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JEE • PHYSICS • SEMI CONDUCTOR DEVICES

Semi conductor devices practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 370 questions

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181 Medium
181 of 370
Remembering +4 | -1
Zener breakdown takes place if
View answer and explanation
Correct option: B
Doped impurity is high
Option B (Doped impurity is high) is correct because Zener breakdown occurs in heavily doped p-n junctions due to strong electric fields.
182 Medium
182 of 370
Understanding +4 | -1
Consider the following statements (A) and (B) and identify the correct answer:

(A) A zener diode is connected in forward bias, when used as a voltage regulator.

(B) The potential barrier of p-n junction lies between 0 V to 0.1 V.
View answer and explanation
Correct option: A
(A) and (B) both are incorrect
Option A ((A) and (B) both are incorrect) is correct because a Zener diode is used in reverse bias as a voltage regulator, and the potential barrier for a p-n junction is typically around 0.3V for Germanium and 0.7V for Silicon.
183 Medium
183 of 370
Analyzing +4 | -1
An AND gate can be prepared by repetitive use of
(a) NOT gate         \,\,\,\,\,\,\,\, (b) OR gate         \,\,\,\,\,\,\,\, (c) NAND gate         \,\,\,\,\,\,\,\, (d) NOR gate
View answer and explanation
Correct option: B
Only (a) and (b) are correct
Option D is correct because an AND gate can be created by using NAND gates or NOR gates repetitively.
184 Medium
184 of 370
Understanding +4 | -1
Given below are two statements:

