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JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1
One mole of an ideal diatomic gas undergoes a thermodynamic process, in which its molar heat capacity varies directly proportional to temperature as C=αT{C}=\alpha{T}, where α\alpha is a positive constant. Work done by the gas when it is heated from initial temperature T0T_0 to a final temperature 3T03 T_0 will be
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Correct option: C
(4αT0−5R)T0\left(4 \alpha {T}_0-5 {R}\right) {T}_0
Option C ((4αT0−5R)T0\left(4 \alpha {T}_0-5 {R}\right) {T}_0) is correct because it is the work done by the gas calculated using the given molar heat capacity and integrating over the temperature range.

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