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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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The density for simple cubic lattice is (where AA is atomic weight, NN is Avogadro’s number and aa is a lattice parameter)
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Correct option: C
ANa3\frac{A}{{N{a^3}}}
Option C (ANa3\frac{A}{{N{a^3}}}) is correct because the density of a simple cubic lattice is calculated by dividing the mass of the unit cell (A/N) by the volume of the unit cell (a3a^3).

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