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NEET • CHEMISTRY • SOLID STATE

Solid state practice · Mixed difficulty

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Showing 181-210 of 238 questions

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181 Medium
181 of 238
Understanding +4 | -1
Which of the following statements is not correct?
View answer and explanation
Correct option: D
The coordination number of S2−  in  ZnS{\mathrm{S}^{2 - }}\;in\;\mathrm{ZnS} is 6
Option D (The coordination number of S2−  in  ZnS{\mathrm{S}^{2 - }}\;in\;\mathrm{ZnS} is 6) is correct because in ZnS, the coordination number of S2−S^{2-} is 4, not 6. Each S2−S^{2-} ion is tetrahedrally surrounded by Zn2+Zn^{2+} ions.
182 Medium
182 of 238
Analyzing +4 | -1
Assertion (A) Both Frenkel and Schottky defects are stoichiometric defects.

Reason (R) Both defects change the density of the crystalline solid.
View answer and explanation
Correct option: C
If Assertion is true but Reason is false.
Option C is correct because while Frenkel and Schottky defects are stoichiometric, only Schottky defects change the density of the solid.
183 Easy
183 of 238
Application +4 | -1
In a cubic crystal, A\mathrm{A} atom placed at every corners and B\mathrm{B} atom placed at every centre of face. The formula of compound is
View answer and explanation
Correct option: B
AB3A{B_3}
Option B (AB3A{B_3}) is correct because A atoms at the corners contribute 1/8 each, totaling 1 A atom, and B atoms at the face centers contribute 1/2 each, totaling 3 B atoms.
184 Easy
184 of 238
Remembering +4 | -1
For orthorhombic system axial ratios are a≠b≠ca \ne b \ne c and the axial angles are
View answer and explanation
Correct option: B
α=β=γ=900\alpha = \beta = \gamma = {90^0}
Option B is correct because in an orthorhombic system, the axial ratios are unequal (a≠b≠ca \ne b \ne c), but all the axial angles are equal to 90 degrees (α=β=γ=900\alpha = \beta = \gamma = 90^0).
185 Medium
185 of 238
Understanding +4 | -1
Which of the following point defects are shown by Ag Br (s) crystals

