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NEET • CHEMISTRY • SOLID STATE

Solid state practice · Medium

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Showing 1-30 of 112 questions
1 Medium
1 of 112
Application +4 | -1
Calculate the ionic radius of a Cs+\mathrm{C}{\mathrm{s}^ + } ion, assuming that the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a CI−\mathrm{C}{\mathrm{I}^ - } ion is   0.181  nm\;0.181\,\,nm
View answer and explanation
Correct option: D
0.176nm0.176\mathrm{ }nm
Option D (0.176nm0.176\mathrm{ }nm) is correct because it's the calculated ionic radius of Cs+ based on the given information.
2 Medium
2 of 112
Remembering +4 | -1
In the unit cell of FCC system, the number of octahedral and tetrahedral holes are
View answer and explanation
Correct option: B
4,8
Option B (4, 8) is correct because in a face-centered cubic (FCC) unit cell, there are 4 octahedral holes and 8 tetrahedral holes.
3 Medium
3 of 112
Remembering +4 | -1
Which one of the following has Frenkel defect?
View answer and explanation
Correct option: B
AgBr\mathrm{AgBr}
Option B (AgBr) is correct because AgBr exhibits both Schottky and Frenkel defects due to the relatively small size of Ag+ ions, allowing them to occupy interstitial sites.
4 Medium
4 of 112
Application +4 | -1
If AgCl is doped with 10−6{10^{ - 6}} mol% of CdCl2CdC{l_2}, the concentration of cation vacancies will be
View answer and explanation
Correct option: C
6.02×1015 mol−16.02 \times {10^{15}}\,mo{l^{ - 1}}
Option C is correct because each CdCl2CdCl_2 introduces one cation vacancy in AgCl. The concentration of cation vacancies is equal to the concentration of CdCl2CdCl_2 which is 10−6{10^{-6}} mol% of AgCl.
5 Medium
5 of 112
Understanding +4 | -1
In the laboratory, sodium chloride is made by burning the sodium in the atmosphere of chlorine which is yellow in colour. The cause of yellow colour is
View answer and explanation
Correct option: A
Presence of electrons in the crystal lattice
Option A (Presence of electrons in the crystal lattice) is correct because the yellow color in NaCl crystals is due to F-centers, which are electrons trapped in anion vacancies.
6 Medium
6 of 112
Analyzing +4 | -1
Statement I: NiONiO is expected to have more defects than NaClNaCl.

