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NEET • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Medium

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Showing 31-60 of 238 questions
31 Medium
31 of 238
Remembering +4 | -1
The angular acceleration of a body, moving along the circumference of a circle, is
View answer and explanation
Correct option: B
Along the axis of rotation
Option B (Along the axis of rotation) is correct because angular acceleration is a vector quantity that points along the axis of rotation, determined by the right-hand rule.
32 Medium
32 of 238
Analyzing +4 | -1
The potential energy of a particle of mass 1 kg1 \mathrm{~kg} is U=10+(x−2)2U=10+(x-2)^2. Here, UU is in joule and xx in metre on the positive XX-axis. Particle travels upto x=+6 mx=+6 \mathrm{~m}. Choose the correct option.
View answer and explanation
Correct option: C
Both (1) and (2) are correct
Option C (Both (1) and (2) are correct) is correct. The particle oscillates between x = -2 and x = 6, and the maximum kinetic energy is found by calculating the potential energy difference.
33 Medium
33 of 238
Analyzing +4 | -1
Identify the correct statements from the following:

A. Work done by a man in lifting a bucket out of a well by means of rope tied to the bucket is negative.

B. Work done by gravitational force in lifting a bucket out of a well by a rope tied to the bucket is negative.

C. Work done by friction on a body sliding down an inclined plane is positive.

D. Word done by an applied force on a body moving on a rough horizontal plane with uniform velocity is zero.

E. Work done by the air resistance on an oscillating pendulum is negative.

Choose the correct answer from the options given below:
View answer and explanation
Correct option: B
B and E only
Option B (B and E only) is correct. Work done by gravity when lifting is negative, and work done by air resistance is always negative.
34 Medium
34 of 238
Analyzing +4 | -1
Potential energy function along xx-axis in a certain force field is given as U(x)=x44−2x3+112x2−6xU(x)=\frac{x^4}{4}-2 x^3+\frac{11}{2} x^2-6 x. For the given force field,

(i) the points of equilibrium are x=1,x=2x=1, x=2 and x=3x=3

(ii) the points x=2x=2 is a point of unstable equilibrium

(iii) the points x=1x=1 and x=3x=3 are points of stable equilibrium

(iv) there exists no point of neutral equilibrium Which one of the following is the set of correct options?
View answer and explanation
Correct option: B
(i), (ii), (iii), (iv)
Option B ((i), (ii), (iii), (iv)) is correct. All the statements are correct based on the analysis of the potential energy function and its derivatives.
35 Medium
35 of 238
Understanding +4 | -1
Which of the following statements is FALSE for a particle moving in a circle with a constant angular speed?
View answer and explanation
Correct option: B
The acceleration vector is tangent to the circle
Option B (The acceleration vector is tangent to the circle) is correct because, in circular motion, the acceleration vector points towards the center of the circle (centripetal acceleration), not tangent to it.
36 Medium
36 of 238
Analyzing +4 | -1
The potential energy function associated with the force F⃗=4xyi^+2x2j^\vec{F}=4 x y \hat{i}+2 x^2 \hat{j} is
View answer and explanation
Correct option: D
Not defined
Option D (Not defined) is correct because the given force is non-conservative, meaning the work done depends on the path, and a potential energy function cannot be defined.
37 Medium
37 of 238
Application +4 | -1
A point of application of a force F⃗=5i^−4j^+2k^\mathrm{\vec F} = 5\hat i - 4\hat j + 2\hat k is moved from r1→=2i^+7j^+4k^ to r2→=5i^+2j^+3k^\overrightarrow {{\mathrm{r}_1}} = 2\hat i + 7\hat j + 4\hat k\,to\,\overrightarrow {{\mathrm{r}_2}} = 5\hat i + 2\hat j + 3\hat k the work done is
View answer and explanation
Correct option: A
22 units
Option A (22 units) is correct because the work done is the dot product of the force and the displacement vector.
38 Medium
38 of 238
Analyzing +4 | -1
The displacement x in metre of a particle of mass m kg moving in one dimension under the action of a force is related to the time t in second by the equation t=x+3t = \sqrt x + 3, the work done by the force (in joule) in first six seconds is
View answer and explanation
Correct option: B
Zero
Option B (Zero) is correct because the work done by the force is zero as the velocity remains constant after t=3s.
39 Medium
39 of 238
Analyzing +4 | -1
Statement I: The tendency to overturn of skidding/overturning is quadrupled, when a cyclist doubles his speed of turning.

