Question

One mole of an ideal diatomic gas undergoes a thermodynamic process, in which its molar heat capacity varies directly proportional to temperature as ${C}=\alpha{T}$, where $\alpha$ is a positive constant. Work done by the gas when it is heated from initial temperature $T_0$ to a final temperature $3 T_0$ will be

Accepted Answer

$\left(4 \alpha {T}_0-5 {R}\right) {T}_0$

Answer

$4 \alpha {T}_0^2$

Answer

$\left(\alpha T_0-R\right) \frac{3 T_0}{2}$

Answer

$\left(3 \alpha {T}_0-5 {R}\right) \frac{{T}_0}{2}$

JEE PHYSICS MCQ: THERMODYNAMICS

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