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NEET • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Medium

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Showing 61-90 of 210 questions

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61 Medium
61 of 210
Analyzing +4 | -1
A physical quantity x depends on quantities y and z as follows: x=Ay+Btan⁡C zx = Ay + B\tan C\,z where A, B and C are constants. Which of the following do not have the same dimensions
View answer and explanation
Correct option: D
x and A
Option D (x and A) is correct because the dimensions of x are not necessarily the same as A, since A is multiplied by y, and y may have different dimensions than x.
62 Medium
62 of 210
Application +4 | -1
In a vernier callipers, one main scale division is x  cmx\;cm and nn division of the vernier scale coincide with (n−1)\left( {n - 1} \right) divisions of the main scale. The least count (in cm) of the callipers is
View answer and explanation
Correct option: C
xn\frac{x}{n}
Option C (xn\frac{x}{n}) is correct because the least count is calculated by finding the difference between one main scale division and one vernier scale division.
63 Medium
63 of 210
Remembering +4 | -1
The unit of the coefficient of viscosity in S.I. system is
View answer and explanation
Correct option: D
kg/m−skg/m - s
Option D (kg/m−skg/m - s) is correct because it represents the correct SI unit for the coefficient of viscosity.
64 Medium
64 of 210
Remembering +4 | -1
The dimensions of surface tension are
View answer and explanation
Correct option: D
MT−2M{T^{ - 2}}
Option D (MT−2MT^{-2}) is correct because surface tension is force per unit length, and its dimensional formula reflects this relationship.
65 Medium
65 of 210
Application +4 | -1
The dimension of quantity (L/RCV) is
View answer and explanation
Correct option: C
[A−1]\left[ {{A^{ - 1}}} \right]
Option C ([A−1{A^{ - 1}}]) is correct because it involves finding the dimension of (L/RCV) where L is inductance, R is resistance, C is capacitance, and V is voltage. Since L/R has the dimension of time [T], CV has the dimension of charge [AT], and L/RCV becomes [T/AT] = [A-1].
66 Medium
66 of 210
Application +4 | -1
The position of a particle at time t is given by the relation x(t)=(v0α  )(1−eαt),  x\left( t \right) = \left( {\begin{array}{cccccccccccccccccccc} {\frac{{{v_0}}}{\alpha }}\\ \; \end{array}} \right)\left( {1 - {e^{\alpha t}}} \right),\; where v0{v_0} is constant and α>0\alpha > 0 . The dimensions of v0{v_0} and α\alpha are respectively
View answer and explanation
Correct option: A
M0L1T−1 and T−1{M^0}{L^1}{T^{ - 1}}\,and\,{T^{ - 1}}
Option A (M0L1T−1 and T−1{M^0}{L^1}{T^{ - 1}}\,and\,{T^{ - 1}}) is correct because the dimensions of x(t) must be length (L), which implies v0{v_0} has dimensions of LT−1LT^{-1} and α\alpha has dimensions of T−1T^{-1} to make the exponent dimensionless.
67 Medium
67 of 210
Analyzing +4 | -1
The physical quantity which is not a unit of energy is
View answer and explanation
Correct option: B
MeV-sec
Option B (MeV-sec) is not a unit of energy because MeV is a unit of energy, and multiplying it by seconds gives a unit of energy multiplied by time, not just energy.
68 Medium
68 of 210
Remembering +4 | -1
What is the SI unit of electron mobility?
View answer and explanation
Correct option: A
m2V−1s−1\mathrm{m}^2 \mathrm{V}^{-1} \mathrm{s}^{-1}
Option A (m² V⁻¹ s⁻¹) is correct because electron mobility is defined as drift velocity per unit electric field, leading to these units.
69 Medium
69 of 210
Application +4 | -1
The dimension of magnetic field in M, L, T and C (coulomb) is given as
View answer and explanation
Correct option: B
MT−1C−1M{T^{ - 1}}{C^{ - 1}}
Option B (MT−1C−1M{T^{ - 1}}{C^{ - 1}}) is correct because it correctly represents the dimensions of the magnetic field in terms of mass, time, and charge.
70 Medium
70 of 210
Remembering +4 | -1
The dimensions of stress are equal to
View answer and explanation
Correct option: B
Pressure
Option B (Pressure) is correct because stress is defined as force per unit area, which is the same definition as pressure.