Statement II: tan⁡θ=v2Rg⇒\tan \theta=\frac{\mathrm{v}^2}{\mathrm{Rg}} \Rightarrow becomes 4 times as vv doubled.
View answer and explanation
Correct option: A
If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I
The correct answer is A. Statement I is true because the overturning tendency is related to the centripetal force, which increases with the square of the velocity. Statement II correctly explains this relationship with the formula for the banking angle.
40 Medium
40 of 238
Application +4 | -1
A small ball is dropped from a height of 10 m on horizontal floor. If the coefficient of restitution between ground and ball is 0.5 then maximum height to which ball will rise after second collision with ground is
View answer and explanation
Correct option: B
62.5 cm
Option B (62.5 cm) is correct because after each collision, the height is reduced by a factor of e2e^2, where e is the coefficient of restitution.
41 Medium
41 of 238
Application +4 | -1
Two masses of M and 4M are moving with equal kinetic energy. The ratio of their linear momentum is
View answer and explanation
Correct option: C
1:21:2
Option C is correct because the ratio of linear momenta is the square root of the ratio of the masses when kinetic energies are equal.
42 Medium
42 of 238
Understanding +4 | -1
A peculiar spring has a force law F=−dx3F=-{d} x^3 which of the following is true?
View answer and explanation
Correct option: A
Potential energy at point xx when U=0U=0 at x=0x=0 is dx44\frac{d x^4}{4}
Option A (Potential energy at point xx when U=0U=0 at x=0x=0 is dx44\frac{d x^4}{4}) is correct because the potential energy is the integral of the force with respect to displacement.
43 Medium
43 of 238
Application +4 | -1
A cane filled with water is revolved in a vertical circle of radius 4 m and the water just does not fall down. The time period of revolution will be
View answer and explanation
Correct option: D
4 sec
Option D (4 sec) is correct because it is the time period calculated using the condition that the water just does not fall down, implying the minimum speed at the top is gr\sqrt{gr}.
44 Medium
44 of 238
Understanding +4 | -1
Statement-I: The work done by all forces on a system equals to the change in kinetic energy of that system. This statement is true even if non-conservative forces act on the system.
Statement-II: The total work done by internal forces may be positive.
View answer and explanation
Correct option: A
Statement-I &\& II are true.
Statement-I & II are true. The work done by all forces equals the change in kinetic energy, and internal forces can do positive work.
45 Medium
45 of 238
Application +4 | -1
A body of mass 5 kg is placed at the origin, and can move only on the x-axis. A force of 10 N is acting on it in a direction making an angle of 600{60^0} with the x-axis and displaces it along the x-axis by 4 metres. The work done by the force is
View answer and explanation
Correct option: D
20 J
Option D (20 J) is correct because the work done is calculated by multiplying the force component along the displacement with the displacement.
46 Medium
46 of 238
Understanding +4 | -1
Work done by a frictional force is
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because frictional force can do positive, negative, or zero work depending on the frame of reference and the direction of motion.
47 Medium
47 of 238
Application +4 | -1
A body moves from a position r1=(2i^−3j^−4k^){r_1} = \left( {2\hat i - 3\hat j - 4\hat k} \right) m to a position, r2=(3i^−43j^−5k^){r_2} = \left( {3\hat i - 43\hat j - 5\hat k} \right) m under the influence of a constant force F=(4i^−4j^+5k^)F = \left( {4\hat i - 4\hat j + 5\hat k} \right) N. The work done by the force is
View answer and explanation
Correct option: A
57 J
Option A (57 J) is correct because the work done is the dot product of the force and the displacement vector.
48 Medium
48 of 238
Understanding +4 | -1
You accidentally bump into a bookcase. It tilts briefly but then returns to upright, and you breathe a sigh of relief. When you first bumped the bookcase, its center of gravity moved
View answer and explanation
Correct option: A
Upward and its gravitational potential energy increased.
The correct answer is A. When the bookcase tilts, its center of gravity rises, increasing its gravitational potential energy, which then causes it to return to its upright position.
49 Medium
49 of 238
Understanding +4 | -1
Which of the following quantities measured from different inertial reference frames are same?
View answer and explanation
Correct option: D
Kinetic energy
Option A (Force) is correct because force is invariant under Galilean transformations, meaning it remains the same in different inertial frames.
50 Medium
50 of 238
Understanding +4 | -1
For a particle in non-uniform accelerated circular motion
