cv=RC_p - C_v = R is exact for ideal gases at all pressures and nearly true for real gases at moderate pressures.
316 Medium
316 of 363
Understanding +4 | -1
The heat capacity per mole of water is (R is universal gas constant)
View answer and explanation
Correct option: A
9R9R
Option A (9R9R) is correct because, according to the equipartition theorem, each atom in a water molecule contributes 3R to the molar heat capacity, and a water molecule has 3 atoms.
317 Medium
317 of 363
Understanding +4 | -1
Pi,ViP_i, V_i and Pf,VfP_f, V_f are initial and final pressures and volumes of a gas in a thermodynamic process respectively. If PVn=P V^n= constant, then the amount of work done is
View answer and explanation
Correct option: A
Minimum for n=γn=\gamma
Option C (Minimum for n=0n=0) is correct because the work done is minimum for isobaric process where n=0.
318 Medium
318 of 363
Remembering +4 | -1
which of the following is the unit of specific heat
View answer and explanation
Correct option: B
J/kg  0CJ/kg{\;^0}C
Option B (J/kg  0CJ/kg{\;^0}C) is correct because specific heat is defined as the amount of heat required to raise the temperature of 1 kg of a substance by 1 degree Celsius.
319 Medium
319 of 363
Understanding +4 | -1
A system goes from AA and BB via two processes II and IIII as shown in figure. If ΔU1\Delta {U_1} and ΔU2\Delta {U_2} are the changes in internal energies in the process II and IIII respectively, then
View answer and explanation
Correct option: A
ΔU1=ΔU2\Delta {U_1} = \Delta {U_2}
Option A (ΔU1=ΔU2\Delta {U_1} = \Delta {U_2}) is correct because the change in internal energy is a state function and depends only on the initial and final states, not the path taken.
320 Medium
320 of 363
Remembering +4 | -1
The process in which no heat enters or leaves the system is termed as
View answer and explanation
Correct option: D
Adiabatic
Option D (Adiabatic) is correct because an adiabatic process is defined as one in which no heat is exchanged between the system and its surroundings.
321 Medium
321 of 363
Understanding +4 | -1
Which of the following statements is correct for a thermodynamic gaseous system?
View answer and explanation
Correct option: C
Temperature of system may decrease inspite of heat is being absorbed by the system
The correct answer is C (Temperature of system may decrease inspite of heat is being absorbed by the system) because if the system does work while absorbing heat, its internal energy and thus temperature can decrease.
322 Medium
322 of 363
Application +4 | -1
A Camot engine with efficiency 50% takes heat
from a source at 600 K. In order to increase the
efficiency to 70%, keeping the temperature of sink
same, the new temperature of the source will be:
View answer and explanation
Correct option: D
1000 K
Option D (1000 K) is correct because it is calculated by first finding the temperature of the sink using the initial efficiency and source temperature, and then using the new efficiency and the same sink temperature to find the new source temperature.
323 Medium
323 of 363
Understanding +4 | -1
The internal energy of the gas increases in
View answer and explanation
Correct option: B
Adiabatic compression
Option B (Adiabatic compression) is correct because in adiabatic compression, work is done on the gas, increasing its internal energy.
324 Medium
324 of 363
Understanding +4 | -1
Assertion (A) : First law of thermodynamics can be applied for ideal gases only.

Reason (R) : First law is simply, law of conservation of energy.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D (If Assertion is false but the Reason is true) is correct because the first law of thermodynamics applies to all systems, not just ideal gases, and it is indeed a statement of energy conservation.
325 Medium
325 of 363
Understanding +4 | -1
When you make ice cubes, the entropy of water
View answer and explanation
Correct option: C
decreases
Option C (decreases) is correct because when water freezes into ice, it becomes more ordered, thus decreasing entropy.
326 Medium
326 of 363
Understanding +4 | -1
In isothermal expansion, the pressure is determined by
View answer and explanation
Correct option: B
Compressibility only
Option B is correct because in an isothermal expansion, the pressure is inversely proportional to the volume, and compressibility is the measure of the change in volume with pressure.
327 Medium
327 of 363
Application +4 | -1
1 mm31\,m{m^3} of a gas is compressed at '11' atmospheric pressure and temperature 270C to 6270C{27^0}C\,to\,{627^0}C. What is the final pressure under adiabatic condition (γfor the gas=1.5)\left( {\gamma for\,the\,gas = 1.5} \right)
View answer and explanation
Correct option: A
27×105N/M227 \times {10^5}N/{M^2}
Option A (27×105N/M227 \times {10^5}N/{M^2}) is correct because it follows from the adiabatic condition equation relating pressure and temperature.
328 Medium
328 of 363
Application +4 | -1
A Carnot engine takes heat from a reservoir at 627∘C{627^ \circ }C and rejects heat to a sink at 27∘C{27^ \circ }C. Its efficiency will be
View answer and explanation
Correct option: C
45718
Option C (02-Mar) is correct because the efficiency of a Carnot engine is calculated using the temperatures of the hot and cold reservoirs.
329 Medium
329 of 363
Understanding +4 | -1
A perfect gas contained in a cylinder is kept in vacuum. If the cylinder suddenly bursts, then the temperature of the gas
View answer and explanation
Correct option: A
remains constant
Option A is correct because the free expansion into a vacuum is an adiabatic process with no work done, resulting in no temperature change.
330 Medium
330 of 363
Application +4 | -1
During an adiabatic process, the pressure pp of a fixed mass of an ideal gas changes by Δp\Delta p and its volume VV changes ΔV\Delta V. If γ=Cp/Cv\mathrm{\gamma } = {C_p}/{C_v} , then ΔV/V\Delta V/V is given by
View answer and explanation
Correct option: C
−Δpγp- \frac{{\Delta p}}{{\mathrm{\gamma }p}}
Option C (−Δpγp- \frac{{\Delta p}}{{\mathrm{\gamma }p}}) is correct because it is derived from the adiabatic process equation relating pressure and volume changes.
Revision notes and key takeaways

Review THERMODYNAMICS in your textbook or class notes, then use this set to check your understanding.

Showing 301-330 of 363 questions

Your practice

0 / 363 answered · 363 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.