i) Schottky defect ii) Frenkel defect

iii) Metal excess defect iv) Metal deficiency defect
View answer and explanation
Correct option: A
i and ii
Option A (i and ii) is correct because AgBr(s) crystals show both Schottky and Frenkel defects.
186 Easy
186 of 238
Remembering +4 | -1
In antifluorite structure, the negative ions:
View answer and explanation
Correct option: C
Are arranged in ccp
Option C (Are arranged in ccp) is correct because in the antifluorite structure, the positions of cations and anions are reversed compared to the fluorite structure. The negative ions (anions) form the ccp lattice.
187 Hard
187 of 238
Application +4 | -1
Consider the bcc unit cells of the solids 1 and 2 with the position of atoms as shown below. The radius of atom BB is twice that of atom A.A. The unit cell edge length is 50% more is solid 2 than in 1. What is the approximate packing efficiency in solid 2?
View answer and explanation
Correct option: B
0.9
Option B is correct because the packing efficiency for solid 2 is calculated considering the increased edge length and the doubled radius of atom B. This results in a packing efficiency close to 0.9.
188 Medium
188 of 238
Remembering +4 | -1
Which type of solid crystals will conduct heat and electricity?
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Correct option: D
Metallic
Option D (Metallic) is correct because metallic solids have delocalized electrons that can conduct heat and electricity.
189 Medium
189 of 238
Understanding +4 | -1
The correct statement regarding F-centre is
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because F-centers involve electrons trapped in voids, which cause color and increase conductivity.
190 Easy
190 of 238
Understanding +4 | -1
Which of the following statement is true?
View answer and explanation
Correct option: D
A Frenkel defect is formed when an ion is displaced from its lattice site to an interstitial site
Option D (A Frenkel defect is formed when an ion is displaced from its lattice site to an interstitial site) is correct because this is the definition of a Frenkel defect.
191 Medium
191 of 238
Understanding +4 | -1
Which defect may be present in NaClNaCl crystal?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because NaCl crystals can exhibit Schottky defects, non-stoichiometric defects, and impurity defects.
192 Hard
192 of 238
Application +4 | -1
Experimentally it was found that a metal oxide has formula M0.98O.{M_{0.98}}O. Metal MM, present as M2+{M^{2 + }} and M3+{M^{3 + }} in its oxide. Fraction of the metal which exists as M3+{M^{3 + }} would be
View answer and explanation
Correct option: B
0.0408
Option B (0.0408) is correct because it represents the fraction of M that exists as M3+ calculated based on charge neutrality.
193 Medium
193 of 238
Application +4 | -1
The edge of unit cell of fcc Xe crystal is 620 pm. The radius of Xe atom is
View answer and explanation
Correct option: C
219.25pm219.25\mathrm{ }pm
Option C (219.25pm219.25\mathrm{ }pm) is correct because in an FCC lattice, the radius is related to the edge length by r=24ar = \frac{{\sqrt{2}}}{{4}}a.
194 Easy
194 of 238
Understanding +4 | -1
Density of a crystal remains unchanged as a result of
View answer and explanation
Correct option: C
Frenkel defect
Option C (Frenkel defect) is correct because Frenkel defects involve ions moving within the lattice, so the mass and volume remain constant, thus density remains unchanged.
195 Easy
195 of 238
Application +4 | -1
Sodium metal crystallizes in a body centred cubic lattice with the cell edge a=4.29A∘{\mathrm{a = }4.29\mathop \mathrm{A}\limits^ \circ }. The radius of sodium atom is :
View answer and explanation
Correct option: A
1.8574  A∘\mathrm{ }1.8574\;\mathop \mathrm{A}\limits^ \circ
Option A (1.8574;A∘\mathrm{ }1.8574;\mathop \mathrm{A}\limits^ \circ) is correct because it's the calculated radius for a BCC lattice given the edge length.
196 Medium
196 of 238
Understanding +4 | -1
The melting point of RbBr\mathrm{RbBr} is 682∘C\mathrm{682}^\circ \mathrm{C}, while that of NaF\mathrm{NaF} is 988∘C\mathrm{988}^\circ \mathrm{C}. The principle reason that melting point of NaF\mathrm{NaF} is much higher than that of RbBr\mathrm{RbBr} is that :
View answer and explanation
Correct option: C
The internuclear distance rc+ra{r_\mathrm{c}} + {r_\mathrm{a}} is greater for RbBr\mathrm{RbBr} than for NaF\mathrm{NaF}
Option C (The internuclear distance rc+ra{r_\mathrm{c}} + {r_\mathrm{a}} is greater for RbBr\mathrm{RbBr} than for NaF\mathrm{NaF}) is correct because a smaller internuclear distance in NaF leads to stronger electrostatic forces and thus a higher melting point.
197 Easy
197 of 238
Remembering +4 | -1
Potassium crystallizes in a bcc lattice, hence the coordination number of potassium metal is
View answer and explanation
Correct option: D
8
Option D (8) is correct because in a body-centered cubic (bcc) lattice, each atom is surrounded by 8 nearest neighbors, giving it a coordination number of 8.
198 Easy
198 of 238
Understanding +4 | -1
A solid XX melts slightly above 273  K273\;K and is a poor conductor of heat and electricity. To which of the following categories does it belong?
View answer and explanation
Correct option: D
Molecular
Option D (Molecular) is correct because molecular solids have low melting points and are poor conductors of heat and electricity due to weak intermolecular forces.
199 Medium
199 of 238
Application +4 | -1
An atom forms face centered cubic crystal with density d=8.92 g/mLd=8.92 \mathrm{~g} / \mathrm{mL} and edge length a=3.6×10−8 cma=3.6 \times 10^{-8} \mathrm{~cm}. The molecular mass of atom in amu is
View answer and explanation
Correct option: B
63 amu63 \mathrm{~amu}
Option B (63 amu63 \mathrm{~amu}) is correct because the molecular mass can be calculated using the density, edge length, Avogadro's number, and the number of atoms per FCC unit cell.
200 Medium
200 of 238
Understanding +4 | -1
If the value of ionic radius ratio (rcra)\left( {\frac{{{r_c}}}{{{r_a}}}} \right) is 0.52 in an ionic compound, the geometrical arrangement of ions in crystal is
View answer and explanation
Correct option: D
Octahedral
Option D (Octahedral) is correct because an ionic radius ratio of 0.52 falls within the range (0.414 - 0.732) that corresponds to an octahedral arrangement.
201 Easy
201 of 238
Understanding +4 | -1
Which is the wrong statement regarding a crystal containing Schottky defect?
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Correct option: C
The density of the overall crystal remains the same
Option C (The density of the overall crystal remains the same) is the wrong statement. Schottky defects involve missing ions, which reduces the density.
202 Easy
202 of 238
Remembering +4 | -1
In the fluorite structure, the coordination number of Ca2+C{a^{2 + }} ion is
View answer and explanation
Correct option: C
8
Option C (8) is correct because in the fluorite structure (CaF2CaF_2), each Ca2+Ca^{2+} ion is surrounded by 8 F−F^- ions, giving it a coordination number of 8.
203 Medium
203 of 238
Understanding +4 | -1
Potassium fluoride has NaClNaCl type structure. What is the distance between K+{K^ + } and F−{F^ - } ions if cell edge is aa cm?
View answer and explanation
Correct option: A
a2cm\frac{a}{2}\mathrm{cm}
Option A (a2cm\frac{a}{2}\mathrm{cm}) is correct because in a NaClNaCl type structure, the distance between nearest cation and anion is half of the cell edge.
204 Easy
204 of 238
Remembering +4 | -1
Which one of the following metal oxides is antiferromagnetic in nature?
View answer and explanation
Correct option: A
MnO2\mathrm{Mn}{\mathrm{O}_2}
Option D (Fe3O4F{e_3}{O_4}) is correct because it is a well-known example of a ferrimagnetic substance, exhibiting a net magnetic moment due to unequal alignment of magnetic moments.
205 Medium
205 of 238
Remembering +4 | -1
Which of crystal systems contains the maximum number of Bravais lattices?
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Correct option: D
Orthorhombic
Option D (Orthorhombic) is correct because the orthorhombic crystal system has the maximum number of Bravais lattices, which is 4.
206 Medium
206 of 238
Understanding +4 | -1
Statement I: Amorphous B2O3\mathrm{B}_2 \mathrm{O}_3 could be considered in the form of a liquid even thougn it looks like a solid, is rigid and shatters when struck with a hammer.

