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NEET • BIOLOGY • PRINCIPLE OF INHERITANCE AND VARIATION

Principle of inheritance and variation practice · Medium

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151 Medium
151 of 188
Application +4 | -1
In Snapdragon, pure line tall plant with red flower was crossed with dwarf and white flowered plant; F1F_1 was test crossed to obtain F2F_2. What is the probability of getting progeny with dominant parental traits?
View answer and explanation
Correct option: D
0%0 \%
Option D (0%0 \%) is correct because a test cross of F1 (dihybrid) will not produce progeny with dominant parental traits if the genes are completely linked.
152 Medium
152 of 188
Remembering +4 | -1
Incomplete dominance is seen in?
View answer and explanation
Correct option: A
dog flower
Option A (dog flower) is correct because incomplete dominance is commonly observed in snapdragons (dog flower), where a heterozygous genotype results in a pink phenotype.
153 Medium
153 of 188
Remembering +4 | -1
Linkage group is
View answer and explanation
Correct option: A
Linearly arranged group of linked gene
Option A (Linearly arranged group of linked gene) is correct because a linkage group consists of genes that are physically located on the same chromosome and tend to be inherited together.
154 Medium
154 of 188
Understanding +4 | -1
Pedigree analysis indicated that Mendel’s principal are also applicable to …A… genetics with some modifications find out like …B… inheritance, sex linked inheritance and others.
Choose the correct option for AA and BB
View answer and explanation
Correct option: C
A-human; B-quantitative
The correct answer is C (A-human; B-quantitative) because pedigree analysis applies Mendel's principles to human genetics with modifications for quantitative inheritance.
155 Medium
155 of 188
Application +4 | -1
Probability of genotype TTrr in F2{\mathrm{F}_2}-generation of a dihybrid cross is
View answer and explanation
Correct option: A
116\frac{1}{{16}}
Option A (116\frac{1}{{16}}) is correct because in the F2 generation of a dihybrid cross, the probability of obtaining the TTrr genotype is 1/16.
156 Medium
156 of 188
Remembering +4 | -1
Jumping genes in maize were discovered by
View answer and explanation
Correct option: B
Barbara McClintock
Option B (Barbara McClintock) is correct because Barbara McClintock discovered jumping genes (transposons) in maize.
157 Medium
157 of 188
Remembering +4 | -1
Mendelism was rediscovered by
I. Morgan
II. De Vries
III. Correns
IV. Tschermark
Choose the correct option
View answer and explanation
Correct option: C
II, III and IV
Option C (II, III and IV) is correct because De Vries, Correns, and Tschermark independently rediscovered Mendel's work.
158 Medium
158 of 188
Remembering +4 | -1
Linkage group in E .coli is/are
View answer and explanation
Correct option: C
1
Option C (1) is correct because E. coli has a single, circular chromosome, thus only one linkage group.
159 Medium
159 of 188
Remembering +4 | -1
Emasculation is the removal of
View answer and explanation
Correct option: B
Anthers before dehiscence
The correct answer is B (Anthers before dehiscence) because emasculation involves removing the anthers from a flower before they release pollen (dehiscence) to prevent self-pollination.
160 Medium
160 of 188
Analyzing +4 | -1
Choose the incorrect statement regarding F2F_2 generation of Mendelian dibybrid cross.
View answer and explanation
Correct option: C
Heterozygous tall plants are present in 37.5%
Option A (Tall plants and round seeds are present in 1 : 1 ratio) is incorrect. The correct ratio is 3:1.
161 Medium
161 of 188
Application +4 | -1
In fruit flies, dumpy wings are shorter and broader than normal wings. The allele for normal wings (D) is dominant to the allele for dumpy wings (d). Seventy five normal-winged and twenty five dumpy-winged flies. The genotype of parents would be
View answer and explanation
Correct option: C
Dd and Dd
Option C (Dd and Dd) is correct because a cross between two heterozygotes will produce a 3:1 phenotypic ratio, which matches the given data.
162 Medium
162 of 188
Application +4 | -1
The total number of progeny obtained through dihybrid cross of Mendel is 1280 in F2{\mathrm{F}_2}-generation. How many are recombinants?
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Correct option: C
480
Option C (480) is correct because in a dihybrid cross, the recombinant phenotypes occur in 6/16 of the progeny. Therefore, with a total of 1280 progeny, the number of recombinants is (6/16) * 1280 = 480.
163 Medium
163 of 188
Remembering +4 | -1
Who clearly proved and define linkage?
View answer and explanation
Correct option: A
Morgan
Option A (Morgan) is correct because T.H. Morgan and his colleagues provided experimental evidence and clearly defined the concept of linkage through their work with Drosophila.
164 Medium
164 of 188
Application +4 | -1
A pure tall and a pure dwarf plant were crossed to produced offsprings. Offsprings were self crossed, then find out the ratio between true breeding tall to true breeding dwarf?
View answer and explanation
Correct option: A
1:11\mathrm{ }:\mathrm{ }1
Option A (1:11\mathrm{ }:\mathrm{ }1) is correct because after selfing the F1 generation (Tt), the F2 generation will have a 1:2:1 genotypic ratio (TT:Tt:tt), resulting in a 1:1 ratio of true-breeding tall (TT) to true-breeding dwarf (tt).
165 Medium
165 of 188
Application +4 | -1
A marriage between normal visioned man and colourblind woman will produce, which of the following types of offspring’s?
