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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Application +4 | -1
In a common base transistor amplifier, the input and the output resistance are 500 Ω500 ~\Omega and 40 Ω40 ~\Omega, and the emitter current is 1.0 mA1.0 \mathrm{~mA}. Find the input and the output voltages. Given α=0.95\alpha=0.95
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Correct option: C
38V38 V
The correct answer is C (38V38 V) because the output voltage is calculated by multiplying the collector current (αiE\alpha i_E) by the output resistance.

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