View answer and explanation
Correct option: D
Velocity is transverse and acceleration has both radial and transverse components
The correct answer is D. In non-uniform accelerated circular motion, the velocity is always tangential (transverse), and the acceleration has both radial (centripetal) and tangential components because both the direction and magnitude of the velocity are changing.
51 Medium
51 of 238
Understanding +4 | -1
If F is the force required to keep a train moving at a constant speed v,the power required is
View answer and explanation
Correct option: D
Fv  Fv\;
Option D (Fv  Fv\;) is correct because power is the product of force and velocity when the force is constant and the velocity is constant.
52 Medium
52 of 238
Application +4 | -1
A sphere of mass M moving with velocity collides elastically with another of mass ‘m’ at rest. After collision their final velocities are V1  and  V2{V_1}\,\,and\,\,{V_2} then the value of  V2\,{V_2} is
View answer and explanation
Correct option: D
2u1+mM\frac{{2u}}{{1 + \frac{m}{M}}}
Option C (2u1+Mm\frac{{2u}}{{1 + \frac{M}{m}}}) is correct because it is derived from conservation of momentum and kinetic energy in an elastic collision.
53 Medium
53 of 238
Understanding +4 | -1
For inelastic collision between two spherical rigid bodies
View answer and explanation
Correct option: D
The liner momentum is conserved
Option D (The liner momentum is conserved) is correct because, in any collision (elastic or inelastic), the total linear momentum of the system is always conserved in the absence of external forces.
54 Medium
54 of 238
Application +4 | -1
A light and a heavy body have equal momenta. Which one has greater K.E.
View answer and explanation
Correct option: A
The light body
Option A (The light body) is correct because for equal momenta, kinetic energy is inversely proportional to mass; hence, the lighter body has greater kinetic energy.
55 Medium
55 of 238
Application +4 | -1
A body constrained to move in Y direction, is subjected to a force given by F⃗=(−2i^+15j^+6k^)\mathrm{\vec F} = \left( { - 2\hat i + 15\hat j + 6\hat k} \right) N done by this force in moving the body through a distance of 10m along Y axis?
View answer and explanation
Correct option: C
150 J
Option C is correct because only the y-component of the force contributes to the work done when the displacement is along the y-axis.
56 Medium
56 of 238
Understanding +4 | -1
When a body moves with a constant speed along a circle
View answer and explanation
Correct option: A
No work is done on it
Option A is correct because the force is always perpendicular to the displacement, hence no work is done.
57 Medium
57 of 238
Application +4 | -1
A uniform chain of mass M and length L is lying on a frictionless table in such a way that its 1/3 part is hanging vertically down. The work done in pulling the chain up the table is
View answer and explanation
Correct option: D
MgL18\frac{{MgL}}{{18}}
Option D (MgL18\frac{{MgL}}{{18}}) is correct because the work done is equal to the change in potential energy of the hanging part of the chain.
58 Medium
58 of 238
Understanding +4 | -1
A ball of mass m moves with speed v and strikes a wall having infinite mass and it returns with same speed then the work done by the ball on the wall is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because the wall's displacement is zero, hence no work is done on the wall.
59 Medium
59 of 238
Understanding +4 | -1
Which of the following statements is false for a particle moving in a circle with a constant angular speed?
View answer and explanation
Correct option: B
The acceleration vector is tangent to the circle
The correct answer is B. For a particle moving in a circle with constant angular speed, the acceleration vector points towards the center of the circle (centripetal acceleration), and the velocity vector is tangent to the circle. Therefore, the statement that the acceleration vector is tangent to the circle is false.
60 Medium
60 of 238
Analyzing +4 | -1
Two students are sitting face to face, at two ends of a long compartment of a train, running at a constant acceleration. They toss a ball to each other, with the same muzzle velocity and at the same inclination to the vertical.
Statement-1: The time intervals for the free fall in either direction are equal.
Statement-2: In the frame of compartment velocity is changing but the vertical velocity remains unaffected by the horizontal acceleration of the cart.
View answer and explanation
Correct option: A
Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1) is correct because the time intervals are equal due to the vertical motion being unaffected by the horizontal acceleration of the train compartment.
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