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NEET • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Medium

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Showing 1-30 of 238 questions
1 Medium
1 of 238
Analyzing +4 | -1
A running man has the same kinetic energy as that of a boy of half his mass. The man speed up by 2  ms−12\mathrm{\;m}{\mathrm{s}^{ - 1}} and the boy changes his speed by x=ms−1x = \mathrm{m}{\mathrm{s}^{ - 1}}, so that the kinetic energies of the boy and the man are again equal. Then x in ms−1\mathrm{m}{\mathrm{s}^{ - 1}} is
View answer and explanation
Correct option: B
+22+ 2\sqrt 2
Option B (+22+2\sqrt 2) is correct because it is the value of x that makes the kinetic energies of the man and boy equal after the speed changes.
2 Medium
2 of 238
Application +4 | -1
A force F⃗=−K(yi^+xj^)\mathrm{\vec F} = - K\left( {y\hat i + x\hat j} \right) (where K is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a,0) and then parallel to the y-axis to the (a,a). The total work done by the force F⃗\mathrm{\vec F} on the particle is
View answer and explanation
Correct option: C
−Ka2- K{a^2}
Option C (−Ka2- K{a^2}) is correct because the work done is path-dependent for this non-conservative force, and the integral along the specified path yields this result.
3 Medium
3 of 238
Analyzing +4 | -1
A body projected vertically from the earth reaches a height equal to earth’s radius before returning to the earth. The power exerted by the gravitational force is greatest
View answer and explanation
Correct option: C
At the instant just before the body hits the earth
Option C (At the instant just before the body hits the earth) is correct because power is the product of force and velocity, and the velocity is greatest just before impact.
4 Medium
4 of 238
Application +4 | -1
Work done when a force, F⃗=(i^+2j^+3k^)\mathrm{\vec F} = \left( {\hat i + 2\hat j + 3\hat k} \right) N acting on a particle takes it from the point r⃗1=(i^+j^+k^){\mathrm{\vec r}_1} = \left( {\hat i + \hat j + \hat k} \right) m to the point r⃗2=(i^+j^+2k^){\mathrm{\vec r}_2} = \left( {\hat i + \hat j + 2\hat k} \right)
View answer and explanation
Correct option: B
−1 J- 1\,J
Option D is incorrect. The correct answer is 3 J. The work done is calculated by taking the dot product of the force vector and the displacement vector.
5 Medium
5 of 238
Analyzing +4 | -1
Assertion (A): A body of mass "m1\mathrm{m}_1" collides another body of mass "m2\mathrm{m}_2" at rest elastically. The fraction of energy transferred to the second body is m1m1+m2\frac{m_1}{m_1+m_2}
Reason (R): In an "inelastic collision" both linear momentum and KE is conserved
View answer and explanation
Correct option: D
If both Assertion and Reason are false
Option D (If both Assertion and Reason are false) is correct because the assertion has an incorrect formula and the reason states that KE is conserved in inelastic collisions, which is false.
6 Medium
6 of 238
Analyzing +4 | -1
The force exerted by a compression device is given by F(x)=kx(x−l)F(x)=k x(x-l) for 0≤x≤l0 \leq x \leq l, where ll is the maximum possible compression, xx is the compression and k{k} is a constant. The work required to compress the body by a distance d{d} will be maximum when:
View answer and explanation
Correct option: D
d=ld=l
Option D (d=ld=l) is correct because the work required to compress the body is maximum when the compression is equal to the maximum possible compression.
7 Medium
7 of 238
Understanding +4 | -1
A body is revolving with a uniform speed v in a circle of radius rr. The tangential acceleration is
View answer and explanation
Correct option: C
Zero
The correct answer is C. Tangential acceleration is the rate of change of tangential velocity. If the speed is uniform, the tangential acceleration is zero.
8 Medium
8 of 238
Remembering +4 | -1
According to work-energy theorem, the work done by the net force on a particle is equal to the change in its
View answer and explanation
Correct option: A
Kinetic energy
The correct answer is A (Kinetic energy) because the work-energy theorem states that the net work done on a particle equals the change in its kinetic energy.
9 Medium
9 of 238
Analyzing +4 | -1
Two masses MA{M_A} and MB{M_B} moving with velocities VA{V_A} and VB{V_B} in opposite direction collide elastically. After that the masses MA{M_A} and MB{M_B} moving with velocity VB{V_B} and VA{V_A} respectively. The ratio (mA/mB)\left( {{m_A}/{m_B}} \right) is
View answer and explanation
Correct option: A
1
Option A (1) is correct because the given conditions imply that the masses are equal.
10 Medium
10 of 238
Application +4 | -1
A body is projected at an angle θ\theta to the horizontal with kinetic energy Ek{E_k}. The potential energy at the highest point of the trajectory is
View answer and explanation
Correct option: C
Eksin⁡2θ{E_k}{\sin ^2}\mathrm{\theta }
Option C (Eksin⁡2θ{E_k}{\sin ^2}\mathrm{\theta }) is correct because it is derived from the conservation of energy and the projectile motion principles.
11 Medium
11 of 238
Analyzing +4 | -1
Select the correct alternative(s)
a) Work done by static friction is always zero
b) Work done by kinetic friction can be positive also
c) Kinetic energy of a system can not be increased without applying any external force on the system
d) Work energy theorem is valid in non-inertial frames also
View answer and explanation
Correct option: B
a, b, d
Option B (a, b, d) is correct because work done by static friction can be zero, work done by kinetic friction can be positive, and the work-energy theorem is valid in non-inertial frames.
12 Medium
12 of 238
Understanding +4 | -1
One end of a light spring of spring constant kk is fixed to a wall and the other end is tied to a block placed on a smooth horizontal surface. In a displacement, the work done by the spring is (1/2)kx2(1 / 2) k x^2. The possible cases are
View answer and explanation
Correct option: A
the spring was initially compressed by a distance xx and was finally in its natural length
The spring was initially compressed by a distance xx and was finally in its natural length. The work done by the spring is positive when it returns to its natural length from a compressed state.
13 Medium
13 of 238
Application +4 | -1
The potential energy of a particle in a force field is U=Ar2−BrU = \frac{A}{{{r^2}}} - \frac{B}{r}, where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is
View answer and explanation
Correct option: B
2A/B
Option B (2A/B) is correct because it is found by setting the derivative of the potential energy function to zero and solving for r.
14 Medium
14 of 238
Analyzing +4 | -1
The potential energy of a particle varies with x according to the relation U(x)=x2−4xU\left( x \right) = {x^2} - 4x . The point x = 2 is a point of
View answer and explanation
Correct option: A
Stable equilibrium
Option A (Stable equilibrium) is correct because the second derivative of the potential energy is positive at x = 2.
15 Medium
15 of 238
Analyzing +4 | -1
A car is moving on a circular path and takes a turn. If R1 and R2{R_1}\,and\,{R_2} be the reactions on the inner and outer wheels respectively, then
View answer and explanation
Correct option: B
R1<R2{R_1} < {R_2}
Option B (R1<R2{R_1} < {R_2}) is correct because the outer wheels bear more weight due to the turning effect and the center of gravity shifting outwards.

