Skip to main content
Back to WORK-ENERGY-POWER

Your Progress

0 / 74 Answered
0
Correct
0
Incorrect
0%
Accuracy
NEET • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Easy

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →
Showing 1-30 of 74 questions
1 Easy
1 of 74
Application +4 | -1
A{A} ball is dropped on the ground from a height of 2 m2 {~m}. If the coefficient of restitution is 0.6 , the height to which the ball will rebound is
View answer and explanation
Correct option: A
0.72 m0.72 {~m}
Option A (0.72 m0.72 {~m}) is correct because the height of rebound is calculated using the coefficient of restitution formula.
2 Easy
2 of 74
Application +4 | -1
When a spring is compressed by 3 cm, the potential energy stored in it is U. When it is compressed further by 3 cm, the increase in potential energy is
View answer and explanation
Correct option: D
3 U
The correct answer is D. The potential energy stored in a spring is proportional to the square of the compression. Compressing it further by 3 cm results in a total compression of 6 cm, leading to a potential energy of 4U, so the increase is 3U.
3 Easy
3 of 74
Understanding +4 | -1
Statement I When a machine-gun fires nn bullets per second with kinetic energy KK, then the power of the machine-gun is P=nKP=n K.

Statement II Power = Work  Time =nk1=\frac{\text { Work }}{\text { Time }}=\frac{n k}{1}
View answer and explanation
Correct option: A
If both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.
Option A is correct because Statement I correctly defines the power of a machine gun firing bullets, and Statement II correctly explains the power calculation as work done per unit time.
4 Easy
4 of 74
Application +4 | -1
A body of mass 5 kg is revolving along a circle of a radius 3 m with a uniform speed of 6 m/s. The centripetal force acting on a body is
View answer and explanation
Correct option: D
60 N
Option D (60 N) is correct because the centripetal force is calculated using the formula F=mv2/rF = mv^2/r, where m is the mass, v is the velocity, and r is the radius.
5 Easy
5 of 74
Understanding +4 | -1
A particle moving with uniform speed in a circular path maintains:
View answer and explanation
Correct option: C
Varying velocity and varying acceleration
Option C (Varying velocity and varying acceleration) is correct because in circular motion, the direction of velocity and acceleration continuously changes, even if the speed is uniform.
6 Easy
6 of 74
Understanding +4 | -1
Which of the following is true?
View answer and explanation
Correct option: C
Momentum is conserved in all collisions but not kinetic energy.
Option C is correct because momentum is always conserved in all types of collisions, but kinetic energy is only conserved in elastic collisions.
7 Easy
7 of 74
Understanding +4 | -1
Potential energy is defined
View answer and explanation
Correct option: A
Only in conservative field
The correct answer is A. Potential energy is defined only in conservative fields because the work done is path-independent in such fields, allowing for a unique potential energy value at each point.
8 Easy
8 of 74
Understanding +4 | -1
In elastic collision, 100% energy transfer takes place when
View answer and explanation
Correct option: A
m1=m2{m_1} = {m_2}
Option A (m1=m2{m_1} = {m_2}) is correct because maximum energy transfer occurs in an elastic collision when the masses of the colliding objects are equal.
9 Easy
9 of 74
Analyzing +4 | -1
Assertion (A): In circular motion work done by all the forces acting on the body is zero.

Reason (R) : Centripetal force and velocity are mutually perpendicular.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D is correct because the assertion is false; work is not always zero in circular motion. The reason is true; centripetal force and velocity are always perpendicular.
10 Easy
10 of 74
Understanding +4 | -1
Assertion: Centripetal force does no work.

