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JEE • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Hard

1 of 5

Understanding +4 | -1

In an adiabatic process, which of the following
statements is true?

View answer and explanation

Correct option: C

The molar heat capacity is zero

The correct answer is C (The molar heat capacity is zero) because in an adiabatic process, no heat is exchanged with the surroundings, making the molar heat capacity zero.

2 Hard

2 of 5

Understanding +4 | -1

Identify the characteristics of an adiabatic process in a monoatomic gas.

(A) Internal energy is constant.

(B) Work done in the process is equal to the charge in internal energy.

(C) The product of temperature and volume is a constant.

(D) The product of pressure and volume is a constant.

(E) The work done to change the temperature from

\mathrm{T}_1

\mathrm{T}_2

is proportional to

\left(\mathrm{T}_2-\mathrm{T}_1\right)

Choose the correct answer from the options given below:

View answer and explanation

Correct option: C

(B), (E) only

Option C is correct because in an adiabatic process, the work done is equal to the negative change in internal energy, and the work done is proportional to the change in temperature.

3 Hard

3 of 5

Application +4 | -1

One mole of an ideal diatomic gas undergoes a thermodynamic process, in which its molar heat capacity varies directly proportional to temperature as

{C}=\alpha{T}

, where

\alpha

is a positive constant. Work done by the gas when it is heated from initial temperature

T_0

to a final temperature

3 T_0

will be

View answer and explanation

Correct option: C

\left(4 \alpha {T}_0-5 {R}\right) {T}_0

Option C (

\left(4 \alpha {T}_0-5 {R}\right) {T}_0

) is correct because it is the work done by the gas calculated using the given molar heat capacity and integrating over the temperature range.

4 Hard

4 of 5

Application +4 | -1

A diatomic gas

(\gamma=1.4)

does

100 \mathrm{~J}

of work in an isobaric expansion. The heat given to the gas is:

View answer and explanation

Correct option: A

350 \mathrm{~J}

Option A (

350 \mathrm{~J}

) is correct because for an isobaric process, the heat given to the gas is calculated using

Q = \Delta U + W

, where

\Delta U = \frac{f}{2} nR \Delta T

and

W = nR \Delta T

. For a diatomic gas,

f = 5

5 Hard

5 of 5

Application +4 | -1

A monoatomic gas

(\gamma = 5/3)

is suddenly compressed to 1/8 of its original volume adiabatically, then the pressure of the gas, will change to

View answer and explanation

Correct option: D

32 times its initial pressure

Option D (32 times its initial pressure) is correct because the pressure changes by a factor of 32 when the volume is compressed adiabatically to 1/8 of its original volume.

Revision notes and key takeaways

Review THERMODYNAMICS in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 5 single-correct-answer MCQs on THERMODYNAMICS.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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