Explore Other Chapters in PHYSICS

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UNITS & MEASUREMENTS 392 MCQs MECHANICAL PROPERTIES OF FLUIDS 317 MCQs MOTION IN PLANE 307 MCQs MAGNETIC EFFECT OF CURRENT 282 MCQs THERMAL PROPERTIES OF MATTER 269 MCQs GRAVITATION 258 MCQs
16 Medium
16 of 238
Understanding +4 | -1
You lift a heavy book from the floor of the room and keep it in the book&ndash;shelf having a height 2 m. In this process you take 5 seconds. The work done by you will depend upon
View answer and explanation
Correct option: B
Weight of the book and height of the book-shelf
Option B (Weight of the book and height of the book-shelf) is correct because the work done against gravity depends on the weight and the vertical displacement.
17 Medium
17 of 238
Understanding +4 | -1
Work done by the gravitational force on a body of mass &lsquo;m&rsquo; moving on a smooth horizontal surface through a distance &lsquo;s&rsquo; is.
View answer and explanation
Correct option: C
0
Option C is correct because the gravitational force acts vertically, and the displacement is horizontal, making the work done zero.
18 Medium
18 of 238
Understanding +4 | -1
If a particle is compelled to move on a given smooth plane curve under the action of given forces in the plane F⃗=xi^+yj^\mathbf{\vec F} = x\hat i + y\hat j , then
View answer and explanation
Correct option: A
F⃗.dr→=x  dx+y  dy\mathbf{\vec F}.\overrightarrow {\mathbf{dr}} = x\,\,dx + y\,\,dy
Option A is correct because the dot product of the force and displacement vectors equals xdx + ydy, representing the work done by the force.
19 Medium
19 of 238
Analyzing +4 | -1
Two particles A and B move with constant velocities v1→  and  v2→\overrightarrow {{v_1}} \,\,\mathrm{and}\,\,\overrightarrow {{v_2}}. At the initial moment their position vectors r1→  and  r2→\overrightarrow {{r_1}} \,\,\mathrm{and}\,\,\overrightarrow {{r_2}}
respectively. The condition for particles A and B for their collision is:
View answer and explanation
Correct option: B
r1→ − r2→  ∣r1→ − r2→∣ = v⃗2−v⃗1∣v⃗2−v⃗1∣ \frac{{\overrightarrow {{r_1}} \, - \,\overrightarrow {{r_2}} \,\,}}{{\left| {\overrightarrow {{r_1}} \, - \,\overrightarrow {{r_2}} } \right|}}\, = \,\frac{{{{\vec v}_2} - {{\vec v}_1}}}{{\left| {{{\vec v}_2} - {{\vec v}_1}} \right|}}\,
Option B is correct because it states that the relative position vector and the relative velocity vector must be in the same direction for a collision to occur.
20 Medium
20 of 238
Analyzing +4 | -1
Statement I A point particle of mass mm moving with speed vv collides with stationary point particle of mass MM. If the maximum energy loss possible is given as f(12mv2)f\left(\frac{1}{2} m v^2\right), then

f=(MM+m)f=\left(\frac{M}{M+m}\right)