Reason: Force and displacement are perpendicular to each other.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because centripetal force acts perpendicular to the displacement, resulting in zero work done.
11 Easy
11 of 74
Application +4 | -1
From a water fall, water is pouring down at the rate of 90 kg/s on the blades of a turbine. If the height of the fall is 90 m the power delivered to the turbine is approximately equal to
View answer and explanation
Correct option: D
81 kw
The correct answer is A. The power delivered to the turbine is calculated using the formula P=mgh/tP = mgh/t, where m/t is the mass flow rate, g is the acceleration due to gravity, and h is the height of the fall.
12 Easy
12 of 74
Application +4 | -1
Two bodies of masses m1  and  m2{m_1}\,\,\mathrm{ and }\,\,{m_2} have same kinetic energy. The ratio of their momentum is
View answer and explanation
Correct option: B
m1m2\sqrt {\frac{{{m_1}}}{{{m_2}}}}
Option B (m1m2\sqrt {\frac{{{m_1}}}{{{m_2}}}}) is correct because it is derived from the relationship between kinetic energy and momentum.
13 Easy
13 of 74
Analyzing +4 | -1
The two moving particles collide and clump together on a smooth horizontal surface. The following statements are given below
a) Mechanical energy is conserved
b) Total energy is conserved
c) Work done by the system is positive
d) Work done by the system is negative
Choose the correct option.
View answer and explanation
Correct option: D
(b) and (d) are correct
Option D ((b) and (d) are correct) is correct because in an inelastic collision, total energy is conserved, but mechanical energy is not, and the work done by the system is negative due to energy loss.
14 Easy
14 of 74
Application +4 | -1
A body mass 9 kg is raised from a certain depth. By the time it is raised by 9m if its velocity is 2 m/s work done during this time is (take g=10 m/s2g = 10\,m/{s^2})
View answer and explanation
Correct option: A
828 J
Option A (828 J) is correct because the work done is equal to the change in potential energy plus the change in kinetic energy.
15 Easy
15 of 74
Application +4 | -1
A force of 5 N is applied on a 20 kg mass at rest. The work done in the third second is,
View answer and explanation
Correct option: A
258J\frac{{25}}{8}J
Option A (258J\frac{{25}}{8}J) is correct because the work done is calculated using the distance traveled in the third second and the applied force.
16 Easy
16 of 74
Application +4 | -1
An artillery piece of mass M1M_1 fires a shell of mass M2M_2 horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is:
View answer and explanation
Correct option: A
M2M1\frac{M_2}{M_1}
Option A (M2M1\frac{M_2}{M_1}) is correct because it is derived from the conservation of momentum and the definition of kinetic energy.
17 Easy
17 of 74
Application +4 | -1
A bag of sand of mass 9.8 kg9.8 \mathrm{~kg} is suspended by a rope. A bullet of 200 g200 \mathrm{~g} travelling with speed 10 ms−110 \mathrm{~ms}^{-1} gets embedded in it, then loss of kinetic energy will be
View answer and explanation
Correct option: B
9.8 J
Option A (4.9 J) is correct because it is the loss of kinetic energy calculated after the bullet gets embedded in the sandbag using conservation of momentum.
18 Easy
18 of 74
Application +4 | -1
A body of mass m accelerates uniformly from rest to v1{v_1} in time t1{t_1}. As a function of time t, the instantaneous power delivered to the body is
View answer and explanation
Correct option: D
mv12tt12\frac{{mv_1^2t}}{{t_1^2}}
Option D (mv12tt12\frac{{mv_1^2t}}{{t_1^2}}) is correct because the instantaneous power is calculated using P=FvP = Fv, where F=maF = ma and a=v1t1a = \frac{{v_1}}{{t_1}}, leading to the given expression.
19 Easy
19 of 74
Application +4 | -1
The wheel of radius 4 cm with a linear velocity 5 ms−1.5\,m{s^{ - 1}}. What is the angular velocity of the wheel in rad/sec is
View answer and explanation
Correct option: B
125
Option B (125) is correct because the angular velocity is calculated using the formula ω=v/r\omega = v/r, where v is the linear velocity and r is the radius.
20 Easy
20 of 74
Analyzing +4 | -1
Assertion: A cyclist leans inwards while taking a turn, while a man sitting in a car leans outwards on a curve.

