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NEET • BIOLOGY • PRINCIPLE OF INHERITANCE AND VARIATION

Principle of inheritance and variation practice · Mixed difficulty

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Showing 181-210 of 365 questions

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181 Easy
181 of 365
Understanding +4 | -1
Linkage groups are always present on the
View answer and explanation
Correct option: A
Homologous chromosomes
Option A (Homologous chromosomes) is correct because linkage groups are formed by genes present on the same homologous chromosome.
182 Medium
182 of 365
Remembering +4 | -1
Fruitfly is excellent model for genetics because of
I. Small life cycle (two week)
II. Can be feed on simple synthesis medium
III. Single mating produce large number of progeny
IV. Clear differentiation of sexes
V. Many heredity variation can be seen with low power microscopes
Choose the correct option
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because fruit flies have a short life cycle, can be easily fed, produce many offspring, have clear sex differentiation, and exhibit easily observable hereditary variations.
183 Easy
183 of 365
Understanding +4 | -1
When two genetic loci produce identical phenotypes in cis and trans position, they are considered to be
View answer and explanation
Correct option: A
Pseudoalleles
Option A (Pseudoalleles) is correct because pseudoalleles produce identical phenotypes in both cis and trans configurations.
184 Hard
184 of 365
Remembering +4 | -1
XXY genotype shows:
View answer and explanation
Correct option: B
Hermaphrodite
Option A (Male) is correct because XXY genotype results in Klinefelter's syndrome, which is a male phenotype.
185 Easy
185 of 365
Application +4 | -1
A normal woman whose father was colour blind is married to a normal man. The sons would be
View answer and explanation
Correct option: B
50% color blind
The correct answer is B (50% color blind) because the woman is a carrier, and the man is normal, resulting in a 50% chance of colorblind sons.
186 Easy
186 of 365
Application +4 | -1
Mahesh (who is colourblind) and Soni (who is not colourblind) have a daughter Alia. Rishi (who is not
colourblind) and Neetu (who is a carrier) have a son Ranbeer. Alia and Ranbeer get married. What is the
probability that their daughter will be colorblind?
View answer and explanation
Correct option: B
0.25
The correct answer is B (0.25) because the probability of their daughter being colorblind depends on Alia being a carrier and Ranbeer passing on the colorblind allele.
187 Medium
187 of 365
Remembering +4 | -1
Incomplete dominance is shown by
View answer and explanation
Correct option: B
MirabilisMirabilis
Option B (MirabilisMirabilis) is correct because Mirabilis jalapa (Four O'Clock plant) is a classic example of incomplete dominance, where the heterozygous offspring show an intermediate phenotype.
188 Hard
188 of 365
Analyzing +4 | -1
Genes A, B and C are linked. Genes A and B are more close than A and C. Find out the correct option for the given statements
I. A might be before B and C
II. B might be between A and C
III. C might be between A and B
IV. More crosses has occurred between A and C than A and B
View answer and explanation
Correct option: D
I, II and IV
Option D (I, II and IV) is correct because if A and B are closer than A and C, then A might be before B and C, B might be between A and C, and more crosses have occurred between A and C than A and B.
189 Medium
189 of 365
Understanding +4 | -1
When both parents are of blood type AB, they can have children with
View answer and explanation
Correct option: B
A, B, and AB blood types
Option B (A, B, and AB blood types) is correct because parents with AB blood type can produce offspring with A, B, or AB blood types, but not O.
190 Easy
190 of 365
Remembering +4 | -1
Identify a Mendelian disorder from the following.
View answer and explanation
Correct option: C
Phenylketonuria
Option B (One X-chromosome of mother) is correct because the mother must be a carrier (XhX) and passes on the Xh chromosome to half of her sons, making them haemophilic, and to half of her daughters, making them carriers.
191 Medium
191 of 365
Remembering +4 | -1
In which genetic condition, each cell in the affected person has only one sex chromosome, i.e. XO?
View answer and explanation
Correct option: A
Turner’s syndrome
Option A (Turner’s syndrome) is correct because Turner's syndrome is characterized by having only one sex chromosome (XO).
192 Medium
192 of 365
Remembering +4 | -1
Phenylketonuria, Huntington’s disease and sickle cell anaemia are caused respectively due to disorders associated with
View answer and explanation
Correct option: D
Chromosome-12, chromosome-4 and chromosome-11
Option D (Chromosome-12, chromosome-4 and chromosome-11) is correct because Phenylketonuria is associated with chromosome-12, Huntington’s disease with chromosome-4 and sickle cell anaemia with chromosome-11.
193 Medium
193 of 365
Analyzing +4 | -1
A colorblind man with hypertrichosis married a woman whose mother is homozygousnormal visioned and
father is colorblind. Then in their progeny
View answer and explanation
Correct option: B
Half of the male children are with both colorblindness and hypertrichosis
Option B (Half of the male children are with both colorblindness and hypertrichosis) is correct because it considers the inheritance patterns of both X-linked colorblindness and Y-linked hypertrichosis.
194 Hard
194 of 365
Application +4 | -1
How many gametes can be produced by a diploid organism, if it is heterozygous for 4 loci?
View answer and explanation
Correct option: C
1616
Option C (1616) is correct because the number of gametes produced by a diploid organism heterozygous for 4 loci is 24=162^4 = 16.
195 Medium
195 of 365
Analyzing +4 | -1
How many statements are correct according to given type of cross:

