Crossing the ${{\rm{F}}_1}$-hybrid with a double recessive genotype

Crossing between two genotypes with recessive trait

Crossing between two ${{\rm{F}}_1}$-hybrids

Crossing between two genotypes with dominant trait

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NEET • BIOLOGY • PRINCIPLE OF INHERITANCE AND VARIATION

Principle of inheritance and variation practice · Medium

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91 Medium

91 of 188

Analyzing +4 | -1

How many statements are correct according to given type of cross:

Aa Bb Cc DD X Aa Bb Cc DD

a. It is trihybrid cross

b. It is tetrahybrid cross

c. 8 Types of gametes are formed

d. 9 types of genotypes are formed

View answer and explanation

Correct option: C

Option B (Sex-linked dominant) is correct because all daughters inherit the affected X chromosome from their father and express the disease, while sons inherit the Y chromosome and are unaffected.

92 Medium

92 of 188

Application +4 | -1

A color blind woman marries a normal visioned male. In the offspring

View answer and explanation

Correct option: D

All sons are color blind and daughters are carriers

Option D (All sons are color blind and daughters are carriers) is correct because the color-blind woman can only pass on the colorblindness allele, making all sons colorblind and all daughters carriers.

93 Medium

93 of 188

Remembering +4 | -1

The specific pair of chromosomes which determine the sex of the individual called

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because sex chromosomes are also known as allosomes or heterosomes.

94 Medium

94 of 188

Application +4 | -1

Types of gametes formed by the plant with genotypes AABbccDD will be

View answer and explanation

Correct option: D

Option D (2) is correct because only the 'c' locus is heterozygous (Bbcc), so the number of gametes is

2^n = 2^1 = 2

95 Medium

95 of 188

Application +4 | -1

Tall (T) is completely dominant over dwarf (t). Red flower colour (R) is incompletely dominant over white (r),
the heterozygote being pink. Plant having genotype of TtRr is self pollinated. What would be the proportion
of plants with both dwarf and pink characters in its progeny?

View answer and explanation

Correct option: A

2 out of 16 plants

Option A (2 out of 16 plants) is correct because the proportion of dwarf and pink plants is determined by considering the independent assortment of the two genes and the incomplete dominance of the flower color.

96 Medium

96 of 188

Analyzing +4 | -1

A plant of

{\mathrm{F}_1}

- generation has genotype ‘AABbCC’. On selfing of this plant, the phenotypic ratio in

{\mathrm{F}_2}

- generation will be

View answer and explanation

Correct option: C

Multiple allelism

The question is flawed. The correct answer should be a dihybrid cross ratio of 3:1 for the Bb gene, since the other genes are homozygous. The provided answer is incorrect.

97 Medium

97 of 188

Remembering +4 | -1

Universal donor is

View answer and explanation

Correct option: B

\mathrm{O R}{\mathrm{h}^ - }

Option B (

\mathrm{O R}{\mathrm{h}^ - }

) is correct because individuals with blood type O Rh-negative lack A, B, and Rh antigens, making their blood compatible with most recipients.

98 Medium

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Understanding +4 | -1

Telomere repetitive DNA sequences control the function of eukaryotic chromosomes because they

View answer and explanation

Correct option: D

Prevent chromosome loss

Option D (Prevent chromosome loss) is correct because telomeres are repetitive DNA sequences at the ends of chromosomes that protect them from degradation and fusion, thus preventing chromosome loss.

99 Medium

99 of 188

Understanding +4 | -1

During …A… both members of chromosome pair as well as …B… separate and pass to different gametes. Choose the correct option for A and B

View answer and explanation

Correct option: B

A-meiosis; B-allele pair

Option B (A-meiosis; B-allele pair) is correct because during meiosis, both members of a chromosome pair, as well as allele pairs, separate and pass to different gametes.

100 Medium

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Understanding +4 | -1

Pure tall plants are crossed with pure dwarf plants. In the

{\mathrm{F}_1}

-generation, all plants were tall. These tall plants of

{\mathrm{F}_1}

-generation were selfed and the ratio of tall to dwarf plants obtained was 3: 1. This is called

View answer and explanation

Correct option: A

Dominance

The correct answer is A (Dominance) because the observation that all F1 plants were tall and the F2 generation had a 3:1 ratio of tall to dwarf plants demonstrates the principle of dominance, where the tall allele masks the dwarf allele.

