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JEE • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Easy
1 of 16
Application +4 | -1
A gas expand 0.25  m30.25\,\,{m^3} at constant pressure 103N/m2,{10^3}N/{m^2}, the work done is
View answer and explanation
Correct option: B
250 J
Option B (250 J) is correct because it accurately calculates the work done during the gas expansion at constant pressure.
2 Easy
2 of 16
Understanding +4 | -1
The increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo?
View answer and explanation
Correct option: B
Adiabatic
Option B (Adiabatic) is correct because if the increase in internal energy equals the work done *on* the system, then no heat is exchanged with the surroundings, which is the definition of an adiabatic process.
3 Easy
3 of 16
Understanding +4 | -1
Statement-1: When an ideal gas is taken from a given thermodynamic state AA to another given thermodynamic state BB by any polytrophic process, the change in the interval energy of the system will be the same in all processes.
Statement-2: Internal energy of the gas depends only upon its absolute temperature.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1) is correct because the change in internal energy depends only on the initial and final states, and for an ideal gas, internal energy depends only on temperature.
4 Easy
4 of 16
Understanding +4 | -1
When heat is added to a system, which of the following is not possible?
View answer and explanation
Correct option: C
Neither internal energy increases nor work is done by the system
Option C (Neither internal energy increases nor work is done by the system) is correct because the first law of thermodynamics dictates that added heat must either increase internal energy or do work.
5 Easy
5 of 16
Understanding +4 | -1
Assertion: The internal energy of a real gas is function of both, temperature and volume.
Reason: At constant pressure, some heat is spent in expansion of the gas.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because the internal energy of a real gas depends on both temperature and volume due to intermolecular forces, and energy is used for expansion at constant pressure.
6 Easy
6 of 16
Understanding +4 | -1
The work done in an isothermal expansion of a gas depends upon
View answer and explanation
Correct option: C
Both temperature and expansion ratio
Option C (Both temperature and expansion ratio) is correct because the work done in an isothermal expansion depends on both the temperature and the ratio of final to initial volume.
7 Easy
7 of 16
Understanding +4 | -1
Assertion: In adiabatic process work is independent of path.
Reason: In adiabatic process work done is equal to negative of change in internal energy.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion
Option A is correct because in an adiabatic process, the work done is independent of the path and is equal to the negative change in internal energy, which is the correct explanation.
8 Easy
8 of 16
Understanding +4 | -1
A thermodynamical system is changed from state(p1V1)to(p2,V2)\left( {{p_1}{V_1}} \right)\mathrm{to}\left( {{p_2},{V_2}} \right) by two different processes, the quantity which will remain same will be
View answer and explanation
Correct option: D
ΔQ−ΔW\mathrm{\Delta }Q - \mathrm{\Delta }W
Option D (ΔQ−ΔW{\Delta }Q - {\Delta }W) is correct because the change in internal energy (ΔU{\Delta }U) is path-independent and equals ΔQ−ΔW{\Delta }Q - {\Delta }W.
9 Easy
9 of 16
Understanding +4 | -1
The internal energy of a system remains constant
when it undergoes

(A) a cycle process

(B) an isothermal process

(C) an adiabatic process

(D) any process in which the heat given out by the
system is equal to the work done on the system

Choose the correct statement
View answer and explanation
Correct option: D
A, B, D
Option A, B, D is correct because internal energy remains constant in a cyclic process, an isothermal process, and any process where heat given out equals work done.
10 Easy
10 of 16
Understanding +4 | -1
Which of the following is not a state function?
View answer and explanation
Correct option: B
Work done in isothermal process
Option B (Work done in isothermal process) is correct because work done is a path-dependent function, not a state function.
11 Easy
11 of 16
Understanding +4 | -1
Statement-1: A quasi-static process is so called because it is a sudden and large change of the system.
Statement-2: An adiabatic process is no quasi-static because it is a sudden and large change of the system.
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option D (Statement-1 is false, Statement-2 is true) is correct because a quasi-static process is slow and gradual, while an adiabatic process can be sudden.
12 Easy
12 of 16
Understanding +4 | -1
Heat added to a system is equal to
View answer and explanation
Correct option: D
Sum of above all the three factors
Option D (Sum of above all the three factors) is correct because, according to the first law of thermodynamics, heat added to a system equals the change in internal energy plus the work done by the system, and internal energy includes both kinetic and potential energy.
13 Easy
13 of 16
Understanding +4 | -1
For an isothermal expansion of a perfect gas, the value of ΔPP\frac{{\Delta P}}{P} is equal
View answer and explanation
Correct option: B
−ΔVV- \frac{{\Delta V}}{V}
Option B is correct because for an isothermal process, the relationship between pressure and volume changes can be derived from the ideal gas law.
14 Easy
14 of 16
Understanding +4 | -1
Assertion: First law of thermodynamics is a restatement of the principle of conservation.
Reason: Energy is fundamental quantity.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
The correct answer is C (If assertion is true, but reason is false) because the first law of thermodynamics is indeed a restatement of the principle of conservation of energy, but energy being a fundamental quantity is not the correct reason.
15 Easy
15 of 16
Understanding +4 | -1
A gas has nn degrees of freedom. The ratio of specific heat of gas at constant volume to the specific heat of gas at constant pressure will be
View answer and explanation
Correct option: A
nn+2\frac{n}{n+2}
Option A (nn+2\frac{n}{n+2}) is correct because it represents the ratio of specific heat at constant volume to specific heat at constant pressure for a gas with n degrees of freedom.
16 Easy
16 of 16
Remembering +4 | -1
Which of the following has maximum specific heat
View answer and explanation
Correct option: A
Water
Option A (Water) is correct because water has a higher specific heat capacity compared to alcohol, glycerine, and oil.
Revision notes and key takeaways

Review THERMODYNAMICS in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 16 single-correct-answer MCQs on THERMODYNAMICS.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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