71 Medium
71 of 210
Understanding +4 | -1
The unit of potential energy is
View answer and explanation
Correct option: B
g(cm/sec)2g{\left( {cm/\mathrm{sec}} \right)^2}
Option B (g(cm/sec)2g{\left( {cm/\mathrm{sec}} \right)^2}) is correct because potential energy is related to mass, gravitational acceleration, and height, resulting in these units.
72 Medium
72 of 210
Analyzing +4 | -1
The thrust developed by a rocket-motor is given by F=mv+A(p1−p2)F = mv + A\left( {{p_1} - {p_2}} \right), where m is the mass of the gas ejected per unit time, vv is velocity of the gas, A is area of cross-section of the nozzle, p1.p2{p_1}.{p_2} are the pressures of the exhaust gas and surrounding atmosphere. The formula is dimensionally
View answer and explanation
Correct option: A
Correct
Option A (Correct) is correct because both terms in the equation have the dimensions of force.
73 Medium
73 of 210
Remembering +4 | -1
Unit of Stefan's constant is
View answer and explanation
Correct option: B
Jm−2 s−1 K−4\mathrm{Jm}^{-2} \mathrm{~s}^{-1} \mathrm{~K}^{-4}
Option B (Jm−2 s−1 K−4\mathrm{Jm}^{-2} \mathrm{~s}^{-1} \mathrm{~K}^{-4}) is correct because Stefan's constant relates radiated power to area and temperature, hence the units.
74 Medium
74 of 210
Analyzing +4 | -1
Which of the following is not represented in correct unit
View answer and explanation
Correct option: C
Energy =kg-m/sec
Option C (Energy = kg-m/sec) is not represented in the correct unit because the correct unit for energy is kg-m²/sec² (Joule).
75 Medium
75 of 210
Application +4 | -1
If L=2.331  cm,  B=2.1  cm,L = 2.331\;cm,\;B = 2.1\;cm, then L+B=
View answer and explanation
Correct option: C
4.4 cm
Option C (4.4 cm) is correct because the sum should be rounded to the least number of decimal places among the given lengths.
76 Medium
76 of 210
Application +4 | -1
In the equation XX=3YZ2X = 3Y{Z^2} X and Z have dimensions of capacitance and magnetic induction respectively. In MKS system, the dimensional formula of Y is
View answer and explanation
Correct option: D
M−3L−2Q4T4{\mathrm{M}^{ - 3}}{\mathrm{L}^{ - 2}}{\mathrm{Q}^4}{\mathrm{T}^4}
Option C (M−3L−2Q4T8{\mathrm{M}^{ - 3}}{\mathrm{L}^{ - 2}}{\mathrm{Q}^4}{\mathrm{T}^8}) is correct because we can express the dimensions of Y in terms of capacitance (X) and magnetic induction (Z).
77 Medium
77 of 210
Analyzing +4 | -1
A quantity xx is given by (IFv2/WL4)\left(I F v^2 / W L^4\right) in terms of moment of inertia II, force FF, velocity vv, work WW and Length LL. The dimensional formula for xx is same as that of :
View answer and explanation
Correct option: C
energy density
Option C (energy density) is correct because the dimensional formula for xx matches that of energy density, which is [ML⁻¹T⁻²].
78 Medium
78 of 210
Application +4 | -1
In the relation y=r sin (ωt−kx),  \left( {\omega t - kx} \right),\;, the dimensions of ω/k\omega /k are
View answer and explanation
Correct option: B
[M0L1T−1]\left[ {{\mathrm{M}^0}{\mathrm{L}^1}{\mathrm{T}^{ - 1}}} \right]
Option B [M0L1T−1]\left[ {{\mathrm{M}^0}{\mathrm{L}^1}{\mathrm{T}^{ - 1}}} \right] is correct because ω/k represents the wave velocity, which has dimensions of length per time.
79 Medium
79 of 210
Application +4 | -1
If C and R represent capacitance and resistance respectively then the dimensions of RC are
View answer and explanation
Correct option: B
M0L0T{M^0}{L^0}T
Option B (M0L0T{M^0}{L^0}T) is correct because the dimensions of RC are equivalent to time, which is the time constant in an RC circuit.