101 Medium

101 of 188

Analyzing +4 | -1

In a normal couple, half of the sons are haemophilic while half of the daughters are carriers, the defective gene is located on

View answer and explanation

Correct option: B

One X-chromosome of mother

Option C (Phenylketonuria) is correct because Phenylketonuria is a single-gene (Mendelian) disorder caused by a mutation in the PAH gene, while Down's, Turner's, and Klinefelter's syndromes are chromosomal disorders.

102 Medium

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Application +4 | -1

Red flower (RR) are dominant over white flowers (rr). Tall plants (TT) are dominant over dwarf plants (tt). If a plant with genotype TTRr is crossed with ttrr plant, then what percentage will have red flowers on tall plants:

View answer and explanation

Correct option: C

50 \%

Option C (

50 \%

) is correct because the cross TTRr x ttrr will produce 50% tall plants with red flowers (TtRr).

103 Medium

103 of 188

Analyzing +4 | -1

Mendel could not find out linkage because
I. some genes are linked but they are too far apart for crossing over to be distinguished from independent assortment
II. linked genes, were never tested for the same time in same cross
III. all seven genes, were present on the same chromosomes
IV. all seven genes were present on 4 chromosome but they were present far apart
Find out the correct option

View answer and explanation

Correct option: A

I and II

Option A (I and II) is correct because Mendel's genes were either unlinked or far enough apart on the same chromosome that linkage was not detected, and he did not test all seven genes in the same cross simultaneously.

104 Medium

104 of 188

Application +4 | -1

A colour blind man marries a woman with normal sight who has no history of colour blindness in her family. What
Is the probability of their grandson being colour blind?

View answer and explanation

Correct option: B

0.5

Option A (0.25) is correct because the grandson's probability of being colourblind depends on his mother (the daughter of the colourblind man) being a carrier and passing the recessive allele to her son.

105 Medium

105 of 188

Analyzing +4 | -1

Three children in a family have blood types O, AB and B respectively. What are the genotypes of their parents?

View answer and explanation

Correct option: A

{\mathrm{I}^\mathrm{A}}\mathrm{i and}{\mathrm{I}^\mathrm{B}}\mathrm{i}

Option A (

{\mathrm{I}^\mathrm{A}}\mathrm{i and}{\mathrm{I}^\mathrm{B}}\mathrm{i}

) is correct because this combination of parental genotypes allows for all three blood types (O, AB, and B) to be present in the offspring.

Explore Other Chapters in BIOLOGY

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ANIMAL KINGDOM 756 MCQs PLANT KINGDOM 415 MCQs ANATOMY OF FLOWERING PLANTS 404 MCQs MOLECULAR BASIS OF INHERITANCE 404 MCQs CHEMICAL COORDINATION AND INTEGRATION 387 MCQs EVOLUTION 362 MCQs

106 Medium

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Understanding +4 | -1

Test cross involves

View answer and explanation

Correct option: C

Crossing the

{\mathrm{F}_1}

-hybrid with a double recessive genotype

The correct answer is C (Crossing the

{\mathrm{F}_1}

-hybrid with a double recessive genotype) because a test cross involves crossing an F1 hybrid with a homozygous recessive individual to determine the genotype of the F1 hybrid.

107 Medium

107 of 188

Analyzing +4 | -1

Assertion: In Cucurbita pepo, variety of fruit is
result of recessive epistasis.

Reason: In recessive epistatsis, a recessive gene
at one locus enhances the expression of another
gene, at a different locus.

View answer and explanation

Correct option: D

If both Assertion and Reason are false

Option D (If both Assertion and Reason are false) is correct because in Cucurbita pepo, fruit shape is determined by dominant epistasis, not recessive, and recessive epistasis involves a recessive gene masking the expression of another gene, not enhancing it.

108 Medium

108 of 188

Application +4 | -1

In a cross of four O’clock plants in the progeny half pink flower plants and half white flower plants are produced, the genotype of plant crossed is

View answer and explanation

Correct option: C

{R^1}{r^2} \times {r^2}{r^2}

Option C (

{R^1}{r^2} \times {r^2}{r^2}

) is correct because this cross produces half pink (

{R^1}{r^2}

) and half white (

{r^2}{r^2}

) offspring.

109 Medium

109 of 188

Understanding +4 | -1

The TWO horizontal lines between a male and female in pedigree analysis indicates

View answer and explanation

Correct option: D

Consanguineous mating

Option D (Consanguineous mating) is correct because two horizontal lines in pedigree analysis specifically indicate mating between closely related individuals.