Statement II: B−O\mathrm {B -O} arrangement is random and B2O3\mathrm{B}_2 \mathrm{O}_3 is not crystalline.
View answer and explanation
Correct option: A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
Option A is correct because amorphous solids like B2O3B_2O_3 resemble liquids in their disordered structure, and this disorder is due to the random arrangement of B-O bonds, making it non-crystalline.
207 Easy
207 of 238
Remembering +4 | -1
The crystal are bounded by plane faces (f)(f), straight edges (e)(e) and interfacial angel (c)(c). The relationship between these is :
View answer and explanation
Correct option: A
f+c=e+2f + c = e + 2
Option A (f+c=e+2f + c = e + 2) is correct because it represents Euler's formula for polyhedra, relating the number of faces, edges, and corners in a crystal.
208 Easy
208 of 238
Understanding +4 | -1
In a crystal, the atoms are located at the position of ……….potential energy.
View answer and explanation
Correct option: C
Minimum
Option C (Minimum) is correct because atoms in a crystal lattice arrange themselves to minimize potential energy, leading to a stable configuration.
209 Medium
209 of 238
Application +4 | -1
CsBr\mathrm{CsBr} crystal has bcc structure. It has an edge length of 4.3 Å. The shortest interionic distance between Cs+\mathrm{C}{\mathrm{s}^ + } and Br−\mathrm{B}{\mathrm{r}^ - } ions is
View answer and explanation
Correct option: C
3.72A∘3.72A \circ
Option C (3.72A∘3.72A \circ) is correct because it's the calculated shortest interionic distance in a BCC structure.
210 Easy
210 of 238
Remembering +4 | -1
Packing efficiency of fcc lattice is
View answer and explanation
Correct option: A
π32\frac{\pi }{{3\sqrt 2 }}
Option A (π32\frac{\pi }{{3\sqrt 2 }}) is correct because it is the formula for packing efficiency in a face-centered cubic (fcc) lattice, derived from the ratio of the volume occupied by atoms to the total volume of the unit cell.
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