Statement II: NaClNaCl is an ionic compound.
View answer and explanation
Correct option: B
Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I
Option B (Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I) is correct because NiO has more defects due to higher charge density and NaCl being ionic is a true statement, but not the reason for the defect difference.
7 Medium
7 of 112
Application +4 | -1
In a binary compound, atoms of element AA form a hcp structure and those of element MM occupy 2/32/3 of the tetrahedral voids of the hcp structure. The formula of the binary compound is
View answer and explanation
Correct option: B
M4A3{M_4}{A_3}
Option B (M4A3{M_4}{A_3}) is correct because in an HCP structure, the number of tetrahedral voids is twice the number of atoms, and 2/3 of these voids are occupied by M.
8 Medium
8 of 112
Understanding +4 | -1
6:6  NaCl6:6\,\,NaCl Co-ordination changes to 8:88:8 Co-ordination on
View answer and explanation
Correct option: A
Applying high pressure
Option A (Applying high pressure) is correct because applying high pressure favors structures with higher coordination numbers, causing the 6:6 NaCl coordination to change to 8:8.
9 Medium
9 of 112
Application +4 | -1
If the distance between Na+\mathrm{N}{\mathrm{a}^ + } and CI−\mathrm{C}{\mathrm{I}^ - } ions in NaCl crystal is ‘aa’ pm what is the length of the cell edge?
View answer and explanation
Correct option: C
2a  pm2a\,\,\mathrm{pm}
Option C (2a  pm2a\,\,\mathrm{pm}) is correct because in NaCl, the distance between Na+ and Cl- ions is half the cell edge length.
10 Medium
10 of 112
Understanding +4 | -1
Si doped with Sb is an example of ______ semi conductor. While the one which is doped with Ga is _____ type semi conductor
View answer and explanation
Correct option: A
n – type, p – type
Option A (n – type, p – type) is correct because Si doped with Sb (antimony, group 15) is n-type, and Si doped with Ga (gallium, group 13) is p-type.
11 Medium
11 of 112
Remembering +4 | -1
The structure of Na2O\mathrm{N}{\mathrm{a}_2}\mathrm{O} crystal is
View answer and explanation
Correct option: D
Antifluorite type
Option D (Antifluorite type) is correct because Na2O\mathrm{N}{\mathrm{a}_2}\mathrm{O} has a structure where the positions of cations and anions are reversed compared to the fluorite structure.
12 Medium
12 of 112
Understanding +4 | -1
Select the incorrect statement
View answer and explanation
Correct option: D
Density of crystal always increases due to substitutional impurity defect
Option D is the incorrect statement because substitutional impurity defects can either increase or decrease the density of the crystal, depending on the mass of the impurity.
13 Medium
13 of 112
Application +4 | -1
A compound is formed by element A and B is cubic. AA atoms are at the corners and BB atoms are at the face centre. What is the formula?
View answer and explanation
Correct option: C
AB3A B_3
Option C (AB3A B_3) is correct because A atoms at the corners contribute 1/8 each, totaling 1, and B atoms at the face centers contribute 1/2 each, totaling 3.
14 Medium
14 of 112
Application +4 | -1
The orthorhombic, the value of a,b,a,b, and cc are respectively 4.2A∘,6.8A∘4.2\mathop \mathrm{A}\limits^ \circ ,6.8\mathop \mathrm{A}\limits^ \circ and 8.3A∘.8.3\mathop \mathrm{A}\limits^ \circ . Given the molecular mass of the solute is 155 g mol−1\mathrm{mo}{\mathrm{l}^{ - 1}} and that of density is 3.3g/cc, the number of formula units per unit cell is
View answer and explanation
Correct option: C
4
Option C is correct because the number of formula units per unit cell (Z) is calculated using the formula Z = (ρ * V * NA) / M, where ρ is density, V is the volume of the unit cell, NA is Avogadro's number, and M is the molecular mass. The result is approximately 4.
15 Medium
15 of 112
Application +4 | -1
A solid is made of two elements XX and ZZ. The atoms ZZ are in ccp arrangement while the atom XX occupy all the tetrahedral sites. What is the formula of the compound?
View answer and explanation
Correct option: C
X2Z{X_2}Z
Option C is correct because in a ccp arrangement, there is one atom per lattice point, and the number of tetrahedral sites is twice the number of atoms. Therefore, if Z atoms are in ccp, there are 2Z tetrahedral sites occupied by X atoms, resulting in the formula X2Z.
16 Medium
16 of 112
Understanding +4 | -1
For an ionic crystal of the general formula AXAX and coordination number 6, the value of radius ratio will be
View answer and explanation
Correct option: A
in between 0.732 and 0.414
Option A (in between 0.732 and 0.414) is incorrect. The correct range is between 0.414 and 0.732 because a coordination number of 6 corresponds to an octahedral geometry, and the radius ratio for octahedral geometry falls within that range.
17 Medium
17 of 112
Analyzing +4 | -1
Assertion : No compound has both Schottky and Frenkel defects.

Reason : Both defects change the density of the solid.
View answer and explanation
Correct option: D
If both the Assertion and Reason are incorrect.
Option D (If both the Assertion and Reason are incorrect) is correct because a compound can have both Schottky and Frenkel defects under specific conditions, and only Schottky defects change the density of the solid significantly.
18 Medium
18 of 112
Application +4 | -1
The interionic distance for cesium chloride crystal will be
View answer and explanation
Correct option: D
32a\frac{{\sqrt 3 }}{2}a
Option D (32a\frac{{\sqrt 3 }}{2}a) is correct because in a CsCl structure, the interionic distance is half the body diagonal of the cubic unit cell.
19 Medium
19 of 112
Understanding +4 | -1
Which of the following compounds is likely to show both Frenkel and Schottky defects in its crystalline form?
View answer and explanation
Correct option: A
AgBrAgBr
Option A (AgBrAgBr) is correct because AgBrAgBr exhibits both Frenkel and Schottky defects due to the relatively small size of Ag+Ag^+ ions allowing them to occupy interstitial sites (Frenkel), and the possibility of missing ions (Schottky).
20 Medium
20 of 112
Understanding +4 | -1
The following is not a function of an impurity present in a crystal
View answer and explanation
Correct option: A
Establishing thermal equilibrium
Option A (Establishing thermal equilibrium) is correct because impurities do not directly establish thermal equilibrium; this is achieved through heat transfer processes.
21 Medium
21 of 112
Application +4 | -1
A metal has bcc structure and the edge length of its unit cell is 3.04A∘3.04\mathop \mathrm{A}\limits^ \circ. The volume of the unit cell in   cm3\;\mathrm{c}{\mathrm{m}^3} will be
View answer and explanation
Correct option: B
2.81×10−23  cm32.81 \times {10^{ - 23}}\;\mathrm{c}{\mathrm{m}^3}
Option B (2.81×10−23  cm32.81 \times {10^{ - 23}}\;\mathrm{c}{\mathrm{m}^3}) is correct because it is the volume of the unit cell calculated from the given edge length.
22 Medium
22 of 112
Analyzing +4 | -1
Assertion (A): Covalent crystal have the higher melting point.