View answer and explanation
Correct option: B
Colourblind sons and carrier daughters
Option B (Colourblind sons and carrier daughters) is correct because the colourblind woman (XcXc) can only pass on the Xc allele, and the normal man (XY) passes on either X or Y, resulting in colourblind sons (XcY) and carrier daughters (XXc).
166 Medium
166 of 188
Understanding +4 | -1
Incomplete linkage is …A… . Complete linkage is …B… . Choose correct option for A and B
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Correct option: A
A-common, B-rare
Option A (A-common, B-rare) is correct because incomplete linkage allows for some recombination, making it more common, while complete linkage prevents recombination, making it rare.
167 Medium
167 of 188
Understanding +4 | -1
The phenotype of F1 hybrid resemble both of the parents in
View answer and explanation
Correct option: A
Co-dominance
Option A (Co-dominance) is correct because in co-dominance, both alleles are expressed equally in the heterozygote, resulting in a phenotype that resembles both parents.
168 Medium
168 of 188
Remembering +4 | -1
Principle or laws of inheritance were enunciated by
View answer and explanation
Correct option: A
Mendel
Option A (Mendel) is correct because Gregor Mendel is credited with formulating the principles or laws of inheritance through his experiments with pea plants.
169 Medium
169 of 188
Application +4 | -1
A plant heterozygous for three allelic pairs, undergoes selfing, then how many genotypes regarding these alleles will be produced in F1F_1 generation?
View answer and explanation
Correct option: D
27
Option D (27) is correct because for n heterozygous allelic pairs, the number of genotypes in the F1 generation after selfing is 3n3^n, and in this case, 33=273^3 = 27.
170 Medium
170 of 188
Remembering +4 | -1
Mendel was a
View answer and explanation
Correct option: B
Austrian monk
Option B (Austrian monk) is correct because Gregor Mendel was an Austrian monk known for his work on genetics.
171 Medium
171 of 188
Application +4 | -1
A normal woman, whose father was colour blind is married to a normal man. The sons would be
View answer and explanation
Correct option: B
50 % colour blind
Option B (50 % colour blind) is correct because the woman is a carrier, and there's a 50% chance her sons will inherit the colorblindness allele from her.
172 Medium
172 of 188
Understanding +4 | -1
Example of interagenic gene interaction is/are
View answer and explanation
Correct option: D
All of the above
Option D is correct because incomplete dominance, codominance, and multiple alleles are all examples of intergenic gene interactions.
173 Medium
173 of 188
Remembering +4 | -1
Disorder inherited as Mendel’s law of inheritance called
View answer and explanation
Correct option: A
Mendelian disorder
Option A (Mendelian disorder) is correct because Mendelian disorders are inherited according to Mendel's laws of inheritance, involving single genes with dominant or recessive patterns.
174 Medium
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Understanding +4 | -1
The possibility of a female becoming a haemophilia is …A… rare because mother of such a female has to be at least …B… and the father should be …C…
Choose the correct option for A, B and C
View answer and explanation
Correct option: A
A-extremely, B-carrier, C-haemophilic
Option A (A-extremely, B-carrier, C-haemophilic) is correct because a female can only have hemophilia if her mother is at least a carrier and her father is hemophilic.
175 Medium
175 of 188
Remembering +4 | -1
Night blindness can be corrected by giving vitamin- …A… but colour blindness can’t be cured because it is …B… disease.
Choose the correct option for A and B
View answer and explanation
Correct option: A
A-A; B-genetic
Option A (A-A; B-genetic) is correct because night blindness can be corrected by giving vitamin A, but color blindness is a genetic disease and cannot be cured by vitamins.
176 Medium
176 of 188
Understanding +4 | -1
Harmful mutation does not get eliminated from the gene pool because they are mainly
View answer and explanation
Correct option: A
Dominant, which have beneficial effect on population and carried by heterozygous individuals
Option A is correct because harmful dominant mutations can persist if they have a beneficial effect in heterozygotes, preventing their complete elimination.
177 Medium
177 of 188
Application +4 | -1
A normal women whose father was colourblind, is married to a normal man. The sons would be
View answer and explanation
Correct option: B
50% colourblind
The correct answer is B (50% colourblind) because the woman is a carrier, and the man is normal, resulting in a 50% chance of colorblind sons.
178 Medium
178 of 188
Application +4 | -1
In a H – W population, 16 % of population is provided with 400 ebony fruit flies , then the total population is ( Note : ebony is not a dominant trait )
View answer and explanation
Correct option: B
2500
The correct answer is B (2500) because if 16% of the population are ebony fruit flies, and that number is 400, then the total population can be calculated.
179 Medium
179 of 188
Analyzing +4 | -1
Linked Gene pair Cross Over Value (COV)
T and U 25
T and V 5
V and U 30
U and W 10
V and W 20
COV are given for linked gene pair. Find out their sequence in the chromosome
View answer and explanation
Correct option: A
VTWU
Option D (VWTU) is correct because the gene sequence is determined by minimizing the distances between adjacent genes based on the given crossover values.
180 Medium
180 of 188
Analyzing +4 | -1
A diseased man marries a normal woman and they get three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this disease is
View answer and explanation
Correct option: A
Sex-linked dominant
Option D (Both (A) and (R) are false) is correct because X-linked recessive traits show transmission from carrier female to male progeny and exhibit crisscross inheritance.
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