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NEET • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Easy

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Showing 61-74 of 74 questions

61 Easy

61 of 74

Application +4 | -1

\bar F = \left( {55i + 16j - 4k} \right)N

and

V = \left( {3i - 5j + 6k} \right)\,m/s

. Then instantaneous power is

View answer and explanation

Correct option: A

The correct answer is A (61) because instantaneous power is the dot product of force and velocity vectors.

62 Easy

62 of 74

Understanding +4 | -1

Assertion: In elastic collision, kinetic energy is conserved.
Reason: Energy is always conserved.

View answer and explanation

Correct option: B

If both assertion and reason are true but reason is not correct explanation of the assertion.

Option B (If both assertion and reason are true but reason is not correct explanation of the assertion) is correct because both the assertion (kinetic energy is conserved in elastic collisions) and the reason (energy is always conserved) are true, but the conservation of energy in general doesn't specifically explain why kinetic energy is conserved in elastic collisions.

63 Easy

63 of 74

Understanding +4 | -1

In inelastic collision :-

View answer and explanation

Correct option: D

Total energy and momentum are conserved but kinetic energy is not conserved

Option D is correct because in an inelastic collision, total energy and momentum are conserved, but kinetic energy is not conserved.

64 Easy

64 of 74

Application +4 | -1

A particle of mass

m \mathrm{~kg}

is travelling at constant speed

v \mathrm{~m} / \mathrm{s}

round a circle of radius

r_{m^{\prime}}

(a) If

v=8

and

r=2

, find the magnitude of the central acceleration (in

\mathrm{m} / \mathrm{s}^2

View answer and explanation

Correct option: A

Option A (32) is correct because the centripetal acceleration is calculated using

a = v^2/r

, where v is the speed and r is the radius.

65 Easy

65 of 74

Application +4 | -1

The work done in dragging a stone of mass 100 kg up an inclined plane 1 in 100 through a distance of 10 m is (take

\mathrm{g} = 9.8\mathrm{\;m}{\mathrm{s}^{ - 2}}

)

View answer and explanation

Correct option: D

98 J

Option D (98 J) is correct because the work done is equal to the change in potential energy, which is mgh, where h is the vertical height gained.

66 Easy

66 of 74

Understanding +4 | -1

When the frame of reference is rotated

View answer and explanation

Correct option: D

Both (2) and (3)

Option D (Both (2) and (3)) is correct because rotating the frame of reference does not change the vector itself, but its components may change.

67 Easy

67 of 74

Understanding +4 | -1

Which of the following is not a state function?

View answer and explanation

Correct option: D

Work done by non-conservative force

Option D is correct because work done by non-conservative forces depends on the path taken, not just the initial and final states.

68 Easy

68 of 74

Understanding +4 | -1

Statement I: A particle moving in a vertical circle, has a maximum kinetic energy at the highest point of its motion.
Statement II: The magnitude of the velocity remains constant for a particle moving in a horizontal plane.

View answer and explanation

Correct option: D

Statement I is false; Statement II is true

Option D (Statement I is false; Statement II is true) is correct because kinetic energy is minimum at the highest point in a vertical circle, and velocity is constant in magnitude for uniform circular motion in a horizontal plane.

69 Easy

69 of 74

Application +4 | -1

An unbanked circular highway curve on level ground makes a turn of

90^{\circ}

. The highway carries traffic at

108 \,\mathrm{km}-\mathrm{hr}^{-1}

, and the centripetal force on a vehicle is not to exceed

1 / 10

of its weight. What is the approximate minimum length of the curve, in

\mathrm{km}

View answer and explanation

Correct option: A

1.4 \mathrm{~km}

Option A (1.4 km) is correct because it is calculated by finding the radius of the curve using the centripetal force condition and then determining the arc length for a 90-degree turn.

70 Easy

70 of 74

Application +4 | -1

Sand is falling on a conveyor belt at the rate of

5\,kg\,{s^{ - 1}}

. The extra power required to move the belt with a velocity of

6\,m{s^{ - 1}}

View answer and explanation

Correct option: B

180 W

The correct answer is B. The extra power required is equal to the rate of change of kinetic energy of the sand. P = d/dt (1/2 * m * v²) = v² * dm/dt = (6 m/s)² * 5 kg/s = 180 W.

71 Easy

71 of 74

Application +4 | -1

A particle moves in a circle of radius 5 cm with constant speed and time period

0.2\,\,\pi

seconds. The acceleration of the particle is [in

m/{s^2}

]

View answer and explanation

Correct option: A

Option A (5) is correct because the centripetal acceleration is calculated using

a = v^2/r

a = \omega^2 r

, where

\omega = 2\pi/T

72 Easy

72 of 74

Application +4 | -1

A water pump lifts water at the rate of 5 litre per second through an average height of

8 \mathrm{~m}

from a well of depth

12 \mathrm{~m}

. Its power will be:

View answer and explanation

Correct option: B

980 watt

Option B (980 watt) is correct because the power is calculated by multiplying the mass flow rate, gravity, and the total height.

73 Easy

73 of 74

Application +4 | -1

A ball falls from a height of

16 {~m}

on a floor and rebounds to a height of

4 {~m}

. The coefficient of restitution for collision is :-

View answer and explanation

Correct option: B

\frac{1}{2}

Option B (1/2) is correct because the coefficient of restitution is the square root of the ratio of the rebound height to the initial height.

74 Easy

74 of 74

Application +4 | -1

A uniform force of

\left( {3\hat i + \hat j} \right)

newton acts on a particle of mass 2 kg. The particle is displaced from position

\left( {2\hat i + \hat k} \right)m

to position

\left( {4\hat i + 3\hat j - \hat k} \right)m

. The work done by the force on the particle is

View answer and explanation

Correct option: D

9 J

Option D (9 J) is correct because the work done is the dot product of the force and the displacement vector.

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