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NEET UG CHEMISTRY MCQ: SOLID STATE

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The distance between an octahedral and tetrahedral void in fcc lattice would be :-
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Correct option: D
3a4\frac{\sqrt{3} a}{4}
Option D (3a4\frac{{\sqrt 3 a}}{4}) is correct because it represents half the distance between the body center (octahedral void) and a corner (tetrahedral void) in an FCC lattice.

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