Statement II Maximum energy loss occurs when the particles get stuck together as a result of the collision.
View answer and explanation
Correct option: A
If both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.
The correct answer is A because Statement I is correct, Statement II is correct, and Statement II is the correct explanation of Statement I. The maximum energy loss occurs when the particles stick together, leading to the given expression for energy loss.
21 Medium
21 of 238
Remembering +4 | -1
Work done by a conservative force on a system is equal to
View answer and explanation
Correct option: B
The change in potential energy of the system
The correct answer is B. Work done by a conservative force is equal to the negative change in potential energy, which can be stated as the change in potential energy with a negative sign.
22 Medium
22 of 238
Application +4 | -1
A 2.0 kg block is dropped from a height of 40 cm onto a spring of spring constant k=1960  Nm−1k = 1960\;\mathrm{N}{\mathrm{m}^{ - 1}} . Find the maximum distance the spring is compressed
View answer and explanation
Correct option: D
0.10m0.10\mathrm{ }m
Option D (0.10m0.10\mathrm{ }m) is correct because it's calculated by equating the potential energy loss of the block to the spring's potential energy gain at maximum compression.
23 Medium
23 of 238
Application +4 | -1
A rock of mass m is dropped to the ground from a height h. A second rock with mass 2m is dropped from the same height. When second rock strikes the ground, what is its kinetic energy?
View answer and explanation
Correct option: A
Twice that of the first rock
Option A (Twice that of the first rock) is correct because the kinetic energy is directly proportional to the mass when dropped from the same height.
24 Medium
24 of 238
Analyzing +4 | -1
A free body of mass 8 kg is travelling at 2 meter per second in a straight line. At a certain instant, the body splits into two equal parts due to internal explosion which releases 16 joules of energy. Neither part leaves the original line of motion finally, then
View answer and explanation
Correct option: B
One part comes to rest and the other moves in the same direction as that of the original body
Option B (One part comes to rest and the other moves in the same direction as that of the original body) is correct because it satisfies the conservation of momentum and energy after the explosion.
25 Medium
25 of 238
Analyzing +4 | -1
The potential energy function along the positive xx-axis is given by U(x)=−ax+bx,aU(x)=-a x+\frac{b}{x}, a and bb are constants. If it is known that the system has only one stable equilibrium configuration, the possible values of aa and bb are
View answer and explanation
Correct option: A
a=−1,b=2a=-1, b=2
Option A (a=−1,b=2a=-1, b=2) is correct. For stable equilibrium, the second derivative of the potential energy must be positive, and the first derivative must be zero at the equilibrium point.
26 Medium
26 of 238
Application +4 | -1
A body of mass 10 kg is acted upon by two forces each of magnitude 10 N making an angle of 600{60^0} with each other. Find the net acceleration of the body
View answer and explanation
Correct option: B
3ms−2\sqrt 3 \mathrm{m}{\mathrm{s}^{ - 2}}
Option B (3ms−2\sqrt 3 \mathrm{m}{\mathrm{s}^{ - 2}}) is correct because the net force is the resultant of the two forces, and acceleration is calculated using Newton's second law.
27 Medium
27 of 238
Understanding +4 | -1
Assertion (A) : When water in a bucket is whirled fast overhead, the water does not fall out at the top of the circular path.

Reason (R) : The centripetal force in this position on water is more than the weight of water.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
Option A is correct because the water doesn't fall out due to the centripetal force being greater than the weight of the water at the top of the circular path.
28 Medium
28 of 238
Application +4 | -1
A ball of mass m moving the velocity V collides head on with another ball of the same mass at rest. If e is coefficient of restitution, their velocities after collision are
View answer and explanation
Correct option: A
(1−e)V2,(1+e)V2\frac{{\left( {1 - e} \right)V}}{2},\frac{{\left( {1 + e} \right)V}}{2}
Option A ((1−e)V2,(1+e)V2\frac{{\left( {1 - e} \right)V}}{2},\frac{{\left( {1 + e} \right)V}}{2}) is correct because it represents the velocities after collision derived from conservation of momentum and the coefficient of restitution.
29 Medium
29 of 238
Remembering +4 | -1
For motion under an external conservative force, which quantity is conserved?
View answer and explanation
Correct option: B
Mechanical energy
Option A (A body can have momentum without energy) is the wrong statement because a body with momentum must have kinetic energy, as momentum is directly related to velocity and mass.
30 Medium
30 of 238
Application +4 | -1
When a 1.0 kg mass hangs attached to a spring of length 50 cm, the spring stretches by 2 cm. The mass is pulled down until the length of the spring becomes 60 cm. What is the amount of elastic energy stored in the spring in this condition, if g=10  m/s2g = 10\;m/{s^2}
View answer and explanation
Correct option: B
2.0 joule
Option B (2.0 joule) is correct because it is the elastic potential energy calculated using the spring constant and the final extension.
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