Statement I: Aˉ⋅Bˉ‾=A+B\overline{\bar{A} \cdot \bar{B}}=A+B

Statement II: Aˉ+Bˉ‾=A⋅B\overline{\bar{A}+{\bar{B}}}=A \cdot B

Which of the following statement(s) is/are correct?
View answer and explanation
Correct option: A
Statement I and Statement II both are correct
Option A is correct because both statements are correct applications of De Morgan's laws and double negation.
185 Medium
185 of 370
Understanding +4 | -1
For a transistor to work as an amplifier
View answer and explanation
Correct option: C
It's emitter junction is in forward bias and collector junction is in reverse bias
Option C (It's emitter junction is in forward bias and collector junction is in reverse bias) is correct because this configuration places the transistor in the active region, which is necessary for amplification.
186 Medium
186 of 370
Understanding +4 | -1
Which of the following statements is correct for proper working of zener diode?
View answer and explanation
Correct option: B
Reverse bias voltage applied must be greater than zener breakdown voltage
Option B (Reverse bias voltage applied must be greater than zener breakdown voltage) is correct because a Zener diode operates in the reverse breakdown region to maintain a constant voltage.
187 Medium
187 of 370
Understanding +4 | -1
A pp-type material is electrically …….
View answer and explanation
Correct option: C
Neutral
Option C (Neutral) is correct because a p-type material has an equal number of protons and electrons, making it electrically neutral.
188 Medium
188 of 370
Remembering +4 | -1
The electrical circuit used to get smooth output from a rectifier circuit is called
View answer and explanation
Correct option: B
Filter
Option B (Filter) is correct because a filter circuit is specifically designed to smooth the output of a rectifier by reducing ripple.
189 Medium
189 of 370
Understanding +4 | -1
A full wave rectifier is used to convert 50 Hz50 {~Hz} ac to dc. Then the number of pulses per sec present in the rectified voltage is
View answer and explanation
Correct option: B
100
Option B (100) is correct because a full-wave rectifier doubles the frequency of the input AC signal.
190 Medium
190 of 370
Application +4 | -1
The reverse bias in a junction diode is changed from 10 v10 \, \mathrm{v} to 25 v25 \, \mathrm{v} then the value of current changes from 30 μA30 \, \mu A to 80 μA80 \, \mu A. The resistance of the junction diode will be [Ω][\Omega]
View answer and explanation
Correct option: C
3×1053 \times 10^{5}
Option C (3×1053 \times 10^{5}) is correct because it is calculated using Ohm's law for the change in voltage and current in the diode.
191 Medium
191 of 370
Understanding +4 | -1
The correct relation between α\alpha (ratio of collector current to emitter current) and β\beta (ratio of collector current to base current) of a transistor is
View answer and explanation
Correct option: D
α=β1+β\alpha = \frac{\beta }{{1 + \beta }}
Option D is correct. The correct relationship between alpha and beta in a transistor is given by the formula α=β1+β\alpha = \frac{{\beta}}{{1 + \beta}}.
192 Medium
192 of 370
Understanding +4 | -1
Identify the incorrect statement regarding a superconducting wire
View answer and explanation
Correct option: B
Transport current flows through the entire area of cross-section of the wire
Option B (Transport current flows through the entire area of cross-section of the wire) is correct because in a superconductor, current flows only on the surface.
193 Medium
193 of 370
Analyzing +4 | -1
A semi conductor has an electron concentration of 8×10138 \times 10^{13} per cm3\mathrm{cm}^3 and a hole concentration of 5×10125 \times 10^{12} per cm3\mathrm{cm}^3. The electron mobility is 25000 cm2 V−1 s−125000 \mathrm{~cm}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1} and the hole mobility is 100 cm2 V−1 s−1100 \mathrm{~cm}^2 \mathrm{~V}^{-1} \mathrm{~s}^{-1}. Then,
View answer and explanation
Correct option: A
The semiconductor is n-type.
Option A (The semiconductor is n-type) is correct because the electron concentration is significantly higher than the hole concentration, indicating an n-type semiconductor.
194 Medium
194 of 370
Understanding +4 | -1
Identify the property which is not characteristic for a semiconductor?
View answer and explanation
Correct option: C
The charge carriers are electrons and holes in the valence band at higher temperatures
Option C (The charge carriers are electrons and holes in the valence band at higher temperatures) is correct because at higher temperatures, electrons move to the conduction band, not remain in the valence band.
195 Medium
195 of 370
Remembering +4 | -1
Zener diode is used for
View answer and explanation
Correct option: C
Stabilization
Option C (Stabilization) is correct because Zener diodes are primarily used to maintain a constant voltage in voltage regulator circuits.
196 Medium
196 of 370
Understanding +4 | -1
Avalanche breakdown in a p−np - n junction diode is due to
View answer and explanation
Correct option: D
Cumulative effect of increased electron collision and creation of added electron-hole pairs
Option D is correct because avalanche breakdown occurs due to the cumulative effect of increased electron collisions and the creation of additional electron-hole pairs.
197 Medium
197 of 370
Understanding +4 | -1
A) For a diode the forward bias resistance is low as compared to the reverse bias resistance

