JEE PHYSICS MCQ: THERMODYNAMICS

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During an adiabatic compression, 830 J of work is done on 2 moles of a diatomic ideal gas to reduce its volume by 50%. The change in its temperature is nearly: (

R = 8.3\,J{K^{ - 1}}\,mo{l^{ - 1}}

)

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Correct option: C

20 K

Option C (20 K) is correct because it is calculated using the formula for work done during an adiabatic process.

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\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)