80 Medium
80 of 210
Application +4 | -1
A Vernier Calipers has 1mm marks on the main scale. It has 20 equal divisions on the Vernier scale which match with 16 main scale divisions. For this Vernier calipers, the least count is
View answer and explanation
Correct option: D
0.2 mm
Option D (0.2 mm) is correct because the least count is calculated by finding the difference between one main scale division and the equivalent vernier scale division.
81 Medium
81 of 210
Application +4 | -1
Given X=(Gh/c3)1/2X = {\left( {Gh/{c^3}} \right)^{1/2}} , where G,h and c are gravitational constant, Planck’s constant and the velocity of light respectively. Dimensions of X are the same as those of
View answer and explanation
Correct option: C
Length
Option C (Length) is correct because dimensional analysis of the given expression results in the dimensions of length.
82 Medium
82 of 210
Remembering +4 | -1
Dimensional formula for force is
View answer and explanation
Correct option: B
[MLT−2]\left[ {\mathrm{ML}{\mathrm{T}^{ - 2}}} \right]
Option B ([MLT−2][\mathrm{ML}{\mathrm{T}^{ - 2}}]) is correct because force is mass times acceleration, and the dimensional formula for acceleration is [LT-2].
83 Medium
83 of 210
Understanding +4 | -1
The unit of self-inductance is
View answer and explanation
Correct option: C
Ohm second
Option C (Ohm second) is correct because self-inductance (L) is related to voltage (V) and rate of change of current (dI/dt) by V = L(dI/dt), so L = V/(dI/dt).
84 Medium
84 of 210
Remembering +4 | -1
What is the dimension of Luminous flux?
View answer and explanation
Correct option: A
[cd1][\mathrm{cd^1}]
Option A ([cd1][\mathrm{cd^1}]) is correct because Luminous flux is measured in lumens, and lumens are defined in terms of candela (cd), the SI unit of luminous intensity.
85 Medium
85 of 210
Remembering +4 | -1
The dimensions of torque are
View answer and explanation
Correct option: B
[ML2 T−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]
Option B ([ML²T⁻²]) is correct because torque is the product of force and distance, so its dimensions are [MLT⁻²][L] = [ML²T⁻²].
86 Medium
86 of 210
Analyzing +4 | -1
In the context of accuracy of measurement and significant figures in expressing results of experiment, which of the following is/are correct
(1) Out of the two measurements 50.14 cm and 0.00025 ampere, the first one has greater accuracy
(2) If one travels 478 km by rail and 397 m by road, the total distance travelled is 478 km
View answer and explanation
Correct option: C
Both are correct
Option C (Both are correct) is correct because both statements regarding accuracy and significant figures are valid.
87 Medium
87 of 210
Understanding +4 | -1
The number of significant figures in all the given numbers 25.12, 2009, 4.156 and 1.217×10−41.217 \times {10^{ - 4}} is
View answer and explanation
Correct option: D
4
Option D (4) is correct because each of the given numbers has four significant figures.
88 Medium
88 of 210
Understanding +4 | -1
Which of the following is/are the units of strength of magnetic field at a point?
View answer and explanation
Correct option: C
NA−1  m−1\mathrm{N}{\mathrm{A}^{ - 1}}\mathrm{\;}{\mathrm{m}^{ - 1}}
Option C (NA−1  m−1\mathrm{N}{\mathrm{A}^{ - 1}}\mathrm{\;}{\mathrm{m}^{ - 1}}) is correct because the magnetic force on a current-carrying wire is F = BIL, so B = F/(IL), and the units are N/(A*m).
89 Medium
89 of 210
Analyzing +4 | -1
Which of the following physical quantities have the
same dimensions?
View answer and explanation
Correct option: A
Electric displacement (D→)(\overrightarrow D )
and surface charge
density
Electric displacement (D→\overrightarrow D) and surface charge density have the same dimensions because electric displacement is defined as charge per unit area.
90 Medium
90 of 210
Application +4 | -1
Dimensions of permeability are
View answer and explanation
Correct option: A
A−2M1L1T−2{A^{ - 2}}{M^1}{L^1}{T^{ - 2}}
Option A (A−2M1L1T−2{A^{ - 2}}{M^1}{L^1}{T^{ - 2}}) is correct because it matches the dimensional formula for permeability derived from the force between two current-carrying wires.
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