B) In rectifier circuits capacitor input filters use large capacitors.
View answer and explanation
Correct option: A
A, B are true
The correct answer is A (A, B are true) because diodes have low forward resistance and capacitor input filters use large capacitors to reduce ripple.
198 Medium
198 of 370
Understanding +4 | -1
When p−np - n junction diode is forward biased then
View answer and explanation
Correct option: C
Both the depletion region and barrier height are reduced
Option C (Both the depletion region and barrier height are reduced) is correct because forward bias reduces the potential barrier and allows current to flow, shrinking the depletion region.
199 Medium
199 of 370
Application +4 | -1
In p-n-p transistor circuit, the collector current is 10 mA10 \mathrm{~mA}. If 90%90 \% of the holes reach the collector, find emitter and base currents.
View answer and explanation
Correct option: A
1 mA1 \mathrm{~mA}
Option A (1 mA) is correct because the base current is the difference between the emitter current and the collector current.
200 Medium
200 of 370
Application +4 | -1
The binary number 10111 is equivalent to the decimal number
View answer and explanation
Correct option: C
23
Option C (23) is correct because the binary number 10111 is equivalent to the decimal number 23 when converted using the base-2 system.
201 Medium
201 of 370
Understanding +4 | -1
Digital circuit can be made by repetitive use of this gate
View answer and explanation
Correct option: D
NAND
Option D (NAND) is correct because NAND gates are universal gates and can be used to implement any digital circuit through repetitive use.
202 Medium
202 of 370
Understanding +4 | -1
On increasing the reverse bias to a large value in a p−n  p - n\; junction, diode current
View answer and explanation
Correct option: C
Suddenly increases
Option C (Suddenly increases) is correct because, at a high reverse voltage, the junction breaks down, leading to a sudden rise in reverse current.
203 Medium
203 of 370
Understanding +4 | -1
Assertion: A NN type semiconductor has a large number of electrons but still it is electrically neutral.
Reason: A NN type semiconductor is obtained by doping an intrinsic semiconductor with a pentavalent impurity.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B (If both assertion and reason are true but reason is not the correct explanation of assertion) is correct because while both statements are true, the reason doesn't directly explain why the N-type semiconductor is electrically neutral.
204 Medium
204 of 370
Application +4 | -1
A specimen of silicon is to be made P-type semi-conductor for this one atom of indium, on an average, 5×1075 \times 10^7 silicon atoms. If the number density of silicon is 5×10225 \times 10^{22} atom /m3/ \mathrm{m}^3. Then the number of acceptor atom per cm3\mathrm{cm}^3 will be
View answer and explanation
Correct option: C
1.0×10151.0 \times 10^{15}
Option C (1.0×10151.0 \times 10^{15}) is correct because it is the number of acceptor atoms per cm³ calculated from the given doping ratio and silicon density.
205 Medium
205 of 370
Understanding +4 | -1
In the binary number system 1+1=1+1=
View answer and explanation
Correct option: B
10
Option B (10) is correct because in the binary number system, 1 + 1 equals 10.
206 Medium
206 of 370
Remembering +4 | -1
The minimum potential difference between the base and emitter required to switch a silicon transistor ‘ON’ is approximately
View answer and explanation
Correct option: A
1 V
Option A (1 V) is correct because the minimum base-emitter voltage required to turn on a silicon transistor is approximately 0.7V, which is closest to 1V.
207 Medium
207 of 370
Application +4 | -1
An n-p-n transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance is 100  Ω100\;\Omega and the output load resistance is 10  kΩ.10\;k\Omega . The common emitter current gain β\beta is
View answer and explanation
Correct option: A
102{10^2}
Option A (102{10^2}) is correct because it accurately calculates the common emitter current gain using the given power gain, input resistance, and output resistance.
208 Medium
208 of 370
Understanding +4 | -1
Some statements are given about semi-conductors
a. Semi-conductor materials have crystalline structure and their atoms are bound together by covalent bonds
b. On adding suitable impurity even in small amounts, conductivity of semi-conductors increases appreciably.
c. Semi-conductor materials have sharply defined energy-levels for any electron belonging to a particular orbit.
d. Semi-conductors have negative temperature coefficient of resistance.
View answer and explanation
Correct option: D
Only a, b and d are correct
Option D (Only a, b and d are correct) is correct because semiconductors have crystalline structures, their conductivity increases with impurities, and they have a negative temperature coefficient of resistance.
209 Medium
209 of 370
Understanding +4 | -1
If no external voltage is applied across PP-NN junction, there would be
View answer and explanation
Correct option: B
An electric field pointing from NN-type to PP-type side across the junction
Option C is correct because a built-in electric field exists from the N-type to the P-type side due to the diffusion of charge carriers.
210 Medium
210 of 370
Understanding +4 | -1
The electrical conductivity of an intrinsic semiconductor at 0 K is
View answer and explanation
Correct option: B
Is equal to zero
Option B (Is equal to zero) is correct because at 0 K, intrinsic semiconductors behave like insulators, having zero conductivity.
Revision notes and key takeaways

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