In ${CaF}_2$, fluorite type structure, ${F}^{-}$ions occupy

All the octahedral voids + half of tetrahedral voids

Possess orderly arrangement over long distances

The radius of $\mathrm{Li}^{+}$ion is $60 \mathrm{~pm}$ and that of $\mathrm{F}^{-}$is $136 \mathrm{~pm}$. Structure of $\mathrm{LiF}$ and coordination number is

Like $\mathrm{CsCl}, \mathrm{C} . \mathrm{Na}=8$

nti fluoride, $\mathrm{C} . \mathrm{No} .=8$

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JEE • CHEMISTRY • SOLID STATE

Solid state practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 199 questions

1 Easy

1 of 199

Remembering +4 | -1

{CaF}_2

, fluorite type structure,

{F}^{-}

ions occupy

View answer and explanation

Correct option: A

All the tetrahedral voids

Option A (All the tetrahedral voids) is correct because in the CaF2 fluorite structure, Ca2+ ions form the ccp lattice and F- ions occupy all the tetrahedral voids.

2 Medium

2 of 199

Analyzing +4 | -1

Consider a body centred cubic (BCC) arrangement, let

\mathrm{d}_{\mathrm{e}}

\mathrm{d}_{\mathrm{fd}}, \mathrm{d}_{\mathrm{bd}}

be the distances between successive atoms located along the edge, the face-diagonal, the body diagonal respectively in a unit cell. Their order is given by -

View answer and explanation

Correct option: C

\mathrm{d}_{\mathrm{fd}}>\mathrm{d}_{\mathrm{e}}>\mathrm{d}_{\mathrm{fd}}

Option D (d_bd > d_e > d_fd) is incorrect. The correct order is d_fd > d_e > d_bd because the face diagonal is longer than the edge, which is longer than the body diagonal when considering successive atoms.

3 Easy

3 of 199

Analyzing +4 | -1

A mineral having the formula

\mathrm{AB}_2

crystallizes in ccp lattice with

\mathrm{A}

atoms occupying the lattice points. Pick out the correct statements of the following

View answer and explanation

Correct option: A

100 \%

occupancy of tetrahedral voids, C.N. of

\mathrm{B}=4

Option A (100 % occupancy of tetrahedral voids, C.N. of B=4) is correct because in a ccp lattice with A atoms at lattice points, there are 4 A atoms per unit cell, requiring 8 B atoms to satisfy the AB2 formula. This means all 8 tetrahedral voids are occupied, and the coordination number of B in a tetrahedral void is 4.

4 Easy

4 of 199

Remembering +4 | -1

Which one of the following metal oxides is antiferromagnetic in nature?

View answer and explanation

Correct option: A

\mathrm{Mn}{\mathrm{O}_2}

Option A (

\mathrm{Mn}{\mathrm{O}_2}

) is correct because manganese dioxide (

\mathrm{Mn}{\mathrm{O}_2}

) exhibits antiferromagnetic behavior.

5 Easy

5 of 199

Remembering +4 | -1

Wax is an example of :

View answer and explanation

Correct option: C

Molecular crystal

Option C (Molecular crystal) is correct because wax consists of large organic molecules held together by weak intermolecular forces.

6 Medium

6 of 199

Understanding +4 | -1

The following is not a function of an impurity present in a crystal

View answer and explanation

Correct option: A

Establishing thermal equilibrium

Option A (Establishing thermal equilibrium) is correct because impurities do not directly contribute to establishing thermal equilibrium in a crystal.

7 Medium

7 of 199

Remembering +4 | -1

Which has no elements of symmetry?

View answer and explanation

Correct option: D

Triclinic

The correct answer is D (Triclinic) because the triclinic crystal system has no elements of symmetry, meaning it lacks rotational axes, mirror planes, and a center of inversion.

8 Easy

8 of 199

Remembering +4 | -1

Which among the following is an example of ferro magnetic compound

View answer and explanation

Correct option: C

Cr{O_2}

Correct Answer + Core Reason: Option C (

CrO_2

) is correct because chromium dioxide (

CrO_2

) is a well-known ferromagnetic material.

9 Hard

9 of 199

Analyzing +4 | -1

A compound of formula

{A_2}{B_3}

has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms?

