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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
A body is moving horizontally at a height of 9 m has its P.E = K.E. Then velocity of that body is
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Correct option: B
13.5 m/s
Option B (13.5 m/s) is correct because when potential energy equals kinetic energy, mgh=(1/2)mv2mgh = (1/2)mv^2, so v=2gh=2∗9.8∗9≈13.3m/sv = \sqrt{2gh} = \sqrt{2 * 9.8 * 9} \approx 13.3 m/s. The closest value is 13.5 m/s.

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