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JEE CHEMISTRY MCQ: SOLID STATE

1 Hard
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Application +4 | -1
Sodium metal crystallizes as a body centred cubic lattice with the cell edge 4.29A∘4.29{A^{^{^ \circ }}} What is the radius sodium atom?
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Correct option: A
1.857×10(−8)cm1.857\mathrm{ \times }{10^{( - 8)}}cm
Option A (1.857×10(−8)cm1.857\mathrm{ \times }{10^{( - 8)}}cm) is correct because the radius of the sodium atom in a BCC lattice is calculated using the formula r=3a4r = \frac{{\sqrt 3 a}}{4}, where a is the cell edge.

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