View answer and explanation

Correct option: C

hcp lattice-

B

\frac{1}{3}

tetrahedral voids-

A

The correct answer is C (hcp lattice-

B

\frac{1}{3}

tetrahedral voids-

A

) because in an hcp lattice, the number of tetrahedral voids is twice the number of atoms, and the formula

{A_2}{B_3}

implies that A occupies 1/3 of the tetrahedral voids.

10 Medium

10 of 199

Understanding +4 | -1

In a face centred cubic cell, an atom at the face contributes to the unit cell

View answer and explanation

Correct option: B

\frac{1}{2}\;part

Option B is correct because in a face-centered cubic (FCC) unit cell, an atom located at the face center is shared by two unit cells, thus contributing only 1/2 to each unit cell.

11 Easy

11 of 199

Remembering +4 | -1

The number of atoms

\left( n \right)

contained within a body centred cubic cell is:

View answer and explanation

Correct option: B

Option B (2) is correct because a body-centered cubic cell has one atom at each of the 8 corners (each contributing 1/8) and one atom at the center, totaling 2 atoms.

12 Easy

12 of 199

Remembering +4 | -1

Amorphous solids:

View answer and explanation

Correct option: C

Do not undergo clean cleavage when cut with knife

The correct answer is C (Do not undergo clean cleavage when cut with knife) because amorphous solids lack long-range order and thus break irregularly.

13 Medium

13 of 199

Application +4 | -1

The radius of

\mathrm{Li}^{+}

ion is

60 \mathrm{~pm}

and that of

\mathrm{F}^{-}

136 \mathrm{~pm}

. Structure of

\mathrm{LiF}

and coordination number is

View answer and explanation

Correct option: A

\mathrm{NaCl}, \mathrm{C} . \mathrm{No} .=6

Option A (Like

\mathrm{NaCl}, \mathrm{C} . \mathrm{No} .=6

) is correct because the radius ratio falls within the range that favors an

\mathrm{NaCl}

structure with a coordination number of 6.

14 Easy

14 of 199

Remembering +4 | -1

A solid having no definite shape is called :

View answer and explanation

Correct option: A

Amorphous solid

Option A (Amorphous solid) is correct because a solid having no definite shape is called an amorphous solid.

15 Medium

15 of 199

Remembering +4 | -1

In which pair most efficient packing is present

View answer and explanation

Correct option: B

hcp and ccp

Option B (hcp and ccp) is correct because both hexagonal close-packed (hcp) and cubic close-packed (ccp) structures have the highest packing efficiency of 74%.

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16 Easy

16 of 199

Remembering +4 | -1

Crystals can be classified into ……. Basic crystal habits.

View answer and explanation

Correct option: A

Option A (7) is correct because crystals can be classified into 7 basic crystal habits.

17 Easy

17 of 199

Remembering +4 | -1

The crystal are bounded by plane faces

(f)

, straight edges

(e)

and interfacial angel

(c)

. The relationship between these is :

View answer and explanation

Correct option: A

f + c = e + 2

Option A (

f + c = e + 2

) is correct because it represents Euler's formula for polyhedra, relating faces, edges, and vertices (or interfacial angles in this context).

18 Easy

18 of 199

Analyzing +4 | -1

The cation-anion bond have the largest amount of covalent character for:

View answer and explanation

Correct option: C

\mathrm{CdS}

Option C (

\mathrm{CdS}

) is correct. CdS has the most covalent character due to the smaller size and higher polarizing power of Cd²⁺ compared to the other metal ions.

19 Medium

19 of 199

Understanding +4 | -1

For an ionic crystal of the general formula

AX

and coordination number 6, the value of radius ratio will be

View answer and explanation

Correct option: A

in between 0.732 and 0.414

Option A (in between 0.732 and 0.414) is correct because a coordination number of 6 corresponds to an octahedral geometry, which has a radius ratio range of 0.414 - 0.732.

20 Medium

20 of 199

Understanding +4 | -1

Select the incorrect statement

View answer and explanation

Correct option: D

Density of crystal always increases due to substitutional impurity defect

Option C (

1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^{10}},4{s^2}4{p^6}4{d^{10}},5{s^2}5{p^6}

) is correct because it represents a complete octet in the outermost shell, characteristic of noble gases.