Reason (R): Covalent bonds are stronger than ionic bonds.
View answer and explanation
Correct option: C
(A) is correct but (R) is not correct
Option C is correct because covalent crystals generally have high melting points due to the strong covalent bonds, but covalent bonds are not always stronger than ionic bonds (e.g., NaCl has a higher lattice energy than diamond).
23 Medium
23 of 112
Understanding +4 | -1
Select the correct statements.
(A) Crystalline solids have long range order.
(B) Crystalline solids are isotropic
(C) Amorphous solids are sometimes called pseudo solids
(D) Amorphous solids soften over a range of temperatures.
(E) Amorphous solids have a definite heat of fusion
Choose the most appropriate answer from the options given below
View answer and explanation
Correct option: D
(A), (C), (D) only
Option D ((A), (C), (D) only) is correct because crystalline solids have long-range order, amorphous solids are pseudo solids, and amorphous solids soften over a range of temperatures.
24 Medium
24 of 112
Remembering +4 | -1
The statement that, “It is possible to choose along the three co-ordinate axes unit distance a,b,ca,b,c not necessarily of the same length, such that the ratio of there intercepts of any plane in the crystal is given by in ma:nb:pcma:nb:pc where m,n,pm,n,p are either integral whole numbers including infinity or fraction of whole number” is known as :
View answer and explanation
Correct option: A
Hauy’s law of rationality of indices
Option A (Hauy’s law of rationality of indices) is correct because Hauy's law describes the rational relationship between intercepts of crystal planes and unit distances along crystal axes.
25 Medium
25 of 112
Understanding +4 | -1
In a face centred cubic cell, an atom at the face contributes to the unit cell
View answer and explanation
Correct option: B
12  part\frac{1}{2}\;part
Option B (12 part\frac{1}{2}\,part) is correct because an atom at the face of a face-centered cubic cell is shared by two unit cells.
26 Medium
26 of 112
Remembering +4 | -1
Which is an example of ferroelectric compound?
View answer and explanation
Correct option: C
Barium titanate
Option C (Barium titanate) is correct because Barium titanate (BaTiO3) is a well-known example of a ferroelectric compound.
27 Medium
27 of 112
Remembering +4 | -1
Gold crystallizes with a
View answer and explanation
Correct option: D
fcc
Option D (fcc) is correct because gold (Au) crystallizes in a face-centered cubic (fcc) structure.
28 Medium
28 of 112
Remembering +4 | -1
The percentages of void space for simple cubic, body centered cubic and hexagonal close packed arrangement respectively are
View answer and explanation
Correct option: A
48,32,26
Option A (48,32,26) is correct because the packing efficiencies for simple cubic, body-centered cubic, and hexagonal close-packed arrangements are 52%, 68%, and 74% respectively, leading to void spaces of 48%, 32%, and 26%.
29 Medium
29 of 112
Understanding +4 | -1
Right option for the ratio of number of octahedral voids and total octahedral and tetrahedral voids in face centred cubic unit cell is
View answer and explanation
Correct option: C
0.04375
Option C (0.04375) is correct because it accurately calculates the ratio of octahedral voids to the total number of octahedral and tetrahedral voids in an FCC unit cell.
30 Medium
30 of 112
Analyzing +4 | -1
Assertion (A): In NaCl{NaCl} crystal each Na+{Na}^{+}ion is touching 6 Cl−6 \, {Cl}^{-}ions but these Cl−{Cl}^{-}ions do not touch each other.

Reason (R): The radius ratio is greater than 0.414 required for exact fitting.
View answer and explanation
Correct option: A
Both (A) and (R) are correct and (R) is the correct explanation of (A)
Option A is correct because in NaCl, each Na+Na^+ ion is surrounded by 6 Cl−Cl^- ions, and the radius ratio is greater than 0.414, preventing the Cl−Cl^- ions from touching each other.
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