Aa Bb Cc DD X Aa Bb Cc DD

a. It is trihybrid cross

b. It is tetrahybrid cross

c. 8 Types of gametes are formed

d. 9 types of genotypes are formed
View answer and explanation
Correct option: C
2
Option B (Sex-linked dominant) is correct because all daughters inherit the affected X chromosome from their father and express the disease, while sons inherit the Y chromosome and are unaffected.
196 Medium
196 of 365
Application +4 | -1
A color blind woman marries a normal visioned male. In the offspring
View answer and explanation
Correct option: D
All sons are color blind and daughters are carriers
Option D (All sons are color blind and daughters are carriers) is correct because the color-blind woman can only pass on the colorblindness allele, making all sons colorblind and all daughters carriers.
197 Hard
197 of 365
Understanding +4 | -1
Assertion (A): Multiple alleles can be found only when population studies are made.

Reason (R): Occasionally, a single gene product may produce more than one effect.
View answer and explanation
Correct option: B
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
Option B (Both (A) & (R) are true but the (R) is not the correct explanation of the (A)) is correct because while both statements are true, the reason does not explain why multiple alleles are found through population studies.
198 Medium
198 of 365
Remembering +4 | -1
The specific pair of chromosomes which determine the sex of the individual called
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because sex chromosomes are also known as allosomes or heterosomes.
199 Medium
199 of 365
Application +4 | -1
Types of gametes formed by the plant with genotypes AABbccDD will be
View answer and explanation
Correct option: D
2
Option D (2) is correct because only the 'c' locus is heterozygous (Bbcc), so the number of gametes is 2n=21=22^n = 2^1 = 2.
200 Medium
200 of 365
Application +4 | -1
Tall (T) is completely dominant over dwarf (t). Red flower colour (R) is incompletely dominant over white (r),
the heterozygote being pink. Plant having genotype of TtRr is self pollinated. What would be the proportion
of plants with both dwarf and pink characters in its progeny?
View answer and explanation
Correct option: A
2 out of 16 plants
Option A (2 out of 16 plants) is correct because the proportion of dwarf and pink plants is determined by considering the independent assortment of the two genes and the incomplete dominance of the flower color.
201 Easy
201 of 365
Remembering +4 | -1
Linked gene are present on
View answer and explanation
Correct option: A
Same chromosome
Option A (Same chromosome) is correct because linked genes, by definition, are located on the same chromosome.
202 Easy
202 of 365
Remembering +4 | -1
Mendel’s experimental material was
View answer and explanation
Correct option: A
Pisum sativum
Option A is correct because Mendel conducted his famous genetics experiments using the garden pea, Pisum sativum.
203 Easy
203 of 365
Understanding +4 | -1
If a genetic disease is transferred from a phenotypically normal but carrier female to only some of
the male progeny, the disease is
View answer and explanation
Correct option: D
Sex-linked recessive
Option D (Sex-linked recessive) is correct because the disease is transferred from a carrier female (meaning she has one copy of the recessive allele) to only some of her male progeny, which is characteristic of X-linked recessive inheritance.