21 Easy

21 of 199

Remembering +4 | -1

The statement that “All crystals of the same substance possess the same elements of symmetry” is known as :

View answer and explanation

Correct option: C

The law of constancy of symmetry

Option C (The law of constancy of symmetry) is correct because the statement that \"All crystals of the same substance possess the same elements of symmetry\" is known as the law of constancy of symmetry.

22 Medium

22 of 199

Application +4 | -1

An alloy of copper, silver and gold is found to have copper constituting the ccp lattice. If silver atoms occupy the edge centres and gold is present at body centre, the alloy has a formula

View answer and explanation

Correct option: C

\mathrm{C}{\mathrm{u}_4}\mathrm{A}{\mathrm{g}_3}\mathrm{Au}

Option C (

\mathrm{C}{\mathrm{u}_4}\mathrm{A}{\mathrm{g}_3}\mathrm{Au}

) is correct because the ratio of Cu, Ag, and Au atoms in the alloy is 4:3:1 based on their positions in the ccp lattice.

23 Medium

23 of 199

Remembering +4 | -1

Which type of crystal system contain only one Bravais lattice?

View answer and explanation

Correct option: A

Hexagonal

Option A (Hexagonal) is correct because the hexagonal crystal system has only one Bravais lattice, which is the primitive unit cell.

24 Medium

24 of 199

Application +4 | -1

A compound is formed by two elements

X

and

Y.

Atoms of the element

Y

(as anions) make ccp and those of the element

X

(as cations) occupy all the octahedral voids.
What is the formula of the compound ?

View answer and explanation

Correct option: A

XY

Option A (

XY

) is correct because the number of octahedral voids in a ccp lattice is equal to the number of atoms in the lattice, leading to a 1:1 ratio between X and Y.

25 Medium

25 of 199

Remembering +4 | -1

Germanium can be made n-type semiconductor by doping with

View answer and explanation

Correct option: B

Arsenic

Option B (Arsenic) is correct because doping germanium with a pentavalent element like arsenic creates an n-type semiconductor.

26 Medium

26 of 199

Application +4 | -1

A compound is formed by two elements

X

and

Y

. The element

Y

forms cubic close packed arrangement and those of element

X

occupy one third of the tetrahedral voids. What is the formula of the compound?

View answer and explanation

Correct option: A

X_{2} Y_{3}

Option A (

X_2Y_3

) is correct because if Y forms ccp, X occupies 1/3 of tetrahedral voids, leading to the formula

X_2Y_3

27 Medium

27 of 199

Analyzing +4 | -1

What is common in HCP and FCC unit cell?

View answer and explanation

Correct option: D

None of these

The correct answer is D (None of these) because there is nothing common between HCP and FCC unit cells from the given options.

28 Easy

28 of 199

Remembering +4 | -1

Crystals can be classified into ……. Basic crystal habits.

View answer and explanation

Correct option: A

Option A (7) is correct because crystals are classified into 7 basic crystal systems or habits: cubic, tetragonal, orthorhombic, monoclinic, triclinic, hexagonal, and rhombohedral.

29 Medium

29 of 199

Application +4 | -1

Which of the following combination gives

{AB}_2 {O}_4

type structure?

View answer and explanation

Correct option: D

Oxide ions at CCP,

A

ions at

\frac{1}{8}

th of tetrahedral voids and

B

ions at

\frac{1}{2}

of octahedral voids

The correct answer is "Oxide ions at CCP,

A

ions at

\frac{1}{8}

th of tetrahedral voids and

B

ions at

\frac{1}{2}

of octahedral voids" because this arrangement leads to the

AB_2O_4

stoichiometry.

30 Easy

30 of 199

Remembering +4 | -1

The arrangement ABCABC……is referred to as,

View answer and explanation

Correct option: D

Cubic close packing

Option D (Cubic close packing) is correct because the ABCABC... arrangement is characteristic of cubic close-packed (ccp) structures.

Revision notes and key takeaways

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Key Takeaways

✓ This set contains 199 single-correct-answer MCQs on SOLID STATE.
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