Reason: Centripetal acceleration is acting towards the centre of the curve.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because both the cyclist leaning inwards and the man leaning outwards are due to the need to provide the necessary centripetal force, and the reason correctly states the direction of centripetal acceleration.
21 Easy
21 of 74
Application +4 | -1
Two stones are moving with same angular speeds in the radii of circular paths 1 m and 2 m. The ratio of their linear speed is ...X.... Here, X refers to
View answer and explanation
Correct option: B
45689
Option A (2) is correct because the ratio of linear speeds is calculated using v=rωv = r\omega, so v1/v2=r1/r2v_1/v_2 = r_1/r_2 since ω\omega is the same.
22 Easy
22 of 74
Application +4 | -1
A body is projected from ground obliquely. During downward motion power delivered by gravity to it
View answer and explanation
Correct option: A
Increases
The correct answer is A. During downward motion, the vertical component of velocity increases, and since power is the dot product of force and velocity, the power delivered by gravity increases.
23 Easy
23 of 74
Application +4 | -1
A block of mass mm is lowered with the help of a rope of negligible mass through a distance ‘dd’ with an acceleration of g3\frac{g}{3}. Work done by the rope on the block is
View answer and explanation
Correct option: B
−2Mgd3\frac{{ - 2Mgd}}{3}
Option B (−2Mgd3\frac{{ - 2Mgd}}{3}) is correct because the work done by the rope is negative as it acts upwards while the block moves downwards, and the tension is less than the weight due to the downward acceleration.
24 Easy
24 of 74
Application +4 | -1
The kinetic energy of a body is KK. If one – fourth of its mass is removed and velocity is doubled, its new kinetic energy is,
View answer and explanation
Correct option: B
3K3K
Option B (3K) is correct because the new kinetic energy is calculated by adjusting the mass and velocity in the kinetic energy formula.
25 Easy
25 of 74
Application +4 | -1
A bus of mass 6 metric tons is pulled at a speed of 18 kmpH on a smooth incline of inclination 1in 20. Power of the engine is [g=10 ms−2]\left[ {g = 10\,m{s^{ - 2}}} \right]
View answer and explanation
Correct option: A
15 kW
Option A is correct because the power is calculated by finding the component of weight along the incline and multiplying it by the velocity.
26 Easy
26 of 74
Application +4 | -1
A body of mass 8 kg8 \mathrm{~kg} and another of mass 2 kg2 \mathrm{~kg} are moving with equal kinetic energy. The ratio of their respective momenta will be
View answer and explanation
Correct option: B
2:12: 1
Option B (2:12: 1) is correct because the ratio of their momenta is calculated using the relationship between kinetic energy and momentum.
27 Easy
27 of 74
Application +4 | -1
Two masses of 1 kg and 4 kg are moving with equal kinetic energy. The ratio of their linear momentum is
View answer and explanation
Correct option: A
0.043055556
Option A (0.043055556) is incorrect. The correct ratio of their linear momentum is 0.5, not 0.043055556. The kinetic energy is equal, so 1/2∗m1∗v12=1/2∗m2∗v221/2 * m1 * v1^2 = 1/2 * m2 * v2^2. Therefore, v1/v2=sqrt(m2/m1)=sqrt(4/1)=2v1/v2 = sqrt(m2/m1) = sqrt(4/1) = 2. The ratio of momentum is $m1*v1 / (m2*v2) = 1*v1 / (4*v2) = 1/4 * v1/v2 = 1/4 * 2 = 1/2 = 0.5
28 Easy
28 of 74
Application +4 | -1
Two bodies of masses 4 kg4 \mathrm{~kg} and 5 kg5 \mathrm{~kg} are moving with equal momentum. Then the ratio of their respective kinetic energies is
View answer and explanation
Correct option: D
5:45: 4
Option D (5:45: 4) is correct because kinetic energy is inversely proportional to mass when momentum is constant, so the ratio of KE is the inverse ratio of masses.
29 Easy
29 of 74
Analyzing +4 | -1
Statement-1: A body can have energy without having momentum and vice versa.
Statement-2: The body having momentum must necessarily have kinetic energy.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because a body can have energy without having momentum (e.g., potential energy), but a body with momentum must have kinetic energy.
30 Easy
30 of 74
Remembering +4 | -1
Which among the following is a form of energy
View answer and explanation
Correct option: A
Light
Option A (Light) is correct because light is a form of electromagnetic energy.
Revision notes and key takeaways

Review WORK-ENERGY-POWER in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 74 single-correct-answer MCQs on WORK-ENERGY-POWER.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
Showing 1-30 of 74 questions
0 /74
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.