JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

Farad is not equivalent to

View answer and explanation

Correct option: B

q{v^2}

Option B (

q{v^2}

) is correct because Farad is the unit of capacitance, which is equivalent to

\frac{q}{V}

\frac{{{q^2}}}{J}

, and

\frac{J}{{{V^2}}}

, but not

q{v^2}

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