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JEE PHYSICS MCQ: THERMODYNAMICS

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The efficiency of the Carnot engine is 50%50 \% and the temperature of the sink is 500 K500 {~K}. If the temperature of the source is kept constant and its efficiency raised to 60%60 \%, then the required temperature of the sink will be
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Correct option: C
400 K400 {~K}
Option C (400 K) is correct because it is calculated by first finding the source temperature using the initial efficiency and sink temperature, and then finding the new sink temperature for the increased efficiency.

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