204 Medium
204 of 365
Analyzing +4 | -1
A plant ofF1{\mathrm{F}_1}- generation has genotype ‘AABbCC’. On selfing of this plant, the phenotypic ratio in F2{\mathrm{F}_2}- generation will be
View answer and explanation
Correct option: C
Multiple allelism
The question is flawed. The correct answer should be a dihybrid cross ratio of 3:1 for the Bb gene, since the other genes are homozygous. The provided answer is incorrect.
205 Medium
205 of 365
Remembering +4 | -1
Universal donor is
View answer and explanation
Correct option: B
ORh−\mathrm{O R}{\mathrm{h}^ - }
Option B (ORh−\mathrm{O R}{\mathrm{h}^ - }) is correct because individuals with blood type O Rh-negative lack A, B, and Rh antigens, making their blood compatible with most recipients.
206 Medium
206 of 365
Understanding +4 | -1
Telomere repetitive DNA sequences control the function of eukaryotic chromosomes because they
View answer and explanation
Correct option: D
Prevent chromosome loss
Option D (Prevent chromosome loss) is correct because telomeres are repetitive DNA sequences at the ends of chromosomes that protect them from degradation and fusion, thus preventing chromosome loss.
207 Medium
207 of 365
Understanding +4 | -1
During …A… both members of chromosome pair as well as …B… separate and pass to different gametes. Choose the correct option for A and B
View answer and explanation
Correct option: B
A-meiosis; B-allele pair
Option B (A-meiosis; B-allele pair) is correct because during meiosis, both members of a chromosome pair, as well as allele pairs, separate and pass to different gametes.
208 Hard
208 of 365
Remembering +4 | -1
How many matching are corrects:

a. Haemophilia - Queen victoria pedigree

b. Phenylketonuria - Inborn error of metabolism

c. Colour blindness - More appears in female than male

d. Sickel cell anaemia - Shape of RBC is biconvex disc
View answer and explanation
Correct option: C
2
Option C (2) is correct because Haemophilia is indeed associated with Queen Victoria's pedigree, and Phenylketonuria is an inborn error of metabolism. Colour blindness is more common in males, and sickle cell anemia results in sickle-shaped RBCs, not biconvex discs.
209 Medium
209 of 365
Understanding +4 | -1
Pure tall plants are crossed with pure dwarf plants. In the F1{\mathrm{F}_1}-generation, all plants were tall. These tall plants of F1{\mathrm{F}_1}-generation were selfed and the ratio of tall to dwarf plants obtained was 3: 1. This is called
View answer and explanation
Correct option: A
Dominance
The correct answer is A (Dominance) because the observation that all F1 plants were tall and the F2 generation had a 3:1 ratio of tall to dwarf plants demonstrates the principle of dominance, where the tall allele masks the dwarf allele.
210 Medium
210 of 365
Analyzing +4 | -1
In a normal couple, half of the sons are haemophilic while half of the daughters are carriers, the defective gene is located on
View answer and explanation
Correct option: B
One X-chromosome of mother
Option C (Phenylketonuria) is correct because Phenylketonuria is a single-gene (Mendelian) disorder caused by a mutation in the PAH gene, while Down's, Turner's, and Klinefelter's syndromes are chromosomal disorders.
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