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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1
If speed (V)(V), acceleration (A)(A) and force (F)(F) are considered as fundamental units, the dimension of Young’s modulus will be
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Correct option: D
[V−4A2F][{V^{ - 4}}{A^2}F]
Option D ([V−4A2F][{V^{ - 4}}{A^2}F]) is correct because it represents the dimensional formula of Young’s modulus in terms of velocity, acceleration, and force.

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