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JEE PHYSICS MCQ: THERMODYNAMICS

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A mass mm of lead shot is placed at the bottom of a vertical cardboard cylinder that is 1.5 m1.5 \mathrm{~m} long and closed at both ends. The cylinder is suddenly inverted so that the shot falls 1.5 m1.5 \mathrm{~m}. If this process is repeated quickly 100 times, assuming no heat is dissipated or lost, the temperature of the shot will increase by (specific heat of lead =0.03cal/g∘C=0.03 \mathrm{cal} / \mathrm{g}^{\circ} \mathrm{C} )
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Correct option: D
11.3∘C11.3^{\circ} \mathrm{C}
Option D (11.3∘C11.3^{\circ} \mathrm{C}) is correct because the potential energy lost by the lead shot is converted into thermal energy, increasing its temperature.

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