110 Medium

110 of 188

Application +4 | -1

A violet flowered pea plant is crossed with white flowered pea plant. In

F_1

generation, violet flowered and white flowered plants were produced in

1: 1

ratio. If violet flowered plants of this generation is self crossed then what would be the percentage of pea plant in

F_2

generation which are true-breeding violet flowered?

View answer and explanation

Correct option: C

25 \%

Option C (

25 \%

) is correct because only the homozygous dominant offspring from the self-cross will be true-breeding violet flowered.

111 Medium

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Analyzing +4 | -1

A woman is married for the second time. Her first husband was ABO blood type A, and her child by that marriage was type O. Her new husband is type B and their child is type AB.
What is the women’s ABO genotype and blood type?

View answer and explanation

Correct option: A

{\mathrm{I}^\mathrm{A}}{\mathrm{I}^\mathrm{O}};\mathrm{Blood type A}

Option A (

{\mathrm{I}^\mathrm{A}}{\mathrm{I}^\mathrm{O}};\mathrm{Blood type A}

) is correct because the woman must have an

I^O

allele to produce a child with blood type O with her first husband, who has blood type A.

112 Medium

112 of 188

Analyzing +4 | -1

If Mendel had studied 7 traits using a plant of 12 chromosomes instead of 14
Choose the correct option for probable result

View answer and explanation

Correct option: C

He would have not discovered independent assortment

Option C (He would have not discovered independent assortment) is correct because with fewer chromosomes, linked genes would be more prevalent, obscuring independent assortment.

113 Medium

113 of 188

Understanding +4 | -1

Centromere is required for

View answer and explanation

Correct option: D

Movement of chromosomes towards poles

Option D (Movement of chromosomes towards poles) is correct because the centromere is the point of attachment for spindle fibers, which are essential for chromosome movement during cell division.

114 Medium

114 of 188

Application +4 | -1

If a couple who are carriers for sickle cell
anaemia, decide to become parents, what
will be the odds that their children will also
be carriers?

View answer and explanation

Correct option: B

2 out of 4

Option B (2 out of 4) is correct because when both parents are carriers (heterozygous), there's a 50% (2/4) chance their child will also be a carrier.

115 Medium

115 of 188

Application +4 | -1

Tt is crossed with ______ to give both tall and dwarf progeny in equal number

View answer and explanation

Correct option: C

Option C (tt) is correct because a cross between Tt and tt will produce Tt (tall) and tt (dwarf) progeny in equal numbers.

116 Medium

116 of 188

Remembering +4 | -1

Which of the following law was discovered first by Mendel?

View answer and explanation

Correct option: B

Law of segregation

Option B (Law of segregation) is correct because the law of segregation was the first law discovered by Mendel, based on his monohybrid crosses.

117 Medium

117 of 188

Remembering +4 | -1

Which of the following genes show the hetertozygous condition?

View answer and explanation

Correct option: A

Option A (Rr) is correct because the heterozygous condition is defined by having two different alleles for a gene, represented as Rr.

118 Medium

118 of 188

Understanding +4 | -1

In a dihybrid cross between RRYY and rryy parents, the number of RrYy genotypes in

{F_2}

generation will be

View answer and explanation

Correct option: A

Option A (4) is correct because in a dihybrid cross, the RrYy genotype appears in the F2 generation as a result of independent assortment and recombination.

119 Medium

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Remembering +4 | -1

Ratio observed in dihybrid cross (phenotypically)

View answer and explanation

Correct option: D

9\mathrm{ }:\mathrm{ }3\mathrm{ }:\mathrm{ }3\mathrm{ }:1

Option D (

9\mathrm{ }:\mathrm{ }3\mathrm{ }:\mathrm{ }3\mathrm{ }:1

) is correct because the phenotypic ratio observed in a dihybrid cross, where both parents are heterozygous for two traits, is 9:3:3:1.

120 Medium

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Analyzing +4 | -1

Assertion : A women can go to the court if a
man refuses to own his child. He has blood
group B and women has A while child has O.

Reason : Genetically she is right he can be
father of the child.

View answer and explanation

Correct option: A

If both Assertion and Reason are true and
Reason is the correct explanation of Assertion

Option A is correct because both the assertion and the reason are true, and the reason correctly explains the assertion. The blood groups of the parents and child are genetically possible.

Revision notes and key takeaways

Review PRINCIPLE OF INHERITANCE AND VARIATION in your textbook or class notes, then use this set to check your understanding.

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